public class Fibonacci {
public static void main(String[] args) {
int[] numbers;
numbers = new int[20];
numbers[0] = 0;
numbers[1] = 1;
System.out.println("
[Code] ....
I wrote this program for my Java class to print out the first 20 numbers of the Fibonacci series. My assignment then tells me to Rewrite your program using dynamic array. I'm not sure how to do this.
I'm facing a Problem with the JUnit Test for a Fibonacci rabbits sequence. The JUnit Test should test if the function dynFib(int x) completes the calucation in time. The time given is 100ms. The sequence I wanted to be printed is 0 1 1 2 3 4 6 8 11 15 and I got it but the calculation takes more than 100ms. How can I make it calculate faster without using a loop?
I want to do it recursively and dynamically, I kept trying lots of methods but they did not work.
This is my Code:
public class TestFib { private static int dynFib(int x, Integer[] array) { array = new Integer[x + 1]; if (x < 0) { throw new IllegalArgumentException();
public class FibSeqByIanNeumann { public static void main(String[] args) { Scanner get = new Scanner(System.in); int ctr, num1, num2, fib, maxTimes; System.out.print("How many sequences do you want?: "); maxTimes = get.nextInt(); //inputs the maxium limit of the fib sequence
[code]....
how to do a simple YES/NO Loop so I can try to have it work on my code if I want to try to do the Fibonacci Sequence again.Now I think it might have something to do with a do/while loop.
I am attempting a programming exercise to display the values in the Fibonacci sequence from F0 to F15. I understand the concept, but, for some reason my equation is simply creating a resulting string of numbers that simply increase by 2's. As, I know it is supposed to be the sum of the previous F and the F that precedes that one to total the new F number. It seems so simple yet I seem to be far off. As usual, I have worked my code for your review.
/* * This program calculates the "Fibonacci sequence." * A "sentinel" is used to limit the extent the calculation. */
import acm.program.*; public class bookFibonacciTest2a extends ConsoleProgram { /* Specifies the limit value of the calculations */ private static final int SENTINEL = 16; public void run() { println ("This program display Fibonacci sequence numbers 0 - 15.");
I have to find where in the fibonacci sequence a at number belongs, using a if or while loop.
Example
>55 is a Fibonacci number whose order in the sequence is 11 >35 is not a Fibonacci number. However, it lies between Fibonacci numbers 34 (order: 10) and 55 (order: 11)
import java.util.Scanner; public class While { public static void main(String[] args) { System.out.println("Welcome to the Fibonacci Sequence Detector"); Scanner in = new Scanner(System.in);
Write a recursive method that calculates the Nth number in the Fibonacci sequence. The first and second numbers in the sequence (the base cases) are both 1. After that, each subsequent number is the sum of the previous two. Stated a bit more formally:
fib(n)={1fib(n−1)+fib(n−2)n<2otherwise
For example, here is the first few numbers in the sequence:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
Your fib method should be part of a class named Fibonacci. In addition to the fib method, the Fibonacci class should have a main method that calls fib(9). If the result doesn't equal 34, you should print an error message. Otherwise, it should print out a message saying that it was successful.
After writing your Fibonacci class, answer the following question: How many times is the fibonacci method called when calculating the 5th number in the sequence?
I have to find where in the fibonacci sequence a at number belongs, using a while loop.
Example
>55 is a Fibonacci number whose order in the sequence is 11 >35 is not a Fibonacci number. However, it lies between Fibonacci numbers 34 (order: 10) and 55 (order: 11)
import java.util.Scanner; public class While { public static void main(String[] args) { System.out.println("Welcome to the Fibonacci Sequence Detector");
Modify the Improved Fibonacci application to store its sequence in an array. Do this by creating a new class to hold both the value and a boolean value that says whether the value is even, and then having an array of object references to objects of that class.
Did I just need to declaring the variable in other class (for boolean value and the value itself) or else ?
Here is the code for ImprovedFibonacci.java
Java Code:
class ImprovedFibonacci { static final int MAX_INDEX = 9; /** * Print out the first few Fibonacci numbers, * marking evens with a '*' */ public static void main(String[] args) { int lo = 1; int hi = 1; String mark;
I am trying to find the longest descending sequence without arrays. So 65124976231 would output 9762.
import java.util.*; public class HelloWorld { public static void main(String[] args){ String num = ""; int longestLen = 0; int currLen = 0; String max = "";
[Code]...
I keep getting: The longest descending sequence is: 6512 In an infinite loop.
I mainly would like to know is a int[4][4] or a int [4*4] is more efficient to use. Which takes more storage? Which requires more to process? that kind of stuff.
I need to write a For Loop that prints out the first 12 Fibonacci numbers:1 1 2 3 5 8 13 21 34 55 89 144.The problem I am having is that I can not get the first two 1 numbers. I only get 1.2.3.5.8.....
int a=1; int b=1; for (int i=1; i<12;i++) { System.out.print(a+" "); a=a+b; b=a-b; }
Do I need to add another For Loop that sub-tracks so that I can get the first digit of 1?
public class E09_Fibonacci { static int fib(int n) { if (n <= 2) return 1; return fib(n-1) + fib(n-2); } public static void main(String[] args) { // Get the max value from the command line: int n = Integer.parseInt(args[0]); if(n < 0) { System.out.println("Cannot use negative numbers"); return; } for(int i = 1; i <= n; i++) System.out.print(fib(i) + ", "); } }
please break down fib method shown above. I can't understand how the magic is happening inside that recursion.
Its a program that calculates Fibonacci number.This program uses recursion.
import java.util.Scanner; public class FibonacciMemoization{ static int[] fib = new int[60]; public static void main(String[] args){ Scanner input = new Scanner(System.in); System.out.print("Enter a Number :"); int number = input.nextInt();
I wrote this tail recursive function that mirrors the iterative version, except that the loop in the iterative version is replaced by an if statement here and then a recursive call. Is this truly recursive? I have seen the fibo(n-1) + fibo(n - 2) version, but is this also an acceptable recursive solution? Why is it never solved this way?
public class FiboRecursive { public static int fibo (int n) { int sum = 0; int n1 = 1; int n2 = 1; if (n == 1 || n == 2) { sum = 1;
Write a program that detects Fibonacci numbers. Prompt the user to input a positive integer. Upon input, the program will determine if the number is either a Fibonacci number or not. If a Fibonacci number, then the order of the number in the sequence must be output. If not a Fibonacci number, then the Fibonacci numbers above and below it (including their order in the sequence) must be output. Once it finishes, the program will prompt the user for a new number. The program will exit if the user enters a string (such as “quit”) instead of an integer. Use the sample output file, fib-seq-det.txt, to view a sample session
This is my project, I wrote a programs that tells you if the input number is a fibonacci number or not. For some reason it only works for some Fibonacci numbers but not all of them.
import java.util.Scanner; public class While { public static void main(String[] args) { System.out.println("Welcome to the Fibonacci Sequence Detector "); Scanner in = new Scanner(System.in); System.out.print("Please input a number for analysis: "); int input = in.nextInt();
I have to create a program that calculates the nth Fibonacci number and returns that to the user. Fibonacci said his number sequence would describe the ideal breeding patterns of immortal rabbits. So, you are going to make this vision a reality.
First, take in a numeric value from the user and calculate that value in the fibonacci series. Next, find an image of a rabbit and display the image on a GUI (put the image as an icon on a label!) the number of times returned by the algorithm (Put all the aforementioned labels on one panel with FlowLayout!).
You need to remove the old images from the Panel. Probably the easiest way to do this is to create a whole new panel and remove the old one (hint: the remove method of JPanel should come in handy)
You could use an array of JLabels You will need to create a new JLabel and add each member of the array to the panel I should be able to scroll to see any images that are off screen
I am having difficultly on to making the array list for JLabel, and getting the Fibonacci sequence to show the pictures of rabbits. Below is my current code.
import java.awt.FlowLayout; import java.awt.*; import java.awt.event.*; import javax.swing.*; public class Rabbit extends JFrame
Here is my program and results and I am having a error on line 38 which is "public static long fib01(long paramLong)" The program does give me my results but I am trying to correct there error.
public static void main(String[] args) { { System.out.print("
" + String.format("%-10s", new Object[] { "Index" })); System.out.print(String.format("%-15s", new Object[] { "Fibonacci01" })); System.out.print(String.format("%-15s", new Object[] { "Fibonacci02" })); System.out.println(String.format("%-15s", new Object[] { "Fibonacci01" }));
I'm trying to change the code on a Fibonacci series program that would allow me to exit the loop early if I exceed a specified number. The user enters any 2 random numbers (which will be the 1st 2 no.'s of the Fibonacci sequence printed to screen) and then continues up to a 'limit' on the number of numbers set in code. Here's the code:
int[] array = new int[limit]; //Define an array whose length is set by an int value for limit!! array[0] = x; //User supplies a int value for x which takes the 1st position in the array!! array[1] = y; //...and an int value for y in the 2nd position!! for (int i = 2; i < limit; i++) //Start from the 3rd position of the array when carrying out calculations!! { array[i] = array[i-1] + array[i-2];
[Code] ....
To exit the code/ 'limit' early if the array prints a number higher than 100, I tried putting a 'while' condition before the last line, as follows:
while (array[i] < 100) System.out.print(array[i] + " ");
Can I even use a 'while' loop within an array, or is there some other way I need to integrate it?
I know my problem is my lack of understanding of OOP but I have searched for a solution and can't even seem to get close.This is a very simplified version of what I will need to do. I have a button and six textboxes. When the button is pressed I want to take the text from textbox6 and place it in textbox1, textbox2, textbox3, textbox4, and textbox5.
I need sometthing better then this brut force method.Java Code:
package textboxes; public class TextBoxesGUI extends javax.swing.JFrame { public String NewText; public TextBoxesGUI() { initComponents();