public static void f() {
int n = 5;
p(n, 2 * n);
}
public static void p(int a, int b) {
int x = 1;
q(x, a + b);
}
public static void q(int x, int y) {
int z = x + y;
x = 0;
...
} mh_sh_highlight_all('java');
When we write x = 0; that refers to the formal parameter int x and hence it's the formal parameter that changes value. why isn't the value of the actual parameter also changing?
I have a question about query execution strategy ...
Scenario: let's suppose I've to query a table with a query like
SELECT F1, F2, F3 FROM MYTABLE WHERE F1 = ? AND F2 = ? AND F3 = ?.
I need to execute this query changing parameters' actual values in a combinatorial way, until a combination gives back at least one row or all combinations are unsuccessfully tried. For instance, I may have this sequence of values:
(V1,V2,V3); (V1,V2,""); (V1,"",V3); (V1,"","");
where V1, V2, V3 may by string values and V1 is always present, not null, and not blank in each combination.
A first strategy may be to prepare the statement, clear the parameters each time I execute the query, until stop condition is met.
I wonder if may be more efficient transform the query into
SELECT F1, F2, F3 FROM MYTABLE WHERE F1 = V1
and cycling over the cursor and, for each cursor row, verify if the returned tuple (F1,F2,F3) matches the combination (V1x,V2x,V3x). When at least 1 rows matches, or all combination are done, I'll exit iteration.
I wrote a Chess game that uses socket to connect to another computer, and allow player vs player and player vs computer game sessions.
However, there is a problem which I noticed.
When you get the IP address of the computer in which the program is running, you are not getting the computer's actual IP, you are getting the Router's IP.
Is there a way to get around this.
So the problem is that when I go to another computer, located in a different house or lets say from my school, the program cannot connect back to my home IP, because it uses the router's ip, not the computer's ip I am running the server program.
Is there a way to get the Computer's IP, not the router's ip when summoning or invoking the get IP address method from the socket class?
When I say that the socket class is acquiring the router's ip, well that's done without my interfering...I don't know why it does that, it is somehow recognizing the router and not the computer.
The thing is that the server program is written that any client program is able to connect to the home server.
But when I run the program from a different location other than the current home, the sockets don't connect because it is somehow recognizing the router's ip not the computer's ip.
I have an applet that uses JPanels to draw images in. I want to include actual jpgs now instead. The applet points to a .jar file. I want to use any number of images here, do I have to include them all in the jar file or is there another way to "point" to them (like html)?
Now lets say that I want to access a method 'addInterest()' that is in the 'SavingsAccount' class I would have to do: '((SavingsAccount)s).addInterest();'
The question I have is why do I have to cast 'b' to SavingsAccount? Isn't the actual object reference of 'b' already an instance of 'SavingsAccount' class? How does the 'BankAccount' affect the object itself? I'm really confused as to what class is truly getting instantiated and how BankAccount and SavingsAccount are both functioning to make the object 'b'.
So I created this line class and when I try to create Line object with parameters, I don't know how to pass the parameters properly. It has to return two points, so it should be like [(1,2),(5,12)].I tried different things likeLine l1=new Line(Point p1(1,2),Point p2(5,12)); and similar, but nothing worked.
package line; import java.awt.Point; public class Line { private Point p1; private Point p2;
public class TestClass { public TestClass(String k){System.out.println(k);} public static void main(String[] args) { try { hello(); } catch(Exception e){System.out.println(e);}
[Code] ....
Explain how to catch block act as constructor with parameter?
I have this JAVA written but I can't get the parameters for the if statements right.
import java.util.Scanner; public class myFirstJAVA { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Please enter command: "); String text = input.nextLine();
I'm trying to pass a parmeter to a jsf page from a servlet(i.e. associated with paypal adaptive api), but I keep getting the following error, even though the productType on ProductDetailsVO is a String.
INFO: WARNING: FacesMessage(s) have been enqueued, but may not have been displayed.
must be a number consisting of one or more digits.), detail=(j_idt2: '45;productType=Sport' must be a number between -2147483648 and 2147483647 Example: 9346)]
Calling JSF page contains:-
returnURL = new URL(new URL(request.getRequestURL().toString()),"pages/paypalpaymentapproved.xhtml?paypalID="+paypalID+";productType=Sport"); response.sendRedirect(returnURL.toString());
My understanding was I could override a method from the superclass, including with different parameters, but when I try to use super. it gives me an error the arguments have to match the superclass. But, if I do that it won't make any sense.
The first code below is the superclass. The issue I'm having is on the second code at lines 7 and 10. The ultimate goal is to make a new class where I'm able to display various packages with or without insurance.
public class Package { double shippingWeight; public char shippingMethod; final char air = 'A'; final char truck = 'T'; final char mail = 'M'; double shippingCost;
How to use a constructor with parameters where the user inputs the information? I'm doing a problem where I create a Delivery class that accepts arguments for the year, delivery number within the year, distance code (1 for short distance, 2 for long), and weight of package. The constructor is supposed to also determine the eight digit delivery number (combining the year and delivery number, like 20140054 for this year, package #54).
I know I'm not close to being done but I'm struck on the application with the constructor parameters. If I'm asking the user to input the information, does that mean I have to create a no argument constructor so it will compile? Right now it won't compile because it's asking for the parameters but I can't put them.
This is the class:
public class Delivery { int year; int delNum; double weight; int code;
[Code] .....
And the error is:
CreateDelivery.java:22: error: constructor Delivery in class Delivery cannot be applied to given types; Delivery firstDelivery = new Delivery(); ^ required: int,int,int,double found: no arguments reason: actual and formal argument lists differ in length 1 error
I have made a class here that has two methods. As you guys can notice, in my two methods that I made, I have listed some arguments in there with parameters. My question is that the variables im using in first method, can they be identical on my second method? Is this ok to do?
public class StudentScore { private int math; private int science; private int calc; private int history; private int pe;
So while experimenting with constructors, repeating constructors with the same parameters, and with different parameters. I got an output -explaining how I got it.
I made 2 classes. a "support class" (has all the info) and an "execute class" (executes info).
Support:
package inschool; public class Constructors { String video; public Constructors() { video = "frozen";
[Code] ....
Execute:
package inschool; //this is part of Constructors class public class App{ public static void main(String[] args){
[Code] ....
The Output:
the video name is frozen Second constructor running Constructor running! the video name is frozen
Output Explanation:
constructor call number 1 and 3 are the same (essentially) and both refer to the same constructor.
My Question: if both call #1 and #3 refer to the same constructor, why is the output for #1 "the video name is frozen"
while the output for #3 used both methods in the accessed constructor-with the resulting output as "Constructor running!" and "the video name is frozen"
I double checked the output-and this time made sure to scroll up ... its the same result
If I have a method that takes an ArrayList of a class called Piece and it uses the setPosition() method from Piece. It is changing the value of the array that I passed in, but I want the ArrayList to stay the same outside of the method. Is there any way I can change only the values on the inside of the method, but keep the same position values outside the method?Here is an example.
Piece class Java Code: public class Piece { private int xCoor; private int yCoor;
I want to have parameters that I use the "void" for, in other words it doesn't return anything.
class code { void go() { int TestStuff t = new TestStuff(); t.takeTwo(12,34) } void takeTwo (int x, int y) { int z = x + y; System.out.println("Total is:" + z); } }
I'm using JSF framework. I can let Netbeans to create the persistence unit and hardcodes connection parameters into the persistence.xml file or i can use resource tag in context.xml file or using another file like property file or class for holding connection parameters like username and password; what is the most secure way or expert way to use connection properties in my app or there is no difference?
What is the difference between Attributes and Parameters.that is difference between two methods request.getAttribute() and request.getParameter() and why we have this two methods?
I am using AXIS2 tomcat6 and jre1.6.0_07 and I created java project using net beans. but when I execute java2wsdl I am getting the following. Can you solve my problem? Also I would like to know what is the function of java2wsdl and its parameters?T
Now If I hit /Allen it sets init parameter for both servlet MyServlet and jsp JjspInit. I don`t have any servlet all I have is a web.xml and a jsp page. But accessing JjspInit.jsp directly gives null.
How hiting the url /Allen prints valu. This code is on JjspInit.jsp .
So does that mean that in web.xml I have registered this jsp as the target for /Allen. And one more question directly accessing the jsp page shows null it means init parameter haven`t been set.