Histogram That Allows To Visually Inspect Frequency Distribution Of A Set Of Values

Apr 4, 2014

Design and implement an application that creates a histogram that allows you to visually inspect the frequency distribution of a set of values . The program should read in an arbitrary number of integers that are in the range 1 to 100 inclusive; then produce a chart similar to the one below that indicates how many input values fell in the range 1 to 10, 11 to 20, and so on. Print one asterisk for each value entered.

No input prompt

Terminate input by typing CTRL/Z (two keys typed at the same time) on a separate input line (use CTRL/D on Linux/UNIX systems)

Use hasNextInt() to terminate your input

Format as below (slightly different from the text example)

Z:dbraffittWeek10> javac Histogram.java

Z:dbraffittWeek10> java Histogram

10 10 10 10 10 20 20 20 20 20 20

20 25 35 45 55 65 75 85 95

ctrl/z

1 - 10 | *****

11 - 20 | *******

21 - 30 | *

31 - 40 | *

41 - 50 | *

51 - 60 | *

61 - 70 | *

71 - 80 | *

81 - 90 | *

91 - 100 | *

What I can not figure out is how to use hasNextInt() to terminate the loop. How to not have an input prompt. How to use ctrl z to terminate the input. Or to make it where it doesn't involve range values like -1.

Java Code:

import java.util.Scanner;
public class Histogram
{
public static void main (String[] args)
{
Scanner scan = new Scanner (System.in);
int [] nums = new int[101];

[Code] ....

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Create Histogram That Allow To Visually Inspect Frequency Distribution Of A Set Of Values

Apr 4, 2014

Design and implement an application that creates a histogram that allows you to visually inspect the frequency distribution of a set of values . The program should read in an arbitrary number of integers that are in the range 1 to 100 inclusive; then produce a chart similar to the one below that indicates how many input values fell in the range 1 to 10, 11 to 20, and so on. Print one asterisk for each value entered.

No input prompt
Terminate input by typing CTRL/Z (two keys typed at the same time) on a separate input line (use CTRL/D on Linux/UNIX systems)
Use hasNextInt() to terminate your input
Format as below (slightly different from the text example)
Z:dbraffittWeek10> javac Histogram.java
Z:dbraffittWeek10> java Histogram

[Code] ....

What I can not figure out is how to use hasNextInt() to terminate the loop. How to not have an input prompt. How to use ctrl z to terminate the input. Or to make it where it doesn't involve range values like -1.

import java.util.Scanner;
public class Histogram {
public static void main (String[] args) {
Scanner scan = new Scanner (System.in);
int [] nums = new int[101];
 
[Code] .....

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I figured I should give a little background on the program, this program is reading from a text file of names and decade numbers(for each name) and storing each line into an object array. From there, there are menus and based on the users decision they can type a name and get a histogram, compare names with histograms, ect. Below this main method, I have provided the area where I have gotten the null pointer exception.

Here is the main method for the Client "nameApp"

Also excuse the formatting and curly braces for now!

public class NameApp{

private static boolean validInput;
private static boolean done = false;
private static boolean validDecade;
private static boolean validName;

[Code] ....

And here is the method in the same Client that is getting the null pointer exception:

The pointer exception is on line 6 which is:

if (nameInput.equalsIgnoreCase(list[i].getName())){
private static int checkListArray(String nameInput, Name[] list){
int nameLocation = -1;
int listLength = list.length;

[Code] ....

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I prompted the user to enter inches of rainfall for seven days and stored them in an array. Now, I am trying to display a histogram of this data using a nested loop, but for each inch, I have to display a * like this:

Rainfall Histogram:
****
***
**
******
********
**********
**

The only way I know how to display a number of *s according to user input is by an if statement. I copied and pasted from a similar class assignment I did, so what I have so far is pretty messy and nonsensical:

static char DetermineRainfall(int inches)

System.out.println("Histogram");
//char inches;
for(inches = 0; inches < 7; inches++)
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The following program should read in a file on my desktop (I have the path set in Netbeans to that location) and produce a Histogram. Instead I am receiving this error.

Exception in thread "main" javax.imageio.IIOException: Can't read input file!
at javax.imageio.ImageIO.read(ImageIO.java:1301)
at Histogram.main(Histogram.java:9)
Java Result: 1
BUILD SUCCESSFUL (total time: 0 seconds)

Here is the code for the Histogram:

import java.awt.image.BufferedImage;
import java.io.File;
import javax.imageio.ImageIO;
public class Histogram {
public static void main(String[] args) throws Exception {
int[][][] ch = new int[4][4][4];

[code]...

Why it's not reading the file?

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This is what I've done so far :

public static void main(String[] args) {
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int count = 0;
for(int i = 0; i <array.length; i++) {
int val = array[i];
for(int j = i+1; j<array.length; j++)

[Code] .....

I think I'm on the right track as it correctly prints out the frequency of the first 3 elements, but I'm definitely going wrong somewhere as it just doesn't do it right after that!

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import java.io.*;
 
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public static void main (String [] args) throws IOException {
File file1 = new File ("letternumberfrequency.txt");
BufferedReader in = new BufferedReader (new FileReader (file1));
 
[Code] ....

But, let's just say that now I have the following characters in the text file, "letternumberfrequency.txt":
71 geese - 83 cars - 58 cows- 64 mooses- 100 ants- 69 bangles- 90 molehills - 87 noses

The numbers inside that text file would be considered as strings, am I right? But I want to extract the numbers so that I can also be able to count their frequency - not as individual digits but as whole numbers (that is how many "71", "83", "58", "64", etc. are there...). Would using "Double.parseDouble ()" work?

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[Code] .....

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These are all arraylists and not arrays

I have currently two arrays.

Java Code:

String[] chunks = {"a","b","c"};
int[] freq = {2,4,3}; mh_sh_highlight_all('java');

I am looking for a way to order these from greatest to smallest based on frequency.

The resulting arrays should be:

Java Code:

chunks = {"b","c","a"};
freq = {4,3,2}; mh_sh_highlight_all('java');

Because b is most frequent, and a is least frequent.

One way I can think of doing this is a two dimensional String array

Java Code: String[][] fullHold = {{"b","c","a"},{"4","3","2"}}; mh_sh_highlight_all('java');

Then sort based on the character values of the second row.

How can I sort a two dimensional array based on a single row (where it will rearrange the other rows in accordance).

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I have built a binary tree, from a file. In each node, I am storing each word as a string, and an int frequency for each time the word occurs. For the assignment, I need to find how many words occur only once in the file. I wrote the program, but for some reason I am getting a number different from what my professor is expecting.

As far as I know, this file has loaded into the tree correctly, because all of my other answers in the assignment are correct. What am I doing wrong?

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private int findUniqueWords(Node subTree, int uniqueCount) {
// Base Case: At the end of the branch
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[Code] ....

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[code]....

It is now printing out the value of myDeck[5] but I need to print out first 5 values.

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[code]....

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