So if I wanted to tell the user that the fifth letter they entered is "____" how would I do that.
I am prompting the user to enter a word and then displaying the length of the String. Now I want to display to the user what the fifth letter of the String they entered is.
import java.util.Scanner;
public class StringPractice
{
public static void main(String [] args) {
Scanner input = new Scanner(System.in);
String word;
int lenght;
Example : I have code and name but my code must start with the first letter of the inputed name if the 2 input is match it will be inserted into database
code = "A"001 name ="Angela" = success this will inserted into database
else
code ="B"002 name="Angela" =failed this will not inserted into database
else
code="A"003 name="Andy" =success still accepts the input cause they have diff code number
What I am thinking on this was compare the code the name? if == it will be inserted but how do i get the 1st letter of the input name?
Alright so I wrote a switch statement that decides what range to print based on the letter grade input.
import java.util.Scanner; public class SwitchPractice { public static void main(String [] args) { Scanner scan = new Scanner(System.in);
[code]...
It works fine, but once it the user enters a letter grade and then displays the value, it does not prompt the user for another letter grade so that it can perform the output again. Also if I wanted to display an error message to the user if they enter an invalid letter grade how would I do that. I tried using a while loop and if statement in the switch statement but that didn't work.
I'm trying to convert the first letter of every word in a String to uppercase. I've managed to isolate the first letter of every word and then make it uppercase but I don't know how to replace it.
public static StringBuffer makeUpperCase(){ String str = String.valueOf(input2); for(int i = 0; i < str.length(); i++){ if(str.charAt(i) == ' '){ char var = str.charAt(i + 1); var = Character.toUpperCase(var); System.out.println(var); } }
I have got a pretty good framework working for my hangman game so far, however I am quite stumped on how to find multiple instances of the same letter in a single string. I am using indexOf to find the instance of a character in a string, but it only returns the first instance. So if the words(s) contain(s) multiple instances it doesn't register the rest.
public static void main(String[] args) { String word = "crazy horse"; String answer=""; String space=" "; String dash="-";
I have a problem with functions connected to strings.
I have a random String, e.g. "Hello World!" and I have to change every capital Letter into a small letter and vise versa. This alone would be fairly simple, but I have to do it with two other strings.
lowercase= "abcde...z" and
uppercase="ABCDE...Z". Every small letter stands at the very same position as the capital letter, but in the other string.
There should be a letter for letter search in lowercase and uppercase for the letters of "Hello World".
How I could solve the task, however I need a way to search the first string, here "Hello World", according to position. A statement which does: "Give me the letter of position x". This found letter should be able to be stored in a variable or else be able to be used by another statement. And it should be compatible with a for lope.
I'm trying to create a private method called capitalize() which takes String nameModel in any uppercase/lowercase combination and returns it with the first letter uppercased and all other lowercased. E.g. "stePHeN" returns "Stephen" . This is what I've written so far:
I'm having trouble with the last few lines of the code. It's supposed to take a replacement string entered by the user and print out the new string. For some reason it's now allowing me to enter a replacement string
import java.util.Scanner; public class Project02 { public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); System.out.print("Enter a long string: "); String lString = keyboard.nextLine();
[Code] ....
Output:
Enter a long string: the quick brown fox jumped over the lazy dog Enter a substring: jumped Length of your string: 44 Length of your substring: 6 Starting position of your substring in string: 20 String before your substring: the quick brown fox String after your substring: over the lazy dog Enter a position between 0 and 43: 18 The character at position 18 is x
Enter a replacement string: Your new string is: the quick brown fox over the lazy dog <------ isn't taking user input
Write a program that continuously asks for an alphabet letter, and stops when a non-alphabet letter is entered. Then output the number of upper case letters, lower case letters, and vowels entered ....
I'm having a hard time with this problem, this is what I have, but I can not use two integers, I have to use one integer and a string...
This is the question:
Write a method called printStrings that accepts a String and a number of repetitions as parameters and prints that String the given number of times. For example, the call:
printStrings("abc", 5);
will print the following output: abcabcabcabcabc
This is what I attempted:
public class printStringsproject { public static void printStrings(int abc, int number) { for (int i = 1; i <= number; i++) { System.out.print("abc"); } } public static void main(String[] args) { printStrings(1, 5); } }
I can't figure out how to print this string only five times. I tried to use the * operator, but that doesn't work with strings apparently, unles i'm not importing correctly.
import java.lang.String; public class Looparray { public static void main(String args[] { for (String myStr= "Hello there!";;) { System.out.print (myStr); System.out.print(" "); } } }
I'm having a small error with my code, it is getting rid of the first letter of the string after the first line printed.
import java.util.*; public class PrintPyramidName { public static void main(String[] args) { System.out.println("What is your name?"); Scanner input = new Scanner(System.in);
Here i want to print the String from Starting character which is given by user..Here i given below the image like my concept..here we put .(dot and enter R)eclipse will print the method name which is starting from R..
So I need to write a program that reads through a String and counts how many vowels there are and prints them out as it finds them. This is what I have so far:
I am writing to a text file via user input and it is saving all the user input to the file but it is just printing one word per line. I would like it to print the string on one line and print the next string on the next line upon them hitting enter.
public void textFile() { Scanner reader = new Scanner(System.in); System.out.println("Enter file name: "); String fileName = reader.next(); File f = new File(fileName); PrintWriter p = null;
I have a college question ask me to write a class StringRevert which does the following:
-prompting user for an interger n -creating an array of n string -repeatedly read character string from user input and store them in the array until end of array is reached or user input -quit(quit should not saved in array) -print the string from array in reverse order, from last enter to first enter. -assume user always supplie correct input
This is what I've done so far but how to get it working.
import java.util.Scanner; public class StringRevert { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println("enter value of n: "); int n1 = in.nextInt(); String[] n = new String[n1];
I have a large text file of 1 GB size. I need to print the line when a matching word is found in a particular line. Below is the code I am using. But if there are many lines that has the matching word, it's taking lot of time. Any solution to print the lines much faster.
Scanner scanner = new Scanner(file); while (scanner.hasNextLine()) { String line = scanner.nextLine(); if(line.contains("xyz")) { System.out.println(line); } }
I just tried to fill an array with some numbers, calculated by a other function.I just tried to print this array as array, but it doesnt work. Maybe its just about the main method.
public static void main(String[] args) { ggT(5); }
Basically the class is supposed to have a static variable that keeps track of the number of companies (numberOfCompanies) that have been created and a static method that returns the value of this variable. I need to have a constructor and a method to addEmployee, a method to printCompany, and a toString method. The addEmployee method will check that there is only 1 salesperson, 2 designers, and 4 manufacturing persons at a time and will check that there are no more than 7 employees of the company.
The addEmployee method will return a String indicating what the error is (i.e. "There is already a sales person in this company") or a null if the employee was added. If attempting to name a third company, an error message will be shown. what i have so far but my print company mmethod returns null company class :in which i am obliged to use inputdialog because it says that it cannot return void when i use the showmeassage diaolog.
company class:
import java.util.ArrayList; import javax.swing.JOptionPane; public class Company { private ArrayList<Employees> list ; private static int numberOfCompanies;
[Code] ....
error message when print button is clicked:
Exception in thread "AWT-EventQueue-0" java.lang.RuntimeException: JOptionPane: parentComponent does not have a valid parent at javax.swing.JOptionPane.createInternalFrame(Unknown Source) at javax.swing.JOptionPane.showInternalOptionDialog(Unknown Source) at javax.swing.JOptionPane.showInternalMessageDialog(Unknown Source)
I'm writing a java program in eclipse of a tic-tac-toe game. I have to create it using JTextField's only I'm having trouble where the JTextField will only accept one letter and will only accept X and O is there any particular way to do this I started off with this piece of code
String text=tf1.getText(); if(text.length()>1) { System.out.println("this is not allowed"); tf1.setText("");
But it doesn't work so is there something I'm missing....
