Convert Hexadecimal To Decimal WITHOUT Using Integer ParseInt Method
Mar 12, 2014
So I have to write a java program that converts hexadecimals to decimals without using the whole "integer.parseInt(AB1, 16)" method. I tried looking up how to do this but every forum/site I went to used this same method.
Java programming, I decided to write a code today that would convert decimal numbers to hexadecimal numbers. Unfortunately, it does not compile. The error message is "cannot find symbol - variable A", and might be the same error for the other variables B,C,D,E,F.
Here is my code:
public class dec2hex { public static void main (String [] args) {int nbr = 99; char a = A; char b = B; char c = C;
import java.util.Scanner; public class FindHexString { public static void main(String[] args) { String hexString = ""; //output a hex string int decNumber;//decimal number to be converted int storeInput; //copy f input decimal number
[Code] ....
I am trying to figure out how to convert from decimal to hexadecimal without using the java library function. This is just a guess. I could be wrong.
I am using a static method to convert a string to an Integer object. Next using a instance method to convert Integer object to an int.
Compiler is giving me two "cannot find symbol" errors:
One pointing to the dot operator between "Integer.valueOf(s)"
The other pointing to the dot operator between "obj.intValue()"
I have latest JDK installed: jdk-7u51-windows-x64.exe
Looks like JCL installed correctly with rt.jar file located in "lib" directory under "Program Files"
Following is source code:
Java Code:
public class StringToInt { public static void main (String args []) { String s = "125"; Integer obj = Integer.valueOf(s); int i = obj.intValue(); i += 10; System.out.println(i); } } mh_sh_highlight_all('java');
I am having an issue with my program. It is supposed to convert from a binary number to a decimal number such as bin 101 = dec 5. my first and foremost issue is that when I use System.out.println(parseBin("101")); it returns 5 as it should. However when I change 101 to 1013 it returns 13??? Why is this happening and why are my exceptions not catching the issue?
//import java.util.Scanner; public class BinaryFormatException { public static void main(String[] args) throws BinFormatException{ System.out.println(parseBin("1013")); //Scanner input = new Scanner(System.in); //System.out.println("Please enter a binary number using 1's and 0's: "); //String binString = input.nextLine();
I'm working on creating the Binary to Decimal program . hat is wrong with this part of my code. Why does it not take you into the loop.
import java.util.Scanner; public class question5 { public static void main(String[] args) { System.out.println("Enter a Binary number. "); // collect Scanner keyb = new Scanner(System.in); //
I am new to java programming and using bluej for programming and i have tried this question what i have have given in title ... How to do the following question without using strings.
Write a java program to input a binary value and convert it into decimal and Vice Versa. Without using String. Please make it for blue j format.
I know how to do this program it is just not coming to me. The whole point is to calculate and display the base (base-2 or binary, base-8 or octal and base-16 or hexadecimal) in representation of 'N'. The symbols A, B, C, D, E, F should display 10, 11, 12, 13, 14, and 15 in hexadecimal system.
import java.io.*; import java.util.Scanner; public class ChangeBase { public static void main(String[]args) { double num;
How i would convert this java code to display using the printf statement, with two decimal places to the right...here is the source code so far, but it has a few errors and needs to be reformated for printf
import java.util.Scanner; // scanner class public class PROB3_CHAL15 { public static void main(String[] args) { double checks =0, totalfee =0, fee = 10, fee1 =.1, fee2 = .08, fee3 = .06, fee4 = .04, checkFee; String input; Scanner keyboard = new Scanner(System.in);
I have to make a programm where the user gives you the bank sorting code and the account number and you give him the IBAN. That was so far no problem and I was done within minutes except of one thing that I simply can't figure out even though im trying since weeks. At some point I have to convert a string to integer. My research told me its with parseInt() and I dont get a syntax error when I compile my programm (using BlueJ). But when executing the programm stops and gives me some weird bug message. Here is code and bug message:
Java Code:
public class IBAN { public IBAN(String Bankleitzahl, String Kontonummer) { Bankleitzahl=Bankleitzahl.replace(" ",""); // Die Leerzeichen werden entfernt int Anzahl=Bankleitzahl.length(); // Auf der Variabel Anzahl wird die Anzahl der Zeichen von der Bankleitzahl gespeichert
If I use the class DecimalFormat to format long number, how can I convert it back to integer?
DecimalFormat longFormat = new DecimalFormat("#,###"); long testLong=11000; String strLong=longFormat.format(testLong); System.out.println("NUM : " + strLong); //Assume that at this point I don't have //testLong, I have only the strLong value... long newLong=Long.parseLong(strLong) * 2; //java.lang.NumberFormatException: For input string: "11,000
I am working with a JFormattedTextField. After adding the text of the FormattedTextField to an LinkedList i want to read it out and sum it up. So I have a problem to convert the String to and integer...
Example:
23.00 - to 23.00 + 11.00 - to 11.00 --> 34.00
I have tried it with splitting the string but it didn't work. How to do it?
public class MyInteger { private int value; public MyInteger(int number){ value = number; System.out.println("Constructor created with value of " + value);
[code]....
I can't seem to get the value for integer1 and integer2 to pass with the setValue method. I get a runtime error stating the I need to have an int value for these two integers.
The problem occurs at the second to last line of text in this code.
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package reversing_digits; import java.util.Scanner; public class Reversing_digits { /** * @param args the command line arguments */ public static void main(String[] args) { Scanner input = new Scanner(System.in);
I am writing a program to convert a base 10 integer to any base 2-16. Here are the terms:"The method is to convert the decimal value the user selected into whatever base the user selected and print the converted value one place value at a time by using an index into an array of characters 0-9 amd A-F that is initialized to contain those characters.In the method you will find the largest place value (i.e. power of the base) that will divide into the decimal number.
Then you can set up a loop that will operate from that power down to and including the 0th power to determine how many times each place value goes into the decimal number. Using the loop counter, index into the character array to print the character that corresponds to the quotient number and then subtract the product of the place value and the quotient from the decimal number. With the power (loop index) decreased, repeat until you finish the 0th place value. Here's what I have so far:
import java.io.*; import java.util.Scanner; public class ConvertIt {//start program public static void main(String[] args) {//start main Scanner input = new Scanner(System.in); System.out.println("Enter a positive integer from 0 to 10000."); int number = input.nextInt();
I need to convert c# function to java method. The important thing is String strKey. Parameters for testing are strMask= 4634958 and strSN=1394901184 and the result must be strKey = 2156325482!!! The result that I am getting with my Java code is 2138641814.This is C# code:
I'm sure the solution is simple, but I cannot find it.
/*reads a hexadecimal number input by the user and gives the corresponding base-10 value */
public class HexConverter { static int i; //used to keep place in the hexadecimal sequence given by user public static void main(String[] args) { //declaration of variables String hexgiven; //the hexadecimal sequence given by user
I am writing a program that converts any base 10 number to bases 2-16. I have the code for everything up through hexadecimal conversion, for that requires the use of letters. I understand an array list may be of use however I do not understand how to use that in this code. Below is what I have so far
import java.util.*; import java.io.*; public class convertBase { public static void main(String[] args) { int base; int number; String newNum;
[code].....
I commented out the hexadecimal portions.How would I go about coding for letters?