Bubble Sort - Array Out Of Bounds Exception
Jan 10, 2015
I am having trouble with an array out of bounds exception. I understand what the error means (that I am trying to access part of array that does not exist). But I do not see the error in my code.
Java Code:
public class bubbleSort
{
public static void main(String []args)
{
int i;
int array [] = {12,9,4,99,120,1,3,10};
[code]....
View Replies
ADVERTISEMENT
Feb 18, 2009
I am getting Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at lsb2.main(lsb2.java:44)Here is the code:
Java Code: import java.io.*;
import java.lang.Integer.*;
import java.lang.Math.*;
import java.util.*;
class lsb2
[code]....
View Replies
View Related
Jan 28, 2014
java.lang.ArrayIndexOutOfBoundsException: 991
at Champion.main(Champions (1) (1).java:209)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Nativ e Method)
[Code]....
View Replies
View Related
Mar 22, 2014
class test{//class
public static void main(String[]args) {
String booking [][]= new String [30] [6] ;//two dimensional array
System.out.println("Enter the seat column you want");//column entry
char column=Keyboard.readChar();
System.out.println("Enter the seat row you want");//row entry
int row=Keyboard.readInt();
[code]...
cant get my in put to go in to the index
View Replies
View Related
Mar 20, 2015
The following code generates an array out of bounds exception
int[] myArray1 = new int[5];
for(int j = 0; j < myArray1.length; j++)
{
myArray1[j] = 10;
System.out.println("myArray1["+j+"] : " + myArray1[j]);
}
for (int i : myArray1) {
System.out.println("Blah myArray1["+i+"] : " + myArray1[i]);
}
The exception
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
at Tutorial2.main(Tutorial2.java:40)
View Replies
View Related
Jan 24, 2015
I have two codes of needed to run but after processing, the said above error is preventing it from getting the general output of the code.I can't seem to find my errors or I don't have any clue at all, if perhaps you know, here's the codes:
Error :
PHP Code:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at simpleOutput.main(simpleOutput.java:13)
public class simpleOutput {
public static void main(String args[]){
int n = Integer.parseInt(args[0]);
for(int i = 1; i <= n; i++){
}
for(int i = 1; n <= i; n++){
System.out.print((i*n)+" ");
[code]....
View Replies
View Related
Oct 21, 2014
I need to read from a text file given to us that has a list of books with authors names and book titles separated by an @ symbol for our delimiter. Here is the code I have right now, but it throws an ArrayIndexOutOfBoundsException at line 7...and I am unsure why?
import java.io.*;
import java.util.*;
public class Driver {
public static void main(String[] args) {
new Driver(args[0]);
[Code] ....
I realize that it must have something to do with my command line argument...but I am unsure what. Am I not entering the file name correctly?
View Replies
View Related
Apr 27, 2015
I have to make a flowchart that shows a bubble sort. Here is the exact directions: provide a flowchart for a bubble sort, and write the pseudo-code that corresponds to the flowchart. You can assume the existence of a swapElement method (ie. use the predefined process symbol).one that does one pass through the array and returns a boolean if items were swapped (I'll call this the one pass method) another method that repeatedly calls the one pass method until that method returns false.This means that your flowchart will have two separate pieces for the one pass method and for the overall flow of the program (this one would use the predefined process symbol for the one pass method).
I have looked up what a bubble sort. It says it is another type of sort that involves repeatedly stepping through the array comparing adjacent items and swapping them if they are in the wrong order.The sort steps through the list multiple times until no swaps are needed, at which point the list is sorted.
View Replies
View Related
Mar 4, 2014
I am trying to find out the logic behind the Bubble sort,
for(a=1; a < size; a++)
for(b=size-1; b >=a ; b--){
if(nums[b-1] > nums[b]){
t=nums[b-1];
nums[b-1] = nums[b];
[code]....
View Replies
View Related
Jun 13, 2014
I have been doing a program that allows the user to input students names and numerical grade values. I have already completed 3/4 of the program but am stuck on the bubblesort method as this is what it requires:
The program must have an indefinite loop, which prompts the user to select a sorting criterion or to end the program, and must also use bubble sort. Note: The user may either select name or grade as the sorting criteria. The program must use bubble sort to sort that data according to the specific criteria and then use another loop to display the data. This process must continue until the user ends the program.
My problem is, while i can easily do the bubblesort, where to look on how to link elements of the two arraylists I'm using (one for grades, one for names) so that when the user decides what sort they want, the individual's name and grade stays together.
View Replies
View Related
Jun 10, 2014
import java.io.*;
Class bubble
{
public static void main()throws IOException
{
BuffetedReader br=new BufferedReader (new InputStreamReader (System.in));
int j, k, temp;
String st[]=new string [10];
[Code] .....
View Replies
View Related
Apr 8, 2015
I am working on a class that sorts and matches items in a collection of arrays. In the end, elements common to all 3 arrays should be printed. The idea is that as the first array is compared to the second it stores the matched items in tempArray. When all items are compared the tempArray should overwrite the checked array, and the process continues until all arrays are checked. I have set all the checking in a do loop that should run while the value is <= to the array length. This allows all items in the reference array to be checked. I get an index out of bounds message but not where I would expect it. I have tried varying the condition in the do while loop in the match method, but it did not change the result. There may be other issues I have not addressed with solving the algorithm, but this one has me stumped and I am not able to progress.
package testing;
public class TestMatchMain {
public static void main(String[] args) {
Comparable[] innerCollection0 = {1,2,3,4,5};
Comparable[] innerCollection1 = {1,1,5,6,7};
[Code] .....
View Replies
View Related
Nov 24, 2014
Why I have this out of bounds exception? I highlighted the code that the error is in
public String encrypt() {
//TODO: Complete this method
int groupMoves = 0;
int testing = 0;
String encrypted = "";
//a b c d e f g h i j k l
//1 2 0 1 2 0 1 2 0 1 2 0
[Code] ....
View Replies
View Related
Jul 13, 2014
I can't even run the program, because it gives me index out of bounds exception but what exactly went wrong.
I feel that even after it's able to run it will be totally wrong, but one thing at a time /*Write a method called longestSortedSequence that accepts an array of integers as a parameter and returns the length of the longest sorted (nondecreasing) sequence of integers in the array.
For example, in the array {3, 8, 10, 1, 9, 14, -3, 0, 14, 207, 56, 98, 12}, the longest sorted sequence in the array has four values in it (the sequence -3, 0, 14, 207), so your method would return 4 if passed this array. Sorted means non-decreasing, so a sequence could contain duplicates. Your method should return 0 if passed an empty array.
*/ public class ten {
public static void main(String[] args) {
int[] arr = {3, 8, 10, 1,9, 14, -3, 0, 14, 207, 56, 98, 12};
longestSortedSequence(arr);
System.out.println(longestSortedSequence(arr));
[code]....
View Replies
View Related
Apr 8, 2015
I get the following error when trying to run my hangman program:
Exception in thread "main" java.lang.StringIndexOutOfBoundsExceptiion.
Why am I getting this error?
import java.util.*;
import java.io.*;
public class hangman {
public static void main(String[] args) throws FileNotFoundException{
Scanner kb = new Scanner(System.in);
String filename;
[Code] .....
View Replies
View Related
Jul 13, 2014
My problem is that I can't even run the program, because it gives me
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 13
at domashno.ten.longestSortedSequence(ten.java:37)
at domashno.ten.main(ten.java:17)
Code :
public static void main(String[] args) {
int[] arr = {3, 8, 10, 1,9, 14, -3, 0, 14, 207, 56, 98, 12};
longestSortedSequence(arr);
System.out.println(longestSortedSequence(arr));
}
public static int longestSortedSequence(int[] arr) {
[Code] ....
View Replies
View Related
Mar 16, 2015
I have an issue with an IndexOutOfBoundsException. I am trying to populate a db from another using arraylists and arrays. I can get the data but the program fails when trying to run the inserts. I am trying to perform SQL in batches of 5. I have added a comment to the failing line.
/*Set in code at beginning*/
ArrayList<String[]> privacyList = new ArrayList<String[]>();
ArrayList<String[]> statementBuffer = new ArrayList<String[]>();
/*Some sql is performed and the following String array is populated*/
while (rs.next()) {
String[] row = new String[55];
resultSetIsEmpty = false;
row[0] = rs.getString("ID");
[Code] ....
View Replies
View Related
Oct 21, 2014
import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import java.awt.*;
import java.awt.event.*;
[Code] ......
Just cant see where the array is out og bounds the array ButtonList has 9 buttons....
View Replies
View Related
Jan 16, 2014
Goal this time is to take a charArray, copy it into another charArray while reversing the things in it.
E.g. charArray["!ollaH"] into charArrayNew["Hallo!"]
My first idea was to revert the stuff in the Array with a ! cause i saw earlier that u can work with that too revert booleans. Sadly i didnt happen to make it work.
Next thing i thought of was a for loop to go trough the charArray and copy every section into charArrayNew just at the opposite end.
Java Code:
import java.util.Arrays;
public class aufgabe43 {
public static void main(String[] asgr){
char[] charArray
[Code] .....
Eclipse doesn't show any errors, and as u told me last time i did include import java.util.Arrays; to output the array in the end.
When i try to compile the code eclipse returns with an error
Java Code:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 68
at aufgabe43.main(aufgabe43.java:8) mh_sh_highlight_all('java');
Which I frankly don't understand since the array . Length is exactly the same.
View Replies
View Related
Apr 14, 2015
I am trying to print out all of the values of an array and the average. I am getting part of the printout but I am also getting an array out of bound error message. what I am doing wrong?
int [][] points = new int [2] [3];
points [0][0]= 3;
points [0][1]= 2;
points [0][2]= 4;
points [1][0]= 2;
points [1][1]= 2;
points [1][2]= 2;
int totalPoints = 0;
int totalShots = 0;
[code]...
View Replies
View Related
Mar 26, 2014
It seems that all of my arrays in the class Calculations are out of bounds, and I do not seem to know why.
Java Code:
/**
public class DataAnalyzer
{
public static void main (String[] args) {
//This creates an instance of ReadFiles
ReadFiles aReadFiles = new ReadFiles();
Calculations aCalculations = new Calculations();
[code]....
View Replies
View Related
Nov 30, 2014
I have been working on this program for a while and now i seem to be stump it throws an outof Bound array exception error, this program is a matrix multiplication program and spits out the resulting matrix using multithreading. i have a running one and result is
2 -1 0
1 0 3
-1 1 3
but this program's result is:
2 0 0
1 0 0
-1 0 0
it reads a txt document as an commandline arguement the text file reads just like this below:
3 2 2 3
1 0
0 1
-1 1
2 -1 0
1 0 3
the following is my code:
import java.util.*;
import java.io.*;
public class P3 {
public static int matrix1[][];
public static int matrix2[][];
[code].....
View Replies
View Related
Nov 11, 2014
I have a 2-D character array and I was wondering if I can compare a given index to an out of bounds index and what would I have to write? For instance
if(array[0 - 1][0 - 1] == 'indexoutofbounds'){ **// I know that 'indexoutofbounds' is probably not the right wording**
stuff happens
}
If I can do this what would I actually have to write in where it says 'indexoutofbound' ?
I will be using this for many indexes so it wont always be [0 - 1][0 - 1] it could be [4 - 1][3 - 1] in which case it wouldn't be out of bounds and wouldn't move onto "stuff happens"....
View Replies
View Related
Apr 26, 2015
I am making a very simple 2D array game where the player is asked what size they would like the game board to be. After entering, it displays the board and the player 'P' starts at index [0][0]. After that, they are asked for an action, which can be "up", "down", "left", "right", or "exit". I will be including some extra later (like a treasure at the end, or random obstacles), but for now this is what the game consists of.
I was instructed to "do nothing" when/if the player attempts to go out of bounds. I am trying to simply print an error, such as "Out of bounds! Try again.", then prompt the player again for an action. I even tried to make a boolean method to catch it, but to no avail.
I don't want the exception to occur at all. I just simply want the error message to print to the player and ask for another action. I would prefer not to use try/catch, or try/catch/finally since I already tried that and it still gave the exception error.This program consists of two classes. I will show the class containing the main first, then the client-server type class second.
import java.util.Scanner;
public class Driver {
public static void main(String[] args) {
World world = new World();
boolean keepPlaying;
keepPlaying = true;
boolean isOutOfBounds;
isOutOfBounds = false;
int height = 0;
int width = 0;
int x = 0;
int y = 0;
[code]....
View Replies
View Related
Oct 13, 2014
I am receiving an ArrayIndexOutOfBoundsException for the following code, which moves a creature through a 2D array maze. I have altered the clauses of the first if statement for the four direct methods (north, south, east, and west) multiple times (i.e. x + 1 >= 0 && x > 0 && x - 1 > 0 && x < array.length...etc). However, while the code occasionally runs, more often than that it returns this exception. Catching the exception seems like a poor workaround though if worst comes to worst I'll do that.
I included only the relevant functions of the code:
public boolean goNorth(char[][] array) {
boolean success = true;;
x = getX();
//x = this.x;
y = getY();
//y = this.y;
if ((x - 1 >= 0 && x - 1 < array.length)
&& (y >= 0 && y < array[x].length)) {
[Code] .....
View Replies
View Related
Jan 22, 2015
how can I got about sorting an array that contains more than one value in a single element. Such as my array below has 4 values under one element. I know how to sort elements with single values however, slightly confused on this.
import java.util.Scanner;
import java.util.Arrays;
class Mobile
{
[Code]......
View Replies
View Related