Getting Number Format Exception When Trying To Use ParseInt
Feb 17, 2014
The problem occurs at the second to last line of text in this code.
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package reversing_digits;
import java.util.Scanner;
public class Reversing_digits {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
I'm doing this project in JSP.net, with html. and in one of the web pages, what I'm doing is that, a person is transferring an amount to someone else, and if the transfer amount is more than the account balance, then he cannot transfer. else, save details in a table.
Here's the code I've used
<% String t1=request.getParameter("text1"); String t2=request.getParameter("text2"); java.util.Date date1 = new java.util.Date(); SimpleDateFormat ft = new SimpleDateFormat ("dd/MM/yyyy"); int tamt = Integer.parseInt(t2); int bamt = 0;
[Code] .....
But when i enter the fields and click the submit button in the form, to save it in the table, i get the error:
Everything is working great except for my back button at line 172. It works good but if I try to click the "insert" button again. It gives me the java.lang.NumberFormatException error. Other than that it works fine, the "insert" button still works.
package userDatabasePack;
import java.sql.*; import javax.swing.*; import java.awt.*; import java.awt.event.*; public class Database{ //Variables private String username2, insertUser, insertPassword; private int insertUserId;
I am working on a program that will allow a user to input grades for a class of four students who have taken two tests. Based on the grades entered, the program will calculate the averages of the two tests for each student and display it along with their respected letter grades.
Now I can get the program to compile successfully, but after inputting the grades in, I get the error message saying that it cannot format given object as a number. I am using 4 arrays to execute this program and maybe that's why I'm having the trouble? I'm not sure because I am still fairly new at this stuff and can't sen to resolve it.
I was having problems for a while and then finally got excited when I got it to compile without any errors and now I'm getting an error inside my program. All I need to do is format the numbers of the grades into something like: 000, and each of the averages as 000.0. I understand how to do it because I have done it in another program I've done in the past. I just don't know how to fix this error that is coming up.
here is my code:
import java.util.Scanner; import java.text.DecimalFormat; public class TestAverage { /** * A program that will store and process 2 test scores for a class of 4 students. * The program will prompt for the test scores as shown above in the sample run. * After all the data is entered,the program will display the score for test 1, test 2 . * The average of the 2 tests and the letter grade for the class for each student in a tabular format. * *
I am having some issues with errors. Here is my code...
import java.io.*; import java.util.Scanner; public class StormChaser { public static void main(String[] args) { // Constants final int MAX_STORMS = 319;
[Code] .....
I am having issues with these error messages.... I have tried a couple of different things with each error but haven't been able to figure it out.
Exception in thread "main" java.util.UnknownFormatConversionException: Conversion = '1' at java.util.Formatter.checkText(Unknown Source) at java.util.Formatter.parse(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.lang.String.format(Unknown Source) at Storm.toString(Storm.java:98) at StormChaser.DisplayStorms(StormChaser.java:141) at StormChaser.main(StormChaser.java:53)
So I have to write a java program that converts hexadecimals to decimals without using the whole "integer.parseInt(AB1, 16)" method. I tried looking up how to do this but every forum/site I went to used this same method.
This one is working if i set value in fmt but what i want to happen is when i enter a number in textbox it will be fommated on the format that i want, so i think i need to an of og text and set it into value of fmt? <y plan is when I enter a number in textbox it will automatically formatted ....
I am writing a program using a given test drive... I am supposed to write two classes according to the test drive. The calculated correct answer should be 115.50 but i keep getting 115.52 instead and i just can't figure out what i'm doing wrong.
Here is the test drive code:
import java.text.NumberFormat; public class FinalTester { public static void main(String[] args) { double avgPurchase; Order[] lastYear = new Order[4];
I am working with a program I wrote for class. I got it to compile and do what I want, But I was wondering how I can format my methods to to display a decimal with 1-2 decimal places. Would I create a method in my NumberAnalysis class to do it for me? Or would I declare an instance of the DecimalFormat class in my main method?
import java.util.Scanner; //Needed for Scanner Class import java.io.*; //Need for File and IOException import java.text.DecimalFormat; public class Ex8_11 { public static void main(String[] args) throws IOException{ { DecimalFormat decformatter = new DecimalFormat("#0.00");
[Code] .....
This is my output:
Lowest Number: 1.09 Highest Number: 82.76 Total Number: 367.89000000000004 Total Average Number: 30.657500000000002
Think I just solved the answer to my own question, I did it by declaring double variables in my main method and called the methods and instantiated the variables into the methods... Is there a better way to do this?
package lesson4.skowronek; import java.util.Scanner; //Needed for Scanner Class import java.io.*; //Need for File and IOException import java.text.DecimalFormat; public class Ex8_11 { public static void main(String[] args) throws IOException{
In my cs class, we have to write a program that throws an exception if the user enters a negative number, the program should prompt the user to enter only positive numbers and then let them retype the number. But everytime I throw an exception, my program gets suspended.
What am I doing wrong, or is there no way to continue a program if an exception is thrown? Does the program automatically get suspended when an exception is thrown?
try{ do { N = kb.nextDouble(); if(N<0) { throw new NegativeArraySizeException(); } else j++; } while(j==0); fill.size(N); } catch(NegativeArraySizeException e) { System.out.println("The number you entered must be positive. Please try again."); }
I was giving a quick skim to some tutorials on the internet where I have found the exception that is handled is also declared in the throws clause of the method wrapping the try-catch block. For a code representation consider the following:
public void methodName() throws IOException { try { ... } catch (IOException ex) { .... TODO handle exception }
Right, so I got this program. It takes input from the user and assigns it to fields on an object. But, it's meant to check the users input. If the user enters bad input, it's supposed to throw this exception. For each of these exceptions, theres a class specifically for it.
public class PayrollDemo { public static void main(String[] args) { Payroll pr = new Payroll ("Test Name", 234); System.out.println("Current Employee Information. "); System.out.println("Name: " + pr.getName()); System.out.println("ID: " + pr.getID()); System.out.println("Hourly Pay Rate: " + pr.getHourlyPayRate());
[Code] ....
And this is the exception class.
public class InvalidNameException extends Exception { /** No-arg constructor */ public InvalidNameException() { super("Invalid name"); } }
PayrollDemo.java:43: error: cannot find symbol InvalidNameException.InvalidNameException(); ^ symbol: method InvalidNameException() location: class InvalidNameException 1 error
It's just meant to tell the user that they entered an invalid value, which would mean if they entered an empty string instead of a name.
I have a beginning Java Program I have been working on that creates a number guessing program where the computer guesses a number that the user is thinking of within a certain range. I so far have the program below, but need getting rid of a few kinks/ adding features.
-First, I need to set it up so that the user will be prompted and give a range. It should run and produce something like this:
Welcome to this first-ever mind-guessing program!
Please pick a range (higher than 1 and no larger than 50): 32
You will choose a number between 1 and 32... and I will try to guess it.
With each of my guess, you will tell me whether I am too high (h or H), too low (l or L), match (m or M), or you want to quit (q or Q). My objective is to find the number using as few guesses as possible.
-Second, the game is supposed to give up and restart after failing the five, guesses, but for some reason, after it fails the fifth time, it prompts a fifth guess once again instead, then restarts after- I need to prevent this, so that it should look something like this:
My fourth guess is 17: h My guess is too high?
My fifth guess is 16: h *** I am unlucky this round. I give up.
Let's play!
My first guess is 10: etc..
import java.util.*; import java.lang.Math; public class numguessprac1 { // Declaring variables public static String input; public static int quit; public static int guess; public static int wins;
So I am currently writing my first assignment and have run into problems with my coding. The task was to have someone enter a 5 digit number and in return, I list each number on their respective lines. We also must create an error if a number other than 5 digits was entered. My problem is that when they enter a 1 or 2,3,4,6,7,8 digit number.. the error message occurs along with the rest of the messages (listing the numbers, etc). I want the program to end (or even re-ask to enter the numbers) if they incorrectly enter the data.
trying to write a program that takes a user inputted number and converts it to a binary number.
Here's what I have:
package com.java2novice.algos; import java.util.Scanner; public class Converter { static Scanner console = new Scanner(System.in); public void printBinaryFormat(int number){ int binary = console.nextInt();
In a forest, there are some bamboo trees .The length of each tree get doubled during winter and increases by one unit in summer , write a Java program to calculate the total length of n number of bamboo trees in M number of seasons. The season always starts with winter.
import java.util.Scanner; public class Tree { public static void main(String args[]) { int length; int season;
We have triangle made of blocks. The topmost row has 1 block, the next row down has 2 blocks, the next row has 3 blocks, and so on. Compute recursively (no loops or multiplication) the total number of blocks in such a triangle with the given number of rows.
I am trying to create a method that prints the square root of a number up to a certain number. It needs to take a single int parameter for example "n" , and then print all of the (positive) even perfect squares less than n, each on a separate line. I want the method to be called something like this:
public void Squares(int n) { }
I need the output to look something like this:
Example: if n = 40, your code should print
4 16 36
So I have been working for a few hours now and am really stuck.
This is what I have so far:
int count = 0; int n = 4; int max = n; while(count < max) { System.out.println(n); n = n * n; count++;
I am working on a little nothing project, but I wanted to create a random number generator for a silly game where the user guesses the number.I have used google, but they are using LOG statements, what it does.
