Combining Characters Into A String
Sep 10, 2014
So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:
J
G
N
N
Q
As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code
import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;
[Code] ....
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Sep 27, 2014
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
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Apr 5, 2014
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
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Sep 16, 2014
how we can handle the string with special characters. For instance:
123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"
I get some user inputs with double quotes and i need to split to 80 chars line.
.length fails to get the length if it contains special characters like double quotes and ?
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Apr 8, 2014
like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
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Oct 17, 2014
As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?
Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}
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Jul 5, 2014
I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?
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May 7, 2014
I just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";
[code]....
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Oct 2, 2014
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
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Nov 4, 2014
I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.
import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;
[Code] ....
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Oct 1, 2014
I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.
Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)
Here is my code:
public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];
[Code] .....
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Sep 26, 2014
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
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Jun 30, 2014
In this simple example, I print a byte array to String:
Java Code:
import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};
[Code] ....
However, Eclipse prints out strange boxes, which I was unable to copy into this message.
It's supposed to print out the values of the bytes. What am I doing wrong?
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Dec 11, 2014
I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".
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Jan 27, 2015
I was trying to create a java program which can remove the repeated characters in a String. For ex-
Input: kamehamehaaa
Output: kameh
Here is my code:-
import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
System.out.println("Enter a word");
[Code] ....
On executing the program, StringOutOfBoundsIndex error occurs.
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Feb 18, 2014
I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."
What good is n-4 going to do if the string's lengths varies?
Here's what I have written thus far:
import java.util.Scanner;
public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");
[Code] .....
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Jul 3, 2014
I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.
Java Code:
String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');
What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.
I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.
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Sep 27, 2014
i have this code that I need to input into a GUI interface. how to start mixing the two together.
import java.util.Scanner;
import java.util.Date;
import java.text.ParseException;
[Code]....
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Jun 9, 2014
I have a JMenuItem "Find" in the Edit Menu. I want to add a shortcut key to the JMenuItem.
For Find for example i want to use Ctrl + F
Here is my 'Action' for 'Find' which can be used via Edit->Find. It works.
Find = new AbstractAction(){
public void actionPerformed(ActionEvent e){
String word = JOptionPane.showInputDialog(new MainWindow(),"","Find",PLAIN_MESSAGE);
new WordSearcher(textArea,word);
}
};
WordSearcher() is a class i am using to search the word
Now i want to add a KeyListener for ctrl+F, for doing the same purpose. Even this one works.
private KeyListener k1 = new KeyAdapter()
{
public void keyPressed(KeyEvent e)
{
if(e.isControlDown())
{
if(e.getKeyCode()== KeyEvent.VK_F)
[Code] ....
But the problem here is i have to write the same code twice. Is there some way by which I can Use the already written Action Find in the KeyListener.
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Mar 20, 2014
All I need to do is show in just one JFrame the two combined JFrames. One JFrame namely leftPanel will appear to the left or west and the other namely rightPanel to the right or east using BorderLayout. I already did creating them first as JPanels or as internal classes and subsetted them in one JFrame but that didn't work because it looked messy. And now I've created them as two separate JFrames, compiled separately, and tried to subset them as one in the JFrame. I didn't add any functionality to this program because all I intend to do is to show those two JFrames together in one JFrame. Here's the code:
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class dirtyIceCream extends JFrame {
leftPanel westPanel;
rightPanel eastPanel;
public dirtyIceCream()
[code].....
What am I missing or did I code anything wrong here? Or should I use NetBeans IDE for anything as complicated as this?
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Mar 8, 2014
Combining switch statements into if...else decisions? I'm basically trying to teach myself java and am at the point where I have to combine two user inputted values into if...else statements, only I don't really grasp how to do so. (This stuff is soooo addictive.) I'm trying to let the user input the type of residence they have, how many hours they are usually home, and then recommend a pet based on that. I just don't get how to input both selections they make in if...then statements. I get a bunch of errors as soon as I start the if...else part.
import java.util.Scanner;
public class PetAdvice
{
public static void main(String[] args)
{
int houseType;
int hourHome;
[Code] ....
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May 28, 2014
I have developed an application using Java JSP and PostgreSQL database which inputs data from users including multiple file uploads in different formats (MS Word, Excel, PDF etc.). The uploaded files are also stored in the database.
My client wants the software to print a report in PDF format which includes all user data entered (in a defined format) along with all the uploaded documents as appendices.
How the system can include all uploaded files into one PDF report?
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May 28, 2014
I have developed an application using Java JSP and PostgreSQL database which inputs data from users including multiple file uploads in different formats (MS Word, Excel, PDF etc.). The uploaded files are also stored in the database.
My client wants the software to print a report in PDF format which includes all user data entered (in a defined format) along with all the uploaded documents as appendices.
How the system can include all uploaded files into one PDF report?
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May 21, 2014
The problem is i want to replace some string text with foreign characters, but JTextArea returns plainText.
For Example:
str = new String();
str.replace('e', 'é');
textArea.setText(str);
but textArea returns plainText.
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Mar 7, 2014
I'am trying to converting string data into xml data using xml beans and StringEscapeUtils.This is work fine but in one case it if the data contains special characters.
Code snippet
--------------------
import org.apache.commons.lang3.StringEscapeUtils;
import org.apache.xmlbeans.XmlException;
import org.apache.xmlbeans.XmlObject;
public class ParseXMLData {
public static XmlObject parseXML(String stringXML) {
XmlObject xmlObject = null;
[Code] ....
success case
---------------------------
i/p------<aaa><bbb>This converts string to xml</bbb></aaa>
o/p---<aaa><bbb>This converts string to xml</bbb></aaa>
Failer case
-----------------
i/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
expected o/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
Observed that it converts < to '<' but as per xml rules, if data contains '< ' it fails. I want to convert staring and end tags to xml format and if data in b/w middle of starting and ending tags do'n need to convert it. How to do it.
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Mar 7, 2014
Is that the only way to code the JOptionPane? Seems rather similar to Sys.out
--- Update ---
I had more than this, but post was deleted somehow and this was the gist of it:
for(i = 0 ; i < charArray.length; i++){
if(Character.isDigit(charArray(i))){
address.replace("6", "*");
address.replace("7", "*");
Is there a better way to scan a character array for digits and replace any number in the array with another character ("*") in this case? The array is the address, " 1234 Runner Road " .
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