Bar Code Parser - Spitting Out 0s

Nov 6, 2014

My program has to take the given bar code, check for correct characters and correct length, then it has to give the corresponding zip code. It instead just spits out 0's. I can't find where the problem is.

public class GavinBarnesrealHw7
{ public static void main(String[] args)
{ boolean length;
boolean good_char;

String zip = "||:|:::|:|:||::::::||:|::|:::|||";

[Code] .....

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Create A New Xml File With DOM Parser

May 29, 2014

I try to create a new xml file with DOM parser and i get this error in line 73.

Java Code: package RunMABS;
import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;

[code]....

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Nov 9, 2014

I've recently tried to write a file parser for the .x3d file type as it's one of the few 3d model types I can find written in easy to understand (and interpret) English. While it technically does work (or what I have so far), the issue is that it takes far too long (17 minutes) to parse just a part of the file (the vertices of the model).This is the code for the object itself:

import java.io.*;
import com.sun.j3d.utils.geometry.*;
import javax.media.j3d.*;
import javax.vecmath.*;
public class ModelLoader {
BranchGroup object = new BranchGroup();
BufferedReader reader;
String line = "start";

[code]....

Anyway, here are some observations I've made about the file:

-The line in the file itself that contains all the vertices is all one giant string according to the file.
-There are apparently 18,000 vertices in all (according to the command at line 18).
-Unless Netbeans automatically terminates infinite loops after a certain amount of time, it is most definitely NOT an infinite loop as I have seen the program terminate on its own (after 17 minutes, though).

I had a theory that maybe organizing each vertex into its own line and then having the program switch to the next line when it's done reading that vertex might make the program run faster, but I'm not sure why it would, so I thought I'd come here in case that theory turned out to be a dead end.

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Feb 11, 2014

There is JAVA Sql parser which supports all ASCII characters in my project. This parser fails when the query contains multi byte characters.We have used UTF8 encoding. How to handle multi byte chars.

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Mar 26, 2014

i am having a below piece of code in my worker thread. In my output i am getting xml records from the database. I'm sending this output to a input stream & finally to a sax parser.My query is, before sending to the parser i need to store the input stream in buffer. The buffer should store 1000 records. For every 1000 records the parser should be called from buffer.

while (orset.next()) {
output = orset.getString("xmlrecord");
writeCount++;
InputStream in = new ByteArrayInputStream(output.getBytes("UTF-8"));
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[code]....

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Feb 9, 2015

how to use SAX Parsers. I've looked at a few tutorials and have the generals down. I have an xml file that the parser is trying to read. As you see below, at the start of each element, I add the tag to an arrayList of the tags. I create a stringBuilder to capture the text between tags, this won't work unless it occurs at the end of an element. If it occurs at the start, it never gets the chance to read the text.

This is where the problem occurs. For nested tags, like project, it reads the last nested tags' text and stores it in the text arrayList. Project may be the first indexed tag in the tags arrayList, but project's text is the fourth indexed element of the text arrayList. So when my test print the arrayLists by index, it gets thrown off. I want over tags to store a blank space in the text array, and at the same index of the tag its associated with. How would I do this?

I've tried overwriting the text arrayList, but couldn't get my logic thought out for how to determine if a tag was nested. I always ended up overwriting blank space to each element.

xml file:

<?xml version="1.0"?>
<project
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"
xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>na-ata-custom-delivery-bench-code-exercises</groupId>
<artifactId>na-ata-custom-delivery-bench-code-exercises</artifactId>
<version>0.0.1-SNAPSHOT</version>

[code]...

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Mathematical Parser Only Returns Size2 And Not Size In Android App

Feb 1, 2014

Using exp4j which is a mathematical parser twice in one routine (or separated) in Eclipse and only the size2 is calculated when app is run in eclipse.

private void calculate size(){
String s1 = size.getText().toString();
String s2 = size2.getText().toString();
try {
Calculable result= new ExpressionBuilder(s1).build();
size1.setText(Double.toString(result.calculate())) ;

[Code] .....

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Feb 27, 2014

I have a program that is a XML-parser, and it works fine when I'm running it from NetBeans. But when I create a JAR-file and run the very same program, it cannot find the xml file. Consider this small program that addresses my problem:

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import javax.xml.parsers.DocumentBuilder;

[Code] .....

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I am searching a XMI parser in java code that read an xmi file and print classes with related attributes.

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Aug 23, 2010

I was a bit confused of the code generated by the Axis2 Code Gen.

I have created a logIn(String username, String password) method in my service and used Axis2 Code Gen to generate the Stub.

I try to access the logIn method from my Client using the Stub like below:

TestServiceStub stub = new TestServiceStub("http://localhost:8080/axis2/services/TestService");
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but instead of UserName and password as the parameters, the Stub created a Login object as the parameter for the logIn method. like the one below:

stub.logIn(Login login1);

I wanted to try the logIn method by providing a static userName and password but it seems impossible because the Stub changed the parameter for the logIn method.

how to test the logIn method.

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Aug 29, 2014

The code here I have works fine if I just want to ask the user to enter four digits: //java application that asks user to input binary numbers(1 or 0) and convert them to decimal numbers import java.util.Scanner; //program uses class scanner public class binarynumber{
 
//main method that executes the java application
public static void main(String args[]){
//declares variables
 
int digit;
int base=2;
int degree;
double decimal;
int binary_zero=0;
int binary_one=1;
//create scanner for object input

[code]....

The thing is, I want the java application to input more than four digits for the user and I want it to loop it manytimes f until the user ask it to stop.

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Oct 9, 2014

I need to create a Java program that takes an input a color code in HSV and outputs the equivalent RGB code and Vice versa.

Example:
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Input: (255,0,0)
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If you test on the color RED in HSV:
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Mar 23, 2015

Can i write inner if loop without { and } if it has more lines of code as below

public class TEst111 {
/**
* @param args
*/
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int num=11;
// TODO Auto-generated method stub
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[code]....

I tested to see outer if which does not need { and } even though it has multiple lines in that

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Oct 3, 2014

According to what I read, "when programming in Swing, your GUI creation code should be placed on the Event Dispatch Thread (EDT). This will prevent potential race conditions that could lead to deadlock." (See below for code.)

Why is this? How could making a GUI lead to deadlock?

public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
createAndShowGUI();
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Apr 24, 2014

I have a assignment in which the code has to scrape a web page for a little bit of data including the link to the next page, follow the link, and do this 100 times. It is scraping all the data correctly, including the link, but it isn't following the link to scrape the data on that next page. Instead, it is displaying the first page's data 100 times. I have the code in a while loop where it reads in one character at a time from the page into a string and then uses pattern matching to get the data and the next link from the string. Then it correctly displays the data and should loop back to connect to that next link and read one character at a time into the string and so on.

I have printed the link to the console and it is good. I don't get any errors. I just can't figure out where exactly the problem is. Here is my code:

import java.awt.*;
import java.io.*;
import java.net.*;
import java.util.regex.*;
import javax.swing.* ;
public class SimpleWebSourceGetter{
static void getSourceCode(String url) {
String mystring = "";

[Code] ....

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Apr 14, 2015

I have had to create a text analyser. I have created the program but it is all within the main method. The specification states that I have to have at least two methods within my Program.

import java.io.*;
import java.text.SimpleDateFormat;
import java.util.*;
import javax.swing.*;
import javax.swing.filechooser.FileNameExtensionFilter;
public class Analyser {
public static void main(String[] args) throws FileNotFoundException,
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[code]....

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Mar 4, 2010

i have made a code for my mandelbrot set, however, it doesn't become mandelbrot, but only an oval in the middle

import java.awt.*;
import java.lang.Object.*;
public class MandelbrotCanvas1 extends Canvas{

boolean draw = false;
ComplexNumber[][] cnSet = new ComplexNumber[600][600];
int depth = 255;
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double ly = -1.25;
double ux = 0.5;
double uy = 1.25;
int size = 600;

[code]....

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Oct 3, 2014

According to what I read, “when programming in Swing, your GUI creation code should be placed on the Event Dispatch Thread (EDT). This will prevent potential race conditions that could lead to deadlock.” (See below for code.)

Why is this? How could making a GUI lead to deadlock?

public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
createAndShowGUI();
}
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Apr 16, 2014

how I can use this class:

Java Code:

public class Coordinate{
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[code]....

How would I use Coordinate in the second code?

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Mar 18, 2015

Code isn't giving me the output that I want and keeps giving me NaN

What I want -

Enter the A value for the line: 2.45
Enter the B value for the line: 4
Enter the C value for the line: -8
Enter the x coordinate of the point: 2.17
Enter the y coordinate of the point: -4

Distance from the point to the line is: 3.9831092774319026

What I am getting

Distance from the point to the line is: NaN

Here is my code-

Tester-

import java.io.*;
import java.util.*;
 class tester
{
public static double A;
public static double B;
public static double C;
public static double distance;
public static void main(String args[])

[Code] ....

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Nov 30, 2014

how do we get the following numbers (1 2 3 5 8 13 21 34 55 89) out of the following code? I can't get my head around this loop....

HTML Code:

public class Fabnoci{
public static void main(String[] args)
{
int n=10,i,f0=1,f1=1,f2=1;
for(i=1;i<=n;i++)
{
f2=f0+f1;

[code]....

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Feb 12, 2014

How do I get my GUI code into a GUI format? I wrote this put it will not make a GUI image.

/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package Ofelia_Inventory_4;
import java.awt.*;
import java.awt.event.*;

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Feb 25, 2014

I want to execute my jsp code to compare two dates after every 10 seconds if user enter date and current sys date are equal it will send the mail to the user automatically. Below is my jsp code

this if condition i want to check the date after every 10 seconds and when two dates are equal it will send the mail using below mail code

if(ExpcReDt.compareTo(dateStr)>0) {
out.println("Expected return date is greater than current date");
}
else if(ExpcReDt.compareTo(dateStr)==0)

[code]....

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Jun 20, 2014

why this code only displays four zeros ?????

public class VargjetUshtrimi2 {
public static void main (String a []) {
int r[] = new int[11];
for (int i = 1 ;i < 10; i++)
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