I'm trying to flip an image horizontally. However because when I flip the images they're offset by a bit, I added "-height" to offset the change in position. Unfortunately, it doesn't seem to be working 100% of the time; some images are adjusted to their correct position but some are not.I'm using this line to flip an image: Java Code: g.drawImage(castle, x, y - height, -width, height, null); mh_sh_highlight_all('java');
I do not understand how I can alter my paintComponent. Is it possible to set my paintComponent to an Image variable, and then flip the image with Math.Radius?
I'm using JavaKara (a graphic Java software to learn coding) on my classes at the moment and we're asked to transform something like this:
In the inverse, where you can see clovers there must not be any and where there aren't you must plant them. PLUS YOU MUST SWITCH THE FIGURE HORIZONTALLY.
This is the result i should obtain:
public class InvertiECapovolgi extends JavaKaraProgram { public void myProgram() { boolean arrayquadrifogli[][] = new boolean[world.getSizeY()][world.getSizeX()]; //[rows][clumns]-->[Y axis][X axis] in kara for (int y = 0; y < arrayquadrifogli.length; y++){ // My Ladybug starts to run through the whole grid
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How to switch everything horizontally!
This is my result:
My ultimate question is, how do i have to edit the second loop, and why, to obtain the horizontally reversed result i'm supposed to obtain?
I'm new to java and I need changing the direction of these balls from a horizontal axis to a vertical axis bouncing in the center. I've tried reversing the integers but there seems to be something i've missed.
package package_bouncingball; import java.applet.*; import java.awt.*; import javax.swing.*; import javax.swing.event.*; public class Class_bouncingball extends Applet implements Runnable { int x_pos1 = 150;
What's a simple way to flip an Image along the vertical or horizontal? I've searched high and low and surprised to find that I can't find something short and compact.
I am working on writing a desktop based email client using swing. First some specifics: I need to show emails in a (dynamically updatable) vertical list. Each item in this vertical list would represent an email showing: (a) the subject, (b) a photo of the sender that I have locally available & a couple of buttons. So, I plan to create a JPanel containing a JLabel to show the Subject, The photo inside a JLabel & JButtons. I have the layout of this panel done and is not a problem.
My problem is with stacking all these JPanels (each representing an email) and showing them on the UI as a list. I am not sure of any way to do this. Moreover, when a new email is received, it has to be displayed at the top of the list (not at the bottom).
Specifically, I need a good way of displaying a vertical list of JPanels & be able to add new JPanels at the top of the list.
I have written a drum machine using Java. Into said drum machine I list all 47 available MIDI drums. The instrument list is placed into a JPanel, along with a gridArray of checkboxes. The JPanel is then in turn added to a scrollpane. I have listed the MIDI drums in order of 'ground-up'. For example, the bass drum is generally at the bottom of most drum kits, so it is at the bottom of my MIDI drums list. Next up would be the snare, followed by the cymbals, and then by all the specialty percussives. Since most beats are started from the 'ground-up', laying to foundation, so to speak, I want the scroll bar of the scrollpane which houses the JPanel, which in turn houses the instrument list and the beat checkboxes, to be positioned, upon opening, at the bottom of the scroll pane. Nothing I have tried works. It always positions the slider somewhere in the middle of the scroll track. Below is a listing of just the buildGUI portion of the code, all the MIDI functionality has been removed to keep the size of the post to this forum down.
In the following piece of code Iam confused as to where the InputMismatchException in the catch block is thrown on the first place? Is the InputMismatchException thrown automatically with declaring to throw the exception?
import java.util.*;
public class InputMismatchExceptionDemo { public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean continueInput = true;
Is it a best practice to return from try block or place return statement after try-catch when we intend to return a value from a method(* Catch block is being also used to rethrow the exception)??
I'm doing project in area of "Cryptography and Network security". I'm having a file with binary Unicode (mean file contain Unicode value of corresponding data (text file)), want to divide that as blocks with the size of 144bits.
Regarding return statements within methods. So I have a method containing try and catch block (as required) and much like when you have an if else statement... I noted you have to return an object for both the try and catch blocks. Now in my case my method should return a List object.
The way I have tried to overcome this:
- I've initialised a List object to null as an attribute of the class I'm working in. - Therefore in the catch block would just simply return the null List object, where as the try block would return the non-empty List (which is what I want). - I then just test to see if the List != null, when the method is invoked... and that is that.
However the method always seems to return null (when it shouldn't).
Modify the program in Assign4 to synchronize access to the instance variable, balance. Save the program as SyncBank.java. Because balance is a double and not an object, it cannot be used as the monitor. Use synchronized methods or synchronized blocks of code as appropriate. Simultaneously test two threads as was done in Assign4. Because the threads can complete too quickly to determine if they are interfering with each other, delay the adding of a deposit by inserting the following code within the synchronized block or method:
It's always good to keep functions smaller and focused on one behavior. So is this safe:
Java Code:
public Unit findBySql(int id){ Unit unit=null; DbConnectionPool dbPool = DbConnectionPool.getInstance(); HashMap<String, String> conditions = new HashMap<String, String>(); conditions.put("id", String.valueOf(id)); String sql = buildSelect("units", "*", conditions);
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As you can see a pass ResultSet to a function which populates the item. But I also make sure that the ResultSet that the passed object is pointing to is closed, so it doesn't leak resources.
I am developing a Client/Server java application, where CSMessage is sent through socket.CSMessage has some data like String type and HashMap<String, String> type.the Client send message:
private ObjectInputStream in; private ObjectOutputStream out; out = new ObjectOutputStream(socket.getOutputStream()); in = new ObjectInputStream(socket.getInputStream());
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When this happen, the only way to make the system to work is to kill the process and restart it, that's bad!
My current lesson in Java is about ArrayLists and I'm having a tough time to understand this bit of code: This exercise is concerned with the problem of deleting a block of items from an ArrayList.
public static void deleteBlock( ArrayList<String> strings, int n ) { for ( int i = 0; i < n; i++ ) { if ( strings.size() > 0 ) strings.remove( i );
So method invia call the method popolaScompiute, inside popolaScompiute there is an iteraction through some id and for some id can occur an error; what i want is the getting the value of id in the first method invia, using the block try/catch. Is there a way to accomplish this?
I can't figure out why my code doesn't work. My task is to replace for example ä=>ae, using this method String.charAt(int index). So here is my code:
public class pich { public static void main(String[] args) { String text = "Die süße Hündin Leica läuft in die Höhle des fülligen Bären "+ "Iliyan (ein Übergrößenträger), der sie zum Teekränzchen eingeladen hat."+ " An ihrem Öhrchen trägt sie modisch eine Ähre."; String textOhneUmlaute = "";
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when I launch my code I get the same String and nothing has changed
public class hello { /** * @param args */ public static void main(String[] args) { int s = new hello().h(); System.out.println(s); } public int h(){ try{ int g = 10/0;
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the output is 7. how the flow is working. i understand that there is a divide by zero exception after which the control goes to catch. what about the return statement in catch . why is it overridden by finally..........