The problem I'm having is when the text box pops up and ask to start with a root name, I cannot enter anything and I am not sure what I have done wrong.
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.util.*;
public class FamilyTreeDemo extends JFrame
[Code] ....
I have to write a program that will input and display a person's family tree. I'm using BlueJ.
View Replies View RelatedI am to design a program in java that will allow a user to Input a list of your family members along with their age and state where they reside. Determine and print the average age of your family and print the names of anyone who live in Texas. I have tried but my results are wrong.
View Replies View RelatedI'm supposed to write a GUI application letting the user enter a file on the text field and display its hex representation in a text area and vice versa.
Here's my code:
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package hexconvertor;
import java.util.*;
import java.io.*;
public class HexConvertor extends javax.swing.JFrame {
[Code] .....
It's not doing anything, I don't understand why.
Here is the code
public static void main(String[] args) {
Scanner Keyboard = new Scanner(System.in);
System.out.print("Please enter your name.");
String name = Keyboard.next();
name = "name";
[Code] ....
public class Regextest {
public static void main(String a[]){
String stream = "ab34ef";
Pattern pattern = Pattern.compile("d*")
[code]....
My question is: The methods start()will give the indexes into the text where the found match starts .d*, this means if a number found.index must be returned. Why doesn't it print 3? 12345
Another question: Why it prints 6?
0>a
.
.
.
5>f
What is this 6 in out put?
I have to write a gui program where I can enter a file name and then it gets displayed in a text area when I click Open. Conceptually, I do not get this. I was thinking of appending the text file into a string or something, but I guess I'm confused on how it all works and how I can open the text file. Not asking for the code, but just a compass or something.
View Replies View RelatedI am trying to draw a binary node tree to a text file.
public class BinaryTreeExample {
public static void main(String[] args) {
new BinaryTreeExample().run();
} static class Node {
Node left;
Node right;
int value;
public Node(int value) {
[Code] .....
This will output:
Building tree with rootvalue25
=================================
Inserted 11 to left of node 25
Inserted 15to right of node 11
Inserted 16to right of node 15
Inserted 23to right of node 16
Inserted 79to right of node 25
Traversing tree in order
=================================
Traversed 11
Traversed 15
Traversed 16
Traversed 23
Traversed 25
Traversed 79
I need to print this information in the form of a graphic to a text file. so for example:
OUTPUT IN TEXT FILE
25
/
11 79
etc...
I am new to making an installer so far i have made only one and i used "install creator"
I just make a watch (clock) application and i want when the windows start its also starts automatically except if it is closed by the user
just like widows clock widget.
importing values from a text file into a Binary Search Tree. Currently my tree is hard coded w/ values in the BTreePrinterTest Class.
BTreePrinter Class:
Java Code:
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
[code]...
My input text file will be in the following format, each row is 1 tree, each empty line between the rows means a new tree.Java Code:
80 45 14 1 2 3 4 51
2 4 7 8 9 6 3 4
1 2 3 4 5 6 7 9 mh_sh_highlight_all('java');
I need to insert a break line to a text message on hitting enter by taking its ascii value i.e 10.I have used node.insert commands.I have tried using node.insertAttribute and node.insertChars but is not working ....
View Replies View RelatedI run this code and a window will pop up, but no graphics :(
I tried to draw a rectangle onto the screen, but it will not show up. I was told to extend JComponent, and I did, but it still does not work.
Java Code:
import javax.swing.*;
import java.awt.Graphics;
import javax.swing.SwingUtilities;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.BorderFactory;
import java.awt.Color;
[Code] .....
I am making a game with java in a program called greenfoot.My problem is that a sound won't play when the player dies and a Game Over screen pops up..
- I have saved the audio file in my sound map of the scenario
- Applied the good name of the file
- tested the sound effect and it's working
this is my code:
public GameOver()
{
setImage(new GreenfootImage("GAME OVER", 100, Color.BLACK, null));
Greenfoot.playSound("fail-trombone-03.wav");
Greenfoot.stop();
}
How to improve my code. I finally was able to create a program that gives you the corresponding letter grade, when you enter in a numeric grade without using an array. The only issue left is that I have to be able to enter 5 grades at a time, and it give me the letter grade for all 5. I have the programming working, but only am able to enter 1 at a time. I am not sure what kind of loop or if I am supposed to use a loop.
public static void main(String[] args){
{
int grade = 0;
Scanner input = new Scanner(System.in);
System.out.println("Enter : ");
grade = input.nextInt();
if (grade >= 90)
[Code] .....
How to do draw the original binary tree based on traversal results?
A binary tree has this pre-order traversal result: A,B,D,H,I,E,F,C,G,K,J (TreeNodes) And the same tree gives the following in-order traversal: B,H,I,D,A,C,F,E,K,G,J. Can you draw the tree structure?
This is a mathematical problem. I got one of the equations I need to compute down to
n^(1/6)
Or the 6th root of n.
Now the Java code I have for this is as follows, since Java has no nth root function I'm raising it to a power of a 1/6.
System.out.println(Math.pow(64.0, 1/6));
Now, the only thing it will print is 1.0
However the 6th root of 64 is 2!!!!
I have this mapping:
<servlet>
<servlet-name>wsdl</servlet-name>
<jsp-file>/wsdl/bankconnect.html</jsp-file>
</servlet>
<servlet-mapping>
<servlet-name>wsdl</servlet-name>
<url-pattern>/wsdl</url-pattern>
</servlet-mapping>
And this works fine: URL....The war file is deployed under the context root /bankconnect/ I want to make a servlet mapping, before the context root "i still want the context root bankconnect". URL....
PET HG = (0.0023 * Ra * ( MTC + 17.8 ) * ...................? how to write formula/value under the root (maths) function ?
View Replies View RelatedI like to know how to write root function in java applet. I know it in java function. Ex:
import java.lang.*;
public class Maths {
public static void main(String[] args) {
// get two double numbers numbers
double x = 9;
double y = 25;
// print the square root of these doubles
System.out.println("Math.sqrt(" + x + ")=" + Math.sqrt(x));
System.out.println("Math.sqrt(" + y + ")=" + Math.sqrt(y));
}
}
working fine. but If I tried in applet it's not working. Ex:
evap_trans = 0.0135 * SRAD * ( TMEAN + 17.78) * Math.sqrt(TMAX - TMIN);
If I execute above said formulae with out "Math.sqrt" results are ok. If I used then results shows ZERO.
Some algorithm in computing the square root of a number without using any loops?
View Replies View RelatedI'm trying to add a CLASSPATH to a manifest file linking (not sure If that's the right word) to an sqljdbc4.jar file.
If I copy the file Into my root folder and use CLASSPATH: sqljdbc4.jar It works fine.
Class-Path: sqljdbc4.jar
Main-Class: com.ncntech.go
If I try CLASSPATH: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar I receive a "Could not find or load main class" error.
Class-Path: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar
Main-Class: com.ncntech.go
Is the syntax correct for specifying a directory path ?
When I map my servlet to the ROOT of the site, the javascript, CSS and image files are not served. The conversation between the server and browser shows the files are being sent, but they are not rendered in the browser. This happens in both Firefox and Chrome.
If I change the mapping to anything other than the root, such as /x/, everything works as it should.
Here's my web.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
[Code] .....
I have an app that saves pdfs and images from a web page. The web sections send info to the server elements running in Java. I have hardcoded the path to where the images and pdfs need to be saved but on the server, these paths will be different. I'd prefer to just save them to something like:
whateverMyDeploymentDirectoryIs/files/pdfs
or something. How do I find out what my root directory is so that I can make the path relative instead of hard coded?
This is the code that I wrote but I have two problem with two buttons one of them ... I want to delete the selected text inside the text Area which represented as b[8] and the other button that I want to select parts of the texts which represented as b[0]....
Here is the code..
package KOSAR2;
import java.awt.BorderLayout;
import java.awt.Container;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
[Code] .....
I need to make some operations with a file. I struggle to understand why Apache is throwing this error:
(The system cannot find the file specified)
My file is located in the root directory of the project.
And here is how I indicate the path to it:
String filePath = "default.jpg";
InputStream inputStream = new FileInputStream(new File(filePath));
If I put the file in the Eclipse folder, it works... But I need it to work if I put it in my project's root folder.
I am trying to create a method that prints the square root of a number up to a certain number. It needs to take a single int parameter for example "n" , and then print all of the (positive) even perfect squares less than n, each on a separate line. I want the method to be called something like this:
public void Squares(int n) {
}
I need the output to look something like this:
Example: if n = 40, your code should print
4
16
36
So I have been working for a few hours now and am really stuck.
This is what I have so far:
int count = 0;
int n = 4;
int max = n;
while(count < max) {
System.out.println(n);
n = n * n;
count++;