public static void main(String[]args) { Scanner input = new Scanner(System.in); System.out.print("Type your text: "); String text = input.nextLine(); int counter = text.length(); if(text.length()> 16)
[Code] ....
And input is: abcdefghijklm
output is:
Java Code:
a b c d e f g h i j k l m x x x mh_sh_highlight_all('java');
So all i want is, if i type: abcdefghijklm
I want this output:
Java Code:
a e i m b f j x c g k x d h l x mh_sh_highlight_all('java');
I have a string value returned from a background tool that will range from 0 to possibly terabytes as a full number. I want to format that number to use commas and to reduce the character count using an appropriate size modifier (KiB, MiB, GiB, etc). I've tried converting the string number to a Double value using Double.parseDouble() and then performing the math based on the size of the value with this code:
I have errors in the "if" and both "else if" ... The compiler says "cannot convert from String to boolean and int to String ...
instructions:
1. Add two private instance variables, String courseName and char grade to this class.
2. Add accessor and mutator methods for these instance variables.
3. Add a method register which receives an integer data type and returns String data type according to the argument passed to it ("Math" for 1, "English" for 2, "No course" for any other input)
What I have so far:
package assignment9; public class BannerUser { private int userId; public int getUserId() { return this.userId; } public void setUserId(int userId)
//Students Full Name firstName = JOptionPane.showInputDialog("Enter student " + "first name."); lastName = JOptionPane.showInputDialog("Enter student " + "last name."); // Get test grade (numbers) [b]test1 = JOptionPane.showInputDialog("Enter test1 grade")[/b];
The line in bold is where that error comes up. I know it something simple but I can't remember. I declared both firstName and lastName as Strings and then the test1 I declared as double. I had a similar error in a previous assignment where I had a integer(age) input and then i had an output statement asking for a name all I needed to do was put keyboard.nextLine(); after my age input and I was fine.
I have to make a programm where the user gives you the bank sorting code and the account number and you give him the IBAN. That was so far no problem and I was done within minutes except of one thing that I simply can't figure out even though im trying since weeks. At some point I have to convert a string to integer. My research told me its with parseInt() and I dont get a syntax error when I compile my programm (using BlueJ). But when executing the programm stops and gives me some weird bug message. Here is code and bug message:
Java Code:
public class IBAN { public IBAN(String Bankleitzahl, String Kontonummer) { Bankleitzahl=Bankleitzahl.replace(" ",""); // Die Leerzeichen werden entfernt int Anzahl=Bankleitzahl.length(); // Auf der Variabel Anzahl wird die Anzahl der Zeichen von der Bankleitzahl gespeichert
For my classes I wrote I have puts strings into a stack and also a queue and am wondering how to take the top of the stack and the front of the queue and turn those into strings in my main class and run them through while loops that will detect if they are palindromes or not. Right now I am trying to peek and use first to put in my while loop but they don't work with the .charAt because they are not considered strings I think.
import java.util.Stack; public class Palindrome { public static void main(String[] args) { // TODO Auto-generated method stub String enteredLine; int leftStack, rightStack; int leftQueue, rightQueue;
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a"; String name = "Angelina"; char c = code.charAt(0); char n = name.charAt(0);
If I use the class DecimalFormat to format long number, how can I convert it back to integer?
DecimalFormat longFormat = new DecimalFormat("#,###"); long testLong=11000; String strLong=longFormat.format(testLong); System.out.println("NUM : " + strLong); //Assume that at this point I don't have //testLong, I have only the strLong value... long newLong=Long.parseLong(strLong) * 2; //java.lang.NumberFormatException: For input string: "11,000
First project here and it has been a steep learning curve. I have some code in the TwoWaySerialComm class that will write to a Com port. In my other class EBIAlarm i have my GUI. The aim of my app is the send strings out of the Com port by pressing Jbutton1-3 I can open the Com port but I don't know how to send the string.
Some of the numbers can be converted from int to string , other cant. My problem is in if (input.length() == 3) and if (input.length() == 4. Basically having problems printing the 3 digit and 4 digit
public static void main(String[] args) { System.out.print("Skriv: "); Scanner console = new Scanner(System.in); String input = console.nextLine(); int firstDigit = 0; int secondDigit = 0; int thirdDigit = 0; int lastDigit = 0;
I'm trying to convert the first letter of every word in a String to uppercase. I've managed to isolate the first letter of every word and then make it uppercase but I don't know how to replace it.
public static StringBuffer makeUpperCase(){ String str = String.valueOf(input2); for(int i = 0; i < str.length(); i++){ if(str.charAt(i) == ' '){ char var = str.charAt(i + 1); var = Character.toUpperCase(var); System.out.println(var); } }
I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
I looked on other examples which have collection of object but I have this extra top level object "AvailableDeliveries" not sure how to handle that level.
How to convert numbers into string without using an array and a method ....
Example of arrayed code:
The code here is working but i want to use the other way for not using array just like switches and if and loops only. I made a code here but i did'nt run what i want to output .....
package UnderPackage; import java.util.Scanner; public class NumberToWords { static Scanner input = new Scanner(System.in); public static void main(String[] args) { int number; int b;
I need a Java algorithm that converts a string of numbers into text. It is related to how a phone keypad works where pressing 2 three times creates the letter "c" or pressing 4 one time creates the letter "g". For example a string of numbers "44335557075557777" should decode where 0 equates to a space.
I am trying to parse a XML string into `org.w3c.dom.Document` object.
I have looked at solutions provided [here](xml - How to convert String to DOM Document object in java? - Stack Overflow), [here](How to create a XML object from String in Java? - Stack Overflow) and a few other blogs that give a variation of the same solution. But the `Document` object's #Document variable is always null and nothing gets parsed.
Here is the XML
XMLMappingValidator v = new XMLMappingValidator("<?xml version="1.0" encoding="utf-8"?> " + "<mapping> " + "<container> " + "<source-container>c:stem.csv</source-container>
[Code] ....
When I call **v.getXML().toString()** I get `[#document: null]`
Clearly, the parse is failing. But I don't understand why.