Iva tried flipping the entire code upside down (expression) and No matter what I do the delete function returns a null pointer exception after my while loops takes the pointer right to where it should be.
package bp;
import java.time.LocalDate;
public class BinaryTree implements IBinaryTree {
private Node root = null;
private int sizeOfTree = 0;
I have some work where I have to create a binary tree. Anyway I am stuck on one of the classes which has several methods I must fill in! The code is below
The headers for each method are: public Node find (member p1)The method find(Member p1) is used to return the node which contains a particular member. It is a private method because the interface to CabinetTree should not provide direct access to the internal nodes. It makes use of the method Node findNode (Member p1, Node current)
and the next method is : Node findNode(Member p1, Node current) which searches the tree from current node to find a node whose value is equal to the Member p1, i.e. a node in the tree such that p1.equals(current.getMember()) is true. If there is no such node then the method should return null.
public class CabinetTree { private Node head; CabinetTree(Member p1) { head = new Node(p1, null);
I am trying to delete entire set of objects from my graphics program. Specifically I am trying to make a bunch of tree trunks, 10 in total, and then delete them all by pressing a button. I can manage to make the trunks but I can only delete one of them.
Below I can walk you through some of my code step by step to show you what I am trying to do:
Java Code:
public void drawTrunk(double width, double height, double xpos, double ypos) { trunks = new ArrayList(10); trunk = new GRect(width / 15.0, height / 3.0); trunk.setFilled(true); trunk.setFillColor(Color.orange);
[Code] .....
So basically I just would like to know how to make this work?
So everything in my program is working EXCEPT when it comes to calculating the result. I am supposed to evaluate the expression using postorder traversal to return the answer. I am honestly not sure how I would get the postorder traversal to return the answer to the expression since the only thing we really went over was how it re-ordered the expression so that it would end in the postorder/postfix order. Anyways, currently the way that I have the public int evaluate(Node node)method set up is giving me a result of 0, which obviously is not correct.
Here's the section that I'm having issues with:
public int evaluate(Node node){ if(node.isLeaf()){ return Integer.parseInt(node.value); } int result = 0; int left = evaluate(node.left); int right = evaluate(node.right);
I have a list of people with a matching telephone extension number, the people are organised in a hierachy tree with some colleagues at the same level and then some junior colleagues. I have been trying to write code that can find the tree height of any given member but I am unable too. Here is my code so far but the left and right are not working because I have not declared them any where in my code.
Java Code:
//hierarchy rank section 7 // **Depth** from node to root (bottom up) public int rank(Member p1){ //to do
I know that for a binary search tree the insert() method is easy. You just kept comparing the values of the nodes, and you would know whether to go left or right depending on the value of the node.However, I am stumped when trying to figure out how to add a node into a normal binary tree where you just keep adding the nodes to the leftmost side, regardless of value.Here is my attempt at the insert() method:
public class RegularTree extends BinaryTree { public CompleteTree() { super(); }
public void insert(Comparable item) { if(this.isEmpty()) { this.setRoot(new TreeNode(item)); return;
Is there a way that I can view my entire binary tree on Eclipse? I remember the old IDE that I used, jGrasp, had a feature in its debugging that would allow me to see exactly what was going on and I want to know if Eclipse has the same thing.
I have a little problem in my code. Using a threaded binary tree and inorder traversal check if every next element is equal to the previous element + 1. You are allowed to use additional functions as long as they are not recursive. I have implemented everything. Problem is that i cant compare elements as i should. They are type E.
I have written a code to get all the nodes below a current Node and it is working but I need to get it to look better if possible. To get the number of nodes below I have created an Array List, which I then go to the first Node below and add all the people to the Array list on the same level till I get to the end of the level, then I go down again until I cannot go down any more. Is there a way I can have my code without having to use an array List? I have put my code below. The brieff about the tree is that you have a parent and below the Parent are children who can have brothers and sisters next to them and after that they also have children below that. The method is trying to find the number of children below any given child
private LinkedList<Node> TempQueue = new LinkedList<Node>(); public int noOfYoungerChildren(Member p1){ Node tmp = find(p1); return countYoungerChildren(tmp);
I create a binary tree and now I would like to display the result in my jsp with conditions.
Each node has 4 elements (id, question, answer, and leftnode rightnode)
If the user clicks "Yes", the program goes to the left of the tree and if he answers "no" to the right of the tree.
For example, the initial question is "you're a man?" If he answers "yes" we will go to the left and page view "you're a singer?" If he answers "no" page displays "you're French? ".
In java, it would
cursor [i]. GetQuestion ()
to the original question.
Then
cursor [i] getQuestion. GetLeftnode () For yes and cursor [i]. GetRightnode (). GetQuestion for no.
Until the, everything works normally, but when I want to loop until there is no longer any issue by
I am trying to implement a simple binary search tree . How can I make a node in the tree which should store two pieces of information: a String variable called name, and a int variable called mark. ..
public class BinarySearchTree<E> implements Comparable<E> { public BinaryTree<E> root; int size; int mark; String name; // Constructor public BinarySearchTree()
I don't see any nodes that I add. Not sure why getting this error.
duplicate found Exception in thread "main" java.lang.NullPointerException at binarysearchtree.delete(binarysearchtree.java:111) at binarysearchtree.main(binarysearchtree.java:196) Java Result: 1 public class node<T>
The assignment is meant to understand and practice tree concepts, tree traversals and recursion. I am requested to use the tree to print the expressions by three ways and evaluate the expression in post-order. This is my node class,
package hw10; public class Node { String value; Node left, right; public Node(String value) {
I'm trying to implement a Binary Search Tree that accepts strings. I cannot figure out how to compare the string value in my add method against the node object. While I could make the node class data be the string type I am trying to make the code be as reusable as possible. So my question is this, is there a simple way I can compare the two that I am missing?
public class BTNode<E> { private E data; private BTNode<E> left, right; //constructor public BTNode(E initialData, BTNode<E> initialLeft, BTNode<E> initialRight) { data = initialData; left = initialLeft; right = initialRight;
I am trying to make binary search tree...I am trying to construct the left part of binary search tree with root node set as 70...It is not working ...My code is
public class Node { /** * @param args */
int root; Node left; Node right; public void insertNode(Node node, int num) { //Node nodeRoot = this; //root of tree we have set to 70...constructing only left of tree with root=70
Start with the tree.java program (Listing 8.1) and modify it to create a binary tree from a string of letters (like A, B, and so on) entered by the user. Each letter will be displayed in its own node. Construct the tree so that all the nodes that contain letters are leaves. Parent nodes can contain some non-letter symbol like +. Make sure that every parent node has exactly two children. Don’t worry if the tree is unbalanced. Note that this will not be a search tree; there’s no quick way to find a given node. You may end up with something like this:
It also says all Letters must be Leaves
Now I had it almost similar to that picture, but it wasn't right. So ive been working on it but im getting some very strange (and frustrating) output from the following methods.
Ive included the display method just for reference. The book told me to use it so I haven't edited it. I believe my main issue is with my (incomplete) insert() method. The output goes into an infinite loop despite having a return statement break the while loop when a character is inserted.
The way I see to solve the problem is just add a (+) whenever a new subtree needs to be created. Say I add A and B, then it first creates a subtree at the root with a (+) and afterwards lists A and B as its leaves. If I insert a C, it should be able to simply move to the right child of the root and deposit the C there.
So I am having trouble with trying to get the main method to work. The program is supposed to construct a BinaryTree, and deserialize a file that is used for the Tree.
Write a Java program to create a binary expression tree in which: leaves are (double) numbers, and interior nodes are binary algebraic operators). As an example, the expression 1 2 + 3 * could be represented as:
The input to the program is an arithmetical expression (already) in postfix notation. Use for testing the sample :
After creating the corresponding expression tree, print it’s traversal in Pre‐Order, In‐Order, and Post‐Order.Evaluate the expression and print its final value (for this example, result should be: 19.00).
I am trying to draw a binary node tree to a text file.
public class BinaryTreeExample { public static void main(String[] args) { new BinaryTreeExample().run(); } static class Node { Node left; Node right; int value; public Node(int value) {
[Code] .....
This will output:
Building tree with rootvalue25 ================================= Inserted 11 to left of node 25 Inserted 15to right of node 11 Inserted 16to right of node 15 Inserted 23to right of node 16 Inserted 79to right of node 25 Traversing tree in order ================================= Traversed 11 Traversed 15 Traversed 16 Traversed 23 Traversed 25 Traversed 79
I need to print this information in the form of a graphic to a text file. so for example:
The purpose of this function is to use a Movie object and a binary search tree to find all movies that have been read in through a file that have a certain rating (G,PG,PG-13,R). The error I am getting is that it seems I am not traversing fully through the tree and therefore only some movies with the rating I search for are output, not all of them with that rating. I have tried figuring out why this is happening and at first I thought my tree was unbalanced, but I am sure it is simply because I am not traversing the tree correctly. I think my implementation in the main is close to what I need but it needs some tweaking. This is my BST class which I created and required to use for this purpose.
public class BinarySearchTree { /** * The head of the tree. */ private Node root; /** * Constructor that declares the head of tree to null. */ public BinarySearchTree() { root = null; } /** * Returns null if head of tree is empty. * @return null if head of tree is empty. */ public boolean isEmpty(){
So in my binary search tree I'm trying to write a method that deletes the idem but for some reason it's not working. I have two things, I have the method and then another piece of code that tests the deletion method. Here's the actual method