Finding And Printing Median Node In Linked List Using Recursion

Nov 3, 2014

The only problem I have now is getting a method to return the median element of a LinkedList without using loops of any kind or by using a global counter anywhere.

I've pretty easily figured out how to get the index value for the median number (there is some lee way allowed. If the list has an even size, any of the middle values are accepted) but I can't figure out how to print it without loops.

I'm sure I need to make a method that finds an element at the given index value, but I don't know how to do it without loops.

Here's all of my code. Inside is my Assignment3 class I use for testing, StudentList which contains the LinkedList head and other List methods, and StudentNode which is obviously, the Node class. Also I've attached the first test1.txt file as well.

import java.io.FileNotFoundException;
import java.util.*;
public class Assignment3 {
public static void main (String []args){
StudentList<StudentNode> myList = new StudentList<StudentNode>();

[Code] .....

I tried making a method that basically counts up the list recursively then a second method that counts down recursively and is supposed to stop once it hits the middle number, then print that node.

Attached File(s) : test1.txt (106bytes)

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Apr 7, 2014

I am trying to advance to the next node in my linkedList. Below is what i have so far.

/**
* Move forward, so that the current element is now the next element in this sequence.
* @param - none
* @precondition:
* isCurrent() returns true.
* @postcondition:
* If the current element was already the end element of this sequence (with nothing after it), then there is no longer any current element.
* Otherwise, the new element is the element immediately after the original current element.
* @exception IllegalStateException
* Indicates that there is no current element, so advance may not be called.
**/

public void advance( ) {
// student implements
if(!isCurrent())
throw new IllegalStateException();
else{
while(cursor != null){
precursor = cursor;
cursor = cursor.getLink();
}
}
}

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return;
}
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[Code] .....

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My problem is accessing this head node and changing it from the quckSort method/class, and I dont want to delete it or simply just change the element value

Main:

public class TestLinkedList {
public static <E extends Comparable<E>> void main(String[] args) {
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L.add(3);
L.add(1);
L.add(2);
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}
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QuickSort:

public class MySort {
public static <E extends Comparable<E>> void quickSort(MyNode<E> list) {
list = list.next;
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Node Class:

public class MyNode<E extends Comparable<E>> {
E element;
MyNode<E> next;
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[code]....

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This is my Code

AddItemToFront
public void AddItemtoFront(Item p)
{
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[Code] ....

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public class DoublyLinkedList<T> implements SimpleList<T> {
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protected int n;
public DoublyLinkedList(){

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n = 0;

[Code] ....

I want to use a dummy node in my implementation of the Doubly Linked List, so it will be easier to code all the methods I need to write. I keep on getting a problem with line 14 and 15:

dummy.next = dummy;

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it prints perfectly. But i'm trying to use a method where it would loop through the list and print out the data for every node in it. when i run my print method i get results such as

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Here is my print method i created

Java Code:

public void print(){
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}
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package project;
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[code]...

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I'm trying to find the median of a set of numbers inputted into an array and I wanted to know how I would pass the array to the median calculator after I use selection sort to organize the numbers.THIS IS THE CODE THAT ORGANIZES THE ARRAY:

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{
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[code]....

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Sentence.java
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[Code] ....

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import java.io.*;
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public static void main(String[] args) throws Exception {
int num = 0;
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[code]...

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import ch11.exceptions.*;
import ch10.LinkedBinaryTree;
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*/
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[Code] ....

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[code].....

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[Code] ....

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[Code] .....

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