I use Eclipse IDE
public class Emp {
private String name;
private String jobTitle;
public void setName(String nameIn){
name=nameIn;
[Code] ....
<terminated> TestClass
Exception in thread "main" java.util.NoSuchElementException: No line found
at java.util.Scanner.nextLine(Unknown Source)
at TestClass.payOneEmp(TestClass.java:21)
at TestClass.main(TestClass.java:13)
I am new to java and still learning. I am trying to execute the code below which compiles successfully, but getting the following error:"Exception in thread "main" java.lang.NoSuchMethodError: main"
Code:
class Dog{
int size;
String name;
String breed;
void bark(){
System.out.println("woof woof");
}
}
class DogTestDrive{
[code]....
I have two classes, where main class is simple with only main function in it. Another class extends Thread and there's couple of functions I want to execute from main class.
Problem: I try to get other.shut() to be run in main class catch() block, after I have stopped the other class's running thread (e.g. by ctrl+c).
I think I need to somehow "pass" the exception from other class to main class so it goes to the catch block?
Code for main class:
Java Code:
public class MainClass {
public static void main(String[] arguments) {
OtherClass other = new OtherClass();
try {
other.exec();
} catch (Exception e) {
other.shut();
[Code] .....
import java.io.Console;
public class Introductions{
public static void main(String[] args){
Console console = System.console();
console.printf("Hello!My name is ---");
}
}
Output :-
Compiling Introductions.java.......
-----------OUTPUT-----------
Exception in thread "main" java.lang.NullPointerException
at Introductions.main(Introductions.java:5)
[Finished in 2.2s with exit code 1]
exception in thread main java.lang.nullpointerexception code 45 and code 116
the lines are highlighted and no the code tags did not show up when I uploaded the file.
I typed '[code]' below:
Java Code: /**
This program demostrates rainfall for a year
*/
[Code].....
I am working on a program that will allow a user to input grades for a class of four students who have taken two tests. Based on the grades entered, the program will calculate the averages of the two tests for each student and display it along with their respected letter grades.
Now I can get the program to compile successfully, but after inputting the grades in, I get the error message saying that it cannot format given object as a number. I am using 4 arrays to execute this program and maybe that's why I'm having the trouble? I'm not sure because I am still fairly new at this stuff and can't sen to resolve it.
I was having problems for a while and then finally got excited when I got it to compile without any errors and now I'm getting an error inside my program. All I need to do is format the numbers of the grades into something like: 000, and each of the averages as 000.0. I understand how to do it because I have done it in another program I've done in the past. I just don't know how to fix this error that is coming up.
here is my code:
import java.util.Scanner;
import java.text.DecimalFormat;
public class TestAverage
{
/**
* A program that will store and process 2 test scores for a class of 4 students.
* The program will prompt for the test scores as shown above in the sample run.
* After all the data is entered,the program will display the score for test 1, test 2 .
* The average of the 2 tests and the letter grade for the class for each student in a tabular format.
*
*
[code]....
My program is user input 20 char and the program will print the most common. So I use another int arr which count the number appears in the original array. i know its not so Effective but I don't know why it run but it stop in the middle. I got this code :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 20
at Ex2.common(Ex2.java:39)
at Ex2.main(Ex2.java:23)
import java.util.Scanner;
class Ex2 {
public static void main(String[] arg) {
Scanner reader = new Scanner (System.in);
char[] arr=new char[20];
System.out.println("Please enter 20 chars:");
for (int i=0;i<20;i++)
[Code] ....
I'm currently learning about Swing but I can't get my head round this piece of the code. Here is a simplified gui (not interested in the gui part but the execution)
public class SwingDemo implements ActionListener {
SwingDemo(){
JFrame jfrm = new JFrame("Simple gui pro");
//rest of code
public static void main(String[] args) {
new SwingDemo();
}
I get the above, create a new instance of SwingDemo in the main thread which starts up the gui through the constructor. However, then the tutorial says that I should avoid doing the above but do this instead:
public class SwingDemo implements ActionListener {
SwingDemo(){
JFrame jfrm = new JFrame("Simple gui pro");
//rest of code
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() { //why do this instead?
public void run(){
new SwingDemo();
}
});
}
}
Reading, it talks about an event-dispatching thread which has completely lost me... Why not just instantiate the object directly instead of creating another thread?
I am designing the game of Snake but it crashes after i added the checkScore() method.
package com.complex.snake;
import java.awt.*;
import java.awt.event.*;
import java.awt.image.BufferedImage;
import java.io.*;
import java.util.*;
import javax.swing.JOptionPane;
[Code] .....
The error i get is : Exception in thread "Thread-3" java.lang.ArrayIndexOutOfBoundsException: 1
I'm working on an assignment for my java class and I am currently stuck with an error/exception,
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:864)
at java.util.Scanner.next(Scanner.java:1485)
at java.util.Scanner.nextInt(Scanner.java:2117)
at java.util.Scanner.nextInt(Scanner.java:2076)
at BabyNames.search(BabyNames.java:45)
at BabyNames.main(BabyNames.java:20)
I input my name, which is able to get my name from the names.txt, however after that, it hits an exception and does not go further on.Also please use the names,
JIMMY
JIMMIE
JIMMU
JIMI
(All can be lowered case), because I am unable to upload the full file for it is very big.
import java.util.*;
import java.awt.*;
import java.io.*;
//Jimmy
//Programming Assignment #6: Baby Names
//This program is going to scan a file with data
//about names and their popularity starting from the 1890's
//and will display their popularity over the years in 10 intervals.
[code]...
The following code generates an array out of bounds exception
int[] myArray1 = new int[5];
for(int j = 0; j < myArray1.length; j++)
{
myArray1[j] = 10;
System.out.println("myArray1["+j+"] : " + myArray1[j]);
}
for (int i : myArray1) {
System.out.println("Blah myArray1["+i+"] : " + myArray1[i]);
}
The exception
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
at Tutorial2.main(Tutorial2.java:40)
Class A{
Public static synchronized void main(String args[]){
Thread t= new thread();
t.start();
Sysout("hi");
t.wait(1000);
Sysout("hello");
}}
Illegal state monitor exception. Why?
For this program, I have to run a slot machine. It runs until right before the do while loop and then I receive the error: Exception in thread "main" java.util.InputMismatch.Exception. Searching around, someone said it was a scanner error and adding a call keyboard.nextLine(); fixes the problem- however with that I receive the same error.
Code :
import java.util.Scanner;
import java.util.Random;
import java.io.*;
public class SlotMachineSimulation
{
public static void main(String[] args) throws IOException
{
int number;
[Code] .....
How do I call a class within the main. For example, this is what i have in my code right now. I am trying to call the class BlackJackGame.
package blackjack
public class BlackJack {
public BlackJack() {
BlackJackGame();
}
}
Spoiler
import java.applet.*;
import java.awt.*;
public class JhonnyBravo extends Applet {
/**
*
* @param g
*/
@Override
public void paint(Graphics g) {
Color skin = new Color(241, 210, 169);
[Code] .....
I have a Dynamic Web Project , and in one of the Class method I am reading an xml file. The problem is until now I am giving the absolute path of file on my system
File quizFile=new File("C:UsersMahtabQuizzesquiz1.xml");
I understand its bad way , so I want to put these xml files in my eclipse project itself.
So I created a new folder called quizzes under src and put all those xml files in quizzes folder.
I am trying to read the file , I tried
File quizFile=new File("quizzesquiz1.xml");
File quizFile=new File("quizzesquiz1.xml");
But getting FileNotFondException , how can I refer to these files.What path should I point to.
I currently use Eclipse to maintain our Java application. I recently upgraded from Java 6 to Java 7. I updated my Eclipse projects to use the Java 7 .jar files. I can run the application from Eclipse via the Run Configuration.
I can also run the Ant build and it completes successfully. When I install the application on my desktop, I receive the "Java Virtual Machine Launcher: Could not find main class..." error. My CLASSPATH is set to ".".
I was reading the book, "Head First Java" and it was talking about how there may be multiple classes in a large application, but there will be only one main method.how does it work that way? How can you have multiple classes, but only one main method?
View Replies View Related I have looked over other people code relating to files that are related to my actual studies in class. My teacher hasn't worked on a lot of file problems so I want to gain some understanding on it.
1.) I have this class with variables declared
import java.io.*;
public class FileDisplay {
private String filename;
FileWriter outputfile;
File Inputfile;
I'm aware that having a private variable would not allow that variable to be accessed outside the code. Vice versa, public variable would do that. The FileWriter and the File Inputfile is something I don't understand, especially have them in classes. What is the purpose of them?
2.)
public class FileDisplay {
private String filename;
FileWriter outputfile;
File Inputfile;
[Code] ....
I have made this code here that opens the output and input file. If I make another method, how would I display the text onto that same file. Hard to clarify for me, but in each method do I just keep creating :
FileWriter outputfile=new Filewriter(filename)
Why I have to place two parameters in the Verify constructor. If the numbers are being typed in by the user and passed through the validate method, what is the point of having them in Verify() ?
First, create three exception classes named NumberHighException, NumberLowException, and NumberNegativeException. Both NumberHighException and NumberLowException should be directly subclassed from the Exception class, but NumberNegativeException should be subclassed from NumberLowException. You can use the BadDataException class that was defined in this module as the model for your exception classes.
Next create a class called Verify that will be used to validate that a number is within a specified range. It should have one constructor that has two int parameters. The first parameter is the minimum number in the range, and the second parameter is the maximum number in the range.
In addition to the constructor, the Verify class should have one method that is named validate. The validate method should have a single parameter of data type int. The parameter contains the number that is being validated. If the value of the parameter is less than zero, the method should throw a NumberNegativeException. If the value is less than the minimum value of the range, it should throw a NumberLowException. If the value is greater than the maximum value of the range, it should throw a NumberHighException. If the value is within the specified range, no exception should be thrown.
Once all of these classes are created, create the driver class called Program5. The driver class should instantiate a Verify object with a range of 10 to 100. It should then do the following:
-Prompt the user to input a number within the specified range.
-Use a Scanner to read the user input as an int. You can ensure that an int was entered because the nextInt method throws an --InputMismatchException if any non-digits are entered.
-Call the validate method to validate that the number is within the range.
-Print an appropriate error message if the value is not within the range, or print the value if it is within the range.
I've been trying to work with custom Exception classes, but I keep running into what I think is an array error. It's in a very monolithic format because I was just trying to bang it out and get it done. Anyway, my issues is I am trying to compare values in the array to the minimum and maximum possible scores for a student (0 and 100) but I have totally forgotten how to do it.
Here is the code, the offending bit is at the very bottom:
package org.CIS407.Lab6;
import java.util.*;
public class TestScore {
public static void main(String[] args) throws ScoreException {
Scanner scan = new Scanner(System.in);
int sz; //holds scanner values
int[] studentArray;
[Code] .....
Right now I'm getting an error when I go to enter the very last student score. It throws an exception.
Here is a sample output of what I'm getting:
Enter number of students
2
Array created successfully. Enter student ID's into array
1
2
Enter number of scores
2
Array created successfully. Enter student scores into the array
50
32
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 2
at org.CIS407.Lab6.TestScore.main(TestScore.java:64)
The error I get when I execute my java file.
Exception in thread "main" java.lang.NullPointerExceptionat DogTestDrive.main(DogTestDrive.java:19)
Here is the source
class Dog {
int size;
String name;
void bark () {
if (size < 60) {
System.out.println("Woof woof");
[code]....
Some background: I'm reading "Head first Java 2nd edition" and I'm going through the examples which is showing me how to change the state of an object. The original code looks like the code below, however the previous chapter went over creating array's of an object, so I created an array of the object "Dog" and wanted to re-write it this way. To my understanding, it should work but it's giving me that error when I execute it. The error itself isn't very clear, if I could get a line number pointed to, that would work.
class Dog {
int size;
String name;
void bark() {
if (size > 60) {
System.out.println(“Wooof! Wooof!”);
} else if (size > 14) {
System.out.println(“Ruff! Ruff!”);
} else {
System.out.println(“Yip! Yip!”);
[code]....
im having an issue with the 3rd thread that are supposed to merge the two sorted sub arrays , i pass the 2 subarrays to my runnable function sortlist and they are renamed IntSortList 1 and 2 and th1.start() and th1.join() are called and it works fine, but then i have another runnable constructor that takes IntSortList 1 and 2 but it does take a runnable. below is the code in my main,
Runnable InSortlist1 = new sortList(data2p1);
Runnable InSortlist1 = new sortList(data2p1);
Thread th1 = new Thread (IntSortlist1);
Thread th2 = new Thread (IntSortlist2);
try
{
th1.start();
th1.join();
[code]....
class A extends Thread
{
String str;
public void run( )
{
//random stuff
}
}
[Code]....
How to access one thread from another thread?
View Replies View RelatedI was giving a quick skim to some tutorials on the internet where I have found the exception that is handled is also declared in the throws clause of the method wrapping the try-catch block. For a code representation consider the following:
public void methodName() throws IOException {
try {
...
} catch (IOException ex) {
.... TODO handle exception
}
}