i dont know how to write main that would open the input file and read using this method...
[/package AssignmentSeven;
import java.io.*;
import java.util.Scanner;
public class Assignment7
{
public static void Towers(int nTowers, int fromTower1, int workTower2, int toTower3) {
if(nTowers == 1)
[code].....
i have an older file I was working on 2 months ago and when i try to open it in eclipse I get a message corruption error. I know this is not possible since I was just working on it a while back, and it's the same program version as what i am currently using..Or would I do a file import instead?
View Replies View RelatedIs there a way we can open a .chm file stored at server through jsp application without downloading the file and saving it to the local machine.
What I googled is : we cannot download .chm files from a web browser and simply click Open. Download the .chm file to your computer first, right-mouse click it in Windows Explorer and select Properties. Then click Unblock.
But I want my users to simply view the file without downloading it.
I was just wondering how would I create a jar file that would open 3 other jar files when I open the jar file with my batch file it and when I type stop in the batch file it will out put the stop command into all 3 of the other jar files.
This is for my Minecraft server so I can launch them all at the same time and inStead of having to enter the commands in all the server batch files I just have to do the command in 1 I know their is things like multi craft to do this but I want the code so I don't have to use multicraft.
I am trying to write a java code for a homework problem in my intro java class but im having problems. This is the problem:
Write a program that open the MyFile.txt and read from a file with these criteria.
1)-The program should display the first five lines of the file’s contents only.
2)-If the file contains less than five lines, it should display the file’s entire content. You must check for end of file and less than 6 lines on the loop iterations.
3)- your program should use loop to read the line by line of the file MyFile.txt.
The serperate myfile.txt has this
I can still remember, at the end of that year, we sat for the last time in our circle together. She played us her favorite song, "like a bridge over troubled water" and quietly passed out a gift she had made for each of us.She had made each of us a pottery heart with our name and the date on it on the back each read "I believe in ME".We all cried including her. She told us she would always remember US. We believed she would.
and this is what the code is suppose to look like after you run it : Java33.png
And this is what i have so far : Java22.png
what needs to go next to complete the javascript to show the first 5 lines of the text files?
In jsp, In windows 7 , IE 11 , I am able to get the downloaded file but still unable to open it.
View Replies View RelatedI have recently taken up some java after a period of time learning batch scripting. the issue I have run into is that my build compiled and ran just
fine when invoking from within the netbeans IDE but after that I 'cleaned and built' the jar and the IDE stored it in the directory that I specified while installing.
I went to that folder, double clicked on my gui and go nothing. So then I opened a command prompt did, "java -jar myapp.jar" and got the following of which has me completely lost:
Exception in thread "AWT-EventQueue-0" javax.persistence.PersistenceException: No Persistence provider for EntityManager named
at javax.persistence.Persistence.createEntityManagerF actory(Persistence.java:85)
at javax.persistence.Persistence.createEntityManagerF actory(Persistence.java:54)
at my.numberaddition.NumberAdditionUI.initComponents( NumberAdditionUI.java:31)
at my.numberaddition.NumberAdditionUI.<init>(NumberAd ditionUI.java:18)
[Code] ....
I am currently working on an application with java and I want to do is upload and download details in .xlsx file. Uploading process is successfully worked but the problem is that when I download the file .xlsx with details at opening the file it gives me the following message :
Excel cannot open the file '(filename)'.xlsx' because the file format or file extension is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file.
I am trying to make a japplet that has open, zoom in and zoom out buttons for pictures. I am not sure how to go about an open button that will read the file. I have the picture url hard coded in the file to open but would like an open button with a file/folder dialogue.
This is what I have so far
import java.awt.BorderLayout;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Image;
import java.awt.event.ActionEvent;
[Code] ......
So I am trying to open a file and store the contents into a two dimensional array. I seem to have no problem using this same basic code to read the file and output it. But when I try to change it so that all the data is stored into the array, it does not work.
Java Code:
public void convertFile()
{
String filePath = ("C:UsersBradDownloadsFB1.csv");
String [][] rowCol = new String [429][6];
try
{
BufferedReader br = new BufferedReader(new FileReader(filePath));
StringTokenizer st = null;
System.out.println("Your file is being converted to an array. This may take several minutes.");
[code]....
In our currenr project we have a requirement to open a local/network driver file/folder using JSF 2.0 <h:outputLink> in Firefox browser find the below sample code & correct it, how to achieve the above requirment
Sample.xhtml
<h:form>
<h:outputLink id="linkID" value="#{demoDataBean.dataLink}" target="_blank" >
<h:outputLabel value="#{demoDataBean.dataLink}" />
</h:outputLink>
[code]...
I'm working on a problem where I have to use the FileInputStream to opens a file that contains the name of a user's favorite book and then displays it.
If the file doesn't exist, then I prompt for the book title and write it to the file using FileOutputStream. This is what I have so far but I'm lost because if I put a file that exists in line 8 then it closes, but if I don't and the user puts their favorite book nothing happens. Or, as far as I can tell nothing does.
import java.io.*;
class DisplayBook {
public static void main(String[] args)
[code]....
I am working on a project that requires me to build a database with random access file, representing products, the base product contains a name (about 30 characters), a price (double), and a quantity (integer). I have worked on this project for probably 15+ hours and have tried so many things and feel like I've barley made any progress...
The part i am really struggling with is taking the data from the text file and creating an object array with it using the product class. Once ive accomplished that, i have to use that data to create a random access file with the data.
Here is the base Product class that must be used to create the objects for the array.
public class Product
{
public String pName;
public String stringName;
public double price;
public int quanity;
[Code] .....
And then here is the data from the text file that i must extract to use to create product objects.
Dill Seed,938,34
Mustard Seed,100,64
Coriander Powder,924,18
Turmeric,836,80
Cinnamon (Ground Korintje),951,10
Cinnamon (Ground) Xtra Hi Oil (2x),614,31
Cinnamon (Ground) High Oil (1X),682,19
These continue for about 40-50 entries, they are not separated by a blank line though i had to add those so it would display correctly, each entry is on its own line with name separated with spaces, then price after a comma, then quantity after the second comma.....
I am working on a project that requires me to build a database with random access file, representing products, the base product contains a name (about 30 characters), a price (double), and a quantity (integer). I have worked on this project for probably 15+ hours and have tried so many things and feel like I've barley made any progress...
The part i am really struggling with is taking the data from the text file and creating an object array with it using the product class. Once ive accomplished that, i have to use that data to create a random access file with the data. Here is the base Product class that must be used to create the objects for the array.
public class Product
{
public String pName;
public String stringName;
public double price;
public int quanity;
[Code]...
these continue for about 40-50 entries, they are not seperated by a blank line though i had to add those so it would display correctly, each entry is on its own line with name seperated with spaces, then price after a comma, then quanity after the second comma.....
I am working on a project that requires me to build a database with random access file, representing products, the base product contains a name (about 30 characters), a price (double), and a quantity (integer). I have worked on this project for probably 15+ hours and have tried so many things and feel like I've barley made any progress...
The part i am really struggling with is taking the data from the text file and creating an object array with it using the product class. Once ive accomplished that, i have to use that data to create a random access file with the data.
Here is the base Product class that must be used to create the objects for the array.
public class Product
{
public String pName;
public String stringName;
public double price;
public int quanity;
//Constructor
public Product( String pName, double price, int quanity )
[code]....
and then here is the data from the text file that i must extract to use to create product objects.
Dill Seed,938,34
Mustard Seed,100,64
Coriander Powder,924,18
Turmeric,836,80
Cinnamon (Ground Korintje),951,10
Cinnamon (Ground) Xtra Hi Oil (2x),614,31
Cinnamon (Ground) High Oil (1X),682,19
these continue for about 40-50 entries, they are not separated by a blank line though i had to add those so it would display correctly, each entry is on its own line with name separated with spaces, then price after a comma, then quanity after the second comma.....
I need to write a program that will create an inventory file as a random access file. The problem that I am having is that among the things I need to add to the random access file is a "car name". Since random access files are byte based I don't know how I could possibly write and then read a string value.
View Replies View RelatedI have been assigned to write a program that has a user input random numbers then the program is to sort them in different ways. I have the coding for the different sorts but, I have an error saying that I am missing a return statement in the "Bubble" method. I am trying to return "arr[i]" in the "for loop" which gives me this error, and when I try to take the "return arr[i]" outside of the "for()" loop the error reads the it cannot locate variable "i".
import java.awt.* ;
import java.awt.event.*;
import javax.swing.*;
public class SwingSorts extends JFrame implements ActionListener
{
JRadioButton bubble;
JRadioButton selection;
[Code] .....
So I was going to try to create a program that prompts input and creates a file (That didn't exist before) with that input as name.Then, the program prompts inputs after stating questions such as 1 + 1, then if the user inputs an answer, put "Question # = Correct "or" Wrong.Code SO Far:
Java Code:
import java.io.BufferedReader;
import java.io.File;
import java.io.InputStreamReader;
public class File_Read {
public File_Read() {//File_Read is the Interactive object
[code]....
So that it puts the Correct or Wrong into the file.
I am splitting a zip file and want to name each fragment with a random name. I want to use java coding for generating this random file name.
View Replies View RelatedHow to force browser to open/save/save as the file from server instead of browser cache.
I am creating a csv file through a pl/sql procedure and forwarding the link to user once user clicks on link he downloads the file, however if the same thing is repeated then browser returns the old cached file instead of new file generated on server.
I have a random access file stream. I have below code I want to written data that is currently pointed by pointer till the end and display that data on System.out Stream but it is not working my code is
//Create a Random Access File
java.io.RandomAccessFile random=new java.io.RandomAccessFile("D:/input.txt","rw");
//Position the pointer to a seek
try {
random.seek(300);
long pointer=random.getFilePointer();
System.out.println("Current Pointer is:"+pointer);
int a;
while((a=random.read())!=-1) {
System.out.println(a);
}
Where am I wrong? Although it is returning actual position of pointer in pointer using
I am creating a read/write, RandomAccessFile that I will use to store several student ID and gpa score. What I don't understand is how I should go about retrieving a particular set of data.
public class ReadWrite {
static Scanner keyboard = new Scanner(System.in);
static String fileName = "Stu.dat";
static RandomAccessFile raf;
public static void main(String [] args) throws FileNotFoundException, IOException {
[Code] .....
I'm trying to save a picture from byte arrays using RandomAccessFile. The file appears but doesn't open (like its corrupted).
I'm using the bittorent protocol which gives a SHA-1 hash that I compare all the bytes with to verify the data. All the bytes pass the hash check and all the hashes are checked. So I'm pretty sure I'm getting all the bytes correctly.
Is there anything I can do that could tell what's going wrong?
public RUBTClient(final TorrentInfo2 tInfo, final String outFileName) {
...
this.outFileName = outFileName;
File destined = new File(outFileName);
try {
destined_file = new RandomAccessFile(destined, "rw");
destined_file.setLength(tInfo.file_length);
} catch (FileNotFoundException e1) {
[Code] .....
The program I'm supposed to create generates a random number between one to ten. Then the program is to ask me if I wish to cross the road. If you choose to cross, the outcomes for 0-2 are "You crossed safely." For 3-5, 75% of the time it should say "RIP you got run over", and 35% of the time it should say "You crossed the street." For 6-8, 60% of the time it should say you made it.", and 40% of the time it should say "You died". For 9-10, it should say "RIP".
So far I have gotten the random number generation part working. I have up to here:
import java.util.Random;
public class test4 {
public static void main(String[] args) {
Random random = new Random();
for(int i =0; i < 1; i++){
int num = random.nextInt(10) + 1;
System.out.println("The number of cars on the street are: " + num + "Do you wish to cross the road?");
}
}
}
I'm trying to write data for three products to a random access file, but I have a problem. Each product has a code and a price. After writing them to my file, I want to get to the second field or product. I do this by getting the length for each record, and multiplying it by the field number I want to go to. I use the result for the seek() method of the RandomAccessFile object. It is giving me an EOFException, but when I use 0 for the seek method i get the data for the first poduct or field.
Java Code:
public static void main(String[] args) {
final int RECORD_LENGTH = 16;
try(RandomAccessFile productsOutput = new RandomAccessFile("C:UsersalfonsoDesktopBinaryTestRandom.ran", "rw")) {
String[] codes = {"java", "jsps", "txtp"};
double[] prices = {49.5, 19.9, 29.9};
for(int i = 0; i < codes.length; i++) {
[Code] .....
Well my code is supposed to ask for an input file and then (ex: input.txt), read the input file and create an output.txt file with the anagram for the words in the file. Also it should be displayed on the screen. However my code doesn't display the anagram on screen or the output file!
Heres is the code:
import java.io.*;
import java.lang.*;
import java.util.*;
/* This program will read a file given by the user, read the words within the file and determine anagrams of the given words. If the file that the user inputs is empty, then the program will output "The input file is empty."
* The program will read the file line by line, counting the total number of words read. If there are more than 50 words, "There are more than 50 words."
* will be printed, and the program will terminate. After each line is read, the words in the line will be separated,punctuation characters will be removed, and upper case characters will be switched to lower case.
* If any word is larger than 12 characters, that word will not be considered in the total amount of words in the file and it will not be sorted.
* After each word is read, the letters will be sorted and stored into an array containing each
* word's 'signature'. After all the words have been read, words will be printed to the output file on the same line based upon their signature.
*/
public class Anagram {
//Creating constants for maximum words in file and maximum chars in word
public static final int MAX_CHARS = 12;
public static final int MAX_WORDS = 50;
[Code] ....