First Time Using Generics - Incomparable Type Errors

Aug 29, 2014

I am trying to make a generic method that will replace the data type T with those number types usable with a Scanner object. However, whenever I try to compile, I get errors saying that a Byte/Integer/Double etc are found when only a type T is allowed. This is the beginning of my method. I can;t understand what is wrong with it.

Java Code:

public <T extends Number> T nextRanged(T lowerBound, T upperBound, boolean inclusive, String errorMessage){
// Holds program execution until user inputs a numeric value between the bounds. Prevents all other input without exception.
// Output data type determined by the type of the bounds.
T input = null;
try{
if(input instanceof Byte){
input = new Byte(internalScanner.nextByte());

[Code] ....

The purpose of the method, in the end, will be to provide the nextXXX() functionality of a Scanner object but with built in validation procedures. I could easily do this by making a nextIntRanged(), nextDoubleRanged() etc methods, but this seems wasteful to me.

I meant "incompatible type errors"!

Error example:

ValidatedScanner.java:57: error: incompatible types
input = new Byte(internalScanner.nextByte());
^
required: T
found: Byte

where T is a type-variable:

T extends Number declared in method <T>nextRanged(T,T,boolean,String)

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I have doubt in generics,

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Also, when I type a string in the temperature I get an exception....I can do the same with that as I would the temp type? I think I may just be putting the code in the wrong spot and thats why it isn't working..

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[Code] ....

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Aug 6, 2014

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error: <identifier> expected
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error: illegal start of type
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I cannot seem to figure out what is different about my code!!

import java.util.*;

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[code]..

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