Datepart Function :: Remove Weekdays Name

i used formatdatetime(dt,vblongdate).it gives me in format like monday , august 8th, 2005.but i dont want weekday means monday or tuesday in my date so on.

<%
prior = Request("Date")

if isDate(prior) Then prior = CDate(prior) Else prior = #1/1/1900#

For dt = DateAdd("m",-1,Date()) To Date-1

%>
<OPTION value="<%=dt%>" <%If dt = prior Then response.write "SELECTED" %>><%=FormatDateTime(dt, vbLongDate)%> </option>
<%
Next
%>
</SELECT></center> </td>
</tr>

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How To Use The DatePart Function?

Does anyone know how to use the DatePart function?

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I'm trying to use DatePart and Datediff functions to show the formatted m/dd/yyyy display for the dates of Monday and Friday of the current week. I want it to display as:

Our Weekly Schedule 8/23/2004 thru 8/27/2004:

Can't pinpoint the parameter to check for the current week. Is there a good reference anywhere to show how to use the methods and such of both datepart and datediff, or has anyone programmed something similar prior.

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I am trying (with Classic ASP) to pass from a form multiple selected check boxes. These are the days of the week. On the receiving page I need to check for the selected days between a date range (eg. 1/12/07 - 24/12/07) and write those dats to a database.

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DatePart

Is it possible to pass a variable containing the full date and time to 'DatePart'? I want to grab just the time of day portion of a date. As in: Code:

<%
dim submit_date
submit_date = Now()

submit_time = DatePart("h","n","s", submit_date)
%>

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I get an error with the following code:

sql = "SELECT * FROM tblVisitors WHERE (DatePart("yyyy",
[datetimeentrance])) = (DatePart("yyyy", date()))"

can anyone help me with the correct syntax?

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DatePart Wrong Code

Is there anything wrong with my code (see below) bcoz when 10p-6a shift my
browser returns the error cannot be a zero-length string. Im wondering why,
bcoz the 2 other shift works perfectly.

<%
'Shift: 6a-2p
if DatePart("h", Now()) 5 And DatePart("h", Now()) < 14 then
ShiftID = "A"
end if

'Shift: 2p-10p
if DatePart("h", Now()) 13 And DatePart("h", Now()) < 22 then
ShiftID = "B"
end if

'Shift: 10p-6a
if DatePart("h", Now()) 21 And DatePart("h", Now()) < 6 then
ShiftID = "C"
end if
%>

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DateAdd And DatePart Return 13, 14, 15

I'm trying to increment between the end of lunch and the end of the day. The code below is returning a datePart of 13 instead of 1 (for 1:00:00 PM) and 14 instead of 2:00:00 PM etc. If response.write just counter2 I get a real hour. how can I return the actual hour datePart?

lunchStart = "12:00:00 PM"
lunchEnd = "1:00:00 PM"
dayEnd = "5:00:00 PM"
counter2 = cdate(lunchEnd)

while counter2 >= cdate(lunchEnd) AND counter2 <= cdate(dayEnd)
response.write datePart("h",counter2)
counter2 = dateAdd("h",1,counter2)
wend

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Need To Remove DAY Name

I found a simple date script, which is this:

<%
var_date=date() 'get the current date
var_date=FormatDateTime(var_date,1)
Response.Write(var_date)

Wednesday, September 29, 2004

How can I get this to not display the day of the week, I only want - September 29, 2004

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Remove DAY Name

I found a simple date script, which is this:

<%
var_date=date() 'get the current date
var_date=FormatDateTime(var_date,1)
Response.Write(var_date)
%>

Wednesday, September 29, 2004

How can I get this to not display the day of the week, I only want - September 29, 2004.

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stramount=Trim(Request.form("txtamount"))

response.write stramount

the output sometimes is

50.00 or
50 or
50.

if it is 50.
i want to remove the (dot) at the end. can someone tell me how to use the instr function to see if there is a dot at end and if it is there then remove it.

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my code is as below:

<td align="left" class="BorderLeft" width="1%">
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word = "AAAAABABABBA"
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for i = 0 to len(word)-1
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pic = asc(word1) & ".gif"%>
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<%next%>

</td>

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[vbs]
Response.Cookies("mycookie").Expires = Now()
[/vbs]
and
[vbs]
Response.Cookies("mycookie").Expires = Date() - 100
[/vbs]

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Is there any way to completley remove the cookie?

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