FILE Input Without Delimiter
Apr 28, 2014
This is my input from my text file: 1|John Jay Smith|1985-01-10|2010-05-10|2014-03-05|212-222-2233..So, I have to convert 1 to integer. Break John Smith into first name as John and Middle name as Jay Last name as Smith.If no middle name is given then first is John and Last is Smith . Read 1985-01-10 as a date value . 2010-05-10 as another date value which could be null. 2014-03-05 as another date value which could be null. and at last 212-222-2233 as phone number.
Scanner sc = new Scanner (inFile);
sc.nextLine();
while (sc.hasNext()){
String row= sc.nextLine();
I want to read this line of input and assign the value accordingly.
View Replies
ADVERTISEMENT
Jan 8, 2014
How can I change the value of
String str = "1234|U||45|||"
into
String str = "1234|U| |45| | |"
View Replies
View Related
Apr 20, 2014
Working on my java skills. The is Delimiter function is suppose to return true if there is a delimiter in the string and false otherwise. The main is suppose to call this function and count the number of words in the string:
Here is what I came up with:
import java.util.*;
public class NumberOfWordsInString {
public static void main (String[] args){
Scanner in= new Scanner (System.in);
String s;
[Code] ....
Somehow my method isn't being successfully called by my main and the following error msg was received:
Exception in thread "main" java.lang.Error: Unresolved compilation problems:
length cannot be resolved or is not a field
The method isDelimiter(char) in the type NumberOfWordsInString is not applicable for the arguments (char[])
at javaimprovements.NumberOfWordsInString.main(Number OfWordsInString.java:10)
line 10:
char ch [] = new char [s.length];
and the main doesn't call the isDelimiter function
View Replies
View Related
Mar 22, 2014
I have a text file that has contents as follows:
testing1,true,0,0.0,0,0.0,4.0,0.0,0.0,0.0,0.0
test2,true,0,0.0,0,0.0,4.0,0.0,0.0,0.0,0.0
I am trying to read only the first item in each list using a comma as a delimiter using the following code.
public String[] pList() {
ArrayList<String> names = new ArrayList<String>();
String word;
try {
String path = P_FOLDER + P_FILE;
[Code]....
View Replies
View Related
Feb 13, 2015
I am testing some stuff here is my code:
public static void main(String[] args) {
String[] a = new String[5];
//String input = JOptionPane.showInputDialog(null, "enter input");
Scanner scanner = new Scanner(System.in);
[Code] ....
I am trying to type in 5 strings from java console and print them all out. I am using a "/" as a delimiter. My problem is that it does not print any output after I type strings separated by "/" like this: hello/gea/cae/eaf/aer and press enter. It works if I use JOptionPane but from the console its not working. I want to use the console instead of JOptionPane for this one.
View Replies
View Related
Sep 4, 2014
I have a header in file like below:
EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1
passed to a string
String test = "EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1";
I have to check if the header has only alphanumeric and pipedelimiter is allowed.
Other than these i need to raise an error.
View Replies
View Related
Jul 14, 2014
So I was going to try to create a program that prompts input and creates a file (That didn't exist before) with that input as name.Then, the program prompts inputs after stating questions such as 1 + 1, then if the user inputs an answer, put "Question # = Correct "or" Wrong.Code SO Far:
Java Code:
import java.io.BufferedReader;
import java.io.File;
import java.io.InputStreamReader;
public class File_Read {
public File_Read() {//File_Read is the Interactive object
[code]....
So that it puts the Correct or Wrong into the file.
View Replies
View Related
Sep 24, 2014
Well my code is supposed to ask for an input file and then (ex: input.txt), read the input file and create an output.txt file with the anagram for the words in the file. Also it should be displayed on the screen. However my code doesn't display the anagram on screen or the output file!
Heres is the code:
import java.io.*;
import java.lang.*;
import java.util.*;
/* This program will read a file given by the user, read the words within the file and determine anagrams of the given words. If the file that the user inputs is empty, then the program will output "The input file is empty."
* The program will read the file line by line, counting the total number of words read. If there are more than 50 words, "There are more than 50 words."
* will be printed, and the program will terminate. After each line is read, the words in the line will be separated,punctuation characters will be removed, and upper case characters will be switched to lower case.
* If any word is larger than 12 characters, that word will not be considered in the total amount of words in the file and it will not be sorted.
* After each word is read, the letters will be sorted and stored into an array containing each
* word's 'signature'. After all the words have been read, words will be printed to the output file on the same line based upon their signature.
*/
public class Anagram {
//Creating constants for maximum words in file and maximum chars in word
public static final int MAX_CHARS = 12;
public static final int MAX_WORDS = 50;
[Code] ....
View Replies
View Related
Mar 21, 2015
I am trying to read a file and input each line of the file into an array. I have not set the array size as I was hoping to fill the array using a while loop. Unfortunately the scope of the array does to work inside the while loop so I am being told that the array 'students' has not been initialised even though it has just outside of the while loop. Is it possible to do what I am trying to without having the array initialised in the while loop as surely the array will be reset every time if it was in the while loop? Here is my code:
public static void students(String file) throws FileNotFoundException {
try {
File studentInfo = new File(file);
Scanner input = new Scanner(studentInfo);
String[] students;
[Code] ....
View Replies
View Related
Mar 22, 2014
So my assignment is to read these values from an input file which I previously created. The 10 values represent miles traveled and I convert them using some formula my prof gave me to get the total cost, and output both values to an output file.
My programming question is the first number on the input file isnt a mileage value its the number 10, which is the number of values to be processed, which we're supposed to use in order to control a for or while loop which we'll use to process the contents of the input file. How would I create a while or for loop and get it to skip the first value of the input file?
We're not allowed to use arrays for this assignment.
Also here's my code so far, and it says its not being able to find the file, I made sure the file name is exactly as saved, and its saved in the same directory as the java class that i created for this assignment so I don't see what the problem could be?
Here's my the class with the main method
import java.util.*;
import java.io.*;
public class QudratullahMommandi_3_07 {
public static void main (String[]args)
[Code] ....
This is the error message I get
----jGRASP exec: javac -g QudratullahMommandi_3_07.java
QudratullahMommandi_3_07.java:17: error: unreported exception FileNotFoundException; must be caught or declared to be thrown
Scanner input = new Scanner(inputSource);
^
1 error
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.
View Replies
View Related
Mar 25, 2015
I have the the string value similar to the one which i have to split based on the delimited ","
String SampleString=" 'ab,c', 'xyz', lm,n,o "
I know I can easily call split function which will eventually split the above string. But in my case the delimiter "," , is also a part of the string. If I call the function SampleString.split(',') I will get the output as listed below
ab
c
xyz
lm
n
o
but the expected output is
abc
xyz
lmno
View Replies
View Related
Mar 24, 2015
how I can change my code so that somebody can actually input the specified file path, rather than having it fixed in the code. I previously used
Scanner in = new Scanner(System.in);
System.out.println("What is the filename?");
String input = in.nextLine();
File file = new File(input);
But then the program would not display the frequencies.
import java.io.File;
import java.util.*;
/*
This program will allow the user to enter in a text file name, when prompted the program will anaylser the text and display the frequencies
*/
public class AssP {
public static void main(String[] args ) {
Scanner scan;
try {
Scanner scanner = scan = new Scanner(new File("C:/Users/Mary/workspace/Assingment/src/test.txt"));
[code]....
This is my current code and I need to so the user can load their own files.
View Replies
View Related
Jun 8, 2014
how to add an error message when my program can't find the file the user inputs.
For example:
Enter your source code:
D:Data StructsProjectssrcHelloWorld (I didn't put .java on purpose)
Exception in thread "main" java.io.FileNotFoundException: D:Data StructsProjectsAssignment 3srcHelloWorld (The system cannot find the path specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileReader.<init>(Unknown Source)
at HomeworkDriverFour.main(HomeworkDriverFour.java:14)
//Can I get rid of the exception above and replace it with "File not found!"
Enter your source code:This is what I have so far:
import java.io.*;
import java.util.*;
public class HomeworkDriverFour {
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
[code]...
View Replies
View Related
Oct 25, 2014
The program is reading from file input. how can I replace hate with love the file contains only one line.I hate programing!
Java Code:
[import java.util.Scanner;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
public class Program3 {
public static void main(String[] args) {
Scanner fileIn = null;
[code]...
View Replies
View Related
Oct 12, 2014
Is there anyway to format my input file "IF1.txt" into an excel/csv file, but with the content rearranged into a desired format? (all of this has to be done by a java program)
Here is the input file IFT.txt:
R1 : Integer,3 Food
R2 : Integer,3 ID
R3 : Integer,3 Temp
R4 : Integer,3 Weight
R5 : Integer,3 Age
R6 : Integer,3 Length
[code]...
Desired Output:
TIME Food ID Temp Weight Age Length
00:00:00.001 1 0 0 0 0 0
00:00:00.002 2 0 0 0 0 0
View Replies
View Related
Mar 26, 2014
I'm having some kind of weird problem reading input from a file. It says that my scanner object I'm using to hold an item of information isn't initialized, when I do try to initialize it, it says error variable already initialized. I'm using the scanner to read input from a file whose contents are this
10
150.4
88.4
-3.14
499.4
799.4
1299.8
0
1900.2
901.7
4444.4
This is my program
import java.util.*;
import java.io.*;
public class QudratullahMommandi_3_07 {
Toolkit_General toolKit = new Toolkit_General();
public static void main (String[]args)throws IOException
[Code] .....
This is the error message
QudratullahMommandi_3_07.java:34: error: variable holder2 might not have been initialized
String holder2 = holder2.trim();
^
1 error
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.
View Replies
View Related
Oct 30, 2014
i dont know how to write main that would open the input file and read using this method...
[/package AssignmentSeven;
import java.io.*;
import java.util.Scanner;
public class Assignment7
{
public static void Towers(int nTowers, int fromTower1, int workTower2, int toTower3) {
if(nTowers == 1)
[code].....
View Replies
View Related
May 1, 2015
The following program should read in a file on my desktop (I have the path set in Netbeans to that location) and produce a Histogram. Instead I am receiving this error.
Exception in thread "main" javax.imageio.IIOException: Can't read input file!
at javax.imageio.ImageIO.read(ImageIO.java:1301)
at Histogram.main(Histogram.java:9)
Java Result: 1
BUILD SUCCESSFUL (total time: 0 seconds)
Here is the code for the Histogram:
import java.awt.image.BufferedImage;
import java.io.File;
import javax.imageio.ImageIO;
public class Histogram {
public static void main(String[] args) throws Exception {
int[][][] ch = new int[4][4][4];
[code]...
Why it's not reading the file?
View Replies
View Related
Sep 28, 2014
this is my code...in my code i cant give input form my console...it takes input but it doesn't save in a target file..My code is :-
package filetester;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
[code]....
View Replies
View Related
Mar 19, 2014
I have opened up an input file using
File input=new File("hello.txt")..
Then I have created a scanner object that reads data from the file.
Scanner read_file=new Scanner (input).
my question is when closing the files why can't I just do input.close() since that is also closing the file?
View Replies
View Related
Jun 6, 2014
I'm attempting to compare user input to a text file that I have set up whenever the user types in an employee ID number. I want to be able to tell the user that either the ID number is valid, or that it is not valid and must be re-entered by comparing it to the employee.txt file, and then record the valid ID number to the timeclock.txt file. I'm recording the next available employee ID number instead of the one I typed in. The output of the program looks like this: i82014/06/06 12:16:56 (I typed 1 as the employee ID.)
import java.text.*;
import java.util.*;
import java.io.*;
import java.nio.file.*;
public class TimeClockApp {
// declare class variables
private static EmployeeDAO employeeDAO = null;
private static Scanner sc = null;
[code]....
View Replies
View Related
Oct 14, 2014
So this is probably pretty simple but I can't seem to figure it out. My teacher wants us to write a code that scans a text file, then outputs some text based information AND displays an applet bar graph of the data sorta like this for the text:
Sample Bar Graph
1-10 |*****
11-20 |******
21-30 |**
31-40 |*
41-50 |***********
51-60 |******
61-70 |********
71-80 |***
81-90 |****
91-100 |****
and then an applet thats the same info just a little more graphic. My code interprets the input well, but when i try to make an applet output, the code basically forgets all of my variables and starts anew (when i just state the public static graphic (paint) class after everything) OR it refuses to scan the input file (if i switch the public class from main.....throw ExceptionIO to just public class graphic(paint))
Also, as a side note, any way to have java automatically determine how many separate lines there are in a text file without me having to manually count them.
import java.util.Scanner;
import javax.swing.JApplet;
import java.awt.*;
import java.io.*;
public class Project2 extends JApplet {
[Code] ....
View Replies
View Related
Nov 14, 2014
File dir = new File("file"); //creates folder named file
File dir1 = new File("file.txt"); //creates file
But I want to take in a file name from user e.g.
BufferedReader br = new BufferedReader(is);
String filename = br.readLine( );
File dir = new File(filename + ".txt");
its expecting a string literal is there a way round it to take a string???
View Replies
View Related
Aug 26, 2014
The code for my button is below - I know it is wrong and that I need to change line 8 at least,so I am technically asking the property object if there is a key_name there but I dont quite get how to do that
//code for button
JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
//find selected command
String key_name = textFieldSearch.getText();
[Code] ....
I basically just want the user typed in word to be checked against a keyword in a properties file and if it exists, pull the key and the value back into a panel
View Replies
View Related
Apr 7, 2014
public void savePlants(ArrayList flowerPack) throws IOException
{
Scanner input = new Scanner(System.in);
String name;
[Code].....
When I open the saved file the information I need seems to be saved, but when I try to load and search it the data is not there. This is homework that was due about 2 days ago. I just want to get it right in my head for next time.
This is my text file: ¬í sr java.util.ArrayListxÒ™Ça I sizexp w sr FlowerNÏŠ¨r;¾ Z hasScentZ hasThornsL flowerColort Ljava/lang/String;xr Plant"ô²Ò0¢ I IDL Nameq ~ xp t Roset redsr Fungus“ +) Z isPoisonousL fungusColorq ~ xq ~ t toadstool t brownsr Weed #©éÇÙN Z isEdibleZ isMedicinalZ isPoisonousL weedColorq ~ xq ~ t dandylion t yellowsq ~ t tulip t pinkxq ~ q ~ q ~
View Replies
View Related
Aug 26, 2014
The code for my button is below - I know it is wrong and that I need to change line 8 at least,so I am technically asking the property object if there is a key_name there but I dont quite get how to do that
//code for button
JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
//find selected command
String key_name = textFieldSearch.getText();
[Code] ....
I basically just want the user typed in word to be checked against a keyword in a proeprties file and if it exists, pull the key and the value back into a panel ....
View Replies
View Related