Compile Time Error - Cannot Invoke Read On Primitive Data Type Int

Jul 10, 2014

I have a code in which I am reading input from System.in and Destination is some where else

Here is my code

File file=new File("D:/output.txt");
OutputStream os=new java.io.FileOutputStream(file);
Scanner scanner=new Scanner(System.in);
System.out.println("Enter Data to write on File");
String text=scanner.nextLine();
int c=Integer.parseInt(text);
int a;
while((a=c.read())!=-1)
os.write(a);
System.out.println("File Written is Successful");

In the line while((a=c.read())!=-1)

a compile time error is shown "cannot invoke read on primitive data type int"

Where I am going wrong?

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Overriding Equals Method - Cannot Invoke Equals On Primitive Type (double)

Jan 7, 2014

I am trying to override the equals method for my class TeamMember I have two fields:

private Details details;
private double salary;

Code for override I get an error on salary saying cannot invoke equals (double) on the primitive type (double)

Is their something I am missing/coding wrong?

Java Code:

public boolean equals(Object obj) {
//test exceptional cases
//avoid potential NullPointerException/ClassCastException
if ((obj == null) || (this.getClass() != obj.getClass()))
return false;
TeamMember other = (TeamMember) obj; //cast to a TeamMember object
// compare fields details and salary
return this.details.equals(other.details)
&& this.salary.equals(other.salary);
} mh_sh_highlight_all('java');

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Flow of the int x=3; like where does the 3 go step by step?

Passing Primitive Data Type Arguments (from oracle java tutorials)

Primitive arguments, such as an int or a double, are passed into methods by value. This means that any changes to the values of the parameters exist only within the scope of the method. When the method returns, the parameters are gone and any changes to them are lost. Here is an example:

public class PassPrimitiveByValue {
public static void main(String[] args) {
int x = 3;
// invoke passMethod() with
// x as argument
passMethod(x);

[Code] ....

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Sep 25, 2014

I am currently working on modules of a java program but am having issues with this module . it gives this error code"syntax error on token '?', invalid primitive type".

This is my code:

import java.awt.*;
import java.awt.event.*;
import java.io.PrintStream;
import java.rmi.Naming;
import java.util.StringTokenizer;

[Code] .....

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I get an error when I try to divide 500 miles by 25.5 gallons

Exception in thread "main" java.lang.NumberFormatException: For input string: "25.5"
at java.lang.NumberFormatException.forInputString(Num berFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
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Java Result: 1

[Code] .....

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What Is A Compile Time Constant

Jul 16, 2009

"Because X is a compile time constant, the compiler will Y"... But what exactly is a compile time constant? And how can we determine whether something is treated as such?Obviously, a compile time constant is a constant value that is known at compile time... ... Literals are, by definition, compile time constants -- as they are constants, known at compile time.

But the definition of a compile time constant is a bit more complex. To start, let's examine section 15.28 of the Java language specification.A compile-time constant expression is an expression denoting a value of primitive type or a String that is composed using only the following:

Literals of primitive type and literals of type String Casts to primitive types and casts to type StringThe unary operators +, -, ~, and ! (but not ++ or --)The multiplicative operators *, /, and %The additive operators + and - The shift operators <<, >>, and >>>The relational operators <, <=, >, and >= (but not instanceof)The equality operators == and !=The bitwise and logical operators &, ^, and |The conditional-and operator && and the conditional-or operator ||The ternary conditional operator ? : Simple names that refer to final variables whose initializers are constant expressions Qualified names of the form TypeName . Identifier that refer to final variables whose initializers are constant expressions

This is the full definition of a compile time constant. And as you can see, it contains more than just literals. In fact, literals are merely the first bullet point on the list. Also, note that a compile time constant can apply to any literal that is of primative or String type.The next few bullet points are the operations that can be applied to a constant at compile time. This list is actually pretty long, as it is possible to apply most of the operations at compile time. It may actually be easier to remember what can't be apply at compile time -- pre and post increment and decrement, instanceof operator, or any method calls, are not on the list.

The last few bullets are the most interesting. It is possible to use a variable in the expression -- provided that the variable is a compile time constant variable. So... what is a constant variable? Going back to the JLS (section 4.12.4 to be exact)..4.12.4 final Variables.A variable can be declared final. A final variable may only be assigned to once. It is a compile time error if a final variable is assigned to unless it is definitely unassigned (§16) immediately prior to the assignment.

We call a variable, of primitive type or type String, that is final and initialized with a compile-time constant expression (§15.28) a constant variable. Whether a variable is a constant variable or not may have implications with respect to class initialization (§12.4.1), binary compatibility (§13.1, §13.4.9) and definite assignment (§16).The last part of the definition is the relevant part (I still find it amazing that this is that well hidden in the specification). To be a variable that is a compile time constant, the variable needs to be...declared as finalhave a primative or String typeinitialized (on the same line as the declaration)assigned to a compile time constant expression.

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C:UsersReignDownloadsIntec - Codecourse technology59850dChapter 12WorkWebStocks.java:20: package javax.servlet does not exist
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^
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[code]....

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uploadfromtaptalk1407333378833.jpg

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import java.util.List;
import java.util.Map;
...
HashMap<String, String > myMap = new HashMap<String, String>(){{
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...

Generates this error

C:/FSC/apache-tomcat-6.0.41/webapps/aspen/temp/x2_8656248460570782763/x2_5214718769032742331/StudentExport.java:47: error: <identifier> expected
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Jul 23, 2014

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^
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[Code].....

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I keep getting the error Admit.java:10 cannot find symbol

import java.util.*;
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[Code] ....

The compiler then reads:

Admit.java:10: error: cannot find symbol
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^
symbol: variable ACTScore
location: class Admit
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[Code] .....

10 errors

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When I am compiling(with javac hellojava.java) it shows following error:

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DatagramPacket response = new DatagramPacket(data, data.length,
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[Code] ....

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Java Code :

import oauth.signpost.OAuthConsumer;
import oauth.signpost.commonshttp.CommonsHttpOAuthConsumer;
 import org.apache.commons.io.IOUtils;
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cannot find symbol
v.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
...........................................^
(carrot at the J)

My view file:

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This is the question^

My codes are:

public static int change (int amount) {
int quarters = amount / 25 ;
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[Code] .....

The codes were working when i used System.out.println instead of return, but our teacher required us to use return (functions).

I get the compile error: Unreachable statement.

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