I'm trying to flip an image horizontally. However because when I flip the images they're offset by a bit, I added "-height" to offset the change in position. Unfortunately, it doesn't seem to be working 100% of the time; some images are adjusted to their correct position but some are not.I'm using this line to flip an image: Java Code: g.drawImage(castle, x, y - height, -width, height, null); mh_sh_highlight_all('java');
Page flipping is used in full screen games which entails drawing an imagine off screen then swap with on screen image after drawing has completed.
Is it possible to write a block of code to actually see this happen? Like use this technique on a window that is in windowed mode. Would it draw an image off somewhere by the desktop or would it have to be on the window?
I'm using JavaKara (a graphic Java software to learn coding) on my classes at the moment and we're asked to transform something like this:
In the inverse, where you can see clovers there must not be any and where there aren't you must plant them. PLUS YOU MUST SWITCH THE FIGURE HORIZONTALLY.
This is the result i should obtain:
public class InvertiECapovolgi extends JavaKaraProgram { public void myProgram() { boolean arrayquadrifogli[][] = new boolean[world.getSizeY()][world.getSizeX()]; //[rows][clumns]-->[Y axis][X axis] in kara for (int y = 0; y < arrayquadrifogli.length; y++){ // My Ladybug starts to run through the whole grid
[Code] ....
How to switch everything horizontally!
This is my result:
My ultimate question is, how do i have to edit the second loop, and why, to obtain the horizontally reversed result i'm supposed to obtain?
I'm making a game of checkers for my A2 Computing coursework which is due in within a week. I have completely finished the game, and only thing I have left to do is connect the two JPanels together via a CardLayout that I have made. However I am unsure how to do so
I have kept the code I am displaying to a minimal, hence I have removed all the action listeners for my buttons, anyway the problem I have is that, I would like it so that when the user clicks on the 'Multiplayer' button which is the array button ourButtons[1], it will then transition into my main game screen so that the user can then play a game of checkers.
Here is the main important GUI from my CheckerBoard class:
import java.awt.*; import java.awt.event.*; import javax.swing.*; public class CheckerBoard extends JPanel implements ActionListener, MouseListener { // Main routine that opens an Applet that shows a CheckerBoard public static void main(String[] args) { new CLayout();
The second message dialog result is always 0 ... i want to find the minimum grade...
import javax.swing.*; import java.util.Arrays; public class Parrarrapapa{ public static void main (String[]args){ String length = JOptionPane.showInputDialog("Number of students");
I'm tyring to print the same output in console to a text file, but I can only get the last line of the console output in the text file, not sure what is wrong with my code:
while (in.hasNextLine()) { PrintWriter writer = new PrintWriter("output5.txt"); tempS = in.nextLine().toLowerCase(); System.out.println(wp.bestPages(tempS));
[code]....
What's causing only the last time to be printed in text file? Are there better ways to print console outputs into a text file than PrintWriter?
When I run this code, it is supposed to get one value from turnTimer(); and return it, just as a test. This works when I enter a valid pit. For example. If I were to input "A" when it's player one's turn, it will return 1, like it should. However, if I were to type "H" when it's player one's turn, it returns "Not a valid pit!"(like it should) but then it also returns 12. It shouldn't know that H is 12 because it's in a separate method. I'm confused as to why it's printing both values.
import java.util.*; public class Mancala { static Scanner input = new Scanner(System.in); public static int pit; public static void main(String[]args) { Mancala mancala = new Mancala(); int[] board = {0,3,3,3,3,3,3,0,3,3,3,3,3,3};
I've a ArrayList with dogs on, and I've a function that should allow me to delete a dog from the register and if the dog was found it prints "The dog was deleted" and if the dog doesn't exist in the arraylist it should print "the dog couldn't be found".
Everything works perfect until I shall delete a dog that is not first on the list. Then the program shows first "dog was not found" and on the row after "the dog was deleted" if the dog was second on the list. If it was third I will get 2 messages that the dog wasn't found and then that the dog was deleted. I've no clue why it prints both else and if!
public static void taBortHund(){ //Har tar vi bort hund fran listan //System.out.println(hundlista); System.out.print("Vilken hund vill du ta bort? "); String hunden = tangentbord.nextLine(); for (int taBort = 0; taBort<hundlista.size(); taBort++){
I am stuck and having a problem trying to find what i believe is a simple fix but can't wrap my head around it. For class I needed to make a table that prints out Sin,Cos,Tan for angles in steps of 5 to 180. The problem is in my output with the first couple lines of the table. for angle 5.0 the Sin(.0872) Cos(.9962) and Tan (.0875) are being displayed on the angle line 10.0
public class TrigTable { public static void main(String[] args) { double angle = 0; double sin =0; double cos = 0; double tan = 0;
System.out.println("Angle Sin Cos Tan"); // Table header for the values
[Code] ....
Here is the first couple lines of output:
Angle Sin Cos Tan ----- --- --- --- 0.0 0.0 1.0 0.0 5.0 0.0 1.0 0.0 10.0 0.0872 0.9962 0.0875 15.0 0.1736 0.9848 0.1763 20.0 0.2588 0.9659 0.2679
When I run this code, it is supposed to get one value from turnTimer(); and return it, just as a test. This works when I enter a valid pit. For example. If I were to input "A" when it's player one's turn, it will return 1, like it should. However, if I were to type "H" when it's player one's turn, it returns "Not a valid pit!"(like it should) but then it also returns 12. It shouldn't know that H is 12 because it's in a separate method. I'm confused as to why it's printing both values.
import java.util.*; public class Mancala { static Scanner input = new Scanner(System.in); public static int pit; public static void main(String[]args) { Mancala mancala = new Mancala(); int[] board = {0,3,3,3,3,3,3,0,3,3,3,3,3,3};
I was told to create a program that prints the time between 00:00 (0:00 a.m.) and 23:45 (11:45 p.m.) in the 24-hour clock and 12-hour clock format like this:
Write a method that prints characters using the following: public static void printChars(char ch1, char ch2, int numberPerLine). This method prints the characters between ch1 and ch2 with specific numbers per line. Characters are separated by exactly one space.Test your method with the following main method:
public static void main(String[] args) { printChars(‘A’,’z’,10); printChars(‘0’,’9’,5); }
So I'm trying to write a program that prints out the "most-repeated integer" in an Array.
For example: if an array contains {1,2,2,3} It would print out 2 as the result.This is what I got so far and according to my knowledge I think I'm correct but for some reason it doesn't work.. Please give me some inputs.
public class MostInt{ public MostInt (){ int[] array = {0}; for(int i = 0;i>array.length;i++){ if(i==i++){ System.out.println(i);
I made a heads or tails game but I'm getting a bug when the user says he doesn't want to play anymore. The statistics are printed as many times as the games played. If you want to test the code, write" cap" " pajura" and when the program says "Vrei sa mai joci?" that means "do you wanna play another one?" and you can answer with "da"(yes) or "nu"(nu) Here is the code:
import java.util.Scanner; public class cap_sau_pajura{ private static int user; private static int pc; private static String converted; static int usermove; private static int castiguri = 0; private static int pierderi = 0;
I don't want a tutorial that shows me how to do a util timer with a button, or that prints a message, or that does anything. I want the simplest possible snippet that makes the timer, lets me have it do something, and can be stopped. No bells and whistles, no strings, no sparkles and explosions. Just a timer.
The class Overloading below asks for two names and prints three different greetings. Your task is to write the class methods missing from the class declaration. Methods print the greetings as shown in the example print.
Hint:The names and parameter types of the needed methods can be checked from the main method because all methods are called there. This exercise also does not require you to copy the source code below to the return field.
The method declarations will suffice.
Example output Type in the first name: John Type in the second name: Doe
********** Hi! ********** Hi, John ********** Hi, John and Doe **********
import java.util.Scanner; public class Overloading { public static void main(String[] args) { String firstName, secondName;
package FracCalc; import java.util.Scanner; public class FracCalc { public static void main(String[] args) { Scanner scan = new Scanner(System.in);
int n1 = 0; //n1 = first numerator user have to enter int d1 = 0; //d1 = first denominator user have to enter int n2 = 0; //n2 = second numerator user have to enter int d2 = 0; //d2 = second denominator user have to enter int numeratorAnswer = 0; //calculates numerator of an equation int denominatorAnswer = 0; //calculates denominator of an equation
[code]...
I mean its not that important but i figure it will be better if I could print out the answer both in fraction format and decimal format. while my answer prints in fraction just fine how do i show it in decimal?
System.out.println("");
System.out.print("And "); System.out.print("answer in Decimal is: ");
import java.util.Scanner; public class smallestnumber { public static void main(String args[]) { Scanner input=new Scanner(System.in); int smallest =0; int number;
[Code]...
here is the output of my code:
Enter the number 88 Enter the number 8 Enter the number 6 Enter the number 55
I am trying to write a java program that prints out the number that is the mathematical constant e. As you input a number, the larger it gets , the closer it comes to 2.71828 . Here is my code:
//taylor series that prints out e^1=1+1/1!+1/2!+1/3!+..... import java.util.Scanner; public class taylor_1 { public static void main(String args[]) { Scanner input=new Scanner(System.in); int factorial =1;
I'm trying to create a circular array which prints out 8 numbers that increase by one and don't exceed 9. If they do, the remaining numbers are printed from 0 on-wards. I have code below which does this job, but it doesn't really use an array to loop back.
Java Code:
package Practice;
public class Practice { public static void main(String[] test) { number(7); number(9);
