How do i check INT range for switch case: ?
int grade = 68;
switch (grade) {
case 100:
System. out.println( "You got an A. Great job!" );
break;
case 80:
System. out.println( "You got a B. Good work!");
break;
[code]....
write a program using nested switch case to show the different shops in a shopping mall.
View Replies View Relatedwhy this switch code does not work for the 'Q'. Everything works fine for the other cases, i.e. 1,2,3, and 'q', but when I type in 'Q', I get the default case. Please note all the values have been defined in an earlier part of the code but for simplicity's sake I have removed them below
do {
switch (choix) {
//demande le nombre de patons a achete
case '1':
[Code].....
I am making a programme for a calculator to - Divide, multiply, add and subtract. I have the code written but when I am running it and trying to add it was for some subtracting ....
import javax.swing.JOptionPane;
public class calculator3 {
public static void main(String[] args){
String number1,number2,operatorstring;
double result=0,a,b;
[Code] ....
can give me a sample program which solves with switch case statement with nested if inside?
View Replies View RelatedIf I have an integer variable like int a=9 then in the switch case If i write
switch(a) {
case 4+a: System.out.println("hii");
}
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
So basically what problem it creates for which the language developers did not include it as a proper syntax,is there any reason behimd this because of jump table?
I am stuck with two switch statements that I feel I am close to achieving. My first switch statement is to generate random mathematical operators for the math questions in the game (generated randomly) My second switch statement is to determines which action the system will take upon the correct or incorrect answer. For the first switch statement I have a variable called num. Num is a random integer. I have an operator mapped to each outcome of num. In my second switch statement I am trying to use the variable answer as a variable in the first case but do not know how.
package pkgnew;
import java.util.Scanner;
import java.util.Random;
public class New {
public static void main(String args[]) {
//Declare and construct variables
[Code] ....
In switch case statement string expression whether it will work or not ???
View Replies View RelatedAlright so I wrote a switch statement that decides what range to print based on the letter grade input.
import java.util.Scanner;
public class SwitchPractice
{
public static void main(String [] args)
{
Scanner scan = new Scanner(System.in);
[code]...
It works fine, but once it the user enters a letter grade and then displays the value, it does not prompt the user for another letter grade so that it can perform the output again. Also if I wanted to display an error message to the user if they enter an invalid letter grade how would I do that. I tried using a while loop and if statement in the switch statement but that didn't work.
I decided to code this quiz I took in class about asking the user to input a string and the code is suppose to check for upper case letters. If a upper case letter is found, it should increase a count by one. Once the check is done, it should display the number of uppercase letters. For some reason I am getting this weird compile error stating that symbols can't be found...
Java Code:
import java.util.*;
import java.lang.*;
public class StringCheck{
public static void main(String[] args){
Scanner input = new Scanner(System.in);
System.out.println("please enter a string: " );
String s = input.nextLine();
[Code] ......
So from what iv learnt in Java and programming in general is that using a case statement is far more efficient that using multiple IF statements. I have an multiple IF statements contained within a method of my program, and would like to instead use a case statement.
public String checkPasswordStrength(String passw) {
int strengthCount=0;
String strengthWord = "";
String[] partialRegexChecks = { ".*[a-z]+.*", // lower
".*[A-Z]+.*", // upper
".*[d]+.*", // digits
".*[@#$%!]+.*" // symbols
[code].....
After the executing the code below:-
class Test
{
public static void main(String [] args)
{
String s = new String("new") ;
String d = new String("new") ;
System.out.println((s==d)+ " "+s.equals(d)) ;
System.out.println(s==d + " "+ s.equals(d)) ;
}
}
OUTPUT:- false true
false
Why did the output change in the second print statement?
I'm trying to create a simple java math question quiz using random operators, but keep sinking myself into deeper despair. The numbers must range from 0-9 and given an operator: +,-,/,*,%. Can't create a new method or use Case statements. The code isn't finished but don't want to make it any worse.
package marco;
import java.util.Scanner;
import java.util.Random;
public class Project {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
Random rand = new Random();
System.out.println("How many questions do you want?");
[code]...
I have one template.xhtml file at /template/template.xhtml
<h:head>
</h:head>
<h:body>
<p:layout fullPage="true">
<p:layoutUnit position="north" size="100">
<h:outputText value="header"></h:outputText>
</p:layoutUnit>
<p:layoutUnit position="center">
[Code] ....
I am getting the following exception because of the **ui include** tag in template.xhtml. Is the src attribute of ui include is wrong.:
javax.faces.FacesException: Could not resolve NavigationCase for outcome: index
at org.primefaces.renderkit.OutcomeTargetRenderer.getTargetURL(OutcomeTargetRenderer.java:86)
at org.primefaces.component.menu.BaseMenuRenderer.encodeMenuItem(BaseMenuRenderer.java:162)
at org.primefaces.component.tabmenu.TabMenuRenderer.encodeItem(TabMenuRenderer.java:89)
[Code] ....
If my file name is MyBigXMLFile.xml it won't delete but if I rename it to mybigxmlfile.xml it will delete. How do you get around the case sensitive issue?
View Replies View RelatedI have 2 strings
String value ="/abc_12_1/abc234/abc/filename.txt";
String src="abc"
Sring tgt=xyz
Now I have to replace the string in variable value in case of exact match; I am trying to do the following :
if(value.contains(src)
{
value.replaceall(src,tgt);
}
Now the problem here is it replaces all the occurrence of abc in the string value and I get the below output as :
value=""/xyz_12_1/xyz234/xyz/filename.txt";
However my requirement is only in the case the value exactly matches with source the replacement shd happen. I am expecting the output like this :
String value ="/abc_12_1/abc234/xyz/filename.txt";
Also the above code is in a function which will be called multiple times and the values will keep on changing. However the target and source will remain the same always.
program that calculates and prints the sum of all numbers between two limits as the user types. Like if the user types 1 and 10 on the upper limit, it prints the following text: "1+2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55".
View Replies View RelatedI can't able to find the theta for some type of code like.
for(i=1;i<=n;i++){
for(j=i;j>=1;j=j/3){
....
}
}
How to find the theta for the above code.
for(i=1;i<=n;i++){
for(j=i;j>=1;j=j/K){
....
}
}
and How to find number of steps or time complexity for inner loop if k=3 (odd)
I need the username produced by this program to be in all lower case. The code is below.
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package dcollinshw03;
import java.util.Scanner;
import java.util.Random;
public class DcollinsHW03 {
public DcollinsHW03() {
[Code] .....
I have JUnit exposure only in writing simple programs. Here I have one of the usecases requirement pupose I am generating data file(s) by Java programming and calling this data by Hashmap. My file containing two columns
(1) TimeStamp
(2) Speed.
The file is tab formatted file. The business requirement is to check wether the first column should not be 00000000000000 or NULL or BLANK. My question is, how do I check the first field in a file contaning valid information in Junit test case?
Sample File: ( - tab delimited)
1421103602000 542
0000000000000 989
<NULL> 000
1421103603000 588
1421103604000 700
Unfortunately, I am unable to send my Java code here, It was giving some error while attaching in this thread.
I am having a doubt about how to fix and what could be the code to generate a retroActive salary case in payroll generation. Upto last year(2013) it was working fine.Now it is 2014 and i am stuck as i am new to java.
The system is computing every value in yearly basis,but the inputs are in monthly basis.
How do i write a method in java that will add a <b> or <em> tag to a specific word regardless of case or punctuation for example for "run forest RUN!" adding bold to run would be
<b>run<b> & <b>RUN!<b>
public void addTag(String word, String tag) {
I am storing out of range values in int and byte type
public class OverflowDemo {
public static void main(String args[]) {
int value = 2147483647 + 10;
System.out.println(value);
byte b=127+10;
System.out.println(b);
}
}
Program will give error for only byte type as OverflowDemo.java:8: error: possible loss of precision
byte b=127+1; ^
required: byte
found: int
So why not for Integer?
Any way to shift in a range from 0-9 when I already have the shift value.
The reason I am asking this is because I am writing a telephone validation program and I got most of it complete and all I need to do now is the shift an encrypted phone number given to me by the user, and shift it however many times my shift value is.
Example: I am trying to get this phone number, 545-319-8712 to become 212-086-5489. The shift value is 3. So basically since the phone number given to me is 3 numbers higher than the phone number I am trying to get, so if the first number I receive from the user is higher than 2 then I would shift the number the user gave me down by the shift value I have already gotten.
5 shift down 3 = 2, 4 shift down 3 = 1, etc. But I also want to know how I can make a number like "1" to shift down 3 to become 8. This is the range; 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
If I have to shift a number down 4 spots and I get the number 1 from the user than I want to get the number 1 to first down four times to become 7.
[1] -> 0 -> 9 -> 8 ->[7]
Basically if I have to shift a number down 4 and the number is less than or equal to 3 then I want it to continue from 9 .
Then just reverse the steps if I have to shift a number up, USER gives me "090", i want "212" I shift the number up by 2.
I've done a lot of hardwork for this assignment but I don't know what's why the second textfield which is for output is blank.
All I want is to get the input from user in textfield a and display it in textfield b in lower case.
public void KeyPressed (KeyEvent ke) {
String letter2="";
if(ke.getKeyCode()==KeyEvent.VK_A)
{
letter2=letter2+"a";
btextfield.setText(letter2);
[Code] .....
I need to turn some strings from:
'1-the-high-street'
to:
'1 The High Street'
But...
if string is
'the-dog-and-duck'
I want to achieve
'The Dog and Duck'
...whereby the 'and' is NOT converted to title case
My code as follows:
String propertyPageTitle = "1-the-high-street";
propertyPageTitle = propertyPageTitle.replace("-", " ");
propertyPageTitle = WordUtils.capitalizeFully(propertyPageTitle);
System.out.println(propertyPageTitle);
prints: '1 The High Street'
How could I handle the second scenario so it does not convert 'and' to titlecase?