Business Application - Get Input From User And Converts It Into A String

Apr 24, 2014

So this application gets input from the user and converts it into a string. It then uses various methods to set instance variables of this class and ends up printing those classes to display information to the user about that products.

package javaapplication5;
import java.text.NumberFormat;
import java.util.Scanner;
 public class Product
{
private String product;
private String description;
private double price;
 
[Code] ....

I am getting a logical error. My output is this:

Enter a product for information. Choose either Java or C++
java
Prduct: null Description: null Price 0.0

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ABC is a company that designs and prints personal business cards. The company has asked you to write a Java application to display the layout of the information in a typical business card order. Data items in a typical business card include the customer's name, address, city, state, postcode, home phone number, and work phone number.

Write, compile, and test a Java class that displays these data items in a command window. Alternatively, you could also create it using a dialog box. Please include appropriate comments in your class.

Please named your class BusinessCard(LIM).java. (eq. BusinessCardLIM.java)

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Java Code:

import java.util.Scanner;
public class practice {
public static void main(String[] args) {
Integer finalValue = null;
boolean validValue = false;
Scanner scan = new Scanner(System.in);
int result = 0;

[code]....

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Java Code: // BubbleSort Java
// compile with: javac BubbleSort.java
// run with: java BubbleSort

[Code]....

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I'm stuck at the user input phase. If the user inputs a decimal number within the correct range (lets say between 0-5000 for this example) the conversion goes ahead as planned and the program outputs on the screen the binary equivalent.

If on the other hand the user inputs a number outside of this range ... OR a String OR and empty space, an error message is given and the user is asked to try again. I don't know how to handle it if the user enters the different types...int or String.

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I am having trouble with getting a user input once they enter it in to a JTextArea and then storing it in to a string value. See, I wanted the user to enter an answer in to the JTextArea, and then once I store it in to a string value, I would be able to use it later. I wanted to after storing the variable to print it on to a JLabel, but nothing is showing up... Heres my code.

static String usera[]= new String [10];
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[Code].....

I already initialized the JLabels earlier in my code, and I did not feel the need to post all my code here. This is where I am trying to get the string variable and then printing it out.

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I have the code below that just keeps getting the user's name and displaying it until the user enter's an empty string. Well, to simulate that, I just hit the keyboard instead of entering any name but for some reasons I am not seeing in my code, the programme just keeps looping.
 
System.out.println("Enter your name :
");
Scanner st = new Scanner(System.in);
while(st.hasNext()){
System.out.println("Enter your name :
");
String name = st.nextLine();
System.out.println(name);
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//import statements
import java.util.*; //for scanner class
// class beginning
public class Guess {
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[Code] ....

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Here is my method:

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public boolean guessCharacter(char c){
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Here's what I have:

package com.java2novice.algos;
import java.util.Scanner;
public class Converter {
static Scanner console = new Scanner(System.in);
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[Code]...

Bugs on:

Line 13
Line 17
Line 23

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Apr 7, 2015

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[code]....

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Here is the code:

public void actionPerformed(ActionEvent e) {
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String abc = fieldsymp1.getText();
StringTokenizer str = new StringTokenizer(abc);
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str.nextToken((", ")).trim();
 
[Code] ....

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[Code] .....

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public class PrimeNumber
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Scanner scan = new Scanner(System.in);
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String neg;

public void getUserNum()

[code]...

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Where do I input this segment?

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[Code] ....

This is my client file.

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import java.util.Scanner;
public class Project02 {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter a long string: ");
String lString = keyboard.nextLine();

[Code] ....

Output:

Enter a long string: the quick brown fox jumped over the lazy dog
Enter a substring: jumped
Length of your string: 44
Length of your substring: 6
Starting position of your substring in string: 20
String before your substring: the quick brown fox
String after your substring: over the lazy dog
Enter a position between 0 and 43: 18
The character at position 18 is x

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//-----------------------------------------------------------------
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//-----------------------------------------------------------------

[code]....

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FileInputStream filestream;
BufferedReader reader;
FileOutputStream output;
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String line;

[Code] ......

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package exe
import java.util.*;
public class Review2 {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
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[Code]...

If you cant tell straight away how i have stuffed up, what is happening is this;

When i am promoted to enter my name, 'John Smith'. The word 'John' would be stored in the name variable, while 'Smith' is stored under gender, so the next prompt is then 'Whats your address?'

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/java application to That corresponds the letter grade with the number grade
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[Code]....

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request.getHeader("HTTP_X_FORWARDED_FOR"));
request.getHeader("X-Forwarded-For"));
request.getHeader("Proxy-Client-IP"));
request.getHeader("WL-Proxy-Client-IP"));
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