Determine If User Input Is Fibonacci Number Or Not

Part A: While Loop Program

Write a program that detects Fibonacci numbers. Prompt the user to input a positive integer. Upon input, the program will determine if the number is either a Fibonacci number or not. If a Fibonacci number, then the order of the number in the sequence must be output. If not a Fibonacci number, then the Fibonacci numbers above and below it (including their order in the sequence) must be output. Once it finishes, the program will prompt the user for a new number. The program will exit if the user enters a string (such as “quit”) instead of an integer. Use the sample output file, fib-seq-det.txt, to view a sample session

This is my project, I wrote a programs that tells you if the input number is a fibonacci number or not. For some reason it only works for some Fibonacci numbers but not all of them.

import java.util.Scanner;
public class While
{
public static void main(String[] args) {
System.out.println("Welcome to the Fibonacci Sequence Detector
");
Scanner in = new Scanner(System.in);
System.out.print("Please input a number for analysis: ");
int input = in.nextInt();

[Code] ....