Convert A String Of ASCII Code To Char?
Aug 25, 2014I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
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Comparing Char In If That Convert To String
Apr 30, 2014what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
Convert String To Two Dimensional Char And Output Is Equal To Matrix
Jan 6, 2014I have written the code:
Java Code:
public static void main(String[]args)
{
Scanner input = new Scanner(System.in);
System.out.print("Type your text: ");
String text = input.nextLine();
int counter = text.length();
if(text.length()> 16)
[Code] ....
And input is: abcdefghijklm
output is:
Java Code:
a b c d
e f g h
i j k l
m x x x mh_sh_highlight_all('java');
So all i want is, if i type: abcdefghijklm
I want this output:
Java Code:
a e i m
b f j x
c g k x
d h l x mh_sh_highlight_all('java');
Convert String Array To Char Array
Apr 12, 2015I have an array of Strings, one on each line and I need to convert them into an array of char's.
For Example:
This
is
an
Example
of
what
my
input
is.
In order to accomplish that I did the following-
String[] lotsOfText = a.gettingAnArrayAsAReturn();
char [][] myCharArray = new char [lotsOfText.length] [lotsOfText.length];
for(int i=0; i<lotsOfText.length; i++){
for(int j=0;j<lotsOfText[i].length();j++){
myCharArray[i][j] = lotsOfText[j].charAt(j); }}
But whenever I try this and then try to print the output :
for (int i = 0; i < lotsOfText.length; i++) {
for (int j = 0; j < lotsOfText[i].length(); j++) {
System.out.print(myCharArray[i][j]);
}
}
I get nothing. I'm not sure what's the flaw in my logic, is it the char array initialization that's wrong or is it something else ?
Char To String
Oct 14, 2014I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
How To Put All Char In Loop To String
Mar 16, 2014I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
Getting Char At A Location In String
Oct 21, 2014I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
Check How Many Times Char Is Used In The String
Apr 1, 2014I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
Unable To Count Each Char In A String
Jun 5, 2014I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
If Statement - Char To String Casting?
Aug 3, 2014import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
Split String From Space Char
Mar 30, 2014I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
Check How Many Times Char Is Used In String
Apr 1, 2014I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
Why Print Char 0 (zero) plus String Does Not Work
Apr 3, 2015I have a simple doubt. I was studying and create some code to check the result and I found out a strange situation.
Whats wrong with this code? Why it does not print anything?
char = 0; //integer value
System.out.println( c +" String ");
and why this next works very well?
char = 1; //integer value
System.out.println( c +" String ");
I know that char is stored as a positive integer and assign with 0 is different of assign with '0'.
Finding A String Word In Char Array
Feb 13, 2015I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) {
// Gets the number of rows in the matrix
int rowLength = puzzle.length;
//Gets the number of columns in the matrix.
int colLength = puzzle[0].length;
[Code] ....
How To Compare String Input To Char Array
Feb 8, 2014What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?
View Replies View RelatedReturn Given Char That Matches Input String
Apr 17, 2015Processing a string. How would I only return a given char that matches the input string e.g. v and/or n and/or m.
Everything else that does not match will return a '*' - e.g. user input = t result = *
I assume I need to also iterate through this input string using charAt() ?
How To Convert Numeric String To Formatted String
Sep 11, 2014I have a string value returned from a background tool that will range from 0 to possibly terabytes as a full number. I want to format that number to use commas and to reduce the character count using an appropriate size modifier (KiB, MiB, GiB, etc). I've tried converting the string number to a Double value using Double.parseDouble() and then performing the math based on the size of the value with this code:
Double dblConversionSize;
String stCinvertedSize;
dblConversionSize = Double.parseDouble(theValue);
if (dblConversionSize > (1024 * 1024 * 1024))
stConvertedSize = String.format("%,.000d", dblConversionSize / 1024 / 1024 / 1024) + " TiB";
...
I've also tried using
String.valueOf(dblConversionSize / 1024 / 1024 / 1024) + " TiB";
However, the formatting is failing and I'm either getting a format exception or the result is displayed as a number with no decimal component.
Convert Java Code To Display Using Printf Statement With Two Decimal Places To Right
Feb 26, 2015How i would convert this java code to display using the printf statement, with two decimal places to the right...here is the source code so far, but it has a few errors and needs to be reformated for printf
import java.util.Scanner; // scanner class
public class PROB3_CHAL15
{
public static void main(String[] args)
{
double checks =0,
totalfee =0,
fee = 10,
fee1 =.1,
fee2 = .08,
fee3 = .06,
fee4 = .04,
checkFee;
String input;
Scanner keyboard = new Scanner(System.in);
[code]...
Cannot Convert From String To Boolean And Int To String
Apr 6, 2014I have errors in the "if" and both "else if" ... The compiler says "cannot convert from String to boolean and int to String ...
instructions:
1. Add two private instance variables, String courseName and char grade to this class.
2. Add accessor and mutator methods for these instance variables.
3. Add a method register which receives an integer data type and returns String data type according to the argument passed to it ("Math" for 1, "English" for 2, "No course" for any other input)
What I have so far:
package assignment9;
public class BannerUser
{
private int userId;
public int getUserId()
{
return this.userId;
}
public void setUserId(int userId)
[Code] ......
Convert Int To String
Nov 17, 2014How can i convert int to string ? The error I get is count cannot be resolved.
System.out.print("How many days?: ");
numberOfDays = keyboard.nextInt();
for(int count = ':';count <=memberCount; count++ )
System.out.print("What is band member # " + "'s name?");
memberName = keyboard.nextLine();
System.out.print("What is"+ memberName+"'s instrument?");
instrument = keyboard.nextLine();
members +=(count.toString() +":" + memberName +" -" + instrument + "" );
How To Convert String Into Int
Apr 16, 2014I created a word object representing a specified string under my public class word method such as
Word w = new Word("Blue");
now I am required to return a hashcode for this word, which is an integer based on the words instance data under the method called
public Word(String w);
{
}
I am not sure how to convert the string into an int so I would be able to return a hashcode.
Cannot Convert From String To Double
Oct 4, 2014//Students Full Name
firstName = JOptionPane.showInputDialog("Enter student " +
"first name.");
lastName = JOptionPane.showInputDialog("Enter student " +
"last name.");
// Get test grade (numbers)
[b]test1 = JOptionPane.showInputDialog("Enter test1 grade")[/b];
The line in bold is where that error comes up. I know it something simple but I can't remember. I declared both firstName and lastName as Strings and then the test1 I declared as double. I had a similar error in a previous assignment where I had a integer(age) input and then i had an output statement asking for a name all I needed to do was put keyboard.nextLine(); after my age input and I was fine.
Convert String To Integer
May 21, 2014I have to make a programm where the user gives you the bank sorting code and the account number and you give him the IBAN. That was so far no problem and I was done within minutes except of one thing that I simply can't figure out even though im trying since weeks. At some point I have to convert a string to integer. My research told me its with parseInt() and I dont get a syntax error when I compile my programm (using BlueJ). But when executing the programm stops and gives me some weird bug message. Here is code and bug message:
Java Code:
public class IBAN {
public IBAN(String Bankleitzahl, String Kontonummer) {
Bankleitzahl=Bankleitzahl.replace(" ",""); // Die Leerzeichen werden entfernt
int Anzahl=Bankleitzahl.length(); // Auf der Variabel Anzahl wird die Anzahl der Zeichen von der Bankleitzahl gespeichert
[Code] .....
Convert String To Matrix?
Mar 8, 2014I have string abcdef.I need to convert that string into 2 dimensional matrix.For each 2 characters in the string will be a matrix.For instance:
String: abcdef
Matrix will be: [a b],[c d],[e f]
How to do that in java?
How To Convert A String Object To A Set
Aug 20, 2011I want to store a String.split("seperator") to a Set<String>.
Example:
Java Code: Set<String> = (Set<String>) "a|b|c".split("|"); mh_sh_highlight_all('java');
Sadly String[] and Set are incompatible types.
About the same as using .add three times, but shorter.
How To Take Top Of Stack And Convert It To String
May 2, 2015For my classes I wrote I have puts strings into a stack and also a queue and am wondering how to take the top of the stack and the front of the queue and turn those into strings in my main class and run them through while loops that will detect if they are palindromes or not. Right now I am trying to peek and use first to put in my while loop but they don't work with the .charAt because they are not considered strings I think.
import java.util.Stack;
public class Palindrome {
public static void main(String[] args) {
// TODO Auto-generated method stub
String enteredLine;
int leftStack, rightStack;
int leftQueue, rightQueue;
[Code] .....