Create Password Rule - Valid / Invalid
Oct 31, 2014
Make a password rule, and take input of the password from the user and compare the password with your rule, if the user had entered valid password then print the message, password valid, else the password is invalid for (the whatever) reason.
Rules:-
-Length 8-12
-Should have one numeric character
-No Special Character
-Atleast one UPPERCASE letter
PHP Code:
import java.util.*;
import java.lang.String;
import java.lang.Character;
public class PasswordSpence {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Please enter a Password: ");
String password = input.next();
if (isValid(password)) {
[Code] ....
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Dec 3, 2014
My homework is asking me to write a program that prompts the user to enter a password and displays "valid password" if the rule is followed or "invalid password"
Sample
enter a string for password: wewewx
valid password
It's being graded on
Design of my GUI
Dialog box
User friendliness
Creativity
My current issues with the current code I have written is simply the password doesn't work unless it starts with 2 digits, the other order it displays as wrong. and I have no idea how to add a GUI.
import java.util.*;
import java.lang.String;
import java.lang.Character;
[code]....
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Oct 26, 2014
I have to use wrapper class for this assignment. I need to know if my code is more like object oriented or not and am I using the wrapper class properly here? Let me know if I can make this code better.
I also need to know if I can mask this password input (STRING) using NetBeans/Eclipse IDE?
Password rule is as followed : Length of Password 8-12, with no special characters, including minimum one uppercase letter, and only one numeric value.
Java Code:
import java.util.Scanner;
public class Assignment1
{
private static String password=null;
private static void password_input()
[Code] .....
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Oct 26, 2014
I have to use wrapper class for this assignment. I need to know if my code is more like object oriented or not and am I using the wrapper class properly here? Let me know if I can make this code better.
I also need to know if I can mask this password input (STRING) using NetBeans/Eclipse IDE?
Password rule is as followed : Length of Password 8-12, with no special characters, including minimum one uppercase letter, and only one numeric value.
Here is the code :
import java.util.Scanner;
public class Assignment1
{
private static String password=null;
private static void password_input() {
Scanner input = new Scanner(System.in);
password = input.nextLine();
[Code] .....
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Oct 26, 2014
I have to use wrapper class for this assignment. I need to know if my code is more like object oriented or not and am I using the wrapper class properly here? Let me know if I can make this code better.
I also need to know if I can mask this password input (STRING) using NetBeans/Eclipse IDE? I did search, but I found the console method.
Password rule is as followed : Length of Password 8-12, with no special characters, including minimum one uppercase letter, and only one numeric value.
Here is the code :
import java.util.*;
import java.lang.String;
import java.lang.Character;
public class CheckingPassword {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Please enter a Password: ");
String password = input.next();
[Code] .....
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Oct 26, 2014
I have to use wrapper class for this assignment. I need to know if my code is more like object oriented or not and am I using the wrapper class properly here? Let me know if I can make this code better.
I also need to know if I can mask this password input (STRING) using NetBeans/Eclipse IDE?
Password rule is as followed : Length of Password 8-12, with no special characters, including minimum one uppercase letter, and only one numeric value.
Here is the code :
import java.util.Scanner;
public class Assignment1
{
private static String password=null;
private static void password_input()
[Code] ....
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Apr 21, 2014
Write a program reads in a series of passwords into an array. Store 10 passwords. After creating the password array, have the reader enter a password and see if it is in the array. Fi it is there, print "Valid password" and if it is not there, print "Invalid password."
This is what i have so far
Java Code:
public class passwordMatch
{
public static void main (String [] args){
String [] myArray = new String[10];
myArray[0] = "jasmine22";
myArray[1] = "jackson77";
[Code] .....
It doesn't compile. It gives me error saying .class expected next to String.myArray[]
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Nov 9, 2014
I am a beginner . How to add output for both valid and invalid lines in text file scanned in java ...
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Dec 2, 2014
I have a signed certificate from Entrust which I used to sign a DeploymentRuleSet.xml file. I placed the DeploymentRuleSet.jar in the proper location C:WindowsSunJavaDeployment, afterward the java control panel's security tab shows a link to "show the active deployment rule set" which did not exist prior to coping the file to the directory. When I click on the link a new window opens and says "Rule Set not found" ....
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Apr 1, 2014
How can i create a session when i loged in and how can i invalid it when i logout?
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Aug 3, 2014
Below is my java coding that i have done, but how to save the password after key in the user id and the password. And I also need the system able to unsave the password if the user choose to unsave it .
import java.util.Scanner;
public class Home {
private static Scanner sc;
public Scanner readPass;
static String savedName="";
static String savedPass="";
public static void main (String []args)
[Code] .....
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Nov 19, 2014
I have implemented a deployment rule set for our JRE enterprise deployments and it is working fine. We are currently deploying JRE version 1.8.0_25. I have stumbled upon a Java App (a webcam) on an internet site that I cannot get to run with the deployment rule set.
The rule set works with other java apps, but it’s as though it is ignored for this one. The rule set section in the ruleset.xml with the intention of allowing the webcam to work is as follows:
<rule>
<id location="IP Address of I assume the webcam, address specified in error when launching app" />
<action permission="run" />
</rule>
<rule>
<id location="URL of website hosting the webcam" />
<action permission="run" />
</rule>
I pulled it out of the deployment rule set and added it to the exception list without any luck getting it to work that way. How I can get this app to work with my Deployment Rule Set?
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Apr 4, 2015
username works perfectly, but when I enter password I get this error.
Java Code:
OKbtn.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if(Usernametxt.getText().equals("Admin") &&
(Passwordfld.getPassword().equals("Admin2"))){
System.out.println("permition granted");
}else{
System.out.println("permition Rejected");
[code]....
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Dec 2, 2014
I tried running the code for trapezoidal rule. It's my project in Numerical Methods, here's the code:
static double trapezoidRule (int size, double[] x, double[] y)
{ double sum = 0.0,
increment;
for ( int k = 1; k < size; k++ )
{//Trapezoid rule: 1/2 h * (f0 + f1)
increment = 0.5 * (x[k]-x[k-1]) * (y[k]+y[k-1]);
sum += increment;
[Code] ....
It cannot be compiled and I always get FileNotFoundException. I found on Javadocs that this will be thrown when a file with the pathname does not exist.
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Aug 26, 2014
I am new to JAVA GUI programming and was wondering how you go about getting and testing if a password field text equals something. For example, if the password equals "password" then do something.
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Dec 15, 2014
is the Java upcating and downcasting rules are same for general object type or generics types?
1) Dog dog = new Animal();
Type mismatch can't covert Dog to Animal - complie time error
2) Animal animal = new Animal();
Dog dog = (Dog) animal;
java.lang.ClassCastException: Animal cannot be cast to Dog at runtime.
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Apr 13, 2014
String must be 6 characters, first 3 must be letters, last 3 must be digits..Here is my code:
import java.util.Scanner;
public class ValidTicket {
public static void main (String[] args){
Scanner in = new Scanner (System.in);
String id;
int c=' ',i;
int letterCount=0, digitCount=0;
System.out.printf("Enter ticked id
[code]....
However when I run my program, it does not work:After I enter the string nothing happens.
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Apr 26, 2015
I am required to make a console calculator that takes the values as strings and turns them into doubles. The user needs to be able to enter something like 3+4+5*9/13 on one line and the application give the answer. As of this point I am currently on at the last section as making the user be able to enter the expression and present the answer. I have added an array list containing + - / * and the same with the numbers 1-9...I now need to actually get the information to all come together. I'm not sure how to do that. I *think* I have all the parts for it to work.
public static void main(String[] args) {
String input = ""; // initalize the string
boolean isOn = true; // used for the while loop...when false, the
// program will exit.
final String exitCommand = "Exit"; // exit command
[code]....
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Feb 4, 2015
I have some problems about performing regular expression. In the following code, the output as a result is being "valid last name". But in my opinion, it should be "invalid last name". Because "Doe" has not any space, apostroph or any hypen. Look at the regular expression statement: "[a-zA-Z]+([ '-][a-zA-Z]+)*"
package deneme;
public class Deneme {
public static void main(String[] args) {
String lastName = "Mc-Something"; // Mc-Something
if(!lastName.matches("[a-zA-Z]+([ '-][a-zA-Z]+)*"))
System.out.println("Invalid last name");
else
System.out.println("Valid last name");
}
}
I know that the asterisk qualifier means character(s) in any number.(Is this wrong?) So for "Mc-Something", 'M' corresponds to [a-zA-Z], 'c' corresponds to +, - corresponds to [ '-], 'S' corresponds to [a-zA-Z], "o" corresponds to +, and finally "mething" corresponds to *, doesn't they? But for "Doe", there is no any space, apostroph or hypen.
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Jan 16, 2015
I am creating a JSF 2.0 project, and I am facing a problem when using the rich:pickList (richfaces 4) component with a custom converter.
I can populate the picklist left column rightly. But, when I move some item from left list to the right (by clicking in the pickList "add" button) and I try to submit the form that contains the pickList, I receive the following error message:
"mainForm:picklist: Validation Error: Value is not valid"
I have already overridden the methods equals and hashCode in my model class (Pessoas.java), but the problem remains.
cadastroEvento.xhtml
<rich:pickList id="picklist" converter="ApresentadorEventoConverter" value="#{CadastroEventoBean.pessoasSelecionadas}" var="pessoa" sourceCaption="Pessoas disponíveis" targetCaption="Pessoas selecionadas" listWidth="365px" listHeight="250px" orderable="false">
<f:selectItems value="#{CadastroEventoBean.pessoas}" />
<rich:column>
[Code] .....
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Oct 5, 2014
I am working on allowing a user to enter an ID # using JOptionPane. If the ID is valid, then it will display the ID#, student name, and GPA. If it is not valid, then the window should pop up again to allow the user to enter a valid ID. I have managed to get that far.
I am struggling with once a valid ID # is entered, how do I get the loop to stop? I have tried several different ways, but the code below is the most recent one, and it is still not working!
import javax.swing.*;
public class StudentIDArray
{
public static void main(String[] args)
{
String enteredID;
int idNumber;
int x = 0;
[Code] .....
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Oct 3, 2014
public class TicTacToeGame {
public static void main(String[] args) {
char [][] board = new char [3][3];
displayboard(board);
int count = 0;
boolean loop = true;
[Code] ....
I also try with check if the move is vaild but no luck with that.
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Apr 6, 2015
I am currently working on an application with java and I want to do is upload and download details in .xlsx file. Uploading process is successfully worked but the problem is that when I download the file .xlsx with details at opening the file it gives me the following message :
Excel cannot open the file '(filename)'.xlsx' because the file format or file extension is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file.
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Nov 17, 2014
I'm trying to do a user validation loop that runs until the user enters a valid binary, q, or Q. I think the rest of my program should work as intended, but here is the areas of concern:
public static boolean isBinary(String num) //Check if the entry is binary
{
for(int i = 0; i < num.length(); i++) {
if(num.charAt(i) != 0 || num.charAt(i) != 1){
return false;
[Code] .....
The program runs without errors otherwise.
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Oct 14, 2014
[highlight = java]
public static int getNumberOfPlaylists(Path p)
This method should return the number of files in this path containing a valid M3U header.
How do I get this done?
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Apr 4, 2015
I need to create a program in Java for below question
"Prompt user for three sides of triangle and determine if it is valid triangle and then compute area"
With code and Sudo Code for above question.
I am using Netbean compiler.
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