Display Lowest And Then Next Lowest Number From Array
Jan 5, 2015
I am not getting the result I am looking for, but I'm sure I'm on the right track. I have an array, names + times of marathon runners, and should end up with a program that displays the slowest runner, and the next-slowest runner.
Currently, I get this:
The lowest time is 273.
The lowest time is 243.
Changing names.length to times.length changes nothing.
for (i = 1;... ) changes nothing.
The displayed number should currently only be 243. Why is it displaying 273 first, and at all?
The code:
class Marathon {
public static void main (String[] arguments) {
String[] names = {"Elena", "Thomas", "Hamilton", "Suzie", "Phil", "Matt", "Alex", "Emma", "John", "James", "Jane", "Emily", "Daniel", "Neda", "Aaron", "Kate"};
int[] times = {341, 273, 278, 329, 445, 402, 388, 275, 243, 334, 412, 393, 299, 343, 317, 265};
int min = times [0];
for (int i = 0; i < times.length; i++) {
if (times[i] < min){
min = times[i];
System.out.println("The lowest time is " + min +".");
}
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[code].....
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