Array Prints Out Zeros?

Nov 16, 2014

Ok, so let's say I am having a user input scores and at the end I want to print out the results so I do something like:

int[] Scores = new int[1000];
//code to ask user for input and store into array //

The user only inputs lets say 5 scores out of possible 1000. I then try to print it out by doing something like this:

for(int counter = 0; counter < Scores.length; ++counter) {
System.out.println(Scores[counter])
}

How would I go about printing out only the index's that were input, because right now it prints out the scores and then 995 0's after.

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Populate Array With Leading Zeros

Nov 18, 2014

why I need to populate an array with leading zeros. It sounds like it wants me to populate the entire array for one number (string). When I use next(), it separates the numbers so why do I need to go the leading zeros route?

This assignment will give you practice with external input files and arrays. You are going to write a program that adds together large integers. The built-in type int has a maximum value of 2,147,483,647. Anything larger will cause what is known as overflow. Java also has a type called long that has a larger range, but even values of type long can be at most 9,223,372,036,854,775,807.The approach you are to implement is to store each integer in an array of digits, with one digit per array element. We will be using arrays of length 50, so we will be able to store integers up to 50 digits long. We have to be careful in how we store these digits. Consider, for example, storing the numbers 38423 and 27. If we store these at the front of the array with the leading digit of each number in index 0 of the array, then when we go to add these numbers together, we're likely to add them like this:

38423
27

To simulate this right-shifting of values, we will store each value as a sequence of exactly 50 digits, but we'll allow the number to have leading 0's. For example, the problem above is converted into:

0000000000000000000038423
0000000000000000000000027

Now the columns line up properly and we have plenty of space at the front in case we have even longer numbers to add to these.The data for your program will be stored in a file called sum.txt. Each line of the input file will have a different addition problem for you to solve. Each line will have one or more integers to be added together. Take a look at the input file at the end of this write-up and the output you are supposed to produce. Notice that you produce a line of output for each input line showing the addition problem you are solving and its answer. Your output should also indicate at the end how many lines of input were processed. You must exactly reproduce this output.

You should use the techniques described in chapter 6 to open a file, to read it line by line, and to process the contents of each line. In reading these numbers, you wont be able to read them as ints or longs because many of them are too large to be stored in an int or long. So youll have to read them as String values using calls on the method next(). Your first task, then, will be to convert a String of digits into an array of 50 digits. As described above, youll want to shift the number to the right and include leading 0s in front.

The String method charAt and the method Character.getNumericValue will be useful for solving this part of the problem.You are to add up each line of numbers, which means that youll have to write some code that allows you to add together two of these numbers or to add one of them to another. This is something you learned in Elementary School to add starting from the right, keeping track of whether there is a digit to carry from one column to the next. Your challenge here is to take a process that you are familiar with and to write code that performs the corresponding task.

Your program also must write out these numbers. In doing so, it should not print any leading 0s. Even though it is convenient to store the number internally with leading 0s, a person reading your output would rather see these numbers without any leading 0s.You can assume that the input file has numbers that have 50 or fewer digits and that the answer is always 50 digits or fewer. Notice, however, that you have to deal with the possibility that an individual number might be 0 or the answer might be 0. There will be no negative integers in the input file.You should solve this problem using arrays that are exactly 50 digits long. Certain bugs can be solved by stretching the array to something like 51 digits, but it shouldnt be necessary to do that and you would lose style points if your arrays require more than 50 digits.The choice of 50 for the number of digits is arbitrary (a magic number), so you should introduce a class constant that you use throughout that would make it easy to modify your code to operate with a different number of digits.

Consider the input file as an example of the kind of problems your program must solve. We might use a more complex input file for actual grading. The Java class libraries include classes called BigInteger and BigDecimal that use a strategy similar to what we are asking you to implement in this program. You are not allowed to solve this problem using BigInteger or BigDecimal. You must solve it using arrays of digits.Your program should be stored in a file called Sum.java.

Input file sum.txt
82384
204 435
22 31 12
999 483
28350 28345 39823 95689 234856 3482 55328 934803
7849323789 22398496 8940 32489 859320
729348690234239 542890432323 534322343298
3948692348692348693486235 5834938349234856234863423
999999999999999999999999 432432 58903 34
82934 49802390432 8554389 4789432789 0 48372934287
0
0 0 0
7482343 0 4879023 0 8943242
3333333333 4723 3333333333 6642 3333333333

Output that should be produced
82384 = 82384
204 + 435 = 639
22 + 31 + 12 = 65
999 + 483 = 1482
28350 + 28345 + 39823 + 95689 + 234856 + 3482 + 55328 + 934803 = 1420676
7849323789 + 22398496 + 8940 + 32489 + 859320 = 7872623034
729348690234239 + 542890432323 + 534322343298 = 730425903009860

[code]....