Enter Password - If Correct Next Dialog Box Will Pop Up
Feb 28, 2015
The goal of this section of my assignment is to ask the user for a password. The password entered has to match the password I set in the code. If it is correct the next dialog box will pop up.
my password is set to:
String enterpwd = "";
String correctPassword = "Setpassword";
I am asked to use JOption, I completed as follows:
enterpwd = JOptionPane.showInputDialog(""............JOptionPane.QUESTION_MESSAGE);
then I use IF statements
if (enterpwd == correctPassword)
xyz = JOption .......();
I am getting an error "java.lang.NumberFormatException: For input string: """
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Dec 3, 2014
My homework is asking me to write a program that prompts the user to enter a password and displays "valid password" if the rule is followed or "invalid password"
Sample
enter a string for password: wewewx
valid password
It's being graded on
Design of my GUI
Dialog box
User friendliness
Creativity
My current issues with the current code I have written is simply the password doesn't work unless it starts with 2 digits, the other order it displays as wrong. and I have no idea how to add a GUI.
import java.util.*;
import java.lang.String;
import java.lang.Character;
[code]....
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I found different ways to code this for a button named "closeButton":
- closeButton.getRootPane().setDefaultButton(closeButton);
- thisDialog.getRootPane().setDefaultButton(closeButton);
- SwingUtilities.getRootPane(closeButton).setDefaultButton(closeButton);
Which is best?
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Apr 14, 2014
I simply need to write a program that asks a user to input a password. It has to be in this format: DDD-LL-DDDD. The D's mean Digit and the L's stands for Letter. The User has to enter the Hyphens.
If the password isn't entered in that exact format the program should read out a error. If the hyphens aren't entered the program should read out a error. If there are too many characters entered, there should be a error.
import java.util.Scanner;
public class security {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter Security Code: ");
System.out.println("Use the format: DDD-LL-DDDD and include dashes");
String code = input.next();
char c;
[Code] ....
I'm trying to figure how how to get the code to check if the values entered are in the correct place. I'm also not sure how to make the program check for hyphens. I feel like I'm close though. I can easily add the correct error and valid messages later if I could just figure out this part.
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import java.util.*;
public class test {
Scanner key = new Scanner(System.in);
String in;
int b;
public test()
[Code] .....
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public static void main(String[] args){
{
int grade = 0;
Scanner input = new Scanner(System.in);
System.out.println("Enter : ");
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if (grade >= 90)
[Code] .....
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username works perfectly, but when I enter password I get this error.
Java Code:
OKbtn.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if(Usernametxt.getText().equals("Admin") &&
(Passwordfld.getPassword().equals("Admin2"))){
System.out.println("permition granted");
}else{
System.out.println("permition Rejected");
[code]....
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import javax.swing.JOptionPane;
public class CalcutateTax
{
public static void main (String [] args)
[code]....
The problem is I cant think how to ask the use if he wants to calculate tax due for another taxpayer. If the user says yes, keep calculating, otherwise exit from the program. And how do I keep count of how many people got their tax calculated? Say for example,
JOptionPane.showMessageDialog (null, " We calculated tax for " + xnumber + " number of people.");
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[code]....
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0 0 0
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2 4 8
3 3 27
. . .
. . .
. . .
10 100 1000
I've figured it out but my only problem is the output dialog box displays each row individually (a new dialog box pops up for each row). How do I get it to display the whole table???Here's my code:
Java Code: import java.util.Formatter;
import javax.swing.JOptionPane;
public class Homework2 {
public static void main(String[] args) {
[code]....
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[code]....
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import java.util.Scanner;
import javax.swing.JOptionPane;
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public static void main(String args[]) {
[Code] ....
This program only brings in the first variable and the initial dialog box:
import java.util.Scanner;
import javax.swing.JOptionPane;
//creates a dialog box
public class KgLbs {
public static void main(String args[]) {
[Code] ...
I have attached the actual assignment and what the program should look like.
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[code]...
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import java.awt.GridLayout;
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[Code] ......
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Nov 12, 2014
i need to develop a java program in which it will ask the user "Username" and "Password" and by which it will login to a wesite.
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Dec 4, 2014
I have a question but dont know how I could verify the criterias..
The password should be at least six characters long
The password should contain at least one uppercase and at least one lowercase letter
The password should have at least on digit
Write a class that verifies that a password meets the stated criteria. Demonstrate the class in a program that allows the user to enter a password and then displays a message indicating whether it is valid or not.
I have not created a class because I really have no clue what to write in this case. My main method is:
import java.util.Scanner; // Needed for the Scanner class
public class Password {
public static void main(String[] args) {
// Create a Scanner object to read input.
Scanner keyboard = new Scanner(System.in);
String input;// To hold the input
[Code] .....
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Mar 4, 2014
It had no syntax error but if there would be any other error or if i would receive a wrong result
import java.util.*;
class tester {
public static void test() {
Scanner input=new Scanner(System.in);
int size= 0;
System.out.println("Enter your password:");
String enter=input.next();
size = enter.length();
[Code] .....
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