Find The Longest Decreasing Sub-array

Oct 30, 2014

I have a given array of numbers, and I have to find the longest decreasing sub-array, but the thing is that the elements don't have to be next to each other!

For example, the longest decreasing sub-array for this array : 546 -156 165 -156 -56 -13 5

is 3 (check the bold numbers)

Until now, I have nearly finished my code, but I have one problem...

private static int decreasing(int[] a) {
int result=1, temp=0, br=1;
//Checking all the elements one by one:
for(int i=0;i<a.length;i++){
temp=a[i]; //placing the element on a temp value

[Code] ....

The problem with this code is that it's not smart.. let's say I have : 100 -500 90 80 70

Once it hits -500, none of the other if's with pass....

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How To Find Longest Path In A Matrix

Feb 18, 2015

I have some N*M matrix or N*N matrx , and there's a "worm" that can start from any index in the first column, or, any index in the first row. i need to choose the longest worm that satisfying this :

The index that comes after the index before him must be greater then 1. and i must use recursion, also for helper methods. no loops at all. that's it. i'm having a problem to find the longest worm in the matrix.

My idea was to create an helper array and assign to the array indexes a variable that will count the steps of the worm and finally assigns in to the helper array index. then i used findMax method to find the max value in an index. and thats will be the longest worm. i wrote a lot of code so i wont put it here. i will say that i'm close. if the longest worm is 6 i get in my output 7.

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Oct 24, 2014

I am trying to find the longest descending sequence without arrays. So 65124976231 would output 9762.

import java.util.*;
public class HelloWorld {
public static void main(String[] args){
String num = "";
int longestLen = 0;
int currLen = 0;
String max = "";

[Code]...

I keep getting: The longest descending sequence is: 6512 In an infinite loop.

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Jul 11, 2014

I am trying to make a code that copies the users String to a char array. However, I am in a predicament: since I would not know the exact size of the users String I am left with the options of either making my array large by default, filled in with, lets say 25, empty spaces per index OR starting out with a default size of 1, with an empty space, and then some how increase the size from there.

At this moment I am leaning on the first option, creating a large default array and then deleting the unused values. However, this brings me to my actual question: if I set the non used indexes to null, if that wont give me an error, would that change the size of my array?

Ex:
//lets say i finally copied all of the values and this is the result
char[] word = {'b', 'o', 'b', ' ', ' '};
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Oct 26, 2014

From a given array of positive and negative numbers, I have to find the longest SUB-Array which represents a Zig-Zag sequence...

A Zig-Zag sequence means that one number is possitive, the next one negative, the next one possitive, and so on and so on...

Like this: -1, 4, -5, 6, -9, 2, -9 etc....

So that means, if the array looks like this:

1, 4, -2, -5, 6, -9, 1, -4, 9, -8, 7, 4, -3

the longest sub-array which fulfills the requirement is (the part in bold):

1, 4, -2, -5, 6, -9, 1, -4, 9, -8, 7, 4, -3

and I only need it's length, which in this case is: 8

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Jan 17, 2014

I believe I have this program CounterTester.java down but in my output the program is increasing the way I want it to but it is not decreasing the way I want it to.

public class CounterTester
{
static int myCount;
static int myCount2;
 public CounterTester(int inti) {
myCount = 1;
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[Code] .....

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Nov 27, 2014

I am trying to sort the 5 cards in decreasing order and this is exactly what my professor gave us but it has errors.

int pos;
int max;
for (pos = 0; pos < hand.length; pos++){
max = pos;
for (int i = pos + 1; i < hand.length; i++){
if (hand[max] < hand[i]){
max = i;
}
}
if (max != pos){
int temp = hand[pos];
hand[pos] = hand[max];
hand[max] = temp;
}
}
}

Line 6 has an error with the < operator.
Line 11&13 says cannot convert from card to Int.
This method is passing in Card[] hand

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Mar 24, 2015

I am taking the Class Algorithms and Datastructures and got an assignment for Lab that really throws me off. The goal is to create an Array out of a given CSV file, implement several Methods that get the size of array, etc.

I am still stuck in the first part where the CSV has to be imported into the Array. My problem is that I need a mechanism that figures out the needed size for the Array, creates the array, and only then transfers the data from the CSV.

The list consists of the following wifi related values:

MAC-Adress, SSID, Timestamp, Signalstrength.

These are on the list, separated by comma. The Columns are each of these, and the rows are the four types of values making up the information on a certain wifi network.

The catch is, we are not allowed to use any of the following:

java.util.ArrayList
java.util.Arrays
and any class out of java.util.Collection.

So far I used the BufferedReader to read in the file and tried to implement the array, but I get an arrayindexoutofboundsexception.

Below is my Code (Its still an active construction zone):

public class WhatsThere {
public WhatsThere(String wifiscan) throws IOException {
}
public static void main(String[] args) throws IOException {
// WhatsThere Liste = new WhatsThere(String wifiscan);
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[Code] ....

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Jul 13, 2014

My problem is that I can't even run the program, because it gives me

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 13
at domashno.ten.longestSortedSequence(ten.java:37)
at domashno.ten.main(ten.java:17)

Code :

public static void main(String[] args) {
int[] arr = {3, 8, 10, 1,9, 14, -3, 0, 14, 207, 56, 98, 12};
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}
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[Code] ....

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Jan 28, 2015

Okay so I need to be able to read a file and then be able to find the longest sequence of increasing numbers.

So if the file was this, (this is Ass1Q2_test4.txt)

97 47 56 36 60 31 57 54 12 55
35 57 41 13 82 80 71 93 31 62
89 36 98 75 91 46 95 53 37 99
25 45 26 17 15 82 80 73 96 17
75 22 63 96 96 36 64 31 99 86
12 80 42 74 54 14 93 17 14 55
14 15 20 71 34 50 22 60 32 41
90 69 44 52 54 73 20 12 55 52
39 33 25 31 76 45 44 84 90 52
94 35 55 24 41 63 87 93 79 24

the output should be,

(5,0) with cost 12
(6,0) with cost 14
(6,1) with cost 15
(6,2) with cost 20
(7,2) with cost 44
(7,3) with cost 52
(7,4) with cost 54
(6,3) with cost 71
(5,3) with cost 74
(4,3) with cost 96

Greatest path is of length 10.

Now, the code that I have works, kind of. Instead of recurring several times at each point, it only recurs once.

So say I'm looking at (1,1). With (1,1) being 57. The area around it looks like this.

97 47 56
35 57 41
89 36 98

Now when I look at it, there are several paths it can take. It can go 57, 97 or 57, 89 or 57, 98. However, I'm pretty sure that it just uses the first one that corresponds with the first if statement that is valid. So I start checking north of the value, then northeast, then east, then southeast, which at southeast is where I find my first greater than value. After it finds it's first valid number, it then continues from that number, instead of checking if there are other longer paths stemming from the original value.

In conjunction with that, you can see that the printout just returns all paths from each value. Which isn't what I want. I need a way to store the longest current path, then check each path after to see if it's longer. If it is, it's replaced, if not, it stays the same.

I've also attached Ass1Q2_test4.txt

import java.util.*;
import java.io.*;
public class MaxIncreasingSub {

[Code].....

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[code]....

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Following is the code:

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Nov 6, 2014

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my code is :

Java Code: public static double[] computeAllGrades(int[][] scoreTable, int[] itemPointValues)
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{
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[code]....

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/** */
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/**      * @param args the command line arguments      */
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[Code] ....

Whether this algorithm: [Code] ....

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Dec 5, 2014

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[Code] ....

Also the array is a CO2Data array which is part of the following class:

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[code].....

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Here is what I have so far:

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[Code] .....

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To me it looks right and it seems to work.

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Java Code:

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Oct 26, 2014

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[Code] ....

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