I have a problem with slider which i want to create jlabels in a panel by sliding the slider and get the value but the jlabel doesn't show in jpanel. Below is the code :
JPanel PanelBoxes;
JPanel panel;
JLabel c;
public static void main(String[] args){
DividePanel div = new DividePanel();
div.go();
[Code] ....
I have written a drum machine using Java. Into said drum machine I list all 47 available MIDI drums. The instrument list is placed into a JPanel, along with a gridArray of checkboxes. The JPanel is then in turn added to a scrollpane. I have listed the MIDI drums in order of 'ground-up'. For example, the bass drum is generally at the bottom of most drum kits, so it is at the bottom of my MIDI drums list. Next up would be the snare, followed by the cymbals, and then by all the specialty percussives. Since most beats are started from the 'ground-up', laying to foundation, so to speak, I want the scroll bar of the scrollpane which houses the JPanel, which in turn houses the instrument list and the beat checkboxes, to be positioned, upon opening, at the bottom of the scroll pane. Nothing I have tried works. It always positions the slider somewhere in the middle of the scroll track. Below is a listing of just the buildGUI portion of the code, all the MIDI functionality has been removed to keep the size of the post to this forum down.
import java.awt.*;
import javax.swing.*;
import java.util.*;
public class BeatBoxG
{
JFrame overallOuterFrame;
JScrollPane namesAndSquares;
[code]....
I'm really struggling adding JLabels to my GUI. The code is giving no errors but the JLables aren't showing up as I think I've done something else wrong. Here's my method for adding the JLabels:
public void showGraphics(){
for(int i=0; i<message.length(); i++){
if(message.charAt(i) == '#'){
JLabel localLabel = new JLabel("test label");
getContentPane().add(localLabel);
}
}
}
I think the problem might be to do with how the rest of the GUI is setup and the fact that I haven't specified where to add the JLabel just that I'm adding them.
Here's what my GUI looks like.
I want the JLabels above the JTextArea.
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.util.*;
import java.util.Random;
import java.awt.FlowLayout;
public class Slider3 {
[code]....
The oint is to make an animation using Timer with various frames - So that's my code, but when I define the sider class, I keep getting cannot find symbol errors! I don't know what to do! Is it the change listener? My teacher never really taught us how to do it apart from Actionlistener. He said we might have to put it within an ActionListener?
I have developed JavaFx application with playback option using JavaFx Media player and slider controls. I am updating slider value using javafx mediaplayer.currentTime().addListener() method by adding Change/Invalidate listener.
While playing MP4 video, slider values are not updating (Change/Invalidate listener not getting triggered while playing video) on Mac OS(version : 10.9.1). Below is the sample code snippet.
mediaPlayer.currentTimeProperty().addListener(new InvalidationListener() {
@Override
public void invalidated(javafx.beans.Observable o) {
updateSliderValue();
}
});
I wrote a program that asks the user to enter some information, does some calculations and tells them what they need to order. I know there is a way I just do not know how to do it. I would like the output from the program which is presented in text fields to be printed onto a form I made in excel when a button is pressed.
View Replies View RelatedI want to develop an application, which shows a circular window with close, maximize buttons.
I want to create something like this: [URL]
Having trouble adding leaves to my tree. Developing a stand alone Java app using mainly SWT and Eclipse JavaEE on Windows.The tree is like this:
root
------parentA
--------------childA1
--------------childA2
--------------childA3
------parentB
------parentC
--------------childC1
--------------childC2
My requirement: when a child is selected/clicked I want to create a grandchild (there could be from zero to say 12 grandchildren). Thus if user clicks/selects childA2:
root
------parentA
--------------childA1
--------------childA2
----------------------grandchildA21
--------------childA3
------parentB
------parentC
--------------childC1
--------------childC2
Codewise I have:
import org.eclipse.swt.widgets.Tree;
import org.eclipse.swt.widgets.TreeItem;
Question one: do I need any further tree related imports to get this to work?
final Tree tree = new Tree(shell, SWT.VIRTUAL | SWT.BORDER | SWT.CHECK | SWT.V_SCROLL | SWT.H_SCROLL | SWT.SINGLE );
tree.setHeaderVisible(true);
tree.setBounds(975, 00, 375, 600);
[code]...
And it is here I've tried lots of options but it's like bleak mid winter - no new leaves What seems odd is that I can see the selected/clicked child text item.getText() but if I look at the index it is always -1. And I thought the index would let me create the leaf.
I am tasked with creating several JPanels each of which has a title centered at the top. As such I have created parent panel that each panel extends. However, I am uncertain as to whether drawing the string on the panel or using a JLabel is the best solution. The panels might allow dynamic resizing...
View Replies View RelatedIs it good practice to create a inner class for layered panels with lots of components? In my opinion this makes the code easier to read and a lot less clustered.
View Replies View RelatedWill the code below just create a new blank window rather than call the one I have? I want to call the one I have from my main method ideally.
JMenuItem menuDelete = new JMenuItem("Delete");
menuDelete.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
DeleteEnvironmentWindow deleteEnv = new DeleteEnvironmentWindow();
deleteEnv.setVisible(true);
}
I need to use a counter to keep track of user's input. In this class I am trying to create a combination lock that takes three strings. In the tester class the user inserts three strings and both are compared to see if users input matches correct combination. I have no errors only problem is the setPosition method. My output is always false.
public class CombinationLock {
private String first;
private String second;
private String third;
private String firstGuess;
private String secondGuess;
private String thirdGuess;
private boolean open;
private int counter;
[code]....
I'm building a text editor. At this point, the editor should be able to read and write text and rich text. I create an instance of a RichTextEditor class that I created that extends a superclass I created (that extends JTextPane). Both my rich text and plain text classes extends the superclass I created. I use the this.read() to input my plain text from buffered reader. I think I need to use the read(fileinput stream, rtf document) method from type RTFEditorKit, but I cannot use that because it does not extend RTFEditorKit. I don't want to create a new class that extends RTFEditorKit because I need stuff from the JTextPane.
here are the classes on git... the super: TextEditorPane.java
The plaintext: TextEditorWrap.java
and the rich: RichTextEditor.java
I have fiddled with the read() method in different ways. In all cases, nothing loads. If I use the BufferedReader method, it doesn't give me an RTF, just the code for the RTF file.
How should I proceed? Do I create some sort of RTF interface and implement it?
I need to display a list of environment id's out of my xml file into a JComboBox. I understand fine how to make lists and what not but examples are always hard coded.
View Replies View RelatedHow to create text fields, labels and input boxes on a GUI, we haven't covered these in class as of yet, but I want my project to stand out so I'd like to know how to build a GUI now.
View Replies View Relatedhow to create a tree data structure in java.I tried with a class consisting of node field and arraylist child nodes. but it does not satisfy the requirement.the requirement is that,
root: child1,child2,child3
child1:child4,child5
child2:child6,child7
on traversing it should print all the nodes as given above.no node should have same elements as child.
I have a problem with creating a rectangle in Java. When I create the first rectangle all is ok. But the next, is the problem.
View Replies View RelatedI'm getting a DOMException, "HIERARCHY_REQUEST_ERR". I know that the problem is from the following code towards the bottom in my function, but I don't know how to deal with it. When I get rid of doc.appendChild(staff);, I get rid of the problem, but it obviously doesn't add the new entry to my root element.
Element staff = doc.createElement("Staff");
doc.appendChild(staff);
import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
[Code] .....
I want to create a TASK MANAGER for windows OS using java. Of course i am not expecting any code snippets, that is, what are the classes to be included and moreover HOW to do it.
View Replies View RelatedAnyway I am creating a game for my A2 coursework, most commonly known as Checkers. I have completed my code and everything works as I had planned except that the CheckerBoard itself as well as the checkerpieces do not appear to be showing.
The section of were my board should be present is just a black space. Although my board does not appear to be displaying, all of the actions I perform on it such as clicking certain section produces the planned response, and although I've checked through my code I cannot work out what I've done wrong.
CheckerBoard content = new CheckerBoard(); // Sets the CheckerBoard values into the content to be used in the next line
application.setContentPane(content); // Container holds the values together, Content pane of the CheckerBoard
application.pack(); // Use preferred size of content to set size of application.
Dimension screensize = Toolkit.getDefaultToolkit().getScreenSize();
application.setLocation( (screensize.width - application.getWidth())/2,
(screensize.height - application.getHeight())/2 );
[Code] ....
I have noticed is that within the BoardComplete(), if you change the setBackground(Color.BLACK) to WHITE, it will change the colour of the section to white, but the checkboard is still unshown.
I'm finding common elements in a collection of arrays. This is my code so far.
import java.util.ArrayList;
import java.util.List;
public class CommonElements //< T extends Comparable<T> >
{
Comparable[] comparable;
Comparable[] tempArr;
Comparable[] tempArr1;
Comparable[] newArray = new Comparable[tempArr.length];
int comparisonCount;
[code]....
I'm using this method to sort through my array. The method accepts a collection of arrays (of varying length and of any type) as input, the algorithm input should be no greater than n(k-1). I know I can solve it using a quadratic algorithm, but it won't meet the requirement of the assignment. I did have an idea of storing all my algorithm in one giant array. After storing as one giant array I was going to sort it. After sorting I was going to compare each array side by side and see if they are the same. Here is note my teacher provided.
Note About Testing You will need to develop several sets of test collections for testing your algorithm. The grading rubric mentions covering the case where all the test collections have the same length, as well as covering the case where the test collections are of different lengths. You will also need to think about what constitutes the worst case scenario for this algorithm, since only that scenario will make your analysis of total comparisons performed a meaningful one. You can use the formulas in the grading rubric to tell you how many comparisons you should expect in the quadratic and linear cases. For example, if you have 5 total collections (1 query collection and 4 test collections), each of which contains 10 elements, the total number of comparisons performed in the worst case should be: (k - 1)N2, which for k = 10 and N = 10 is: (5 - 1)102, or 400 comparisons. For the linear algorithm, you should only have N*(k - 1), which is 10*(5 - 1), or 40 comparisons.
Here is Q/A that my teacher provided:
1. Are the elements in the collections already sorted?The input collections may or may not be sorted. Don’t assume that they are sorted.
2. Can I sort the elements in the collections? Am I supposed to sort the elements in thecollections?Yes, you can sort the elements in the collections. It is not required that you do so, however..
3. If I sort the collections, should I count the element comparisons that are performed by the sorting algorithm?No. The only element comparisons you should count are the ones that are directly used to find the common elements. Ignore comparisons performed by any sorting algorithms you use.
4. How do I extract an individual collection from the Object[] collections argument of the findCommonElements method?You will need to typecast each collection as type Comparable[]. For example:Comparable[] currentCollection = (Comparable[])collections[i];
5. Why are we using a one-dimensional Object array instead of a two-dimensional array of type Comparable (e.g., Comparable[][])?In Java, arrays are treated as objects, so only a variable of type Object[] can contain arrays. A variable of type Comparable[] can only contain Comparable elements, not arrays. A variable of type Comparable[][] also can only store Comparable elements. Although it is possible to organize the elements such that all the elements at indexes [1][i], for example, are considered to comprise a collection, this is not the same as having an array that contains other arrays. The additional bookkeeping is required to keep a 2D array organized is more complex than simply performing the typecast described above.
6. Can I use other data structures besides arrays; e.g., HashMaps?No. Although it is easier from a programming perspective to use higher order data structures like HashMaps to find common elements, using these structures simply hides the details. If you were to examine the implementations of those structures, you would probably find that they use relatively inefficient algorithms such as sequential searches to find elements. Additionally, if you use library components, you have no way of counting the number of comparisons performed, since you don’t have access to the source code of those components.
7. Is this a trick question? I can’t think of any way to get below NlogN comparisons.It is not a trick question. It is possible to solve this problem using a number of comparisons proportional to (k – 1) * N.
I just want to ask about a kind inheritance.Let say I have an interface MachineCode.I also have different classes, Binary, Hex and Octal that implements MachineCode
Question: How can I prevent java to create an Object like this:
Binary bin = new Binary();
Hex hex = new Hex();
Octal octal = new Octal();
those declaration above must be compile error,
I want to create Objects of Binary, Hex, and Octal this way:
MachineCode bin = new Binary();
MachineCode hex = new Hex();
MachineCode octal = new Octal();
I am creating a Guessing game program in java code. I am having an issue with the guess class and main/tester class running. The instructions for the game are The computer generates a random # and the user must guess that number in 7 or fewer guesses. If the guesses exceed 7, then the game is over and the user is asked if they want to 'play again?'These are things I need to incorporate into my code:
If Statement
A Loop of some kind
At least three imported methods
At least two methods you create
Obtains input from the user
At least two instance variables
At least two local variables
Some form of concatenation
At least two calculations
import java.util.Random;
public class Guess
{
int computersNumber; // A random number picked by the computer.
int usersGuess = 0; // A number entered by user as a guess.
int guessCount = 0; // Number of guesses the user has made.
[code]...
I would like to use java se api names like, undo, redo, stylededitorkit, htmleditorkit in editorpane swing. So, I don't understand how to use these apis.
View Replies View RelatedI'm trying to create a tile based map JPanel but all I get is a white screen. I'm fairly new to the Java Swing and AWT package so I've been watching tutorials on YouTube so learn as much as I can. I don't know where I'm going wrong.
I've got three classes: Window.java which includes the Main method, Panel.java which is the JPanel and Tile.java to draw all the images into an array.
Window.java:
import javax.swing.JFrame;
public class Window extends JFrame {
public Window() {
setTitle("Project");
setSize(500, 400);
setLocationRelativeTo(null);
[Code] ....
Panel.java:
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.Image;
import javax.swing.JPanel;
public class Panel extends JPanel implements Runnable {
private Image dbImage;
[code]....
I've checked through everything and still cannot find what I'm doing wrong. I did try different codes but I just got errors instead.
I have a java project in Eclipse. I make changes to this project from different computers. I think this is a good opportunity to learn and practice some source control. Is there a source control system which will allow me to do this very easily ? How about Git ? Any outline of the main steps needed to setup this thing with Git, preferably within eclipse itself ? I don't need each and every step to prepare the whole system. I only need the main steps like - download and install git on both machines, rent a server and create a repo on it, grant both computers access to the server etc.
View Replies View Related