Failing To Read Input With Scanner NextLine
Jan 29, 2014I Just made a simple code, but in any case it's not taking the input I'm trying to enter for the city.
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Code Not Running Scanner NextLine After Using Scanner NextInt?
Feb 14, 2015package jdbc;
import java.sql.*;
import javax.sql.*;
import java.util.*;
public class Jdbc {
public static void main(String[] args) {
[code]....
Scanner NextLine Won't Enter Anything
Jan 26, 2014My program is supposed to let me enter the following info for 3 employees: name, number of hours worked this week, and hourly pay rate. It lets me enter the name for the first employee, but for the second and third, it skips over the name and forces me to enter the number of hours worked and pay rate without a name. I have the code and the output posted below. First the program code:
Java Code:
import java.util.Scanner;
public class SalaryCalc {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String name;
double hours;
double rate;
double grossPay = 0;
double overtime;
[code]...
Enter hours worked this week: mh_sh_highlight_all('java'); Notice I can only enter the name for the first employee (Bigfoot). If I wanted to enter "Nessie" for my second employee's name, it skips over the name prompt and prompts me for the hours worked instead.
Query About Use Of NextLine Method Of Scanner Class
Apr 10, 2014My code is as follows:
import java.util.Scanner;
public class GetUserInput {
public static void main (String args[]) {
int i;
float f ;
String s;
[code]....
My Query is: input.nextLine() does not wait for user input. Instead it continues execution from next line. But if I move up input.nextLine(); before both input.nextInt(); and input.nextFloat() in the above code, the execution works fine, input.nextLine(); waits for user input. edited code and output are as follows.
import java.util.Scanner;
public class GetUserInput {
public static void main (String args[]) {
int i;
float f ;
String s;
[code]....
Scanner Does Not Read To The End Of Very Long TXT File
Jul 4, 2014Java Code:
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class PrintALongFile{
public static void main(String[] args) throws FileNotFoundException{
File inFile = new File("C:VeryLongFile.txt");
[Code] .....
When I try to read from a file that's 4,075,904 lines long and 41,646KB in size, it wont go past line 1,266,471. The above code is simplified from my actual program, which actually prints out the results to another file. However, the console (Eclipse IDE) and the output file, both show that it's stopping at the same line.
How can I read the to the very end of my file?
Scanner Taking Input Twice
Oct 29, 2014I have a small bug in my program. The user is asked what person(s) information they want to access but lets say they want captain they must enter "captain" twice. I think it will make more sense to you with the code. I have searched all over to see what is causing the bug but still have found no resolution. I even tried making two different scanners but that didn't work either.
I know the while loop (line 16) I am using is causing the bug because it works fine without that but then I cannot validate the input.
package myproject;
import java.util.Scanner;
public class Enterprise {
public static void main (String[]args){
String userInput;
[Code]......
Console Input Of Strings Using Scanner
May 9, 2015I am having a great deal of frustration trying to use the scanner to get user input from the eclipse console. Here is what I am trying to do.
Print a menu for the user with options, take that (1) char input and run it into a switch statement for processing. I have that done and it is working fine.
If the user chooses to enter strings for storage, They are instructed to enter their string and press enter to complete that string entry. Then enter the next string and press enter, etc.
So I have a While loop for this. Get the scanner input, store it in the LinkedList, get the next scanner input, etc. I get the scanner string and store it in a Linked list. That works fine. The user is instructed to simply enter a blank string to end the entry procedure, like just press Enter on the new line without typing a new string.
The problem is the scanner doesn't seem to return anything for me to Test to close this procedure. How do I TRAP the fact that the user just pressed enter so I can end my procedure? I have tried next() and nextLine() and reset(), etc. And I am getting knowhere.
Parsing Input From A File Using Scanner
Mar 26, 2014I'm having some kind of weird problem reading input from a file. It says that my scanner object I'm using to hold an item of information isn't initialized, when I do try to initialize it, it says error variable already initialized. I'm using the scanner to read input from a file whose contents are this
10
150.4
88.4
-3.14
499.4
799.4
1299.8
0
1900.2
901.7
4444.4
This is my program
import java.util.*;
import java.io.*;
public class QudratullahMommandi_3_07 {
Toolkit_General toolKit = new Toolkit_General();
public static void main (String[]args)throws IOException
[Code] .....
This is the error message
QudratullahMommandi_3_07.java:34: error: variable holder2 might not have been initialized
String holder2 = holder2.trim();
^
1 error
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.
Use Scanner To Get Input And Distinguish Between Int And Text?
Sep 13, 2014Is there any way to use scanner to get input and distinguish between int and text? I'm trying to make a scanner method I can call whenever I need user input no matter if I need int or text. Using two methods (one for int, other for text) at the moment.
import java.util.Scanner;
public class Application {
public static void main(String[] args) {
Person person1 = new Person();
System.out.println("What is your name?");
[Code] .....
Checking To See If Input From Scanner Is Integer
Jun 12, 2014So I clipped this out of my Jeopardy game code and made it into its own project for testing. using this code I want to check to see if the input for wage is an integer?
import java.util.Scanner;
public class test {
/**
* @param args
*/
public static void main(String[] args)
{
Scanner input = new Scanner (System.in);
Obviously right now if you enter "aflwkj" or some such for the wager, the program terminates. How to make a loop that will keep asking the user for a value for wage until the input is an integer?
Creating A Scanner And Putting Input Into Arrays
Apr 15, 2014I'm trying to read user input from the terminal and separate the input into separate arrays depending on if the user input is an integer, scanner, or a string. The terminal should keep asking the user for input until the user types "quit".
import java.util.*;
public class arrayScanner {
public static void main(String[] args) {
ArrayList<Integer> intList = new ArrayList<Integer>();
ArrayList<Double> doubleList = new ArrayList<Double>();
ArrayList<String> otherList = new ArrayList<String>();
[code].....
Polynomials Into Array Using User Input With Scanner
Feb 19, 2014Assignment: Your task is to implement a similar scheme to store polynomials of any number of terms, such that the number of terms and the components (coefficient, variable and exponent) of every term are entered from the keyboard. To implement the interactive input we will using the Java class Scanner, defined in the java.utils standard package. The Scanner class can be used in Java to read data types from a file.
Since the input console (keyboard) is treated as the file called System.in, we can create a Scanner for that input stream as new Scanner (System.in), as shown below. Once you define a Scanner object, using its method next() you can read Strings from the file/keyboard. The incomplete program below is your assignment. You are supposed to complete without changing the existing code. Your output should be the terms of the polynomial entered by the user, separated by + signs. Additional instructions in the code below, that you will change to achieve the requested functionality.
import java.util.Scanner;
public class Polynomials {
public static void storeTerm (int coeff, String var, int exp, String poly[][], int
where){
//ENTER THE COEFFICIENT, VARIABLE AND EXPONENT INTO THE
//ARRAY POLY THAT REPRESENTS THE POLYNOMIAL, AT POSITION "where"
//THAT RANGES BETWEEN INDEX 0 AND POLY.LENGTH-1
[Code] ....
Anyways, I'm not looking for straight answers. I just want to know which section I should start on first because I was advised to tackle programs one problem at a time.
Scanner Object Never Waits For User To Input Anything
Jun 13, 2014The method below is called within a large loop in another method. The code has been boiled down to easily show the problem I'm having. I found that the method worked fine (prompts user for input, gets input, returns input) until I added a statement at the end of the method that closes the Scanner object. When the kb.close() statement is present, the method works the first time through, but subsequent calls to this method only display the prompt and the Scanner object never waits for the user to input anything thereafter.
public int scanIt()
{
int i;
Scanner kb = new Scanner(System.out);
System.out.print("==> "); // prompt for input
if(kb.hasNextInt())
{
i = kb.nextInt();
System.out.println("User entered " + i);
}
kb.close();
}
Scanner That Scans Console For Input To Fetch String Word
Jul 28, 2014I'm having an issue, I have a scanner (Scan.nextLine();) that scans the console for input to fetch the string "word". Then I want to fetch a character using Scan.findInLine(word).charAt(number);. The problem is that the console requires me to write 2 lines in order for the program to move on. I only want the program to scan for a word, and then move on with what it has instead of requiring 2 inputs.
View Replies View RelatedReading Input With Scanner And Checking If User Entered Empty String?
Apr 7, 2015The project is a program that allows the user to enter students and enter grades for each student. One of the requirements is that if there is already a grade stored for the student that it will display the previous grade. IF the user then enters a new grade the new grade will be stored. IF the user simply presses enter (enters an empty string) nothing is done. I have everything working except for the requirement of doing nothing if the user enters an empty string. If I just press enter at this point I get a NumberFormatException.
The below code is a method "setTestGrades" from the student class. This method iterates through each student object stored in an array list and then checks if there is a previous grade (Requirement# unset grades have to default to -1) before allowing the user to set a new grade.
public void setTestGrades(int testNumber) { //Sets the grade for the specified test number for each student in the arraylist.
testNumber -= 1;
Scanner input = new Scanner(System.in);
for (int i = 0; i < studentList.size(); i++) {
System.out.println("Please enter the grade for Test #" + (testNumber + 1) + " For Student " + studentList.get(i).getStudentName());
[code]....
String Concatenation Is Failing
May 23, 2015I am trying to concatenate some strings via: String finalString="(User="+endUserCharge+")";endUserCharge is a string..I get the following error:
caused by: org.codehaus.jackson.JsonParseException: Unexpected character ('(' (code 40)): expected a valid value (number, String, array, object, 'true', 'false' or 'null')
at [Source: java.io.ByteArrayInputStream@3d9127a9; line: 1, column: 2]
How To Use NextLine For Strings
May 12, 2015I am asking the user a question and already have a correct answer. The answer is a string but is more than one word.
When the user types in the correct answer, it still comes up as wrong but I only have the input.next method.
Quote
Why are rabbits ears long?
United states of america
Incorrect!
Java Program Is Failing To Run In Command Prompt?
Jan 23, 2014My Java program is failing to run in command prompt and no result is produced.I am currently using windows 8 and I have changed my Environmental variable to C:Windowssystem32;C:Program filesJavajdkin.
View Replies View RelatedSwing/AWT/SWT :: Trying To Define Visible JTable But Failing
Apr 4, 2014I'm trying to make a simple table with JTable class by reading the following tutorial but when try to see my JTable my program doesn't show me nothing! What i'm doing wrong?
[Code] .....
import javax.swing.JScrollPane;
import javax.swing.JTable;
public class MyFirstTable {
public static void main( String[] args ) {
String[] columnNames = {"First Name",
"Last Name",
[Code] ......
HTTPs Request Authentication Failing Even After Setting Proxy
Jul 11, 2014i am trying to access an https request on a server and authenticating it after passing on username and passwork. I have even set up the proxy of the employer to get the request back as a zipped folder.
I always get an error on: " InputStream reader = con.getInputStream();"
Can be a proxy setting issue too but I am not sure why it should be.
Is there a way to create a secure channel in java to connect to https or by any way the below code could be modified to connect it to the server?
Code is as below:
import java.net.*;
import java.net.Proxy.Type;
import java.io.*;
import javax.net.ssl.HttpsURLConnection;
import com.sun.org.apache.xerces.internal.impl.dv.util.Ba se64;
public class DownloadFile
{
[Code]...
Going To NextLine In Java Buffered Reader
Jul 18, 2014I have a text and I am reading each line in the text with the simple while loop:
BufferedReader br = new BufferedReader(new FileReader(new File(a.txt)));
string line = new String();
while((line = br.readLine())!=null){
if(line.equals("john"))
//skip to next line
else{
//continue something else..
}
}
My question is how do I skip to the next line ? Using apache.commons.io.FileUtils; one could easily have done something like this:
LineIterator it = FileUtils.lineIterator(file, "UTF-8");
String line = it.nextLine(); //this goes to the next line..
How can this be done using BufferedReader ?
Read From File Input
Oct 25, 2014The program is reading from file input. how can I replace hate with love the file contains only one line.I hate programing!
Java Code:
[import java.util.Scanner;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
public class Program3 {
public static void main(String[] args) {
Scanner fileIn = null;
[code]...
How To Just Read User Input
Sep 29, 2014i need to output the unsorted array as well as the sorted array...the sorted array works but i can not get the unsorted array to work.
package Lab7;
import java.util.Scanner;
public class lab10 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner keyboard = new Scanner(System.in);
[Code]...
How To Read Input Of Source Code With FileReader
Oct 19, 2014I'm doing homework and as far as input, my assignment reads: "Your program must take as input the name of a Java source code file such as the source file containing the source code of this assignment." So my question is, how do i do that without linking the directory directly (i.e. C:/users/...)? I'm using FileReader as shown below...
public static void main(String[] args) throws Exception {
FileReader file = new FileReader (WHAT GOES HERE???);
BufferedReader reader = new BufferedReader(file);
String s = "";
String line = reader.readLine();
[Code] .....
Why Won't Read Input File (WordPad Document)
Sep 12, 2014I keep receiving an error in which State.Fall.txt can not be read. I can't point it directly to a drive because someone else needs to open it. I saved it in wordpad as a text file. My question is what did I do wrong in my code that it can't directly access the wordpad document?
import java.io.*;
public class Main {
/**
* @param args the command line arguments
*
*/
public static void main(String[] args) throws IOException
{
// Create an array of individual state objects to hold 50 items
[Code] ....
Make Library That Will Read Some Input Files From A File?
Apr 23, 2015I am trying to make a Library that will read some Input Files from a File . Like When We Enter Nuber from a System.in
1
2
45
667
77
34
and then store these values in int[] array
What I want is I Save all these values in a File and at Run time pass path of that file to command line arguments and then int[] array will be initialize using that
something like this [URL]