While doing trial and error got caught in the below scenario.
public class Crypt {
public static void main (String args[])
{
/*all I want is calculate a binary number (ex -: 22 , 34) using decimal base (10n).
*So, I have to convert 2 p into 10n form so I have to find n in terms of p . We have x as the input.
* The formula works as below.
*2p =10n
*p ln (2) =n ln (10)
*n = p [ln(2) / ln(10)]
*2 p = 10 p [ln(2) / ln(10)]
[Code] ....
I'm trying to insert some data of type date into database table using hibernate.i take the input date from an xhtml form as shown below
addEvent.xhtml
Event Date (dd-mon-yy) :
<br/>
<h:inputText id="eventdate" value="#{eventBean.eventDate}" p:required="required"
p:type="date"/>
<p/>
<h:commandButton value="Add Event" actionListener="#{eventBean.addEvent}" />
<p/>
This is my addEvent method in EventBean.java
public void addEvent(ActionEvent evt) {
uname = Util.getUname();
boolean a = EventDAO.add(this);
if ( a) {
message = "Event has been added!";
[Code] ....
While executing this..i get the following error: ORA-01861: literal does not match format string. Could it be due to any mismatch in date format (chrome browser automatically takes date in the format mm-dd-yyyy )? If yes, how do I resolve it? (I'm using Oracle database)
I'm not getting why my program is giving error.
package rockjava;
import java.text.NumberFormat;
import java.util.Scanner;
public class file4 {
public static void main(String[] args)
[Code] ....
Please Input Num of Pods + Num of Keys= 20.5
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextFloat(Unknown Source)
at alijava.file4.main(file4.java:14)
(It is not accepting double values. However working fine for integers.)
Here is a code and error .....
View Replies View RelatedI have a simple doubt
float k = 0;
k+=0.2;
k=k+0.2; // here compilation error
compliation error Type mismatch: cannot convert from double to float
My question is why not a complilation error at k+=0.2;
So today i was trying to compile a simple script that used to work before on Sublime Text 2, an i got the following error;
javac: invalid flag:
Usage: javac <options> <source files>
use -help for a list of possible options
I already know the script works because i didn't change anything since the last time it work, but anyways just in case i tried running a HelloWorld program just to check it out and i got the same error. The i stop trying to compiling the HelloWorld on Sublime so I went to Terminal and i got the same exact error.
I am having a problem with the JavaFX MediaPlayer playing videos with resolutions greater than 1920x1080px. For testing purpose I downloaded the example from [URL] ... and added the following error-handling:
mediaPlayer.setOnError(new Runnable) {
@Override
public void run() {
System.out.println(mediaPlayer.getError.getMessage());
System.out.println(mediaPlayer.getError.getType());
}
});
When playing a video with a resolution of 1920x1168px, the window became black and I get this console output:
[com.sun.media.jfxmediaimpl.platform.gstreamer.GSTMediaPlayer@5482fb8f] ERROR_MEDIA_INVALID: ERROR_MEDIA_INVALIDUNKNOWN
The video is encoded with h264 and aac (for audio) and is having a resolution of 1920x1168px. The error occurs with each video with a resolution greater than 1920x1080px. Vidoes with a resolution of 1920x1080px or smalle are working fine. The playback of all videos is working with VLC-Player. I tried Java 7_51 and Java 8_5.
I have uninstalled JAVA because I needed to download the 64-bit version but no matter WHAT I do I still get the same installation error message "keyset as registered in invalid" and I was downloading it from [URL] .... I will do whatever it takes to fix this!
View Replies View RelatedI am currently working on modules of a java program but am having issues with this module . it gives this error code"syntax error on token '?', invalid primitive type".
This is my code:
import java.awt.*;
import java.awt.event.*;
import java.io.PrintStream;
import java.rmi.Naming;
import java.util.StringTokenizer;
[Code] .....
Getting the following error at line 13.
Multiple markers at this line - void is an invalid type for the variable loadDictionaryFromFile - Syntax error on token ")", ; expected - Syntax error on token "(", ; expected
Line 13 starts public void load....
Code:
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class PirateTranslator
{
public static void main(String[] args)
[Code] .....
I am new to Java and trying to learn it.I wrote the following program but while creating the method nav i am getting errors.
Error:- void is an invalid type for the variable nav
import org.openqa.selenium.*;
import org.openqa.selenium.firefox.FirefoxDriver;
import java.util.*;
public class YahooHomepage {
private static WebDriver driver;
[Code] .....
I am trying to encrypt a message using RSA algo but getting the following error:
java.io.StreamCorruptedException: invalid stream header
at java.io.ObjectInputStream.readStreamHeader(ObjectI nputStream.java:753)
at java.io.ObjectInputStream.<init>(ObjectInputStream .java:268)
Java Code :
public static final String PUBLIC_KEY_FILE = "C:/TXT.key";
final String originalText = "Text to be encrypted ";
ObjectInputStream inputStream = null;
FileInputStream f= new FileInputStream(PUBLIC_KEY_FILE);
// getting error on the below line
inputStream = new ObjectInputStream(f);
final PublicKey publicKey = (PublicKey) inputStream.readObject();
final byte[] cipherText = encrypt(originalText, publicKey);
what is default literal for Boolean data type?
View Replies View Relatedchar c=(char)-65;
This is legal but how ?? what is the value actually being stored in c ? The output is shown as .
I have a program like below:
final String s1 = "AAA";
final String s2 = "AAA";
String s6 = s1+s2;
String s7 = "AAAAAA";
if ( s6 == s7 ){
System.out.println("s6 and s7 are same" );
}
On running, it prints "s6 and s7 are same". But if i remove the final modifier of s1 and s2 then it's not. What could be the reason?
I need to use print not println to declare stuff and I need to have string literals I think that's /n. Now when I compile it just shows row1, row2 ect. Why does it work like that?
public class art {
public static void main(String[] args) {
//local variables
String row1= "***********************";
String row2= "** *** *** **";
String row3= "** ***** ***** **";
[Code] ...
in Operator/Literals, it says "There is no literal representation for binary numbers in C, C++, or Java." seems "0b11001" could reprensent binary numbers?
int i = 0b100;
System.out.println(i);
the output should be 4.
I thought numeric literal were by default int or doubles, depending on if have a . and numbers after the But I wrote a quick test program as listed below. I understand the float float floatA = 5.5; failed to compile since 5.5 is a literal of type double and you are trying to assign this to a floag
What I am having problems with is byte byteA = 5; 5 is a literal of type int and this is being assigned to a byte and compiler should complain.The compiler does not allow two byte values to be added and assigned to a byte since the result of the addition is an int
class literalTesting{
public static void main(String[] arg){
byte byteA = 5; // allowed WHY I thought literal is an int and assigning int to byte
byte byteB = 10; // allowed
[code]...
I am working with java project which is kind of charting room..but the problem is when am writing the query for listing the message in the conversation the error prevail in my eclipse...string literal is not properly closed by double quote...this is my java file
<%
String uname=session.getAttribute("username").toString();
String pword=session.getAttribute("password").toString();
java.util.Date dat=new Date();
int x=1;
try{
[code]....
string literal is not properly closed by a double quote
View Replies View RelatedIf you write
byte b = 100; it works (implicit conversion of implicit int literal 100 to byte.
But if you have a methodvoid bla(byte b){}
And want to invoke it with a literal (which is an int by default):bla(8) then there is no implicit conversion.
Is the byte b = 100; just an exception in Java? And is it the rule that one has to explicitely cast (narrow) integer literals when passing to smaller-than-int types?
Will I'm tying in my code to set a default number for the JTextField that when the user decide not to put any numbers. Like let say that I want the textfield set to 0 , so then the user do not file it it won't make any problem to the program because its already has a default number.
if (stringGQ != null && stringGW != null && stringGP != null){
stringGQ = gMQ.getText();
stringGW = gMW.getText();
stringGP = gMP.getText();
weightPrice_1M = Double.parseDouble(stringGW) * Double.parseDouble(stringGP);
[Code] .....
Note: This is a small part of my code. when I leave it empty it take the 0 as a value, However, when I write in text field it also take the value of a 0 and the finalTotal is also = to 0.what I'm doing wrong.
What is the difference between float and double?
View Replies View RelatedI am getting the blank value in the array and this code is passed in IVR for playing the values since the first value is blank the prompts arrangements is disturbed. I want to replace the blank space or value by zero.
I have pasted the log and below is the code.
DEBUG - 7053CFEF4819D884638A42F088B507C3:/EntryPoint_1000 : session id:IVREPMSUAT2-2015083130037-4 |
Comm_DBinteraction-trcITELOutput | V_COUNTERTYPE:: | v_counterType : 1,2,3,4,5,6,7,8,9,10
DEBUG - 7053CFEF4819D884638A42F088B507C3:/EntryPoint_1000 : session id:IVREPMSUAT2-2015083130037-4 | Consult_IVR_3000:Comm_DBinteraction-trcITELOutput | V_SPENDINGLIMIT:: | v_spendingLimit :,500.0,59.5,0.0,1101.0,581.5,393.0,0.0,0.0,0.0
[code]....
How do I write a program that shows the max and the min value of a float integer? I found out that in order to get the long I just type in
System.out.println(Integer.MAX_VALUE); and System.out.println(Integer.MIN_VALUE);
I don't know how to do it to a float integer.
//Output is:ERROR.. one of the books says, we can assign float value to int variable, but its giving error.
class floint
{
public static void main(String arg[])
{
int i;
float j=10.12f;
i=j;
System.out.println(i);
}
}