Catch Arithmetic Exception In Program

Jan 29, 2015

I want to catch the exception in my program is the below way:

class Temp
{
public static void main(String s[])
{
try
{
int x=10/s.length;
System.out.println(x);

[Code] ....

I am expecting my program should give output as "java.lang.ArithmeticException: / by zero" but is giving

Temp.java:11: error: ')' expected
catch (ArithmeticException e | ArrayIndexOutOfBoundsException e)
^
Temp.java:11: error: ';' expected
catch (ArithmeticException e | ArrayIndexOutOfBoundsException e)
^
Temp.java:16: error: 'catch' without 'try'
catch (Exception e)
^
Temp.java:22: error: reached end of file while parsing
}
^
4 error

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