Hexadecimal Java Base Converter

Apr 28, 2015

I am writing a program that converts any base 10 number to bases 2-16. I have the code for everything up through hexadecimal conversion, for that requires the use of letters. I understand an array list may be of use however I do not understand how to use that in this code. Below is what I have so far

import java.util.*;
import java.io.*;
public class convertBase
{
public static void main(String[] args)
{
int base;
int number;
String newNum;
 
[code].....

I commented out the hexadecimal portions.How would I go about coding for letters?

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Semantic Error In Hexadecimal Converter

Jun 29, 2014

I'm sure the solution is simple, but I cannot find it.

/*reads a hexadecimal number input by the user and gives the corresponding base-10 value
*/

public class HexConverter
{
static int i; //used to keep place in the hexadecimal sequence given by user
public static void main(String[] args) {
//declaration of variables
String hexgiven; //the hexadecimal sequence given by user

[Code] .....

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Oct 9, 2014

So i'm writing a for loop to convert any number entered to base 10 with any base provided as well. My code does not work because I need a way to reverse the code order, so the new number is printed correctly with the given base. My code so far:

public static void main (String[] args) {
Scanner kb = new Scanner (System.in);
System.out.print("Enter a number :: ");
int numOriginal = kb.nextInt();
System.out.print("Enter a base :: ");
int base = kb.nextInt();

[Code] .....

newBase has a problem with how it calculates the new number, looking for correct newBase code for conversion?

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Program To Convert A Base 10 Integer To Any Base 2 - 16

May 5, 2013

I am writing a program to convert a base 10 integer to any base 2-16. Here are the terms:"The method is to convert the decimal value the user selected into whatever base the user selected and print the converted value one place value at a time by using an index into an array of characters 0-9 amd A-F that is initialized to contain those characters.In the method you will find the largest place value (i.e. power of the base) that will divide into the decimal number.

Then you can set up a loop that will operate from that power down to and including the 0th power to determine how many times each place value goes into the decimal number. Using the loop counter, index into the character array to print the character that corresponds to the quotient number and then subtract the product of the place value and the quotient from the decimal number. With the power (loop index) decreased, repeat until you finish the 0th place value. Here's what I have so far:

import java.io.*;
import java.util.Scanner;
public class ConvertIt
{//start program
public static void main(String[] args)
{//start main
Scanner input = new Scanner(System.in);
System.out.println("Enter a positive integer from 0 to 10000.");
int number = input.nextInt();

[code]...

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Mar 11, 2014

This code is for a GUI Java program that is supposed to convert back and fourth between two numbering systems. For example, binary to decimal or decimal to binary. I have created methods for some of the conversions however, I could successfully develop a method to convert from hex to binary. If you plan to run it to see what happens to the current method that I made please know that in the GUI the north end from left to right is as follows.

The textfield is for user entry of any type of data. The first combobox is for the user specifying to the program what type of data he or she entered. The second combobox is for the user to choose what he wants that data converted to. The button is to convert it. The south side has a textarea that gives out the results. Please note that only some of the conversions work so far. There are comments in the code to label which methods do what converisons. Need to find a method that will convert from hex to binary, what is wrong with the current method.
 
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.FlowLayout;
import java.awt.Rectangle;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
 
[Code] .....

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String run = "c:
s34bil.exe
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how to write the toString to convert this output :

List:
side: 14 color: java.awt.Color[r=0,g=0,b=255]
side: 18 color: java.awt.Color[r=255,g=0,b=0]
side: 12 color: java.awt.Color[r=255,g=255,b=0]
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side: 16 color: java.awt.Color[r=0,g=255,b=0]
side: 10 color: java.awt.Color[r=255,g=200,b=0]
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to this output

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side:18 color:#FF0000
side:12 color:#FFFF00
side:18 color:#FF0000
side:16 color:#00FF00
side:10 color:#FFC800
side:10 color:#FFC800

here is how i have it written now

public String toString()
{
return "side: " + side + " color: " + color + "";
}

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Here is my code:

public class dec2hex
{
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[Code] ....

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import java.util.Scanner;
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[Code] ....

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[code]...

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Here is my code:

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This program requires knowledge of manipulation of Java String objects and methods. It also requires knowledge of Number System Conversions.

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[code]....

90-Point Version Specifics: The 90-point version requires that you write both the fromHexToBin and fromBinToDec methods.

90-Point Version Output

95-Point Version Specifics {The 95-point version requires everything from the 90-point version and adds the fromBinToHex method. For this version, you may assume that the binary number will have a multiple of 4 bits.

95-Point Version Output

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100-Point Version Output

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105-Point Version Output

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XML Code: Url...

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[Code] .....

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[Code] .....

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