Business Application - Get Input From User And Converts It Into A String
Apr 24, 2014
So this application gets input from the user and converts it into a string. It then uses various methods to set instance variables of this class and ends up printing those classes to display information to the user about that products.
package javaapplication5;
import java.text.NumberFormat;
import java.util.Scanner;
public class Product
{
private String product;
private String description;
private double price;
[Code] ....
I am getting a logical error. My output is this:
Enter a product for information. Choose either Java or C++
java
Prduct: null Description: null Price 0.0
View Replies
ADVERTISEMENT
Jun 25, 2014
ABC is a company that designs and prints personal business cards. The company has asked you to write a Java application to display the layout of the information in a typical business card order. Data items in a typical business card include the customer's name, address, city, state, postcode, home phone number, and work phone number.
Write, compile, and test a Java class that displays these data items in a command window. Alternatively, you could also create it using a dialog box. Please include appropriate comments in your class.
Please named your class BusinessCard(LIM).java. (eq. BusinessCardLIM.java)
View Replies
View Related
May 8, 2015
I am trying to code using error handling and I am a bit confused on how to go about doing it correctly. My code converts a string that has all numbers into an integer and the error handling should recognize that if it isn't a proper number and ask the user to try again or enter 'q' to quit.Do I place a throw new exception in the try block and put conditionals like if charAt(i) is some letter or a symbol then throw new exception?
Java Code:
import java.util.Scanner;
public class practice {
public static void main(String[] args) {
Integer finalValue = null;
boolean validValue = false;
Scanner scan = new Scanner(System.in);
int result = 0;
[code]....
View Replies
View Related
Apr 13, 2014
I trying to get this code to get user input instead of reading from a hardcoded array. I'm getting compile errors while trying to get user input. Here's some of the code:
Java Code: // BubbleSort Java
// compile with: javac BubbleSort.java
// run with: java BubbleSort
[Code]....
View Replies
View Related
Jan 14, 2015
I have to take a users input. The general gist of the problem is I want to convert a decimal number entered by the user inputs into it's binary equivalent....the conversion part I know how to do.
I'm stuck at the user input phase. If the user inputs a decimal number within the correct range (lets say between 0-5000 for this example) the conversion goes ahead as planned and the program outputs on the screen the binary equivalent.
If on the other hand the user inputs a number outside of this range ... OR a String OR and empty space, an error message is given and the user is asked to try again. I don't know how to handle it if the user enters the different types...int or String.
View Replies
View Related
Jul 29, 2014
I'm having an issue with my program that needs 2 lines of input when I only want one. First I call Scan.nextLine(); to fetch a word. Then I want Scan.findInLine(word).charAt(number); to scan the string word for a letter instead of having to put another line in the console. How do I make Scan.findInLine(word).charAt(number); scan a single String instead of scanning input typed by the user?
View Replies
View Related
Jan 20, 2015
I am having trouble with getting a user input once they enter it in to a JTextArea and then storing it in to a string value. See, I wanted the user to enter an answer in to the JTextArea, and then once I store it in to a string value, I would be able to use it later. I wanted to after storing the variable to print it on to a JLabel, but nothing is showing up... Heres my code.
static String usera[]= new String [10];
for (int i=0; i< usera.length; i++) {
//These are the JTextArea names
usera[0]= Question1.getText();
usera[1]= Question2.getText();
[Code].....
I already initialized the JLabels earlier in my code, and I did not feel the need to post all my code here. This is where I am trying to get the string variable and then printing it out.
View Replies
View Related
Jul 26, 2014
I have the code below that just keeps getting the user's name and displaying it until the user enter's an empty string. Well, to simulate that, I just hit the keyboard instead of entering any name but for some reasons I am not seeing in my code, the programme just keeps looping.
System.out.println("Enter your name :
");
Scanner st = new Scanner(System.in);
while(st.hasNext()){
System.out.println("Enter your name :
");
String name = st.nextLine();
System.out.println(name);
if(name==" ") break;
}
System.out.println("you are out of the while loop now!!");
View Replies
View Related
Jul 8, 2014
I am trying to make a program that calculates the change due in dollars and cents. The user inputs both the amount due and the amount tendered. My program only works with whole numbers?
View Replies
View Related
Apr 16, 2015
I made a guess a number program but I am having issue figuring out a way that when a user enter's in nothing for the program to spit out a message saying "hey entering nothing doesn't work try again" then ask for input. I have done some research and from what I have found is to read the input in as a String rather than int, and use something like Integer.valueOf() to get the integer value but I am completely lost on how to apply that to my program here is my code
//import statements
import java.util.*; //for scanner class
// class beginning
public class Guess {
public static void main(String[] args ) {
//Declare variables area
int guess, secretNumber = (int) (Math.random() * 10 + 1), lowGuess,highGuess;
[Code] ....
View Replies
View Related
Dec 9, 2014
My assignment is to create a hangman game. One of my first difficulties with it is how to scan the string for an input supplied by the user.
Here is my method:
//Guesses that character c is in the secret word.
//Updates all instance variables accordingly,
//and returns true if c is present in the secret word.
public boolean guessCharacter(char c){
}
View Replies
View Related
May 5, 2014
trying to write a program that takes a user inputted number and converts it to a binary number.
Here's what I have:
package com.java2novice.algos;
import java.util.Scanner;
public class Converter {
static Scanner console = new Scanner(System.in);
public void printBinaryFormat(int number){
int binary = console.nextInt();
[Code]...
Bugs on:
Line 13
Line 17
Line 23
View Replies
View Related
Apr 7, 2015
The project is a program that allows the user to enter students and enter grades for each student. One of the requirements is that if there is already a grade stored for the student that it will display the previous grade. IF the user then enters a new grade the new grade will be stored. IF the user simply presses enter (enters an empty string) nothing is done. I have everything working except for the requirement of doing nothing if the user enters an empty string. If I just press enter at this point I get a NumberFormatException.
The below code is a method "setTestGrades" from the student class. This method iterates through each student object stored in an array list and then checks if there is a previous grade (Requirement# unset grades have to default to -1) before allowing the user to set a new grade.
public void setTestGrades(int testNumber) { //Sets the grade for the specified test number for each student in the arraylist.
testNumber -= 1;
Scanner input = new Scanner(System.in);
for (int i = 0; i < studentList.size(); i++) {
System.out.println("Please enter the grade for Test #" + (testNumber + 1) + " For Student " + studentList.get(i).getStudentName());
[code]....
View Replies
View Related
Mar 30, 2014
I am creating a simple Symptom Checker application. The problem I have is that I'm trying to retrieve user input (JTextField) by comma's using StringTokenizer which contacts the database for a result which matches the user's input (SELECT * FROM DIAGNOSIS WHERE ?, ?, ?) . It successfully finds the correct result however only in a particular format. Not different combinations....
for example, if I enter say within the JTextField: "tearful, nausea, lack of motivation" it will find the result successfully (as that is how it is formatted within the particular column (in the database table) i wish to display a result from) however, if i enter a different combination of these symptoms: "nausea, lack of motivation, tearful" - it will not find any result. I'm very unsure how to make it work regardless of what is inputted first, second or last.
Here is the code:
public void actionPerformed(ActionEvent e) {
try {
String abc = fieldsymp1.getText();
StringTokenizer str = new StringTokenizer(abc);
while (str.hasMoreTokens()) {
str.nextToken((", ")).trim();
[Code] ....
View Replies
View Related
Sep 23, 2014
I need to design, implement, and test a program to input and analyze a name. The program begins by retrieving a user input string from the keyboard. This string is intended to be the user's name. These are the errors we have to search analyze the user input for: No blanks between names firstName and lastName, Non-alphabetic characters in names, Less than two characters in first name, and Less than two characters in last name. Each of these errors must be thrown. All exceptions must be derived from a programmer-defined class called NameException. Each exception should use a detailed message to differentiate among the file types of errors.
This is the format of my NameException class, is the format itself correct? I will fill in the details of each exception I am just wondering if that is how I should set it up.
public class NameException extends Exception {
private String firstName, lastName;
public NoBlanksException(String firstName,String lastName) {
}
public NonAlphabeticalCharactersException(String firstName, String lastName) {
[Code] .....
I was told not to try and catch thrown errors in the main method, would I just create another method in the Driver class to take care of that then?
View Replies
View Related
Nov 11, 2014
I am writing a code in which a user inputs data as a string and that data must be verified as a valid number. A valid number is anything from 0-100. Then all valid numbers are converted into double numbers.
I am having trouble in how to write the validation part of the code.
Is it suppose to be an if, else statement? And if so how is it suppose to be validated?
View Replies
View Related
Apr 9, 2014
Write a java program that will ask a user to input grades until the user inputs the sentinel value -1. The program should test each input to determine whether 0<=grade<=100. If the grade entered is within this range, the program should print "Grade accepted;" if not, the program should print "Invalid input".
View Replies
View Related
Nov 4, 2014
I have been struggling with this program for weeks. This program is supposed to take a user's inputted odd number and then print out all prime numbers lower than that number.
public class PrimeNumber
{
Scanner scan = new Scanner(System.in);
int userNum;
String neg;
public void getUserNum()
[code]...
View Replies
View Related
Jun 30, 2014
I am going to develop a new web application of medium complexity. Right now i am somewhat comfortable with JSF and hibernate. I have never used JSF and hibernate together before.I just wanted to ask if it is good practice to use JSF (for both view layer and handling business logic) and hibernate(for persistence) without spring as a middle layer. The reason why i am asking this is i don't know anything about spring framework.
View Replies
View Related
Apr 9, 2015
Where do I input this segment?
Scanner user_input = new Scanner( System.in );// This line goes at the top with the other global variables
public void getUserInput(){
System.out.print("Enter litres: ");
litres = user_input.nextDouble( );
System.out.print("Enter mileage: ");
mileage = user_input.nextDouble( );
System.out.print("Enter speed: ");
speed = user_input.nextDouble( );
[Code] ....
This is my client file.
class Client{
public static void main(String []args){
Bike R1=new Bike(5.0, 60.0,30.0);//create bike object with params
Bike R2=new Bike();//without params
System.out.println(R1.increaseSpeed());//calling methods
System.out.println(R1.maxDistance());
System.out.println(R2.increaseSpeed());
System.out.println(R2.maxDistance());
}
}
View Replies
View Related
May 22, 2014
I'm having trouble with the last few lines of the code. It's supposed to take a replacement string entered by the user and print out the new string. For some reason it's now allowing me to enter a replacement string
import java.util.Scanner;
public class Project02 {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter a long string: ");
String lString = keyboard.nextLine();
[Code] ....
Output:
Enter a long string: the quick brown fox jumped over the lazy dog
Enter a substring: jumped
Length of your string: 44
Length of your substring: 6
Starting position of your substring in string: 20
String before your substring: the quick brown fox
String after your substring: over the lazy dog
Enter a position between 0 and 43: 18
The character at position 18 is x
Enter a replacement string: Your new string is: the quick brown fox over the lazy dog <------ isn't taking user input
View Replies
View Related
Oct 20, 2014
I am new to Java, programming, and intelliJ. I am trying to make a BMI Calculator using this code as my initial template which converts Fahrenheit to Celsius.
import javax.swing.JFrame;
public class Fahrenheit
{
//-----------------------------------------------------------------
// Creates and displays the temperature converter GUI.
//-----------------------------------------------------------------
[code]....
I created a local field within BMIButtonListener for weight, height, resultLabel, and was able to compile but it did not calculate and listed exceptions.
View Replies
View Related
Nov 26, 2014
I need to convert a .txt file to html text, where the first line is changed to have < h1 > < /h1 > around it and the rest is wrapped in < p > < /p > so for example I read a .txt file that says:
chapter 1
this is a sentence
it would output:
<h1>chapter 1</h1>
<p>this is a sentence</p>
here is what I have so far and I cannot get anything to output.
FileInputStream filestream;
BufferedReader reader;
FileOutputStream output;
String firstline;
String body = "<p>";
String line;
[Code] ......
View Replies
View Related
Feb 18, 2014
Create a Java application that prompts the user to enter their personal details: First name, last name, gender, address, suburb, postcode, and phone number. Then the program displays all of your personal details to the screen as illustrated. Name the file PersonDetails.jav
package exe
import java.util.*;
public class Review2 {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter your full name: ");
String name = scanner.next();
[Code]...
If you cant tell straight away how i have stuffed up, what is happening is this;
When i am promoted to enter my name, 'John Smith'. The word 'John' would be stored in the name variable, while 'Smith' is stored under gender, so the next prompt is then 'Whats your address?'
So its only assigning one word per variable, now as far i understand, a string should not work that way. So where is my mistake?
View Replies
View Related
Aug 3, 2014
I wrote a java application that coverts number grades to letter grades. Here is what it looks like:
/java application to That corresponds the letter grade with the number grade
import java.util.Scanner; //program uses the class scanner
public class gradescore{
[Code]....
View Replies
View Related
Jan 28, 2014
I need to track the client IP address from where user requested to my application.
I tried following:
request.getHeader("HTTP_X_FORWARDED_FOR"));
request.getHeader("X-Forwarded-For"));
request.getHeader("Proxy-Client-IP"));
request.getHeader("WL-Proxy-Client-IP"));
request.getHeader("HTTP_CLIENT_IP"));
request.getHeader("HTTP_X_FORWARDED_FOR"));
request.getRemoteAddr());
String ip = InetAddress.getLocalHost().getHostAddress();
In which InetAddress is giving my local machine IP when i run my application in localhost, but I mapped localhost:8080 with IIS server then InetAddress not giving exact IP address. How can we resolve this?
View Replies
View Related
