[public static void PrintNum () {
int i;
int j = 0;
for (i =100; j<5; i=i)j=100-(i-=1);
System.out.println(i);
} ]
I'm not following how it calculated to 95 since I'm confused with this
part i=i)j = 100-(i-=1);
The Program prompts the user to enter the number of products in the product catalog. The program should then prompt the user for the name and the price of each product in the product catalog. Once all of the products have been entered, the program should output the product information (name and price) of the most expensive product in the catalog. Your solution to keep track of the product with the highest price.
import java.util.Scanner;
public class ProductTester {
private static final String price = null;
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.print("Enter the number of Products: ");
int count = console.nextInt();
[Code] ....
For an assignment
-I am too write a program that checks if 3 numbers (scannerinputted) are three sides of a triangle if not just ignore it.
-If they are the 3 sides to a triangle tell what kinda triangle it is Right/scalene/equilateral etc.
-ignore the 3 numbers if they are <=0
if(side1+side2>side3 && side1+side3>side2 && side2+side3>side1)
System.out.println("This is a Triangle.");
else
System.out.println("Not a Triangle.");
How can I make the program stop immediately if the else statement is checked. I have more "if statements afterward.
so it would say.
"This not a triangle"
"This is scalene or isosceles"
how can I get this output.
"This is not a triangle" and stop there.
I m trying to simplify an if condition as much as possible and i m curious if it can be made more short then i managed to .The problem is simple , a integer number with 3 digits is generated and the user is asked to input another 3 digits integer number ... One of the conditions that need to be verified is if all the digits in each number match but not exactly ( aka 123 and 132 ) .Using only an if statement to verify this what is the most short condition that can be checked to identify when the digits in a 3 digits number match the digits of another 3 digits integer number (not interested if they match exactly) .
The simplest condition i managed to find is :
else if (guessDigit1 + guessDigit2 + guessDigit3
== lotteryDigit1 + lotteryDigit2 + lotteryDigit3
&& (guessDigit1 == lotteryDigit1 || guessDigit1
== lotteryDigit2 || guessDigit1 == lotteryDigit3)
&& (guessDigit2 == lotteryDigit1 || guessDigit2
== lotteryDigit2 || guessDigit2 == lotteryDigit3)) {
System.out.println("Match all digits: you win $3,000");}
Is there a better(shorter ) condition that can be used ?
I need to display button based on the condition in xhtml page.
using JSF2 & richface 4.0
<c:forEach items="#{empList}" var="emp">
How to check condition like empList.size > 0 in xhtml?
if list is having value, need to show buttons.
public int getIndexOfAMonster(String nameToGet){
int retValue = -1; //default is not found
for (int i = 0; i <= numberOfMonsters - 1; i++)
if (monsters[i].getName().equals(nameToGet))
retValue = i;
return retValue;
}
1.What does the if-condition do?If the name of a monster in the array is equal to the name stored in the variable, return the monster's assigned value.
2.What does the for loop do? The loop condition simply loops through the whole arraylists. (In other words, it simply checks each Monster contained in the lists).
3.Assuming that the driver code compiles, explain what it’s use is? If the name of the monster is the same as the variable passed unto this method, return the number assigned to that Monster.
I'm working on a problem that requires me to generator all possible word combinations based on a 7-digit number as input. Many of the generated "words" will be nonsense, but some with be "NEWCARS", "TAKEOUT", etc... This problem mimics the phone number a company would use to support clients remember that number.
I completed the exercise, but I would like to explore more elegant solutions. Specifically, I've used an IF-THEN-ELSE condition inside of a FOR loop. Here is my working code:
package com.johnny_v.exercises.telephone;
public class WordGenerator {
public static void main(String[] args) {
int numOfTimes = 2187;
String two = "ABC";
String three = "DEF";
String four = "GHI";
[code].....
I receive StringIndexOutOfBoundsException exceptions. I it's because multiple conditions are matched. For example, the indexSix is reset to 0 when row is a multiple of 9. Because row is also a multiple of 3, this condition also executes and then increments "indexSix".
Is there a different logic in Java for if statements when it comes to conditions? I mean my attempt to compare a String variable and a String attribute of a class that is on an array of objects was frustrated someway. It will not enter the if block. The two strings are equal. I displayed the values of each strings before the if evaluation and they are equal. The simbol I used was the ==, and I also tried the string.equals(string variable) as well as the compareTo() == 0 option but none of those worked. I wish I knew what it is the way to compare two strings.
View Replies View RelatedHow can we create deadlock condition on our servlet? Does calling doGet() from doPost() and vice versa really cause a deadlock? Or, does it cause a StackOverflowException?
View Replies View RelatedIs it possible to wait for an input for a user and check in the meantime if something else is true?
Now if the server in the meantime says: there is no input needed and tells it the client.
Could the client now somehow change from
input.readLine() to another Method say: quit() ?
I am stuck there because I know the server sends: quit to the client1 but the client2 cannot react because it still waits for an input for the user.
Maybe something with Thread.sleep ?
I am using what is known as a Depth First Search to solve a maze using my own Stack created class for an assignment. The reason I believe I am getting this error is because my program is never meeting the `finishSpot` condition. I have used the debugger and it looks like it is infinitely stuck at the Point before the `finishSpot`. My logic seems to be mostly correct except until the point where my maze solver tries to finish the maze, so i just need meeting that last condition that is causing my program to crash.
This is a sample maze:
*****
*s* *
* * *
* f*
*****
Here is my Main which uses my created Stack class.
//Creates a Stack and determines the start and endpoints.
public static void solveDFS( char [][] maze ){
LinkedStack stack = new LinkedStack();
Point currentSpot = findPoint( maze,'s' );
Point finishSpot = findPoint( maze, 'f' );
findPath( maze,currentSpot, finishSpot,stack );
[Code] ....
I made a mistake it says my program is crashing which it is not, but simply not meeting the condition.
how to translate it into Java language due to lack of experience (2 weeks). My solution I've formed in my head is: create a new array for the numbers that are in improvement and then declare a "max" variable. Check which array's length is higher and print that length. What I don't know to do is: I don't know how to create a new array for each numbers that are passing through the condition.
Note: I couldn't find anything on internet about my problem so that's why I'm here.
My code is this one:
class MyClass {
static int progresie=0;
public static void longest_improvement(Integer[] grades) {
for(int i=0;i<grades.length-1;i++){
if(grades[i]<=grades[i+1]){
progresie ++;
}
}
System.out.println(progresie);
}
}
How can I validate the postal code based on this condition...
9999 may not be used for US province .
If the street province is Mexico or Argentina or Brazil the street postal code must be 9999 ....
In my program one of the panel has a background image and I need that background image to be updated/refresh or changed whenever the panel reaches certain number of clicks
here's the code
Constructor/gui
import java.awt.*;
import javax.swing.*;
import javax.swing.text.*;;
public class demo {
JFrame frame = new JFrame ("Idle Game Test!");
JPanel backGroundPanel = new JPanel ();
[code].....
also is there other way to access those static variables? the way i implemented them works but i do think there are other ways that are more suitable or better but i cant figure out.
As per my knowledge, the instance of operator compiles only if the reference type compared to class type are in the same inheritance tree. According to that, below code should not compile but it compiles FINE!!.
Output:No output generated since the if condition fails
public class InstanceOfTest implements Inter{
public static void main(String arg[]){
Inter iot = new InstanceOfTest();
if(iot instanceof Someone) //here Inter(interface) and Someone(class) are not in the same inheritance tree.
System.out.println("iot is a Someone");
}
}
interface Inter{}
class Someone{}
I have a java application which uses Google Maps to analyze the traffic condition. But sometimes it can be run and work properly, sometimes not. On some computers on which there is installed java, the program can be run, and on some, again with installed java (jre), exactly the same version, the program can not be run. For example the application first run well on my desktop computer, connected in a LAN, and then stopped working well when run. But when I use laptop which uses the WiFi and run the same computer using VMWare, if I connect to the desktop on which the program can not be run, on the laptop the same program can be run well, in the same room, but using the Wifi.
View Replies View RelatedI am trying to create a program that first asks the user for an input in the form: condition = value, where condition is a word from the set {limit, deficient, abundant, perfect, prime}, and value is a positive integer. Then it verifies the input. If the input is invalid it prints a message indicating that and terminates. If the input is valid it prints a table with the number of abundant, deficient, perfect and prime numbers less than or equal to N, where N = 1, 2, 3, ..., limit.
My problem is with the input validation. i want it to read the value as a string and verify if it's integer.
Here is my code
import java.util.Scanner;
public class Factors
{
public static void main (String[] args)
{
Scanner scan = new Scanner(System.in);
int n, f, fsum, p=0, a=0, d=0,pe=0,limit=0,abundant=0, deficient=0;
System.out.print("Enter stoping condition (condition = value): ");
String cond = scan.next();
[Code] ....
I have a task of returning US holiday based on the given date and this utility will be used in a multi thread environment. I have written as below, how to know if my code breaks at any given point by multiple threads
Declared Enum
public enum Holiday {
CHRISTMASDAY("Christmas Day"),
GOODFRIDAY("Good Friday"),
INDEPENDENCEDAY("Independence Day"),
LABORDAY("Labor Day"),
NONE("None");
[code]...
I tried to test this with few concurrent threads, and noticed that the DB call is made for the very first time or when the year being requested is not same as the cached year. But I wanted to see, if this is properly synchronizing and would not fail in any case. My intention is to make a singleton HolidayCalendar, and also synchronized well enough so that every thread using this class gets the required data without blocking each other.
I am trying to print a loop inside an array of a greater size than the loop itself. Like for example I have an array of size 7 but it has only 3 elements.
int[] array=new int[7]
array[0]=2;
array[1]=3;
array[2]=4;
now what I want to do is print these three numbers in a loop so that my array[3]=2;array[4]=3;array[5]=4 ...... till the last one. Also the array could be any size and not just 7.
Here's the code: it's while loop inside a for loop to determine the proper length of a variable:
for (int i = 0; i < num; i++) {
horse[i]=new thoroughbred();
boolean propernamelength = false;
while (propernamelength==false){
String name = entry.getUserInput("Enter the name of horse "
[code]....
I was just wondering what was going on here -- I've initialized the variable, so why do I get this message? (actually the carat was under the variable name inside the parentheses.
I have everything else working. My problem is that when i type "quit" to close the outer loop. It still runs the inner loop. The National Bank manager wants you to code a program that reads each clients charges to their Credit Card account and outputs the average charge per client and the overall average for the total number of clients in the Bank.
Hint: The OUTER LOOP in your program should allow the user the name of the client and end the program when the name entered is QUIT.In addition to the outer loop, you need AN INNER LOOP that will allow the user to input the clients charge to his/her account by entering one charge at a time and end inputting the charges whenever she/he enters -1 for a value. This INNER LOOP will performed the Add for all the charges entered for a client and count the number of charges entered.
After INNER LOOP ends, the program calculates an average for this student. The average is calculated by dividing the Total into the number of charges entered. The program prints the average charge for that client, adds the Total to a GrandTotal, assigns zero to the Total and counter variables before it loops back to get the grade for another client.Use DecimalFormat or NumberFormat to format the numeric output to dollar amounts.
The output of the program should something like this:
John Smith average $850.00
Maria Gonzalez average $90.67
Terry Lucas average $959.00
Mickey Mouse course average $6,050.89
National Bank client average $1,987.67
Code:
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String name = "";
int charge = 0;
int count = -1;
int total = 1;
int grandtotal = 0;
int average = 0;
[code]....
How to convert this program from a while loop to a for loop.
import java.util.Scanner;
public class LongDivision {
public static void main(String arguments[]){
Scanner input = new Scanner(System.in);
System.out.println("Enter the dividend: ");
[Code] ....
How do I convert my for loop below to a while and do while loop?
for(int a=1;a<=9;a++){
for(int b=1;b<=a;b++){
System.out.print(a);
}
System.out.println();
[Code] .....
I am trying to make a program add values from a loop. So what its supposed to do is search through tokens on an imported file. The file lists State, Capital, and then capital population. Then take the population string, turn it into numbers, and then do stuff with the numbers. First I'm supposed to find the Highest and lowest population of the places in the file (which I did without problem), but the finally thing is I'm supposed to add each found population to the last so I can find the average of the populations.
I just cannot seem to grasp how to do that. I THINK I'm supposed to some how store the given value into a variable, but how do I get that variable to add to the new value?
like...?
Get token -> a
b = a
c = a + b
or wait no.....
Java Code :
import java.io.*;
import java.util.Scanner;
public class CapPopS
{
public static void main(String[] args) throws IOException
{
File stateCAP = new File("state-capital-2004population.txt");
if (!stateCAP.exists())
[Code] ....
My teacher wants me to make a program that counts the amount of steps a student takes a day. The program asks for other info such as name, age, college. However I need to write a loop that will allow the user to enter how many ever steps they took and convert them to miles.how exactly to make the steps entered by the user within the loop be their own individual days like monday tuesday etc. Like the loop will ask how many steps did you take monday.. tuesday.. etc for each time it runs.
package StudentInfo;
import java.util.Scanner;
public class studentinfo {
public static void main (String [] args){
Scanner scan = new Scanner(System.in);
[code]....
I need to write a program that measures how long it will take someone to make a million dollars if he is being paid $5.75 an hour, but the pay rate is increase by 0.2% each week after the third week.
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