Count Comparisons In Java Quick Sort

Oct 3, 2014

I have to count the comparisons in the quick sort. I have done it by using a global variable. But I am stuck in doing it recursively.

This is my code.

import static java.time.Clock.system;
import java.util.Arrays;
public class test {
/**
* The swap method swaps the contents of two elements in an int array.
*
* @param The array containing the two elements.
* @param a The subscript of the first element.
* @param b The subscript of the second element.
*
*/

[Code] .....

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Count Comparisons And Assignments In Three Sorting Algorithms

Feb 5, 2015

I have three sorting algorithms in which I must count the number of swaps/copies and comparisons. I am meant to only count the swaps and comparisons that involve anything other than indexes as they are too fast to really matter (according to the professor). My counters are in the right position or not. I keep coming up with swaps/comparisons that don't necessarily match the formulas I'm finding for best/worst case. Makes me think that my counters are somehow out of place or that I don't have enough of them.

Insertion Sort:

public class InsertionSort {
public static void insertionSorter(int[] array) {
int firstValue; // first value in array
int scan; // scan array through the array
int moves = 0; // number of moves

[Code] ....

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I guess the memory gets out of space and we need to increase the stack size in eclipse. How do I increase the stack size in eclipse.? I tried increasing through run--run configurations-- program arguments and typed---- -Xmx4096m but this didn't work in any way.

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So I'm trying to implement a quick sort method for an ArrayList of Strings and right now I'm getting the compiler error message: Exception in thread "main" java.lang.OutOfMemoryError: Java heap space. I don't know what that error means nor how to fix it. I've marked in my code where the error seems to be occurring.

import java.util.ArrayList;
public class quickSort
{
// constructor
public quickSort()

[code]....

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Feb 11, 2015

i'm currently going over single linked list, and i'm coming across an error which i do not know how to get by. I'm using single linked list for now just for study purposes, then i would move on to double.

Error: No enclosing instance of type LList is accessible. Must qualify the allocation with an enclosing instance of type LList (e.g. x.new A() where x is an instance of LList).

public class LList {
private static class Node<E>{
private E data;
private Node<E> next;

[code]....

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Sep 24, 2014

I am having a hard time getting some comparisons with Date to function correctly.I have a driver program and two classes, ZodiacDriver , ZodiacSign and ZodiacTable. In the driver program I build an arraylist of zodiacsigns in zodiactable. That all appears to be working I then pass a birthdate and the zodiac table to a method, determineSign. This is where I am having trouble. Right now Im just trying to match the incoming birthdate with a zodiac's date in the table. however no matter what date I enter, i get pisces, which happens to be at the bottom of the list. If I remove pisces from the list I get the current last zodiac. Here is my code:

ZodiacDriver
Java Code: package zodiac;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
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[code]....

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Using Count Element Method To Count Occurrence Of Characters In Array

Jun 30, 2014

I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}

now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.

How would one go about this using the counting elements technique?

I tried this but not sure how to use the counting elements technique.

char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'};
char[] bucket = new char[(arr[0] * arr.length)];
for (int i = 0; i < len; i++)
bucket[arr[i]]++;

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Apr 20, 2014

I have a HashSet, which I created to prevent duplicates upon output, but of course it's printing duplicates(or else I wouldn't be posting this). The order of my output does not matter, nor the input. The data type is String in the format (x + "," + z), where x and z are integers, creating a collection of coordinate sets. So to prevent the output of duplicates, I'm trying to get rid of the duplicates before they are added to the collection.

I've tried doing a '.equals()' string comparison but what happens is, since my string is added via one variable, it compares itself to itself and if itself equals itself it won't be added to the collection. I really need to keep this as a comparison of a single variable, because creating a key for each value would be sooo ridiculous for this volume of inputs.

So, with that being said, I would like to add one copy of the string, discard the duplicates, and do this thousands of times..

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Determining Average Number Of Comparisons For Quicksort?

Feb 24, 2014

My objective is to execute quick sort ( i was told to convert the pseudocode from the Cormen book) using arrays of increasing sizes and find the average number of comparisons for each of those sizes over 100 iterations. This is a school project and the numbers I am getting are far larger than those of my friends, so I am clearly doing something wrong. I believe it must be in the way that I am collecting and averaging my number of comparisons. I will first give the method in which most of that calculating is done, then I will include the whole program.

public static void tests(int arraySize) {
long numComparisons = 0;
long averageComparisons = 0;
long[] numComparisonsArray = new long[100];
  for(int i = 0; i<100; i++) {
int[] array= genRandomArray(arraySize);

[code]....

I was simply not zeroing out one of my variables

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How To Count 1st Duplicates Value In Array By Using Java

Apr 12, 2015

I have taken array int[] a = {33,33,5,5,9,8,9,9};

In this array so many values are duplicates means 33 comes twice & 5 also comes twice & 9 comes three times. But I want to count the first value which is duplicate means 33 is first value which comes twice so answer would be 2.

I try:

public class FindFirstDuplicate {
public static void main(String[] args) {
int c=0;
int[] a = {33,33,5,5,9,8,9,9};
outerloop:
for(int i = 0; i < a.length; i++) {

[code]....

Output:

33
Count: 1

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May 7, 2014

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public class arrays{
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[Code] .....

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..
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<ProductType ItemID="1001">
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</ProductType>
...
...
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import java.util.Scanner;
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[Code]......

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public static void radixsort( int[] a, int n) {
int i;
int digit = 1;
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[Code] ....

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[Code] ....

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[Code]....

The problem I've been trying to solve is that I am getting the stack overflow at line

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import javax.swing.JOptionPane;
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[Code]...

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}
}

result:

*
**
***

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I'm trying to count the number of elements in an ArrayList which also have duplicates. So for example, in an ArrayList of strings which contains cat, cat, dog, horse, zebra, zebra, the answer should be two.

If an element is found to be a duplicate, that element should then be exempt from the search so if that element is found again it should not increase the duplicate count.

Here is my code:

public int countDuplicates() {
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for (int i = 0; i < list.size()-1;i++) {
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[Code] ....

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Algorithm 4. MaximumArray(Arr)
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