Cannot Get Loop To Work After Catching Exception

Jul 3, 2014

I am trying to get user inputs (double types). so when i get a letter instead of a double i get an exception even though i had a while loop checking for this. so i looked up how to do exception handling and now when i get to that point it catches it but only outputs the message i gave and terminates instead of going through the while loop again. apparently there is no way to go back to before the error happened unless you use a while loop. but the loop isn't working it just terminates.

here's the code:

public static void collectInfo()
{
double firstW=0;
double secondW=0;

[Code].....

and here's the output when i ran the program(console):

Enter hours received for the first week of your paycheck. If you have overtime, just add it to this for example: 3 hours of overtime is 43 hours that week

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Catching Text Message From Exception

Apr 10, 2014

I can't catch the text message from a exception because ex.getMessage() is null.

Code is
 
try {
        .......
    } catch (Exception ex) {
            System.out.println("Error "+ex.getMessage());
            Logger.getLogger(Soap.class.getName()).log(Level.SEVERE, null, ex);
            statD.errMessage = ex.getMessage();
            statD.succes = false;
            return statD;
        }

And the program writes at the console:
 
Error null

Also on the console screen I can see the following message:

Apr 10, 2014 3:00:38 PM SoapUtils.Soap setPostVarsSEVERE: nulljava.lang.NullPointerException at SoapUtils.Soap.setPostVars(Soap.java:830)
Line 830 of Soap.java is inside the try {}.

Why is the ex.getMesage() null?

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Oct 26, 2014

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Ex:
}catch (IOException | SQLException ex) {
System.out.println("Exception thrown");
/**
* i want like this, if IOException is thrown then System.out.println("File not Found");
* if SQLException is thrown then System.out.println("DataBase Error");
*/
}

how to do this without using if-else block?

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Jun 10, 2014

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Jan 28, 2014

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import java.util.*;
public class Excercise04_31 {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);

[Code] ....

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Dec 12, 2014

I made this calculator in C++ and it worked wonderful so I decided to make it in java. When I run the program it gives me no errors but my if statements inside my while loop don't work

import java.util.Scanner;
public class ohmlaw {
public static void main(String args[]) {
float current;
float resistance;
float voltage;
String calchoice = new String();
Scanner cc = new Scanner(System.in);

[code]....

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Apr 16, 2015

I'm writing a code with a cellphone class to set price, brand and serial number. I'm also, in the main method, initializing 100 different cellphone in a matrix style ( up to here I'm fine). I have to use a copy constructor to define some cellphones ( fine too). Another thing I had to do was to generate random numbers and swap the price of the cellphones ( which I'm fine with too). My problem lies after using my static method. I have to display a new matrix with the changed price and return the counter that I used in my method to see how many times it was changed.

My two problems are that if I display my array again after I ran the method, it stays the same ( I didn't "catch" the change so I'm guessing the compiler just didn't keep them in the array). Secondly, I don't know how to return the counter. I don't have any ".getCounter" or something ( what I'm used to). Any input?

My formatting is terrible, I'm trying to improve it no need to point it out

Here's my code:

import java.util.Random;
//Cellphone Class ( apart from main method)
class Cellphone {
private String brand;
private long serialNumber;
private double Price;
//declaration of variables in cellphone class
 
[Code] ......

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Feb 17, 2014

Whats the best way to implement an error catching sequence.I was developing a program to write to a . csv file. and this is one of the methods in it and how I thought Try/ Catch should be implemented. So I have three different possibilities. Another auxiliary class with some constants:

Java Code:

public class Constants {
/**
* Constant name of the file.
*/
public static final String fileName= "inventory.csv";

[code]....

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Dec 9, 2014

I am catching an error in my driver class that reads from a file and sorts the data based on a person's GPA. Here is my code:

import java.io.*;
import java.util.*;
public class Driver {
public static void main(String[] args) {
new Driver(args[0]);

[Code] ....

Why throwing this exception?

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Jan 24, 2014

I was giving a quick skim to some tutorials on the internet where I have found the exception that is handled is also declared in the throws clause of the method wrapping the try-catch block. For a code representation consider the following:

public void methodName() throws IOException {
try {
...
} catch (IOException ex) {
.... TODO handle exception
}

}

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Sep 29, 2014

Right, so I got this program. It takes input from the user and assigns it to fields on an object. But, it's meant to check the users input. If the user enters bad input, it's supposed to throw this exception. For each of these exceptions, theres a class specifically for it.

public class PayrollDemo
{
public static void main(String[] args)
{
Payroll pr = new Payroll ("Test Name", 234);
System.out.println("Current Employee Information.
");
System.out.println("Name: " + pr.getName());
System.out.println("ID: " + pr.getID());
System.out.println("Hourly Pay Rate: " + pr.getHourlyPayRate());

[Code] ....

And this is the exception class.

public class InvalidNameException extends Exception
{
/**
No-arg constructor
*/
public InvalidNameException()
{
super("Invalid name");
}
}

PayrollDemo.java:43: error: cannot find symbol
InvalidNameException.InvalidNameException();
^
symbol: method InvalidNameException()
location: class InvalidNameException
1 error

It's just meant to tell the user that they entered an invalid value, which would mean if they entered an empty string instead of a name.

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Jan 27, 2015

I am trying to print a loop inside an array of a greater size than the loop itself. Like for example I have an array of size 7 but it has only 3 elements.

int[] array=new int[7]
array[0]=2;
array[1]=3;
array[2]=4;

now what I want to do is print these three numbers in a loop so that my array[3]=2;array[4]=3;array[5]=4 ...... till the last one. Also the array could be any size and not just 7.

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Feb 25, 2014

Here's the code: it's while loop inside a for loop to determine the proper length of a variable:

for (int i = 0; i < num; i++) {
horse[i]=new thoroughbred();
boolean propernamelength = false;
while (propernamelength==false){
String name = entry.getUserInput("Enter the name of horse "

[code]....

I was just wondering what was going on here -- I've initialized the variable, so why do I get this message? (actually the carat was under the variable name inside the parentheses.

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Nov 2, 2014

I have everything else working. My problem is that when i type "quit" to close the outer loop. It still runs the inner loop. The National Bank manager wants you to code a program that reads each clients charges to their Credit Card account and outputs the average charge per client and the overall average for the total number of clients in the Bank.

Hint: The OUTER LOOP in your program should allow the user the name of the client and end the program when the name entered is QUIT.In addition to the outer loop, you need AN INNER LOOP that will allow the user to input the clients charge to his/her account by entering one charge at a time and end inputting the charges whenever she/he enters -1 for a value. This INNER LOOP will performed the Add for all the charges entered for a client and count the number of charges entered.

After INNER LOOP ends, the program calculates an average for this student. The average is calculated by dividing the Total into the number of charges entered. The program prints the average charge for that client, adds the Total to a GrandTotal, assigns zero to the Total and counter variables before it loops back to get the grade for another client.Use DecimalFormat or NumberFormat to format the numeric output to dollar amounts.

The output of the program should something like this:

John Smith average $850.00
Maria Gonzalez average $90.67
Terry Lucas average $959.00
Mickey Mouse course average $6,050.89
National Bank client average $1,987.67

Code:

public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String name = "";
int charge = 0;
int count = -1;
int total = 1;
int grandtotal = 0;
int average = 0;
 
[code]....

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Jun 18, 2014

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Dec 13, 2014

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void print2(int n){
if (n<0){
out.printf(" %d",-1);
return;
}
out.printf(" %d", n);
print2(n-1)
out.printf(" %d", n);
}

this should be the output if n is 6: 6 5 4 3 2 1 0 -1 0 1 2 3 4 5 6.

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Mar 6, 2015

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My sample data for the var matrix is

[0,100,100,100]
[0,0,99,98]
[0,0,92,84]
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which shows flows between country A, B, C and D.

I would like to revise the tick labels, so that:

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pnlDeclensions.setAutoscrolls(true);

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Oct 4, 2014

So I'm working on a project and noticed that my toString() method won't work. This is just an example of the type of code that I have in my real project. THIS IS MY MAIN CLASS

XML Code:

package trialanderror;
import java.util.Scanner;
public class TrialAndError {
public static void main(String[] args) {
Scanner keys = new Scanner(System.in);
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[code]....

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I spent almost an hour with my bank experts, but they were unable to solve the problem.

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Later, I discovered that on the Java Control Panel under the Default Browser for Java, it has only IE and Mozilla, with the IE being checked and greyed out.

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Jan 12, 2015

All I am trying to do is to make a section of code execute if two strings are equal. The two strings are userId and "A001062". When I use the debugger in Eclipse, I can see the value of userId as "A001062" but whatever string comparison I try never evaluates to true. I have tried

userId=="A001602"
userId.equals("A001602")
"A001602.equals(userId)
Assigning A001062 to a string called AAA and comparing userId to AAA

My code is as follows. I have also attached a screen shot from the Eclipse Debugger which makes me think the string comparison should succeed. I never see the debugger execute the print line nor do I see the print line on the JBOSS console.

String userId = StringUtils.trim(nextLine[HR_USER_ID]);
String AAA="A001062";
if (userId.intern().equals(AAA.intern())) {System.out.print("MKP1: " + userId+"-"+managerId);}
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Attached image(s)

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Sep 13, 2014

import java.util.*;
public class OneDimenArray {
public static void main(String[] args) {
double[] decimals = new double[12];
double nums = 0.0;
double a = 1.0;
[Code] ....

These are the erroe codes I'm getting;

OneDimenArray.java:13: error: ']' expected
double[] decimals = double[Scanner.nextDouble()];
^
OneDimenArray.java:13: error: ';' expected
double[] decimals = double[Scanner.nextDouble()];
^
2 errors

----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

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Dec 14, 2014

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import java.awt.Dimension;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.PrintStream;
import java.util.Arrays;
import javax.swing.BoxLayout;

[Code] ....

BTW the error is on 310, 311, and 312 and the error is cannot find symbol ....

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// Using JSlider to size an oval.

import java.awt.BorderLayout;
import java.awt.Color;
import javax.swing.JFrame;
import javax.swing.JSlider;
import javax.swing.SwingConstants;
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[Code] .....

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