If I want a webpage to display a random image from about 20 images and not want the user's computer to load all 20 images and sacrafise the load time, can I use the following script? Is the following a good approach? Code:
<%
Const NUMBER_OF_IMAGES = 20
Randomize
Dim intImageNumber
intImageNumber = Int((NUMBER_OF_IMAGES * Rnd) + 1)
%>
<html><body>
<img
src= "images/header<%= intImageNumber %>.jpg"
width = "760"
height = "104"
>
</body></html>
I have done random image display with the help suggestion from this discussion form. now I want to provide link on each image. i.e. all the images display randomly, should have different link. is it possible? if yes, how?
View Replies View Relatedexample:
When u see some sites ,
the advetisement images are changing ,
when ever the browser is refreshed...
.....
like tha i want to do that.....
I have the below ASP function to display a random image from a folder.
<%
Function RandomImage(strPath)
Randomize()
If Right(strPath, 1) <> Chr(47) Then strPath = strPath & Chr(47)
strPhysical = Server.MapPath(strPath)
Set objFSO = Server.CreateObject("Scripting.FileSystemObject")
Set objFolder = objFSO.GetFolder("C:Inetpubwwwrootpag-siteimages
andoms")
Set objFiles = objFolder.Files
For Each objFile in objFiles
strFile = LCase(objFile.Name)
strFiles = strFiles & strFile & vbTab
Next
strImages = Split(strFiles, vbTab)
If UBound(strImages) > 1 Then
RandomImage = strPath & strImages(Int(Rnd(1)*UBound(strImages)))
End If
End Function
%>
and this places the image in the HTML
<img name="Intropic" src="<%=RandomImage("images/randoms/")%>" width="211" height="158" alt="" />
but sometimes the script places a ._ before the image file name in the outputted HTML?
i have some code that displays a random image... and i have some code that refreshes a page ever x seconds. great.
what i want to do is, have sort of like a banner rotating system... not links, just displaying random images every x seconds on a portion of my website... im sure someone has done this before, but im not sure how to go on from here.
I have a client that has a guestbook and they have been getting slammed with spam...
Would like it if someone could post a script to create one of those "input the letters you see here" scripts to prevent the spam bots from being able to post automatically....
I want to provide random image on my asp page. the image will display according to products searched by user.
e.g.
if user enter pharma machine in search box, in result page the banner of pharma company will display. i.e. the banner of manufaturer/exporter of pharma machine will display.
for this i have comapny info table in database
table: comapny_info
fields in comapny_info:
company_name
products (comapny products)
description (company_description)
banner (yes/no)
dusring registration, comapny has to specify whether it wants banner or not. so if there is yes in banner and prodcuts match the search string then banner will display.
this is according to the product seaarched by user.
any idea?
I am currently looking for a script similar to A List Apart Article Random Image Rotation. Unfortunately my clients host does not support PHP. I want to randomly rotate 3 images in the header section each time the page loads.
As it's only 3 images, I could turn to javascript, but then I would need to include that in every page. The header part of the site is an #include file, so I was thinking I wanted to do something like this.. Code:
I was wondering if anyone knows how I can have a random product image shown on a page with information such as product info, price from the db?
View Replies View Relatedi want to display images in my search result page according to search text enetered by user. and i want more than one images display randomly.
View Replies View RelatedOn my index page I have got an area for one product to be displayed randomly from the
database. I have got it workign, but there is one problem i cant get my head around, here is the code so far:
' Initialize ASP RND() function
Randomize()
intRandomNumber = Int (1000*Rnd)+1
strsql = "SELECT TOP 1 art_Artist, art_Title, Rnd(" & -1 * (intRandomNumber) & "*cat_ID)" &_
"FROM eventDisplay " &_
"ORDER BY 3"
The code above isnt working and its when i try and draw out more that one value, as in art_Artist and art_Title.
It works fine if all I want is art_Artist, but as i said when i try to draw out more than one value the randomize function doesnt work.
How bout I go about creating a section on my site that displays a random image, lets say:
1) every time the page is refreshed
2) in a certain amount of mins or hrs the pic changes
3) daily, monthly and so on?
Would I need a database of some sort or can it just be done with some asp code?
This Random image script gets an image out of a folder so NO database is needed, just create a subfolder for your images and upload to your server ...
View Replies View RelatedHowever, what I want to do is include a request.querystring("ID"), so that IF an ID is defined, eg ID=3, , it will display the relevant (not random) information. I've tried this every way I can think and get type mismatches, etc etc. It's probably really simple but I can't see it.
<%
limit=3
redim link(limit)
redim image (limit)
link(1)="xxx"
image(1)="image1.jpg"
link(2)="xxx"
image(2)="image2.jpg"
link(3)="xxx"
image(3)="image3.jpg"
randomize
random=int(rnd*limit)+1
%>
<center>
<a href="<%= link(random) %>">
<img src="<%= image(random) %>" border="0"></a>
I just wanted to know whats the best way to generate 50 or say X amount of number at random without having to repeat any of the previous number...
so far I've the following:
[VBS]<%@LANGUAGE="VBSCRIPT" CODEPAGE="1252"%>
<%
function RandomNumber()
dim theRandom
Randomize
'RandomNumber = Int((upperbound - lowerbound + 1) * Rnd + lowerbound)
theRandom= Int((99 - (0) + 1) * Rnd + (0))
if (theRandom<10) then theRandom = "0" & theRandom
RandomNumber = theRandom
end function
%>[/VBS]
and then I've this in the body of HTML doc: Code:
We have the need to have a random token (a 16 char alphanumeric field) to be used as the key for one of our SQL tables. I have created a random token generator, however after only 3 months in production, it appears that we had an instance where a token that already existed in the tables was created. There are 3810 records currently in the database so it isn't like there are billions of records there.
I contacted an old college buddy of mine who is a mathematician, and he claims, assuming that random really does mean random, that the chances of getting a duplicate token are 1 in 79.5 septillion (79,500,000,000,000,000,000,000,000).
So my conclusion is that this was either a complete freak of nature occurance, or my random generator isn't really all that random. Here is the code behind how I am generating this: Code:
I am trying to generate a random number. I am using randomize and then rnd to return a decimal number between 100 and 120. This will give me a longitude. I am doing something similar to generate a latitude.
I created this on a page which refreshs every minute. I put these points into a map and they are showing up in groups of straight lines. Since rnd is time based will refreshing every 60 seconds return similar numbers?
I have a client who has had a ASP site with an Access database for several years. It stores information for the used cars on his lot. I have stored text in the database that points to the location of the image for each record. Each record will have a thumb image that is supposed to display in a list of vehicles available then the user can select an item from this list and a new page displays with the information and the regular size image. So far everything has worked fine exept for the display of the images which are stored in a separate directory called veh-photos. All I get are image place holders. I am using Dreamweaver 2004 and and Access 2000 for the database.
Following is the code to list vehicles: ....
1.I want to show a image file of type '.tif' in the browser window; for that I'm writting as ASP code page.
2.This '.tif' type image can be shown better with 'Kodak Image Control'.
3.To have this 'Kodak Image Control' on my code page I just add it's ..ocx to tool box and then drag it from 'Toolbox' to the page.
4.Now after dropping this control to the code it's type is getting changed to 'object' instead of type 'ImgEdit'(and I think this is the
reason I don't get correct result).
5.On one button's 'Onclick' event I'm calling a javascript function with which I'm setting a 'Path'and'Display' property of a control.
6.And want to show a image at location -- '..MFTDRCMF919685173-62.tif' which get shown in new browser window but could not get shown in that particular control. That means the path is correct, then what is the problem?
For better understanding of problem I'm pasting a following code which I've tried up till now......
..................................................
<%@ Language=VBScript %>
<% OPTION EXPLICIT %>
<HTML>
<HEAD>
<META NAME="GENERATOR" Content="Microsoft Visual Studio 6.0">
<SCRIPT LANGUAGE=javascript>
<!--
function showpic()
{
var path;
path = document.frmtif.path.value;
alert(path);
document.frmtif.ImgEdit1.Image =path;
document.frmtif.ImgEdit1.Display;
window.parent.self.open(path);
}
//-->
</script>
</HEAD>
<BODY bgColor=#ffe4e1>
<form name="frmtif">
The Image
<P>
<OBJECT id=ImgEdit1 style="WIDTH: 409px; HEIGHT: 218px" type="ImgEdit"
align=left
border=1 classid=clsid:6D940280-9F11-11CE-83FD-02608C3EC08A
name=imgtif></OBJECT>
<input type="hidden" name="path"
value="..MFTDRCMF919685173-62.tif">
<input type="button" name="show" value="Show" onclick="showpic();">
</P>
</form>
</BODY>
</HTML>
..................................................
I am creating a dynamic ASP VBScript page, which gets data from an Access database.
In the database, there is a field which holds a URL to an image. I can get the image to display fine, but where there is no file that matches the URL (i.e. a missing image) I want to display an alternative, default image (e.g. one that says "Awaiting Image"). The field is never blank, but the image file may not exist for all records in the database.
I think what I am trying to get to is the following:
If file exists (using URL from database to get location of image file) then
display image using the url from the database as the image source
else
display default image - hardcoded in program
endif
I have had a go and come up with the attached but I get an error with my if statement...
I can convert an image that is retrieved from a FileUpload object into a byte array and insert it into the database..
When the user signs-up i wish tosimply insert into the Picture (DB Type = Image) field to an image i already have saved in my images folder?
Anyone know of a way to do this? Tutorials, articles or advise??!
Here is my code. I'm using 2 pages.
(Page 1) blob.asp
<%
set Recordset1 = Server.CreateObject("ADODB.Recordset")
Recordset1.ActiveConnection = MM_blob_STRING
Recordset1.Source = "SELECT AboutPic FROM Elizabeth.GF_AboutUs"
Recordset1.CursorType = 0
Recordset1.CursorLocation = 2
Recordset1.LockType = 3
Recordset1.Open()
Recordset1_numRows = 0
%>
<%
Response.contentType = "image/jpg" 'Recordset1.Fields("AboutPic") <---Tried
both methods
size = Recordset1.Fields("AboutPic").ActualSize
blob = Recordset1.Fields("AboutPic").GetChunk(size)
Response.binarywrite(blob)
%>
(Page 2 Show the Image)
<%
Dim urlString
urlString = "?" & Request.QueryString
%>
<% Another rs to show other information as text from the same table %>
<body>
<img src="blob.asp<%=urlString%>" width="194" height="256">
</body>
I'm working on a project where I'm suppose to upload a image to a server. The uploading works fine but when I want to change the image I uploaded to another image I can't get the filepath of the old image to show in my "filefiled"....is it possible to set a "value" where I can retrieve a filepath in a form if the input type is "file"?
View Replies View RelatedThis worked fine for enlarging my images until i put it onto a secure server, anyone know how i can fix it ??? just comes up with the standard box with a red cross in it .. and the url when i click image properties says: http://url/images/<%=request.querystring( which is only part of the code)
View Replies View RelatedI want to display data of a Random Member on my page.. and I did a search in these forums and I tried to do this:
[CODE] SELECT tblMiembros.*, tblDatosPersonales.*
FROM tblMiembros, tblDatosPersonales
ORDER BY rnd(isnull(tblMiembros.ID_APLICANTE) * 0 + 1)"[/CODE]
This doesnt throw any errors. but it always displays the same row... (first in database)
am I doing something wrong? am I missing something?
I have a client asking me about random images on his site, basically I am using the following code:-
<%
RANDOMIZE
Response.write("<IMG SRC='../gfx/bg-img0" & INT((3)*RND()) & ".jpg'>")
%>
Agreed its not the best code, but he is finding that the same image could be repeated like three times in a run.
I have an include file which displays the image, and the random script is placed inside that include. So when he is going from page to page this is where the issue lies.
Can anyone help me out here, is it even possible to have a different image load each time, and not have them repeating.
I am using random number to be used as a unique identifir. Since random numbers are in decimals I am using going to convert it into an integer and since I need to append this Id into my URL, I am converting it into a string. SO my formula looks like this.
CStr(Int((Highest-Lowest+1)*Rnd+Lowest))
S0 now every time a new record is generated would this formula generate a unique number for unique identification in the table. I can't see how it can do it. Say A user is assigned a random number; then another user subscribes so how would the server determines that the random value assigned to next user is not already assigned to any other user.
In case if this can't work (a unique ID for every user) then I'll stick to this very same formula and after the random number is generated, I'll check this number with the table in the database and see whether it's been assigned already. If yes, I'll request another random value, if not then I'll go with it. Is this the right strategy?
is there sombody who can helpme witht he following, i am ''pretty new'' to
php and am looking for a script to show images randomly at a 10/ 15 seconds
interval. is there anybody who can help me with this or does know where to
find a good template script for this?
I'm afraid I have a technical problem here. Basically what happens is that I'm getting some random errors(like Type mismatch... etc) that shouldn't under normal circumstances occur. Then I connect to my server via remote desktop and Recycle the application pool on which my asp pages run. Errors then disappear
View Replies View RelatedI have a file where i want to call a random asp file using the "include file" statement. I know it can be done with images, but can it be done with other asp files? and how?
View Replies View RelatedI want to take 3 records from a database. The selection must first take any record marked as priority and then random records (so there could be 3 priority records and no more or 1 priority and 2 random etc)
My theory is to build a recordset filtered by records marked priority, and if there are less than 3, build a second recordset of all the other records.
Questions
1, how can I select random records form the second recordset, without selecting the same one twice?
2, OR, could I write a sql statement which would randomly select 3 records from my table
3, Or is they a way I could write a query (view) in Access which would do the whole lot for me (select the priority records and then random records up to 3)?
I set up a random code for people registering with my site.....
letters="1234567890abcdefghijklmnopqrstuvwxyz"
for i=1 to 16
Randomize()
rNum=Int(Rnd()*36)+1
code=code&mid(letters,rNum,1)
next
but for some reason it sometimes saves code as an empty string. When I register a fake name, ie zzz, it seems to work fine, but for some of my members is saves as an empty string.
trying to get a random number from 0000 to 9999, is there an easy way to do this? i'm using this for a unique filename and want it to be 4 digits from 0000 to 9999.
View Replies View Related