I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
View RepliesI am currently taking a class in the field. My assignment is to generate 6 unique random numbers using a "Do While" expression. I might be mistaken but doesnt the inner loop execute first and then it works its way out? With this logic I believe my code should work but then again its not.
public class DoLottery {
public static void main (String args[]) {
int max= 10;
int random;
int random2;
int random3;
[code]...
I originally had output at the end but decided to comment it out to see if code would execute if I placed it every time the test was true.
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays;
public class countDigits {
public static void main(String[] args) {
//Create random generator and values
int numbers = (int)(Math.random() * 10);
int arrayCount = 1;
[Code] ....
and my results
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber {
public static void main(String[] args) {
long start = 5000000;
long end = 10000000;
System.out.println("List of prime numbers between " + start + " and " + end);
for (long i = start; i <= end; i++) {
if (isPrime(i)) {
System.out.println(i);
[Code] ....
I've just written a program that generates 100 numbers that range from 0 ~ 25 using arrays, the program calls another method that sorts the even numbers into a separate array and returns the array. I need it to display both arrays, however, when I run my program, the numbers of both arrays are mixed together, and I'm not sure how to separate them.
[ public class Array1
{
public static void main(String[] args)
{
int array [ ] = new int[100];
for (int i = 0; i < array.length; i++)
{
array[i] = (int) (Math.random() * 26);
[Code] .....
Create an integer array with 10 numbers, initialize the array to make sure there are both positive and negative integers. Write a program to generate two arrays out of the original array, one array with all positive numbers and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.
public class problem3 {
public static void main(String[]args){
int[] numbers = {1, 2, 3, 4, 5, -1, -2, -3, -4, -5};
for (int i = 0; i<numbers.length;){
if(i>0){
System.out.println(numbers);
}
else
System.out.println(numbers);
}
}
}
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){
System.out.println("Twenty random integers: ");
int max = 20; // max value for range
int min = 1; // min value for range
Random rand = new Random();
int[] all = new int[20];
[Code] ....
program that calculates and prints the sum of all numbers between two limits as the user types. Like if the user types 1 and 10 on the upper limit, it prints the following text: "1+2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55".
View Replies View RelatedThe assignment is to make a program that prints the number of prime numbers in a range. This is what i have so far. The output is a list of 2s. I created the for loop to cycle through the range of 17-53 and nested a while loop within to test each incident of the for loop to check for divisors starting with 2 until the modulus result is 0 resulting in a false for being a prime number. Then the loop should increment to the next i value. The last part is an if statement that i had intended to add counters to the k variable that would keep track of the number of prime numbers.
boolean isPrime = true;
int j = 2;
int k = 1;
for (int i = 17; i <= 53; i++){
{
while (i % j == 0){
isPrime = false;
[Code] .....
I found an exercise online to create a small program . I have this code that I have done so far:
import java.util.Scanner;
public class Test {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
long a = sc.nextLong(); long b = sc.nextLong();
long count = 0; // counter
for (long c = a; c <= b; c++) {
if (c % 2 == 0 || c % 3 == 0 || c % 5 == 0) {
count++;
}
}
System.out.println(count);
}
}
This program is suppose to give me the number of numbers which are dividable by either 2,3 or 5 in a range of a to b, where a<=b.
FOR EXAMPLE: a=5 b=8 ... output: 14 (since there are 14 numbers in between 5 and 8 which are dividable by either 2,3 or 5.)
It works great for all of the numbers except higher ones such as a=123456789012345678 b=876543210987654321. Here it doesn't give me any output. From what I know it is because the code is still running. But there must be a quicker way ...something that can modify the code so it finishes in the matter of seconds not hours. Something that will fasten the process of checking if the numbers are dividable...
I'm trying to put together a method that formats telelphone numbers, but there's a part of my code that not working. If I enter (305)912-5458 into the variable phoneNumb I get an index is out of range error. I added a lot of system out messages so that I can try to get an idea of why the code was crashing.
public static void main(String[] args) {
int intBegin = 0;
int intEnd = 1;
int length;
String charact;
StringBuilder numbuilder = new StringBuilder();
[Code] .....
The error message I'm getting is:
run:
The length is 13
intBegin is at 0
intEnd is at 1
index is at 0
Charcter ( was not inserted
[Code] ....
I have to ask the user to enter 4 whole numbers, and then the program will calculate:
> x numbers are positive and even
> x numbers are positive and odd
> x numbers are negative and even
> x numbers are negative and odd
but I have trouble with the conditions. How do I form the conditions to calculate this? My professor said I can do this with only four IFs (or ELSE IF). This is what I did:
import java.util.Scanner;
public class Calc{
public static void main(String [] args){
Scanner sc = new Scanner(System.in);
int pe = 0, po = 0, ne = 0, no = 0;
/* four variables for each result
pe - positive even
po - positive odd
ne - negative even
no - negative odd
[Code[ ....
Assume that vehicles are going through a two-way traffic intersection. There are three types of vehicles: car, motor bikes and trucks. Generate a series of 10 random integers, between 1 and 3,inclusive.The numbers represent the type of vehicle as stated below:
NumberVehicle Category
1Car
2Motor bikes
3Trucks
Write a program, using a for loop, to count how many vehicles going through the traffic intersection are cars, motor bikes and trucks. Then, the program should print out the numbers for each vehicle category. There is no user input for this program. How do i do it so they will add up the sum of each vehicle?
The answer should be something like
Number of cars = X
Number of motor bikes = Y
Number of Trucks = Z
but i'm getting
Total number of vehicle:
cars
motorbikes
motorbikes
cars
Trucks
Trucks
motorbikes
motorbikes
Trucks
cars
public static void main(String[] args) {
[code]....
I have a class project working on that is supposed to ask the user for input and create a random set of #'s in 4 rows. However it compiles but doenst run At one point Eclipse was telling me Scanner not closed?
import java.util.Scanner;
public class Matrixbuilder {
// input a number that is used to build a matrix. ie = 4 rows and 4 colums
//get the number
//build the matrix of random integers
//print the matrix
[code]...
Writing a Java program to find sum of numbers in a random string.
(Input=abc235^%$q!12&3 output=250)
If a number has - sign then u should consider it as a negative number.(Input=abc-12t%^&$dcf22 Output=10)
I've been trying to find the easiest way to write to generate a number which is between intervals of a arbitrary min and a max value.I've been searching for this but I don't find this particular thing.I've found that this combination works:
Java Code: int guess = rand.nextInt(max - (min - 1)) + min; mh_sh_highlight_all('java');
But I wonder, is this really the easiest way of writing it?
How do i make this merge sort take on random numbers in an array instead of hard coding the numbers
Integer [] a = {8, 2, 6, 7, 5, 4, 3, 1};
mergeSort(a);
System.out.println(Arrays.toString(a));
}
public static void mergeSort (Comparable [] a){
[code]....
For a project we have to "shuffle" items in an array using random numbers. We are supposed to generate random numbers and use those numbers to exchange array elements. But I am not sure what that means, "exchange array elements". Does that mean you generate 2 random numbers within the length of the array, and then switch the items at those locations in the array?
View Replies View RelatedI need to fix a program in which the user must get a three random numbers in a row. They have five chances. This is what i have so far:
public static void main(String[] args)throws IOException {
// TODO code application logic here
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int num1=(int)(Math.random()*(9-0));
int num2=(int)(Math.random()*(9-0));
int num3=(int)(Math.random()*(9-0));
[Code] ....
I am working on a bingo project and created random numbers between 1 and 75 to generate. I have it set up that it shows the number in a text box and changes the color on the board if the number is called. When I test the program, some numbers are highlighted in addition to the number called. I believe this is because extra numbers are being chosen, but not being noted in the text box. Below is my code for the unique random numbers.
int CallNo;
String CallerTxt = new String();
public void CallNum() {
Random RandCall = new Random();
//Generate Caller Random Number
CallNo = RandCall.nextInt(75)+1;
[Code] ....
I am writing a program that creates an array with random numbers. Then the user can choose what number of the array he/she wants to check the occurance of. This works fine, but the numbers generated seems very weird, only 2 of the 10 possible numbers are generated. 0 and one of the other 9 numbers, the 0 is always 10100 and the other one is always 101.
import java.util.Random;
import java.util.Scanner;
public class OppgaveC {
public static void sjekk() {
int randomArray[]=new int[101];
int countArray[]=new int[10];
Random rand = new Random();
[Code] ....
it also says i have a memory leak on my scanner, ow can i close this?
I'm trying to make the basis of a complex (pseudo)random password generator, but instead of 4 chars it is printing a 3 digit number.
public class PasswordGen {
public static void main (String[] args) {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();
int w = (int) ((Math.random() * 25 +1)); // pick a letter of the alphabet
[Code] ....
I am trying to assign random numbers to a deck of cards without repeating the numbers. What am I doing wrong?
package hokm;
import java.util.Random;
import java.util.Scanner;
public class Hokm
{
public static void main(String[] args) {
int [][] number=new int[52][2];
[Code] .....
I am doing a project to generate three names of fruits. When I take out my switch code the numbers generate randomly, but when I added the switch code back I kept getting three instances of "Bars" as if the random numbers all became 5.
public static void main(String[] args)
{
System.out.println("Enter the amount of money you would like to gamble.");
Scanner keyboard = new Scanner(System.in);
int num1;
int num2;
int num3;
int money;
money = keyboard.nextInt();
[code]...
I was inquiring about selecting random numbers from a Fibonacci array, the original post for which is here: Exiting a 'for' Loop Early. I have managed to achieve this with the following code:
System.out.println("Random numbers from the Fibonacci array");
for(int i = 0; i < limit; i++) //Limit is an 'int' of 15 & is set as the length of the Fib. array. I'm calling it for the Random array, too!!
{
Random dice = new Random();
int randomIndex = dice.nextInt(array.length); //The Fib. array was simply called 'array'!!
if (array[randomIndex] < 100)
{
System.out.print(array[randomIndex]+ " ");
}
}
When the code prints I get a random set of numbers which occur in the Fibonacci sequence preceding it. However, the actual length of this Random array also changes each time, and never more than the limit of 15 specified in the 'for' loop. What I want to try and do is print the Random array with a specific length each time. I've tried changing the conditional statement of the 'for' loop in different ways to set the Random array's length, but had no luck.
Java Code:
import java.util.ArrayList;
import java.util.Random;
public class NumSorting {
public static int numOfComps = 0,
numOfSwaps = 0;
public static void main(String[] args)
[Code] ....
What is wrong with my code in this sorting program? It won't copy the random generated numbers to the sort method. How to get the random generated numbers to copy to the sort method. Below is what the program is displaying.
Original order : 3 2 5 4 1
Selection Sort
Original order:
[I@7a84e4
Number of comps = 10
Number of swaps = 0
Sorted order : 0 0 0 0 0