I have an array made that represents digits and I am trying to make a method so that if there are zeros in front of the first significant digit I want to trim them, I understand you can't re size arrays so I have created a new array, but my code doesn't seem to run correctly? Here is my code I can't figure out what is wrong I've tried everything: (I put stars around the error**)
package music;
import java.util.Random;
public class Music {
private int length; // length of the array
private int numOfDigits; // number of actual digits in the array
int[] musicArray;
I got situation where i have postal code as 0009 in database and the use is entering 0009 but somehow in my java code it only reading 9 from the xml file
This is how i define getter and setter :
When I debug the code i get this :
passed postalcode 9
if a user entered 0009 I what it to remain 0009
Java Code:
public String Postalcode=""; public void setPostalcode(String Postalcode) { this.Postalcode = Postalcode; } public String getPostalcode() { return Postalcode; }
why I need to populate an array with leading zeros. It sounds like it wants me to populate the entire array for one number (string). When I use next(), it separates the numbers so why do I need to go the leading zeros route?
This assignment will give you practice with external input files and arrays. You are going to write a program that adds together large integers. The built-in type int has a maximum value of 2,147,483,647. Anything larger will cause what is known as overflow. Java also has a type called long that has a larger range, but even values of type long can be at most 9,223,372,036,854,775,807.The approach you are to implement is to store each integer in an array of digits, with one digit per array element. We will be using arrays of length 50, so we will be able to store integers up to 50 digits long. We have to be careful in how we store these digits. Consider, for example, storing the numbers 38423 and 27. If we store these at the front of the array with the leading digit of each number in index 0 of the array, then when we go to add these numbers together, we're likely to add them like this:
38423 27
To simulate this right-shifting of values, we will store each value as a sequence of exactly 50 digits, but we'll allow the number to have leading 0's. For example, the problem above is converted into:
Now the columns line up properly and we have plenty of space at the front in case we have even longer numbers to add to these.The data for your program will be stored in a file called sum.txt. Each line of the input file will have a different addition problem for you to solve. Each line will have one or more integers to be added together. Take a look at the input file at the end of this write-up and the output you are supposed to produce. Notice that you produce a line of output for each input line showing the addition problem you are solving and its answer. Your output should also indicate at the end how many lines of input were processed. You must exactly reproduce this output.
You should use the techniques described in chapter 6 to open a file, to read it line by line, and to process the contents of each line. In reading these numbers, you wont be able to read them as ints or longs because many of them are too large to be stored in an int or long. So youll have to read them as String values using calls on the method next(). Your first task, then, will be to convert a String of digits into an array of 50 digits. As described above, youll want to shift the number to the right and include leading 0s in front.
The String method charAt and the method Character.getNumericValue will be useful for solving this part of the problem.You are to add up each line of numbers, which means that youll have to write some code that allows you to add together two of these numbers or to add one of them to another. This is something you learned in Elementary School to add starting from the right, keeping track of whether there is a digit to carry from one column to the next. Your challenge here is to take a process that you are familiar with and to write code that performs the corresponding task.
Your program also must write out these numbers. In doing so, it should not print any leading 0s. Even though it is convenient to store the number internally with leading 0s, a person reading your output would rather see these numbers without any leading 0s.You can assume that the input file has numbers that have 50 or fewer digits and that the answer is always 50 digits or fewer. Notice, however, that you have to deal with the possibility that an individual number might be 0 or the answer might be 0. There will be no negative integers in the input file.You should solve this problem using arrays that are exactly 50 digits long. Certain bugs can be solved by stretching the array to something like 51 digits, but it shouldnt be necessary to do that and you would lose style points if your arrays require more than 50 digits.The choice of 50 for the number of digits is arbitrary (a magic number), so you should introduce a class constant that you use throughout that would make it easy to modify your code to operate with a different number of digits.
Consider the input file as an example of the kind of problems your program must solve. We might use a more complex input file for actual grading. The Java class libraries include classes called BigInteger and BigDecimal that use a strategy similar to what we are asking you to implement in this program. You are not allowed to solve this problem using BigInteger or BigDecimal. You must solve it using arrays of digits.Your program should be stored in a file called Sum.java.
I am writing a program that adds together large integers. I have to store each integer in an array of digits, with one digit per array element. Array length is 50 so integer is 50 digits long. I have to store numbers in right-shifting format with leading zeros. For example,
Sum.txt contains numbers to be added. There could be one or more numbers per line.each line must be read as string with next() since it's assumed to be a very long number. String of digits needs to be converted into an array of 50 digits. Method CharAt and Character.getNumericValue will be useful. All numbers in each line are to be added. There are no negative numbers and individual number might be 0 or answer might be 0. Answer is always 50 digits or fewer.
BigDecimal or BigInteger are not allowed.
I'm lost where it says to put number with leading zeros in a 50 room array. How do I add numbers after formatting numbers with leading zeros?
I got situation where i have postal code as 0009 in database and the use is entering 0009 but somehow in my java code it only reading 9 from the xml file
This is how i define getter and setter
When i debug the code i get
passed postalcode 9
Java Code:
public String Postalcode=""; public void setPostalcode(String Postalcode) { this.Postalcode = Postalcode; } public String getPostalcode() { return Postalcode; } mh_sh_highlight_all('java');
Goal is to: Write a program that prompts the user to input an integer and then outputs both the individual digits of the number and the sum of the digits.
First I don't know where I made mistakes here, and the only error it finds right now is that str2 was not initialized and I cannot figure out where/when to initialize it.
import javax.swing.JOptionPane; public class DigitsAndSum { public static void main (String[] args) { String str1; String str2; int int1 = 0; int int2 = 0;
This is the other code problem I have. The user should be able to enter the amount of digits the array should be shifted left. For example, if the user entered 3 and the array was 1 2 3 4 then it should return 4 1 2 3. here is my code.
public char[] replaced(char[] array, char oldChar, char newChar) { char myFun[] = new char[array.length]; for (int i = 0; array.length > i; i++) { myFun[i] = array[i];
In Oracle SQL, when you do trim(column_name), if column_name is blank spaces only (say datatype is CHAR(8)), then "trim(column_name) is null" is true.
In JPQL, if you do "TRIM ( BOTH FROM p.column_name ) is null", does it evaluate to true just like in Oracle SQL?
The reason I'm asking, is my colleague wrote some code in JPQL like below:
... TRIM ( BOTH FROM CONCAT(p.column_name, '#@') ) = '#@'
He said he originally wanted to compare the TRIM result to empty String '', but the result is false, so he concat the column to some junk.
So if after the TRIM, the result is the same junk he added, then the column contains only blanks. I think this works but there could a simpler way to do it.
public class VargjetUshtrimi2 { public static void main (String a []) { int r[] = new int[11]; for (int i = 1 ;i < 10; i++) {System.out.println( r[i] );} }
I am writing a code that requires a user to input a number, then output the individual digits and then add the sum of the digits. I have the entire program written, but I cannot figure out how to make zeros output as individual digits. If I input 400, it only shows 4 and not 4 0 0. Here is the code:
import java.util.*; public class week4program { public static void main(String[] args) {
I have to seperate a number 9876 to 6 7 8 9, to 9 8 7 6. I need to know how to sum the digits. I have gotten to this point ::
import java.util.*; public class week4program { static Scanner console = new Scanner (System.in); public static void main(String[] args) { int num1; int digit; int sum = 0;
[code]....
To this point its gives me the seperate integers. OK but how do I get the variable integers into seperate containers and then add them up?My assignment is to do that, and what I have above gets me to where I have seperate digits, but how do I catch them into seperate entities to be added to a sum?
I have it so it gives me the sum of any digit, i just cant figure out how to get only the odd digits to add up. for example if I were to type 123. The odd numbers = 4 but using this program i get 6
class SumOfDigits { public static void main(String args[]) { int sum = 0; System.out.println("Enter multi digit number:");
import java.util.Scanner; public class CubesSum { public static void main (String [] args){ int input; System.out.println("Enter a positive integer:"); Scanner in = new Scanner(System.in); input = in.nextInt();
As you can see I'm using a while loop. For part B which is to modify to determine what integers of two, three, and four digits are equal to the sum of the cubes of their digits. So for example, 371 = 3³+7³+1³. How to do it? I need to wrap a for loop around my while loop...
Make a program which takes input from the user (6-digit number) and check how many times each digit gets repeated in the number. Java GUI was used (Netbeans 6.5.1).This is my code. I took the input via a JTextField named tf and displayed the output on JTextArea ta.
- arrays not used as we haven't studied them yet
int num= Integer.parseInt(tf.getText()); int no=num; if(num<100000) ta.setText("Invalid Input. Please Enter 6 digit number"); int n1= num%10; num=num/10; //stores last digit
[code]....
How do I omit the last 5 lines? This problem occurs whenever I input a digit with any recurring digit.What changes/additions should I make?
The following code splits an integer into separate digits. It then adds 7 to each of those digits, and then finds the remainder when the result is divided by ten. To do this it uses the Modulus operator.
public class manipulateIntegers { public manipulateIntegers() { System.out.println("Enter a four digit Integer"); String y = System.console().readLine(); int[] list = new int[5];
[code].....
I understand completely about what modulus does vis-à-vis fetching the remainder, but I don't understand why using the modulus operator gets you each digit individually?
for example, this snippet splits the digits of an integer - but how??
int number; // = some int while (number > 0) { print( number % 10); number = number / 10; }
and why does number have to be reassigned as number / 10?
