I've been trying to find the easiest way to write to generate a number which is between intervals of a arbitrary min and a max value.I've been searching for this but I don't find this particular thing.I've found that this combination works:
Java Code: int guess = rand.nextInt(max - (min - 1)) + min; mh_sh_highlight_all('java');
But I wonder, is this really the easiest way of writing it?
I am working on a bingo project and created random numbers between 1 and 75 to generate. I have it set up that it shows the number in a text box and changes the color on the board if the number is called. When I test the program, some numbers are highlighted in addition to the number called. I believe this is because extra numbers are being chosen, but not being noted in the text box. Below is my code for the unique random numbers.
int CallNo;
String CallerTxt = new String();
public void CallNum() {
Random RandCall = new Random();
//Generate Caller Random Number
CallNo = RandCall.nextInt(75)+1;
[Code] ....
I don't want to use an array. I do not know of a function built into Java to allow me to do this.
View Replies View RelatedI have been set this task, which is supposed to make me code using string arrays. The idea is to generate random sentences.This is what i have been able to do so far :
package usingarraysagain;
public class sentences {
public static void main (String[] args){
String[] NOUNS = { "lizards",
"Nikola Tesla",
[code]....
I am very new to programming. This is for a college assignment. It says in the brief of the assignment that we will need to convert Math.random to output a random number between 1-1000. How can I do this?
View Replies View RelatedFor part of my program, I am trying to ask the user for input on generating a number of random characters. I have already done this with integers and doubles, how would I do this for characters using ASCII values? Would I use the same format as I did for generating integers (Shown in code)?
import java.util.Random;
import java.util.Scanner;
public class NewNumberCharacter {
public static void main(String[] args) {
// Create a Scanner
Scanner input = new Scanner(System.in);
[code]....
My project is writing a program that generates a series of numbers to appear like a social security number (XXX-XX-XXXX). My code runs.. But any number below 10 it just shows one number (XXX-X-XXXX). What do I need to enter in to my code so that if the number is <10 it will show (00,01,02,03....)?
Java Code:
import java.util.Random;
public class IDnumber
{
public static void main (String[] args) {
Random generator = new Random()
int num1 = (generator.nextInt(7) + 1) * 100 + (generator.nextInt(8) * 10) + generator.nextInt(8);
int num2 = generator.nextInt(74);
int num3 = generator.nextInt(10000);
String IDnumber = num1 + "-" + num2 + "-" + num3;
System.out.println(IDnumber);
}
} mh_sh_highlight_all('java');
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){
System.out.println("Twenty random integers: ");
int max = 20; // max value for range
int min = 1; // min value for range
Random rand = new Random();
int[] all = new int[20];
[Code] ....
I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
View Replies View RelatedAssume that vehicles are going through a two-way traffic intersection. There are three types of vehicles: car, motor bikes and trucks. Generate a series of 10 random integers, between 1 and 3,inclusive.The numbers represent the type of vehicle as stated below:
NumberVehicle Category
1Car
2Motor bikes
3Trucks
Write a program, using a for loop, to count how many vehicles going through the traffic intersection are cars, motor bikes and trucks. Then, the program should print out the numbers for each vehicle category. There is no user input for this program. How do i do it so they will add up the sum of each vehicle?
The answer should be something like
Number of cars = X
Number of motor bikes = Y
Number of Trucks = Z
but i'm getting
Total number of vehicle:
cars
motorbikes
motorbikes
cars
Trucks
Trucks
motorbikes
motorbikes
Trucks
cars
public static void main(String[] args) {
[code]....
I have a class project working on that is supposed to ask the user for input and create a random set of #'s in 4 rows. However it compiles but doenst run At one point Eclipse was telling me Scanner not closed?
import java.util.Scanner;
public class Matrixbuilder {
// input a number that is used to build a matrix. ie = 4 rows and 4 colums
//get the number
//build the matrix of random integers
//print the matrix
[code]...
I am currently taking a class in the field. My assignment is to generate 6 unique random numbers using a "Do While" expression. I might be mistaken but doesnt the inner loop execute first and then it works its way out? With this logic I believe my code should work but then again its not.
public class DoLottery {
public static void main (String args[]) {
int max= 10;
int random;
int random2;
int random3;
[code]...
I originally had output at the end but decided to comment it out to see if code would execute if I placed it every time the test was true.
Writing a Java program to find sum of numbers in a random string.
(Input=abc235^%$q!12&3 output=250)
If a number has - sign then u should consider it as a negative number.(Input=abc-12t%^&$dcf22 Output=10)
How do i make this merge sort take on random numbers in an array instead of hard coding the numbers
Integer [] a = {8, 2, 6, 7, 5, 4, 3, 1};
mergeSort(a);
System.out.println(Arrays.toString(a));
}
public static void mergeSort (Comparable [] a){
[code]....
For a project we have to "shuffle" items in an array using random numbers. We are supposed to generate random numbers and use those numbers to exchange array elements. But I am not sure what that means, "exchange array elements". Does that mean you generate 2 random numbers within the length of the array, and then switch the items at those locations in the array?
View Replies View RelatedI need to fix a program in which the user must get a three random numbers in a row. They have five chances. This is what i have so far:
public static void main(String[] args)throws IOException {
// TODO code application logic here
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int num1=(int)(Math.random()*(9-0));
int num2=(int)(Math.random()*(9-0));
int num3=(int)(Math.random()*(9-0));
[Code] ....
I am writing a program that creates an array with random numbers. Then the user can choose what number of the array he/she wants to check the occurance of. This works fine, but the numbers generated seems very weird, only 2 of the 10 possible numbers are generated. 0 and one of the other 9 numbers, the 0 is always 10100 and the other one is always 101.
import java.util.Random;
import java.util.Scanner;
public class OppgaveC {
public static void sjekk() {
int randomArray[]=new int[101];
int countArray[]=new int[10];
Random rand = new Random();
[Code] ....
it also says i have a memory leak on my scanner, ow can i close this?
I am trying to make a program that get input value 1-200 from user. However I would like to make the program to show warning if the input number is not within the range of 1-200. In the end I would like to show the amount of number according to its interval (i.e less 50, 51-100 and so on) ....
import java.util.Scanner;
class test {
public static void main (String[] args) {
int number[]= new int[5];
int number2[]= new int[5];
int a=0,b=0,c=0,d=0,i=0;
[Code] .....
I'm trying to make the basis of a complex (pseudo)random password generator, but instead of 4 chars it is printing a 3 digit number.
public class PasswordGen {
public static void main (String[] args) {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();
int w = (int) ((Math.random() * 25 +1)); // pick a letter of the alphabet
[Code] ....
I am trying to assign random numbers to a deck of cards without repeating the numbers. What am I doing wrong?
package hokm;
import java.util.Random;
import java.util.Scanner;
public class Hokm
{
public static void main(String[] args) {
int [][] number=new int[52][2];
[Code] .....
I am doing a project to generate three names of fruits. When I take out my switch code the numbers generate randomly, but when I added the switch code back I kept getting three instances of "Bars" as if the random numbers all became 5.
public static void main(String[] args)
{
System.out.println("Enter the amount of money you would like to gamble.");
Scanner keyboard = new Scanner(System.in);
int num1;
int num2;
int num3;
int money;
money = keyboard.nextInt();
[code]...
public Map<Integer , String> Timeinterval(int value) {
int i = 1440/value ;
Map<Integer, String> timeInt = new HashMap<Integer, String>() ;
DateTimeFormatter formatter = null ;
for(int a=0 ; a< i ; a++) {
[Code] .....
The argument value gets it value from jsp at rumtime
The moment the control reaches at :- formatter = DateTimeFormat.forPattern("HH:mm");
it could not go beyond this . I executed this part
DateTimeFormat.forPattern("HH:mm"); by pressing cntrl+shift+I
and got this message :- could not resolve type: org.joda.time.format.DateTimeFormat
Basically what I want to do is increment time for eg: if time is 09:00 and I want to increment it by 30 then it should become 09:30 and this goes on till the time loop condition is satisfied, when i researched on net, I found out that Joda library is easirer to work with for such tasks.
I was inquiring about selecting random numbers from a Fibonacci array, the original post for which is here: Exiting a 'for' Loop Early. I have managed to achieve this with the following code:
System.out.println("Random numbers from the Fibonacci array");
for(int i = 0; i < limit; i++) //Limit is an 'int' of 15 & is set as the length of the Fib. array. I'm calling it for the Random array, too!!
{
Random dice = new Random();
int randomIndex = dice.nextInt(array.length); //The Fib. array was simply called 'array'!!
if (array[randomIndex] < 100)
{
System.out.print(array[randomIndex]+ " ");
}
}
When the code prints I get a random set of numbers which occur in the Fibonacci sequence preceding it. However, the actual length of this Random array also changes each time, and never more than the limit of 15 specified in the 'for' loop. What I want to try and do is print the Random array with a specific length each time. I've tried changing the conditional statement of the 'for' loop in different ways to set the Random array's length, but had no luck.
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays;
public class countDigits {
public static void main(String[] args) {
//Create random generator and values
int numbers = (int)(Math.random() * 10);
int arrayCount = 1;
[Code] ....
and my results
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
Java Code:
import java.util.ArrayList;
import java.util.Random;
public class NumSorting {
public static int numOfComps = 0,
numOfSwaps = 0;
public static void main(String[] args)
[Code] ....
What is wrong with my code in this sorting program? It won't copy the random generated numbers to the sort method. How to get the random generated numbers to copy to the sort method. Below is what the program is displaying.
Original order : 3 2 5 4 1
Selection Sort
Original order:
[I@7a84e4
Number of comps = 10
Number of swaps = 0
Sorted order : 0 0 0 0 0
Is my code right for this pseudocode:
<Declaration of the array for storing random integers and other necessary variables and / or constants. >
private int numbers;
private int max;
private int[] integer;
private Random generator;
public integer ( int n, int m )
[code]....
I need to create a program that draws random numbers and stores them in an array. How many numbers to be drawn is dependent on the array length, which is a parameter in the class constructor. (The entire array to be filled!) The program shall, however, just save the figures are not drawn already. (Ie, the array must contain only one instance of each numeral.) All figures drawn should be in the range of 100 to 1000, both limits included. These limits are defined as named constants. When all the numbers are generated and stored in the array, the program should find the largest, smallest and average value of the numbers in the array. In addition, it should find the value closest gjennomnstittetsverdien.