Find A String And Display Line Number And Line Itself?
Oct 20, 2014
I'm creating a program that searches a txt file for a given string, then return the number line and the line itself. However, my testFile class isn't detecting my searchWord methods.
The searchWord and recursiveSearch is written in a java class called BasicFile
public List<String> searchWord(String key) throws Exception {
LineNumberReader lnr = new LineNumberReader(new FileReader(f));
return recursiveSearch(lnr.readLine(), key, lnr);
}
public List<String> recursiveSearch(String currentLineText, String key, LineNumberReader lnr)
[code]....
Is it because I'm using a list instead of a string?
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May 5, 2014
My requirement is to find the line number using multiline string. Here I need to extract the string between FROM and where clause(from the below string) and need to find the line number in the file
SELECT HL.LOCATION_ID,HPS.PARTY_SITE_ID,HCAS.CUST_ACCT_SITE_ID
INTO LN_SITE_LOCATION_ID,LN_LOC_PARTY_SITE_ID,LN_CUST_ACCT_SITE_ID
FROM HZ_LOCATIONS HL,
HZ_PARTY_SITES HPS,
[Code]....
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Sep 10, 2014
Write a program that accepts the line number from the user and prints only that particular line from the Floyd triangle.
Example:
Input: 2
Output: 2 3
Input: 3
Output: 4 5 6
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Nov 21, 2014
I have wrote this class who read from text line by line and save the words in fileOnTable.. Now i don't know what to read in ReadOffer to save the words in object offers and return this.. One more question.. What JUnit test can write for this code..?
package com.example.crazysellout.UserSide;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
[Code] ....
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Feb 18, 2015
How do I make the file reader object move to the next line if there is no more input on the line. Here is my text and output file as you can see that my text file column cuts off on the 2nd line after 70. I want to read that next line which is 100 into my labs variable however its reading it into my final exams variable. I'll also post the code but I didn't think it was necessary.
textfile:
100908095
1008070
10070
output:
Labs Projects Tests Final Exams
100908095
1008070100
70
[import java.util.Scanner;
import java.io.*;
public class MyGrades
{
public static void main (String[] args) throws IOException
{
int lab, project, test;
int finalExam;//Par and Player values
[Code]...
not sure if I code wrapped it correctly
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Oct 15, 2014
If I want to read my file line by line and when it hits a certain value from that point it should start deleting the lines until the tag ends.Just curious will my code actually work at the moment or not because it goes through so many times then goes straight back to the variable declarations at the start of the method and never hits the console print line.
public void removeEnvironment(){
//declare variable to environment id
String environmentID = "Environment id";
String lines = null;
boolean lineFound = false;
boolean end = false;
[code]...
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Apr 12, 2014
I'm doing an assignment for uni and have come across a small hiccup. What I'm trying to do is scan in a text file and read "commands" for it line by line, E.g:
Student Mary 12345 19
Student Joe 12346 19
Change Joe 19 20
Change Mary 19 20
So that lines that begin with the word "Student" indicate that I should create a new student file with that name, student ID, and age.
"Change" indicates that I should be changing the specified student's current age to the new age etc.
What I'm currently doing is something along the lines of this:
Scanner input = new Scanner(new FileReader(args[0]));
String[] line;
while (input.nextLine().startsWith("Student")) {
line = input.nextLine().split("s+");
[Code] ....
The problem I'm having is that every second line seems to be getting skipped (because I'm calling nextLine() so much?) but I can't think of a way to "peek" at the first word of each line without advancing past it. Is there any way of doing this?
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Apr 23, 2015
why I am getting an error at Line 1 - cannot find symbol:
public void timesTwo()
{
String numberString;
int number, answer;
boolean again = true;
[code]....
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Jul 22, 2007
I'm going to be taking an object oriented paradigm using java during intersession in a few months. I'm trying to brush up on it a bit. The problem is. Write an application that displays the numbers 1 to 4 on the same line, with each pair of adjacent numbers separated by one space. Write the program using the following techniques:Use one system.out.printLn statement.Use four system.out.print statement.Use one system.out.printf statement.
This is what i have so far .
Java Code: public class Display
{
public static void main(String [] args) {
System.out.print("1 ");
System.out.print("2 ");
System.out.print("3 ");
System.out.print("4 ");
System.out.println(" ");<----is that what that is supposed to look like, and where it goes?
System.out.printf(" %s %s %s %s ");????
}
} mh_sh_highlight_all('java');
i cant test this my console isn't working right, and i haven't finished my compiler install.
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Dec 8, 2014
how to read file line by line ? Namely my input file I want to read look as follow:
AAA 1, 1
12 222 12
AAA 2, 2
11 122 11
My output file should look as follow:
1, 1, 12
1, 1 222
1, 1, 12
2, 2, 11
2, 2, 122
2, 2, 11
I think the lines need to be stored in ArrayList, then I would like those lines to write to csv file, but how on read I can construct such output file? This is my code for reading file
public ArrayList readFile(String filename)
{
try
{
[Code]....
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Jul 12, 2014
I have a text file that has the following lines:
the boy is smart
He is from Australia
** Highly important line
That's all
Now, I need a regular java expression that would match a line in this file that begins with the ** characters. That is, when I match the text with the regex, I should get only this line :
** Highly important line
How would I write this regex in java?
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Nov 10, 2013
When I try to run Java from the Windows DOS command line, I'm running into trouble:
1. When I run Java from the wrong directory, I get the error Error: cannot find or load main class myapp1.
2. When I get to the "right" directory (.../MyApp1/build/classes/myapp1/, which is where the MyApp1.class file resides), I get the following error:
Exception in thread "main" java.lang.NoClassDefFoundError: MyApp1 (wrong name: myapp1/MyApp1)
1. The CLASSPATH variable is not set (when I type echo %CLASSPATH% the system returns %CLASSPATH%).
2. I also get the same error above when I use: > java -cp . myapp1
3. I've made sure the PATH is set correctly in environment variables, with the Java path at the beginning of the path string).
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Feb 7, 2014
I create a Audit file within my Java program, which gets all the System.out.println lines from the code.
For example, the System.out.println lines in my code are as follows:-
Records initially inserted into edited: 70144
Bad license number records removed: 5
Total records in edited: 70139
Records initially inserted into tabedited:7463
I want all my values aligned after the statement, when they are printed to the Audit File.
Instead of just giving spaces by counting the number of charaters in the line, is there any other way to align them.
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Feb 11, 2015
I'm having trouble with a program, reversing numbers. I got the program itself to work! However, I am having an issue with the output.
import java.util.Scanner;
public class p1a {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int n;
int reverse = 0;
[Code] .....
If I were to input, say 2341, I would get this: The reverse of 0 is 1432
The 0 should have been 2341, or whatever I input. What am I doing wrong?
I tried to move line 21 : (System.out.println("The reverse of " +n+ " is "+reverse);
Above the while loop, but instead get:
The reverse of 2341 is 0
How can I get my input and my result together in the same line?
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Feb 21, 2014
I need to insert a newline into a string where a letter follows a non-letter.
Example String: A63B432
I want to insert a newline after A63
I only have the string class available to me.
I'm familiar with regular expressions however I don't know how to use the String class to insert a newline.
I'm guessing the regular expression I'm looking for would be similar to:
[.0-9_][a-zA-Z]
(for . OR didgit OR underscore followed by an alpha character)
But how to insert a newline between the two?
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Dec 12, 2014
I am checking how to do following task.
01. pickup the selected text file and read the line by line and output the text in to visual text pane.
what i did:.
01. I wrote code that read the text file and output in to jave console/ also some of the interface.
the code read txt file:
Java Code:
String fileName = "C:/Users/lakshan/Desktop/lawyer.txt";
File textFile = new File(fileName);
Scanner in = new Scanner (textFile);
while(in.hasNextLine()){
[code]....
so it will read any text file dynamically and output to the text pane in interface. I think scanner code must be execute after the select the file from the browser and set the scanned result in to variable. then later out put the var as string in some jswing component?
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Aug 15, 2014
how many objects got created at each line (in String pool or in Objects memory):
public class Test {
public static void main(String[] args) {
String s1 = "test";
String s2 = new("test");
String s3 = s1 + s2;
StringBuider sb = new StringBuilder().append(s2);
}
}
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Feb 7, 2015
i'm trying to add new value (string type) in an existent file.say that we have a .txt file which contain "mario"...i ask to the user a new name, and he write for expample "tony", now i want append the word "tony" in the existent file in this way: Iwrote this code:
Java Code:
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
[code]....
first is saved next to the value existing. why? maybe because the program does not check if there is a string in the file?but I do not think. because otherwise it would happen with any name that is not entered in an odd position.
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Aug 13, 2014
write the logic in the below given Java method.
Public static boolean updateNetMap(String filepath, String nodename){
// check the file pointed by filepath to have entry for nodename.
// if it is there, get the start line no and end line no
// Based on the line nos, need logic to remove the contents from the file.
}
Below is the sample node entry, which we need to identify and delete (here nodename is WAS_CD1):
WAS_CD1:
:conn.retry.stwait=00.00.00:
:conn.retry.stattempts=6:
:conn.retry.ltwait=00.00.00:
:conn.retry.ltattempts=6:
:tcp.max.time.to.wait=0:
[Code]...
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Mar 8, 2014
So basically, if a line in a text file contains a certain string, that specific line will be deleted. It should probably be similair to this method?
Java Code:
/**
* Replace text.
* @param replace
* The text to replace.
* @param replaceWith
* The text to replace with.
*/
public static void replaceSelected(String replace, String replaceWith) {
try {
BufferedReader file = new BufferedReader(new FileReader("data/replacer.txt"));
[code]....
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Dec 6, 2014
I am having issues insert each line of the simple textfile into a specific varible I want it to go to. For example my text file is ordered like this
Dallas
78 F
North, 15 mph
dallasimage
Denver
29 F
South, 10 mph
denverimage
and I want Dallas in city variable, 78f in temperature variable, and so on until text ends, at the moment is all goes into city variable, it all prints from there! I tried inserting it into an array but it would read all the lines previous to it in addition to reusing readline and all failed.
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public class Textreader {
public static void main(String[] args) {
[code]....
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Jan 27, 2015
So I'm having a problem with the .hasMoreElement() method. I try to read lineOfInput for a file which contains:
Hobbit, Long,t@gmail.com,475-555-4444,3
Long, Hobbit,b@yahoo.com,445-222-5342,2
Hobbit,Long,b@yahoo.com,465-222-5342,2
Help,Yerp,,455-222-2222,4
but when i get to the ,, on the last line I get a NoSuchElementException and the program crashes.
StringTokenizer inputField = new StringTokenizer(lineOfInput, ",");
while(inputField.hasMoreElements()) //for each fields is a line
{
lastName = inputField.nextElement().toString();
firstName = inputField.nextElement().toString();
email = inputField.nextElement().toString();
phoneNumber = inputField.nextElement().toString();
level = Integer.parseInt(inputField.nextElement().toString());
}
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Oct 19, 2014
I am writing to a text file via user input and it is saving all the user input to the file but it is just printing one word per line. I would like it to print the string on one line and print the next string on the next line upon them hitting enter.
public void textFile() {
Scanner reader = new Scanner(System.in);
System.out.println("Enter file name: ");
String fileName = reader.next();
File f = new File(fileName);
PrintWriter p = null;
[Code] ....
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Jul 6, 2014
I have written the code to read the line from file and save first string as word and and remaining string as meaning..
E.g.: innovation a new method, idea, product, etc.
word = innovation
meaning = a new method, idea, product, etc.
In my code there is no error and have a mistake what it is means first assigning word is ok and while saving meaning ..it saves like
{
a a new a new method } like that
Java Code:
import java.io.BufferedReader;
import java.io.FileReader;
public class Dil{
public static void main(String[] arg)throws Exception
{
BufferedReader in;
[Code] ......
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Feb 8, 2015
Write a java program to accept a string, float and an integer as command line arguments. String value should be displayed. Also the program should display the maximum value of two numbers. Use Integer.parseInt() and Float.parseFloat()
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Feb 18, 2014
I have a large text file of 1 GB size. I need to print the line when a matching word is found in a particular line. Below is the code I am using. But if there are many lines that has the matching word, it's taking lot of time. Any solution to print the lines much faster.
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
if(line.contains("xyz")) {
System.out.println(line);
}
}
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