Find Any String Length Without Using Library Method?
Apr 10, 2014How can find any string length without using any library method??
View RepliesHow can find any string length without using any library method??
View RepliesI get this message in eclispe: Cannot find tag library descriptor for 'http://java.sun.com/jsp/jstl/core"'
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html>
<html>
<head>
In another thread I saw the suggestion that including jstl.jar in classpath would resolve this issue.It tried that but the issue still exists.
I am trying to split a string based on length(example length 5) of the string. But I am having a issues with this substring(start, end) method. I get all substring which are of length 5. But if the last substring is less than 5 then I am not getting that last substring. But I need the last substring even if it is less than 5.
String s = "fjdjfdfjgffgjhfjghfjkhjhjh";
String spLine;
for(int i=0; i<s.length(); i=i+5){
spLine = s.substring(i, (5+i));
}
>
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5
This is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner;
import java.util.StringTokenizer;
public class Brown_Matthew_13117002{
public static int count(String s, int len){
int result=0;
StringTokenizer st=new StringTokenizer(s,"[ ,;]");
[Code] ....
The output would end up being :
hello
There are 0 words of length 0
world
There are 0 words of length 1
how
There are 0 words of length 2
are
There are 3 words of length 3
you
There are 0 words of length 4
The problem asks me to write an expression whose value is the number of characters in a specific string. Normally, it would be a simple task of using the String.length() method, but that is not allowed. In fact, no variable declaration is allowed (it's a MyProgrammingLab assignment, if any are familiar).
Simply put, if I have a String "This is a sample string." is it possible to find the length without assigning it to anything?
In other words, the code must be able to go into the parentheses of System.out.println( ); and correctly print the length of said string.
The answer, for those curious:
System.out.println("This is a sample string.".length());
I didn't know the .length() method could be called on a literal. Now if only I could find out how to close this thread...
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5
ithis is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner;
import java.util.StringTokenizer;
public class Brown_Matthew_13117002{
[Code].....
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5
This is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner;
import java.util.StringTokenizer;
public class Brown_Matthew_13117002{
public static int count(String s, int len){
int result=0;
StringTokenizer st=new StringTokenizer(s,"[ ,;]");
[Code] ....
The output would end up being
hello
There are 0 words of lenghth 0
world
There are 0 words of lenghth 1
how
There are 0 words of lenghth 2
are
There are 3 words of lenghth 3
you
There are 0 words of lenghth 4
I think I need to use string.split instead of stringtokenizer and the while loop is incorrect it needs to loop equal to the number of letters in the longest word. But how to do either of these ?
I defined a java class thus:
class Info{
public String name;
public String version;
public String arch;
double CPUSpeed;
double ranUtil, CPUUtil;
};
But each object of such a class takes many bytes. How can I limit it to one fourth of a Kilo-Byte?
import java.awt.*;
import java.applet.*;
import java.awt.event.*;
public class Assignment extends Applet implements ActionListener {
TextArea textInput = new TextArea(); // user input
Button analyzebutton = new Button("Analyze");
Button resetbutton = new Button("Reset");
Label lbloutput = new Label ("Please enter text into the textbox!");
[Code] .....
The String class stores the characters of the string internally as a private char[] and calling someString.length() results in getting the length field from the character array. I am looking to get the details on how the length is implemented. I understand it is a field, but in the original question I provide sample code and really want to know if/how the resulting byte code may differ when compiled, perhaps I am just not seeing the simple answer through my confusion.
Link ....
How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.
View Replies View RelatedI am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
i am trying to write a class method which will take in a string and returns a string which is the reversed version of that string. it compiles fine but when i try to run it it states Main method not found in class StringReverse,please define the main method as public static void main(String[]args). I am new to java and cannot figure out
import javax.swing.JOptionPane;
public class StringReverse {
public String reverseString(String str){
JOptionPane.showInputDialog(null,"Please enter word");
char c = str.charAt(str.length()-1);
if(str.length() == 1) return Character.toString(c);
return c + reverseString(str.substring(0,str.length()-1));}}
I want to reverse a String that is input
This is what I have tried so far
public class ReverseStringTest {
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
System.out.println("Enter String to replace:");
String temp=in.next();
System.out.println("Reverse String is:"+reverseString(temp));
[code]...
But its not working it is return same string that is Input.
like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
I was given the Java code for a project and I am supposed to build unit tests to test the performance of seven sorting algorithms and I am getting the following error in my Lab1Test file...cannot find symbol: method sorta(int[]) location: class Lab1Test.
Lab1.java
Java Code: package funcollege.comp10062.perflib;
import java.text.DecimalFormat;
import java.util.Arrays;
import java.util.Random;
[code]...
i'm working on a "name sorter" program and i want it so when i add names and such to the list box i can click sort and it sorts the names in A,B,C format.Here is my code:
import org.jdesktop.application.Action;
import org.jdesktop.application.ResourceMap;
import org.jdesktop.application.SingleFrameApplication;
import org.jdesktop.application.FrameView;
import org.jdesktop.application.TaskMonitor;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.Collections;
import javax.swing.Timer;
import javax.swing.Icon;
import javax.swing.JDialog;
import javax.swing.JFrame;
import javax.swing.JPanel;
[code]....
I'm using Netbeans FYI and a java desktop application. Also, i have looked everywhere and even my teacher has had to look further into it, i really want to get it to work.
What's wrong with this statement that it cannot find the method AvailableProcessors();?
Java Code:
Runtime.getRuntime().AvailableProcessors(); mh_sh_highlight_all('java');
Writing a Java program to find sum of numbers in a random string.
(Input=abc235^%$q!12&3 output=250)
If a number has - sign then u should consider it as a negative number.(Input=abc-12t%^&$dcf22 Output=10)
I have to recursively find a given string in a file. I HAVE to use the LineNumberReader class, and the output would be like so:
Line#Found : the string of the whole line
This is the code I've written:
public String findGivenString(String givenString, int currentLineNumber) {
LineNumberReader lnr = null;
try {
lnr = new LineNumberReader(new FileReader(getFile()), 4096);
lnr.setLineNumber(currentLineNumber);
String s = lnr.readLine().toLowerCase();
[Code] ....
I messed around with a bit, and it doesn't change to the new set line. Though the line number is incrementing! So it just keeps checking the first line of the file over and over again, which is why it can't find the given string. Which also throws the StackOverFlow exception I'm getting.
Here's the output if I remove the comment from the System.out...:
String @ that Line# 1: package banking;
String @ that Line# 2: package banking;
String @ that Line# 3: package banking;
String @ that Line# 4: package banking;
....
So you see it keeps checking the same line even though the line number IS incrementing.
i need to find common String between to Strings :
Example 1:
Customer Name 1: Dr. Joe Smith
Customer Name 2: Joseph Smith, MD.
I need to search the string for a match, in this example "Smith"
Example 2:
Customer Name1: New York Market Place
Customer Name 2: NY Marketplace
I need to search the string for a match, in this example Market place
Example 3:
Customer Name1: The Deli on the Corner
Customer Name 2: Corner Deli
I need to search the string for a match, in this example Deli Corner
SimpleDotComTestDrive.java:8: error: cannot find symbol
String result = dot.checkYourself(userGuess);
^
symbol: method checkYourself(String)
location: variable dot of type SimpleDotCom
1 error
Code:
public class SimpleDotCom {
int[] locationCells;
int numOfHits = 0;
public void setLocationCells(int[] locs) { locationCells = locs; }
public String checkYourSelf(String stringGuess)
{ int guess = Integer.parseInt(stringGuess);
String result = "miss"; for (int cell : locationCells) {
[Code] .....
I was trying to find the complete readLine() method In the online docs but all I can get hold of Is:
readLine
public String readLine()
throws IOException
Reads a line of text. A line is considered to be terminated by any one of a line feed
('
'), a carriage return ('
'),
or a carriage return followed immediately by a linefeed.
Returns:A String containing the contents of the line, not including any line-termination characters, or null if the end of the stream has been reachedThrows:IOException - If an I/O error occursSee Also:Files.readAllLines(java.nio.file.Path, java.nio.charset.Charset)
Is It possible to view the actual method syntax online ?
I am trying to run the following code but getting the error above.
import java.io.*;
public class StringBuilder {
public StringBuilder() {
super();
}
public static void main(String args[]) {
// creates empty builder, capacity 16
StringBuilder sb = new StringBuilder();
// adds 9 character string at beginning
sb.append("Greetings");
}
}
Code a Java method that accepts a String array and a String. The method should return true if the string can be found as an element of the array and false otherwise. Test your method by calling it from the main method which supplies its two parameters (no user input required). Use an array initialiser list to initialise the array you pass. Test thoroughly.
public class test {
public static void main(String[] args) {
Printhelloworld();
String[] verbs = {"go", "do", "some", "homework"};
printArrays(verbs);
[Code] .....
So I'm creating a class which when given three inputs uses them as sides of a triangle and tells ther user what type of triangle it is, or if the input is invalid, tells them why it is invalid. I'm readin the input as a string and then trying to split it into a string array, from there checking to see if it has 3 elements.. in which the data is good at that point, and then converting them to ints and checking to see if they're negative ansd finally checking to see if they can work as sides of a triangle ie a+b >c, a+c >b , b+c >a.
I'm trying to split it into an array of strings but am getting an error, and can't seem to figure out why as this should be working from what I've read of the string.split method online.
import java.util.*;
public class TriangleTest{
private int sideA;
private int sideB;
private int sideC;
public static void main(String[] args){
TriangleTest triangle = new TriangleTest("3 4 5");
[Code] ....
The output reads [Ljava.lang.String;@15db9742