How To Check If At Least One Number In A String Is Different From 0
Nov 18, 2014
I'm trying to come up with a method that would validate each turn a player makes. For a turn to be valid, it has to only contain numbers from 0 to 3(inclusive) and at least one digit must not be 0. Here is what I`ve come up with so far. For example, with "303" as the number and "101" as the turn, the turn would be valid and my method should return true, but it does not.
public static boolean turnIsValid (String number, String turn ){
boolean rep=false;
int pos1=0;
char min='0';
char max='3';
while(number.length()==turn.length()&&pos1<turn.length()){
[Code] ....
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Oct 3, 2014
I'm having a hard time with this problem, this is what I have, but I can not use two integers, I have to use one integer and a string...
This is the question:
Write a method called printStrings that accepts a String and a number of repetitions as parameters and prints that String the given number of times. For example, the call:
printStrings("abc", 5);
will print the following output: abcabcabcabcabc
This is what I attempted:
public class printStringsproject {
public static void printStrings(int abc, int number) {
for (int i = 1; i <= number; i++) {
System.out.print("abc");
}
}
public static void main(String[] args) {
printStrings(1, 5);
}
}
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Nov 25, 2014
I need to check numbers from 1-39 and see if the number has been or has not been a winning number in the last week lottery. How to do that?
This is code for random number, 7 numbers
import java.util.ArrayList;
import java.util.Random;
public class Loto {
public static void main(String[] arg) {
ArrayList<Integer> al = new ArrayList<Integer>();
for(int i = 1; i <= 39; i++)
[Code] ....
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Aug 8, 2014
Faster algorithm.... I want to know whether a number n1 is divided by n2 without remainder. I know I can simply write if (n1 % n2 == 0) ... But it's not fast enough.
Currently I use:
double div = (double) n1 / (double) n2;
If (div == (int) div){
...
}
This is faster than the mod operator. I just look forward to any micro optimizations or such.
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Jun 8, 2014
im trying to make a linear search method to check if a number 'n' is included in an array.
PHP Code:
package test;
public class Recursion {
public static void main(String[] args) {
}
static int linearSearch(int n, int[] array)
[code]....
Im getting the following error: this method must have a result type of type int ?? i already have a return type of type int...
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Apr 14, 2015
I have this program where I'm supposed to fill an array with 1000 indices with 1000 randomly generated numbers between 1 and 1000. The program is supposed to check if any of the numbers match an index that is the same value (so for example, the number 4 is in index 4). How to check for that condition, especially using a binary search (I'm also told to use a binary search).
Right now the variable index isn't initialized because I don't know what to initialize it to exactly. How do I check to see if any numbers match the value of the same index?
import java.util.*;
public class Identity {
public static void main(String[] args) {
int [] integers = new int [1000];
// Fill array with randomly generated numbers
int [] display = GenerateRandom(integers);
[Code] ....
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Apr 13, 2014
Write a program that prompts the user for an input number and checks to see if that input number is greater than zero. If the input number is greater than 0, the program does a multiplication of all the numbers up to the input number starting with the input number. For example if the user inputs the number 9, then the program displays the following sum:
9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 362880
That's the question I'm getting and so far all I've got is
import java.util.Scanner;
public class Lab4Q3
{
public static void main (String[] args)
{
int keyboard;
[Code] .....
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
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Feb 5, 2015
Is it possible to check to see if a what a user has entered is a string or a other variable type, if I'm asking this the right way?
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Jul 8, 2014
I have an assignment and one of the prompts is to do a binary search on an array if and only if the array of Strings is sorted. The binary search part I think I have completed, but it is the sorted array check that is throwing everything off. If the array is already sorted, return true; else, return false.
// Check if the array is sorted
public static boolean isSorted(String[] arr) {
//for (int i = 0; i < arr.length-1; i++)
//{
//if (arr[i].compareTo(arr[i+1]) > 0)
//return false;
//}
String[] arrSorted = arr;
Arrays.sort(arrSorted);
[code]....
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Mar 25, 2015
I have a number of objects stored in an ArrayList called inventory. Let's say I have two objects inside.
inventory.add(new Lamborghini(2011, "aventador", 411.3, false));
inventory.add(new Lamborghini(2012, "sesto elemento", 512.3, true));
I am making a function to search through the whole inventory to see if any of the Lamborghini object has a certain model name such as aventador, diablo, etc....
This is what I have but I figured there's a big mistake when I make it true / false; it's making it going through the list and what's return is the last one instead of saying there's such match in the whole list or not.
public boolean hasCarModel(String modelName){
boolean exist = false;
for (Lamborghini lambo : inventory){
String carModelName = lambo.getModelName();
if(carModelName.equalsIgnoreCase(modelName)){
[Code] ....
I figured if I add break; under exist = true; it'll work because as soon as it found one match then it'll turn to true and break out the loop but I don't think this is the best way to do it right?
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Oct 23, 2014
I'm supposed to use stacks (implemented with an array) to check to see if a string is a palindrome. I've finished all my classes and methods, but I'm getting an ArrayIndexOutOfBoundsException when I try to run my demo program.Here are my classes:
public interface Stack {
// Creates an empty stack
public void initializeStack()
// Returns true if the stack is empty, returns false otherwise
public boolean isEmpty();
// The stack can never be full, so always return false
public boolean isFullStack();
[code]...
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
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Oct 2, 2014
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
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Jan 30, 2014
I have doubts in string declaration. As I know we can declare string in two ways:
1. String a=new String("Hello");
2. String b="Hello";
What is exact difference between them? Another thing is when I check (a==b) it retuns me false, but when I check a.equals(b) it returns me with true. Why So?
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Jul 23, 2014
I started using Java a couple of days ago, If you haven't guessed I want to see if the user is typing a full name or not, but I'm actually not too concerned with any more complexity than I mentioned in the title. It's ok if an input like "GLba b" comes out positive.
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Aug 13, 2014
write the logic in the below given Java method.
Public static boolean updateNetMap(String filepath, String nodename){
// check the file pointed by filepath to have entry for nodename.
// if it is there, get the start line no and end line no
// Based on the line nos, need logic to remove the contents from the file.
}
Below is the sample node entry, which we need to identify and delete (here nodename is WAS_CD1):
WAS_CD1:
:conn.retry.stwait=00.00.00:
:conn.retry.stattempts=6:
:conn.retry.ltwait=00.00.00:
:conn.retry.ltattempts=6:
:tcp.max.time.to.wait=0:
[Code]...
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Jun 20, 2014
Java Code:
ButtonGroup bg=new ButtonGroup();
JRadioButton choice1=new JRadioButton();
JRadioButton choice2=new JRadioButton();
JRadioButton choice3=new JRadioButton();
JRadioButton choice4=new JRadioButton();
bg.add(choice1);
bg.add(choice2);
bg.add(choice3);
bg.add(choice4); mh_sh_highlight_all('java');
here i coded out my radio button..i am confused how to get the selected radio button of string and match with another array of String..
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Sep 8, 2014
Basically the requirements are to take a sentence (string of text) and check to see how many times specific words come up and then add to the counter depending on the word.
But I can not seem to get it to add the instances of the goodwords and badwords.
package Strings;
import java.io.*;
public class SentimentAnalyser {
private static String analyse(String text) {
int pw = 0;
int nw = 0;
String[] searchword = { "bad", "terrible", "good", "awesome" };
[Code] ....
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May 19, 2014
//read the file
//make the numbers 1 string line
//count the number of repetitiveness in the string for the numbers
//display four lowest ones
import java.io.*;
import java.util.*;
public class Lottery2
[Code] ....
when I run it the array gets sorted but how do i keep the data in other words
what it is supposed to do is grab numbers from a file, and give me the lowest 4 numbers back. I know the numbers using the array but how do i pull out the lowest 4 and keep the data true no matter what numbers or how many of them are in the file.
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Jan 14, 2014
My requirement is to
1- mask the number(whose length is between 10 to 12).
2- central digits are replaced by 'X' and 1st and last two digits remains unchanged
Input string: dsfjgjkdfgjdsfjg12345678901fdgkhfdklg55555hfdkhg
output string: dsfjgjkdfgjdsfjg12XXXXXXX1fdgkhfdklg55555hfdkhg
In the above example number 123456789012 is masked to 12XXXXXX01 but the number 55555 remains same as length of 55555 is 5 and we will only mask the number whose length is between 10 to 12 .
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Nov 23, 2014
I've to return some value as a string and some as a int, how is this possible? Here's my code:
public class Card {
public void start(){
String [] suit = {"Spade","Club","Diamond","Heart"};
int [] number = {1,2,3,4,5,6,7,8,9,10,11,12,13};}
public String getColour(){
String [] suit = {"Spade","Club","Diamond","Heart"};
[Code] .....
So at the top, i've set it to return value as string because of the King Jack Queen and Ace, but i also have to return as numbers(int). And also i'm using a loop to read all the numbers, is there any other way?
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Sep 12, 2014
I am trying to write a regular expression for a text which has both String and number... like abc1234, xyz987, gh1052 etc. And the string usually contains 2 or 3 characters.
What I need is two Strings one containing the text (abc, xyz, gh etc) and other containing number (1234, 987, 1052, etc.). Have written the code below. but doesn't seem to work.
String query = "abc1052"; //Or query = "zyx900";
String regexp = "(.{3})(d*)|(.{2}(d*))";
Pattern pattern = Pattern.compile(regexp);
Matcher match = pattern.matcher(query);
if(match.find()){
[Code] ....
Also tried with regexp = "(.s*)(.d*)" in no avail.
Finally achieved with regexp = "(D*)(d*)";
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Oct 24, 2014
Some of the numbers can be converted from int to string , other cant. My problem is in if (input.length() == 3) and if (input.length() == 4. Basically having problems printing the 3 digit and 4 digit
public static void main(String[] args) {
System.out.print("Skriv: ");
Scanner console = new Scanner(System.in);
String input = console.nextLine();
int firstDigit = 0;
int secondDigit = 0;
int thirdDigit = 0;
int lastDigit = 0;
[code]....
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Oct 16, 2014
the number of occurrences of a specified character in a string...i tried to do the program occurrences in a given string and i tried the code as below.
code:
import java.util.*;
public class Occurrence
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
[code]....
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Sep 29, 2011
I'm trying to write a method that returns a number, given an uppercase letter as follows:
public static int getNumber(char uppercaseLetter)
The program is supposed to prompt the user to enter a phone number as a string. The input number may contain letters. The program translates a letter (upper- or lowercase) to a digit and leaves all other characters intact.
My code is below:
import java.util.*;
public class PhoneKeypad {
public static void main(String[] args){
System.out.print("Enter a string: ");
Scanner input = new Scanner(System.in);
String phNumber = input.next();
[Code] ....
I am getting these errors:
java.lang.ClassFormatError: Duplicate field name&signature in class file Chapter9/PhoneKeypad
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(ClassLoader.java:791)
at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142)
[Code] ...
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