ASP DateDiff
I face that problems
07/01/2003 06/30/2006 ---------> it should be 3
01/01/2003 02/28/2005 --------->could i get 2 years and 2 months
01/01/2003 03/01/2005 --------->could i get 2 years and 2 months and 1
day
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DateDiff
I am trying to replicate the Ebay Time Left on Auction.
1 Day, 1 hour, 12 minutes.
I would like to calculate this from the current time and date. How do I get
this result?
Datediff
Code:
Set rs = objconn.Execute ("SELECT * FROM members WHERE UserID =" & UserID )
iMinute = DateDiff("n", Now, rs("LastLogin")) 'Find amount of minutes...
iHour = DateDiff("h", Now, rs("LastLogin")) 'Find the amount of hours...
iDay = DateDiff("d", Now, rs("LastLogin")) 'Find the amount of days...
iMonth = DateDiff("m", Now, rs("LastLogin")) 'Find the amount of months...
response.Write(iMinute)
response.End()
is this correct? is doesn't look right what is brings back
DateDiff
I am trying to replicate the Ebay Time Left on Auction. 1 Day, 1 hour, 12 minutes. I would like to calculate this from the current time and date. How do I get this result?
View Replies View RelatedA DateDiff() Question
I'm creating a Help Desk Call Track System... one of the fields we want to store is the length of time the call was "Open." When the call is logged, the Now function is used to pull the date in vbGeneralDate format. When the call is closed, Now is again used to pull the date in the same format.
Our current system uses hours to track calls
To give an example of what is making it to the database...
BeginDate = 2/5/2004 2:19:40 PM
EndDate = 2/5/2004 2:20:09 PM
Then I do this calculation...
Duration = DateDiff("h",BeginDate,EndDate)
The value stored in the database is...
Duration = 14
I'm assuming that it is reading back to 12:00 AM and counting the hours up till 2:00 PM. I'd like to be able to do fractions of hours (displayed in decimals).
Error On Datediff
Can someone tell me why this date range can't function for date diff?
Code : datediff("w","6/10/2005","6/16/2005", vbSunday)
It return 0 instead of the correct value is 1 !!
Why?
I have try others day, it goes well but just this date range ....
Datediff Problem
i have an if else satemement and this part here checks to see if today's date is eactly two weeks away from the expirydate in the database.... however nothing happens so when i did a resopopnse.write i got the datediff difference of 223 ??!! how do i solve this problem?
ElseIf DateDiff("d", FormatMediumDate(created), FormatMediumDate(objRS("ExpiryDate"))) = 14 Then
Response.Write "<div class='Change7'><font color='#FF0000'><b>"&FormatMediumDate(objRS("ExpiryDate"))&"</b</font></div>"
DateDiff Function.
taken from hafiz's thread. i've got problem to check the user's last ectivity which is more than 20 minutes.which one is correct??? this one:Code:
'check if current user's last activity was more than 20 minutes ago
If Abs(DateDiff("n", rs1("LastActivity"), Now()))> 10 Then
or this one Code:
If Abs(DateDiff("n", Now(), rs1("LastActivity")))> 10 Then
the LastActivity datatype is a Text?
Problem With Datediff()
i have a problem with datediff(), it works fine when i run it on my system iis but online its giving unexpected results. for eg.
checkin=30/04/2005
checkout=01/05/2005
nights=datediff("D",checkin,checkout)
result should be "1"
but its giving "-115"
pls. give me a clue to solve this.
Datediff Problem
i have an if else satemement and this part here checks to see if today's date is eactly two weeks away from the expirydate in the database.... however nothing happens so when i did a resopopnse.write i got the datediff difference of 223 ??!! how do i solve this problem?
PHP Code:
ElseIf DateDiff("d", FormatMediumDate(created), FormatMediumDate(objRS("ExpiryDate"))) = 14 Then Response.Write "<div class='Change7'><font color='#FF0000'><b>"&FormatMediumDate(objRS("ExpiryDate"))&"</b</font></div>"
DATEDIFF Calendar
I have a calendar that I am trying to make users fill out a form if their entry is inside the current week. Is there a datediff code that anyone knows of that can do this?
View Replies View RelatedSQL Problem With DateDiff (7 Days Old)
I want to be able to pull all the records from a table "Accounts" which are more than 7 days old. The attribute "DateCreated" stores the date the account was created.
I've tried "SELECT * FROM Accounts WHERE DateDiff('dd', DateCreated, Now()) > 7" but this is coming up with an error (I'm using MS Access db by the way)
Any ideas or help?
Select Statement And DateDiff
i need select statements that counts records from my access database where the time difference is worked out between two fields (datein;dateclosed). Less than 24 hours, >3 days, >5 days, >10 days, >15 days, >30 days, >60 days, >90 days
i am not sure how to construct the statement. If i can just get one, i can hopefully do the rest.
i have now:
strSQL2 = "SELECT Count(*) As Total FROM ptqr WHERE DateDiff('d','" & datein_now & "','" & dateclosed &"')< 1 "
but i get an error:
Microsoft OLE DB Provider for ODBC Drivers error '80040e07'
[Microsoft][ODBC Microsoft Access 97 Driver] Data type mismatch in criteria expression.
/asp/ford_tsb/pscs/reports/charts/Chart5.asp, line 40
DateDiff Coming Up Negative
I was going to use the DateDiff function for something, so I looked up the syntax real quick at w3schools. Here's what they have:
document.write(Date & "<br />")
document.write(DateDiff("m",Date,"12/31/2002") & "<br />")
document.write(DateDiff("d",Date,"12/31/2002") & "<br />")
document.write(DateDiff("n",Date,"12/31/2002"))
Output:1/14/2002
11
351
505440
I put the same code into a simple test document to verify, except for mine has Response.Write. All my numbers came out negative. If I reverse their positions, I get positive numbers. Is the example above wrong or is there something going on with my PC?
Dynamically Showing Datediff
I have a datediff comparision value on my form. Since one of the dates inside the datediff is: now(), I'd like to know if there's a way to show the result dinamically (without reloading the page..). I can't see how to do it from server side...It's possible to use js to fill the field or reload only the field value? detail: I'll need to submit the current diftime value along the other input values on my form at the end of process.
View Replies View RelatedWorking With Time (dateDiff)
I'm having trouble working out the best way of calculating the time difference between two times on the same day. The example I have found des return the hours (in this case 8) but forgets the minutes. I am looking to return the hour & the minute but i've had a look at the dateDiff format and this doesn't seem possible ?
---------------------------------
time1 = "09:15"
time2 = "17:30"
hours = datediff("h",time1,time2) ' in hours
response.write(hours)
----------------------------------
Type Mismatch Error In Datediff
i am facing error as
Microsoft VBScript runtime error '800a000d'
Type mismatch: '[string: ""]'
/pages/result.asp, line 12
Code:
If The DateDiff Is 24 Hours, Delete Record
I just need to know the DateDiff function for what I need to do...
I will store the date of the database record in a variable called 'sDate' what now? (Also, the format is xx/xx/xx 2:4:56 PM/AM)
DateDiff ("d",Now,"12/25/2007")
How do I programaticaly get the "12/25/2007" to upate from year to year?
DateDiff ("d",Now,"12/25/2007")
Please help, I must be a dumb ***, I can't figure it out.