I'm trying to complete a code to convert decimal to octal. however i can't figure out how to print the output correctly. it should be.. Your integer number 160000 is 0470400 in octal. (160000 is the number you input). My code is...
Scanner input = new Scanner(System.in);
int value;
int a;
int b;
int c;
int d;
int e;
int f;
int g;
String result;
[Code] .....
Lastly, my output prints everything correctly, but the input number always is 0.
Ex error: input= 160000
Your integer number 0 is 0470400 in octal.
it should be.. Your integer number 160000 is 0470400 in octal.
I'm trying to convert an octal number into a decimal number. I keep getting a big error that says java:63: error: class, interface, or enum expected. i need to use a public static int convert ( int octalNumber ) along with a public static void main ( String args[] ).
Here is my code. />
[public static void main ( String args[] ) { int foo; int valid = 0; Scanner sc = new Scanner (System.in); System.out.print ("Enter up to an 8-digit octal number and I'll convert it: "); foo = sc.nextInt();
I wrote this small program to take an octal number from the user and convert it to decimal form.
import java.util.Scanner; public class Decimal { public static void main (String args []) //gets octal number from user, later prints conversion { int octal;
[Code] .....
Some conversions work. For example, 77 will be correctly converted to 63, and 77777777 will be converted to 16777215. However, some conversions do not work. An example of this is 775002 gets converted to 74898.
I am trying to convert the double grossPay to 2 decimal places but cannot get it to work ,I am unsure of the correct way of doing this but this is how far I can get
I'm having extreme difficulty in working with a Vector storing a column with a BigDecimal value, and converting that single value into a float. I'm not sure why the code was written this way, but basically, I'm working with something called a vector that has a single Big Decimal value/column (not sure what the correct terminology is), and I want to store that value in a float variable called "dp". However, I don't know how to convert from the Big Decimal to a float.
Code is below:
String s = ""; sql = "SELECT DiscountPercentRate FROM Attendees WHERE AttendeeId=" + attendeeId; Vector v2 = sqldb.getResults(sql); /*I know that sqldb.getResults(sql) returns a vector with a single BigDecimal column of 15.0, in the test example I'm using*/ if (!v2.isEmpty()) { Vector data2 = (Vector)v2.elementAt(0); if (!data2.isEmpty())
[Code] .....
In case you're wondering what the sqldb.getResults() method looks, like, here's a snippet of it - There's an else statement that triggers in my case, adding a BigDecimal column to a vector, and returns that vector.
Vector v = new Vector(); ... else { BigDecimal bd = rs.getBigDecimal(i); vCols.add(bd); } v.add(vCols); ... return v;
How can I take the single result of my SQL query in that Vector/Big Decimal thing, and turn that result into a float value?
import java.util.Scanner; public class FindHexString { public static void main(String[] args) { String hexString = ""; //output a hex string int decNumber;//decimal number to be converted int storeInput; //copy f input decimal number
[Code] ....
I am trying to figure out how to convert from decimal to hexadecimal without using the java library function. This is just a guess. I could be wrong.
I get an error when I try to divide 500 miles by 25.5 gallons
Exception in thread "main" java.lang.NumberFormatException: For input string: "25.5" at java.lang.NumberFormatException.forInputString(Num berFormatException.java:65) at java.lang.Integer.parseInt(Integer.java:580) at java.lang.Integer.parseInt(Integer.java:615) at Mileage.main(Mileage.java:42) Java Result: 1
There's a main menu choosing binary,octa,hexa,and decimal if i choose decimal it will display decimal menu and then i will input the numbers of binary and then it automatically display the converting process for octa hexa and decimal. and if i choose octa . It display the octa menu and i will input the numbers in octa and then it automatically display the converting process for binary hexa and decimal.. and so on.. but in binary if i input 2 it will display invalid .. the same as octa hexa and decimal... in my code the only problem is the converting process. our instructor said no one will use a converter for our project. we will code it manually ..so for a moment .. this is my code..
import java.util.*; import java.lang.*; public class mainmenu { public static void main (String[]args) { Scanner in = new Scanner(System.in); char B, O, H, D, Q, L, N , Y; char bin , pk, pick ;
I'm using eclipse. I'm going to get straight to the point and give all the info I can, if the values in the first code box are used, shouldn't these values be left after all in the second box is done:
remainder=23, arr[0]=100, div=23/10=2.3, whole=2, and decimal=3?
When I use this code, div comes out to be just (2.0).
Java Code:
int leng=10; arr[0]=123; //int arr[1]=100; //int mh_sh_highlight_all('java'); Java Code: if (arr[0]!=arr[1]){ int remainder=arr[0]-arr[1]; arr[0]=arr[0]-remainder; double div=remainder/leng; //double div=Double.valueOf(remainder/leng); int whole=(int) Math.floor(div); int decimal=(int) ((div-whole)*leng); mh_sh_highlight_all('java');
I'm not sure were I'm going wrong in how div is being calculated, but I ultimately need div to be 2.3.
I've also used the second option commented out which still gives (2.0).
Add the following method to the BankAccount class: public String toString()Your method should return a string that contains the account's name and balance separated by a comma and space. For example, if an account object named benben has the name "Benson" and a balance of 17.25, the call of benben.toString() should return:
Benson, $17.25
There are some special cases you should handle. If the balance is negative, put the - sign before the dollar sign. Also, always display the cents as a two-digit number. For example, if the same object had a balance of -17.5, your method should return:
Benson, -$17.50
Here is my code:
public String toString() { String result = name + ", "; if (balance < 0) { result += "-"; } return result += "$" + Math.abs(balance); }
My code only works in case there are full two numbers for the cents part, not for the case when there's only one number. So I wonder how I can add an extra zero when needed.I can get only the decimal part and add a zero if it's less than 10, but I don't know how I can extract just the decimal part from the number. (The balance is just a double and it doesn't have any separate field for dollars and cents).
I do not know how to convert a reversed array to decimal.
The output should be:
How many digits to convert? (user will input) ex. 3 Please input digits: (user will input 3 digits) ex. 0 1 1 The binary digits are: 110 (<-reversed) The decimal value is: 6
Here is my code:
package numbersystemconversion; import java.util.Scanner; public class BinarytoDecimal { static { int digit=0; Scanner input = new Scanner(System.in);
The code is below and the problem I am having is the numbers after the decimal won't add together for the total I am teaching myself java through liang's 10th edition book and I took one of the sample programs further than what was shown. The one in the book only shows the tax amount I simply wanted to make it so that the purchase amount and the tax amount would add together
package javalearning; import java.util.Scanner; public class FindingTax { public static void main(String[] args){ Scanner input = new Scanner(System.in); System.out.print("Enter Purchase amount: ");
I am using NetBeans IDE 8.0.2 to program Java code. I am a beginner in Java.
Instead of getting two decimal places after the point, I am getting three despite using the code format for two ("##.##"). Actually, this happens even if I remove the format code between the quotes. It is as if the program cannot see the format code. Why this happens ?
Here is the relevant program code:
private void convertButtonActionPerformed(java.awt.event.Action Event evt) { double inputNumber = 0; // sets the decimal format
designing a program which allows you to buy stuff from the jframe with 10x items each with different pricing, so once you click the image button the cost of that is displayed in the textfield, ive been trying to set the jtextfield to a decimal point but have not been able to so far,
jTotal.setText(Double.toString(dTotal)); DecimalFormat myFormatter = new DecimalFormat("#####.#"); String output = myFormatter.format(dTotal); a visual aspect of it.
I am having an issue with my program. It is supposed to convert from a binary number to a decimal number such as bin 101 = dec 5. my first and foremost issue is that when I use System.out.println(parseBin("101")); it returns 5 as it should. However when I change 101 to 1013 it returns 13??? Why is this happening and why are my exceptions not catching the issue?
//import java.util.Scanner; public class BinaryFormatException { public static void main(String[] args) throws BinFormatException{ System.out.println(parseBin("1013")); //Scanner input = new Scanner(System.in); //System.out.println("Please enter a binary number using 1's and 0's: "); //String binString = input.nextLine();
I need this program to print out the gpa down to 2 decimal places and I can't figure out how to do it. It keeps saying it can't find decimal format and I'm not sure how to define it.
Java Code:
import java.util.Scanner; public class GPACalculator { public static void main(String[] args) { double creditHours = 0; double gradePoints = 0;
import javax.swing.JOptionPane; import java.text.DecimalFormat; public class Sample3 { public static void main(String args[]){ double amount,iRate,monPay,totalPay; int years; String amountStr;
I am a beginner in Java and I am currently learning about JOption pane.Using Strings I am accepting an input from the user and by using the Interer.ParseInt(variable) option I am able to multiply this two strings using the code below.
String Length; Length = JOptionPane.showInputDialog("Enter the Length"); String Breadth; Breadth = JOptionPane.showInputDialog("Enter the Breadth"); System.out.println(" Area is " + (Integer.parseInt(Breadth) * Integer.parseInt(Length))); System.exit(0);
How Do I make my code accept Decimal values. E.g. My Code should accept 10.02 as Length and 20.42 as Breadth and give the product a Decimal.
so I need my program to print in decimal format and I keep getting an error saying that it cant find symbol "decimalFormat". here's what I have so far.
import java.util.Scanner; public class GPACalculator { public static void main(String[] args) { int creditHours = 0; int gradePoints = 0;
I'm working on creating the Binary to Decimal program . hat is wrong with this part of my code. Why does it not take you into the loop.
import java.util.Scanner; public class question5 { public static void main(String[] args) { System.out.println("Enter a Binary number. "); // collect Scanner keyb = new Scanner(System.in); //
I am currently trying to solve a programming problem on this site, and the problem includes working on a 100 digits of decimal places of a certain irrational number. I tried using BigDecimal class but it displays, correctly me if I am wrong, just 20+ decimal digits. Is there other way to do this?
