FileNotFoundException With Java Scanner With Absolute File Path
Apr 8, 2014
I'm a Java beginner and I've been trying to scan a file using the Java Scanner. I've tried searching online for this error and I only find people's questions who have entered an incorrect relative path. I'm entering in an absolute path and I'm using Eclipse Standard Edition on a 2013 MacBook Pro with Mavericks 10.9.2.
Anyway, the error message I'm receiving on Eclipse is: Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException
at App.main(App.java:12)
public class App {
public static void main(String[] args){
String fileName = "/Users/Student/Documents/index.html";
[code]...
Why it cannot find this file. I've checked the absolute file path of index.html on my Mac and I've copied and pasted it into my code.
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Nov 7, 2014
I am copying the xml files from one folder to other folder, in the source folder, i have some files which have some content like "backing File="$IDP_ ROOT/metadata/iPAU-SP-metadata.xml" but while writing to the destination folder.i am replacing the "$IDP_ROOT" with my current working directory. The entire copying of files is for deploying into tomcat server. The copying is done only when server starts for the first time.Problem: If i change the folder name from my root path in my machine after i run the server,the entire process will be stopped because the destination folder files already contains the content which is with existed files names or folder names.
So i want to change it to relative path instead absolute path. What is the best way to do it? Please look at code below:
[ // Getting the current working directory
String currentdir = new File(".").getAbsoluteFile().getParent() + File.separator;
if(currentdir.indexOf("ControlPanel")!=-1){
rootPath=currentdir.substring(0, currentdir.indexOf("ControlPanel"));
}else{
rootPath=currentdir;
[code]....
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Feb 14, 2014
Is /graphics/image.png a relative path or absolute path?
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Dec 1, 2014
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
Below the drop-box upload code with java.
File inputFile = new File("New Text Document.txt");
System.out.println("inputFile.getAbsoluteFile(): " + inputFile);
FileInputStream inputStream = new FileInputStream(inputFile);
try {
DbxEntry.File uploadedFile = client.uploadFile("/magnum-opus.txt",
DbxWriteMode.add(), inputFile.length(), inputStream);
System.out.println("Uploaded: " + uploadedFile.toString());
} finally {
inputStream.close();
}
In the above code the place New Text Document.txt we have to provide total path of file.
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Sep 30, 2014
I already done my program with images on it but when i convert it to exe , the images is not appearing.
Usually my images are located at documents netbeansprojectprojectimage.jpg
When i run the code on netbeans the images are appearing but when i convert it to exe or jar file run on a computer without netbeans.. images is not appearing ...
import java.awt.*;
import javax.swing.*;
import javax.swing.event.*;
import javax.swing.ImageIcon;
class Phonebook extends JFrame {
private static final int WIDTH = 430;
private static final int HEIGHT = 200;
public Phonebook()
[Code] ....
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Jun 18, 2014
currently I am doing my java web application project ,and it has following steps 1) Upload the txt files 2) java servlet gets the txt file's url , read the data and do the calculation 3) pass the results
I almost finished the second step , and working on the first step .Since there are so many input files at a given time , i have to use drag and drop method to get the file's location.how to pass file's path to servlet.( servlet code can read the data from the given txt file path )software used - tomcat and netbeans 8.0
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Jun 29, 2014
When I try to run the programm, it always throws a FileNotFoundException, algthough the file exists in the same folder as the project. I tested it with the canRead() method and it returned false, but I can't figure out why it can't read from the file
package sumOfFloats;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class SumOfFloats {
[code]...
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May 6, 2014
I am facing a problem while executing a task. My task is to make such a code which will search for my source code file (abc.java) in all directories and then displays the code in textarea inside frame and along with that i also have to display the path of the file in text field. I have coded something but i am really not getting anywhere near my task.
import javax.swing.*;
import java.awt.*;
import java.io.*;
import java.util.*
public class Lab extends JFrame {
[Code] ....
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Mar 25, 2015
I am trying to redefine the FileNotFoundException by creating a new class which extends it, but I am having difficulty. For my class practice, if no file is selected or passed in, an UnknownFileException should occur.My code is the following:
Java Code:
import java.io.FileNotFoundException;
public class UnknownFileException extends FileNotFoundException {
public UnknownFileException() {
super("We couldn't tell what file this is");
}
public UnknownFileException(String message) {
super(message);
[code]....
But I get a compile error stating an unreported FileNotFoundException.
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Feb 14, 2015
package jdbc;
import java.sql.*;
import javax.sql.*;
import java.util.*;
public class Jdbc {
public static void main(String[] args) {
[code]....
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May 12, 2014
What I do wrong when I trying to set path to file in my jar app. I have application which work with xml file. I have next project structure:
/project_root_directory
|_ /lib
|_ /resources/file.xml
|_ /src
So, I need to set correctly path to my jar file, because when I running it from IDE, it works nice. By default it seems:
private File file;
private StreamResult streamResult;
file = new File("resources/file.xml");
streamResult = new StreamResult(file);
And methods where I can modify the DOM structure via transformer in end of methods:
transformer.transform(source, streamResult);
So, I trying set path to file:
private URL url;
...
file = new File(url.getPath());
streamResult = new StreamResult(file);
But it didn't not work, because when I trying to get resource by next condition
url = getClass().getResource("resources/file.xml");
url = getClass().getResource("resources/file.xml");url = getClass().getResource(url = getClass().getResource("resources/file.xml");resources/file.xml");
url - is null
Okay..
I tried next solution
InputStream input = getClass().getResourceAsStream("resources/file.xml");
There, I got also null....
Also, I tried made absolute path
filePath = file.getAbsolutePath();
file = new File(filePath);
streamResult = new StreamResult(file);
But it also didn't work. There I got message seems like: "Can't find resource /User/user1/Desktop/program1/resources/file.xml" - but that's really absolute path to a file.
Also, I tried made it via System.getProperty
String filename = "file.xml";
String workingDir = System.getProperty("user.dir");
finalfile = workingDir + File.separator + "resources" + File.separator + filename;
file = new File(finalfile);
I also made unit test which completed with "green light", but in jar its wrong with message "Can't find resource /User/user1/Desktop/program1/resources/file.xm" ....
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Feb 25, 2014
I was given a text file that has list of names phone numbers, calls in and out etc... Like this
Adams#Marilyn#8233331109#0#0#01012014#C
Anderson#John#5025559980#20#15#12152013#M
Baker-Brown#Angelica#9021329944#0#3#02112014#C
The # are delimiters between data items and each line has the call status as the last item. I need to know how I can display each persons information on the screen in a format such as:
Name Phone Calls Out Calls In Last Call
Marilyn Adams (823) 333-1109 0 0 01-01-2104
John Anderson (502) 555-9980 20 15 12-15-2013
Angelica Baker-Brown (859) 254-1109 11 5 02-11-2014
I have to use substring method to extract the phone number and add parentheses/dashes ect I also must have a while statement and a delimiter...
So Far my code looks like this Also I am in a beginners Java coding class....
import java.util.Scanner;
import java.io.*;
public class phonedata2_1 {
public static void main (String[] args) throws IOException {
String Phonefile, FirstName, LastName;
Scanner PhoneScan, fileScan;
[Code] ....
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Mar 26, 2014
I'm having some kind of weird problem reading input from a file. It says that my scanner object I'm using to hold an item of information isn't initialized, when I do try to initialize it, it says error variable already initialized. I'm using the scanner to read input from a file whose contents are this
10
150.4
88.4
-3.14
499.4
799.4
1299.8
0
1900.2
901.7
4444.4
This is my program
import java.util.*;
import java.io.*;
public class QudratullahMommandi_3_07 {
Toolkit_General toolKit = new Toolkit_General();
public static void main (String[]args)throws IOException
[Code] .....
This is the error message
QudratullahMommandi_3_07.java:34: error: variable holder2 might not have been initialized
String holder2 = holder2.trim();
^
1 error
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.
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Jul 4, 2014
Java Code:
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class PrintALongFile{
public static void main(String[] args) throws FileNotFoundException{
File inFile = new File("C:VeryLongFile.txt");
[Code] .....
When I try to read from a file that's 4,075,904 lines long and 41,646KB in size, it wont go past line 1,266,471. The above code is simplified from my actual program, which actually prints out the results to another file. However, the console (Eclipse IDE) and the output file, both show that it's stopping at the same line.
How can I read the to the very end of my file?
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May 26, 2014
I have a simple txt file, each line simply containing 1 word.I would like each work to represent an index of the array..im having some difficulty populating an array from either a txt file or a scanner.i seem to be able to fill the scanner so to speak with the contents of the text file but not the array. I don't know how to syntax it
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.Arrays;
public class ReadFile
public static void main(String[] args) {
[code]....
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Jul 26, 2014
I get a null pointer error on line 17 of the following fragment. I suspect it has to do with the way I am reading the file, but I'm unsure. I can provide more information or code if necessary.
JFileChooser jfc = new JFileChooser();
jfc.setFileSelectionMode( JFileChooser.FILES_AND_DIRECTORIES );
int userInput = jfc.showOpenDialog( null );
if( userInput == JFileChooser.CANCEL_OPTION ){
[Code] .....
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Feb 6, 2015
I have a code that imports a text file [URL] .... and has a variety of methods for sorting through it. The file is structured differently when loaded into the environment, as each line begins with a movie and lists all of its actors. Each line has a movie title, then its release date in parentheses, and then the actors in the movie all listed and separated by slashes (Ex: /lastname 1, firstname 1/lastname 2, firstname 2/etc.....
Well I tried to create a method to search all the actors in the file for an inputted word and return the ones that have that word somewhere in their names. I managed to get it to work, but the code only runs for one line of it. How should I get this to do what its doing, but for EVERY line?
Code is here: [URL] ....
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Jun 24, 2014
First of all, i am using ubuntu and jdk8. My problem: displaying the current path of a file in my system Approach: I have a file called dummy.txt in a given directory which have enough permissions and i did the following:
File file=new File("dummy.txt");
System.out.println(file.getAbsolutePath().substring(0,file.getAbsolutePath().lastIndexOf("/")));
I expected to see displayed the current path of the file without the name of the file but it is showing a different path. I just want to display the current path of the file without the name.
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Apr 8, 2014
Well I fixed my invalid path problem
Now it is telling me that my file is not found and it is exactly where I put it and told JCreator to look for it.
this is what I get:
javac: file not found: C:Program FilesJavajdk1.8.0docsMyName.java
when I go manually to the address, it is there but for some reason Jcreator cannot find it.
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Jul 3, 2014
Gyazo - e5663e8da42ac46a642895d72836b933.png
As you can see I have specified a file path, as it is needed to draw the image.
The image "sun" is in a certain folder inside the directory of my jar file.
But If I were to send the whole package to my teacher to review. The file path would still remain the same, local to my computer making the image, unloadable.?
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Nov 3, 2014
I have a GUI that has three jTextFiled's. The first on gets filled in with a file that I choose and shows the path to that file with the file name
i.e. - c:
s34bil.exe
un estrun.i
I want to change the file extension from .i to .r in one jTextField and then .i to .o in another jTextField.
I am slowly learning Java. I have this coded in VB, but not sure how to do it in java.
Here is the VB script :
Dim thefile As String = txtInput.Text
Dim fn1 As String = My.Computer.FileSystem.GetName(thefile)
Dim fn2 As String = fn1.Replace(".i", "")
[Code] ....
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May 20, 2014
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
package mbeans;
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.URL;
import java.util.List;
[code]...
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Jan 3, 2015
I'm trying to write a basic java program so that when I run it, I can store the names and codes of some of my school textbooks...I try the scanner statement to input the name of the book but an exception is thrown when I type the name of the book..I have attached the code for my program.
import java.util.Scanner;
public class Books{
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
System.out.print("Enter amount of products : ");
int products= s.nextInt();
long [] code= new long[products];
String[] names = new String[products];
for (int x=1;x<(products+1);x++){
System.out.println("Enter IMEI number "+x);
code[x] = s.nextLong();
System.out.println("Enter name "+x);
[code]....
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Nov 27, 2014
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties);
Properties props = new Properties();
props.load(in);
in.close();
FileOutputStream out = new FileOutputStream(newprop.properties);
props.setProperty("myDirectory","C:Lisa estUpdate" );
props.store(out, null);
out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
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Feb 14, 2015
I was wondering, if, for example I set font for my textarea like this:
area.setFont(new Font("Serif", Font.ITALIC, 18));
Is that last parameter, in this case 18, will be actually the same size for all users? Maybe I should avoid these absolute numbers?
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Jan 18, 2010
I couldn't get this code working:
import java.util.*;
public class scan {
public static void main (String args[]) {
String testi;
Scanner scan = new Scanner(System.in);
[Code] .....
Did i write something wrong or can't Scanner be used with String?
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