How To Compare Integer To A String Variable Array

Apr 17, 2014

I'm trying to do something like this:

Java Code:

for (int i=1; i<2; i++);
int randomNum = rn.nextInt(range) + 1;
if (randomNum == CardList.CARD_NAME[randomNum]){
} mh_sh_highlight_all('java');

But the CARD_NAME variable is a string. I just want to compare the array to the integer.

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How To Limit Users To Only Enter Integer Into String Variable

Feb 7, 2014

I need to allow users only enter integer into a String variable, "input" and I am not sure what statement to use.

import java.util.Scanner;
public class assq2b {
public static void main(String []args) {
Scanner reader = new Scanner(System.in);
String input,b;

[Code] ......

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How To Compare String To Each Element Of String Array

Mar 28, 2014

How do I compare a String to each element of a string array?

For example:

int headscount = 0;
if (coins[i].equals("heads")){
headscount++;
System.out.println("b" + headscount);
}

This doesn't give me the right value because the IDE says that equals() is an incompatible type. I also tried changing the "heads" to an variable, but the results remains the same.

I would prefer using an Array!

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Feb 8, 2014

What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?

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GUI JTextArea - Converting Integer To String Array

Sep 28, 2014

Run the code along with the attached csv file. The GUI contains a short explanation of what I am looking for. I have tried converting the integer array to a string array but the output is not the same as the command line. I receive errors when I compile.

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Swing/AWT/SWT :: Compare Inputted String With Key String

Aug 28, 2014

I have a method for a button so when a user inputs something it then will get the string value and check it against the string value within the properties file to see if it exists.

The properties file is called GitCommands.properties that contains -- > key = value <-- in it

I realised I have not used it correctly hence why I keep getting errors - I am lost on how to use it, I think perhaps that may be the issue here? I need to reference the file but I am doing it wrong? When I do use that piece of code I get null pointer exception too...

textFieldSearch.getText().equals(GitCommands.keys());

This is my button:

JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
FindSelectedKey();

[code] .....

I understand I am missing my piece of code where it states "//determine whether the string is equal to the property file key string" I understand the logic fine but not actually coding it.

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How To Use Previous String Compare To Current String

Mar 2, 2014

I'm having trouble to compare two string from my LinkedList. I took me 2 days now trying figure out how to compare the current string to previous string in the linkedlist. Here is my code.

public int compareTo(LinkedListNode n){
//Compare two string
String myHead = data.toLowerCase();
String comparableHead = data.toLowerCase();
 
return (myHead.compareTo(comparableHead));
}

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How To Compare String In If Else

Feb 10, 2009

how do i compare string in if else ?

cos if i do these, it get an error of

Comparing string using == or !=

if(carModel == "Honda") {

car.setCarID(1);

car.setCarModel("Toyota");

car.setCarDescription("Powered by VVTi Engine");

car.setCarTransmission("Auto");

car.setCarPrice(56000);

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Compare Substring With String?

Apr 22, 2014

Why isn't it working?

Java Code:

if ((line.substring(i,i+2)) == "go")
break; mh_sh_highlight_all('java');

I printed this to check if substring works fine, used this:

Java Code: System.out.println(line.substring(i,i+2) + " : "+ length); mh_sh_highlight_all('java');

So, output:

Er : 1

ra : 2

ag : 3

go : 4

on : 5

n' : 6

'> : 7

Line:

String line = "Eragon'>";

Shouldn't it break loop after printing "go : 4"?

line.substring(i,i+2) prints go here. But if doesn't work.

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How To Compare Public String Value

Sep 7, 2014

I want to make a program in which i write the Months Strings via while into the checkbox.

I already did that but i have also to add an day if February is a loop day.

So my question is how to say java that if Months is equal to February & year is a leap year, add 1. (i didn't wrote the year code because it's not relevant for my problem.)

Java Code:

public String[] Months ={"January","February","March","April","May", "June", "July", "August", "September", "Oktober", "November", "December"};
public Asg1KeapYear() {
initComponents();
int MonthNo = 0;

[Code] ....

Netbeans shows me .equals() on incompatible types on Months.equals, do i have to declare it somehow?

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How To Compare Int To Empty String To Input Error

Apr 16, 2015

I am having issues with the program below everything works but I can't figure out a way to add code that if a user just hits enter without inputting anything it says "entering in nothing is not a valid choice" I am stuck on how to compare a int to a string ...

//import statements
import java.util.*; //for scanner class
// class beginning
public class Guess {
public static void main(String[] args ) {
//Declare variables area

[Code] ....

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How To Compare String In Binary Search Tree

Aug 31, 2014

I'm trying to implement a Binary Search Tree that accepts strings. I cannot figure out how to compare the string value in my add method against the node object. While I could make the node class data be the string type I am trying to make the code be as reusable as possible. So my question is this, is there a simple way I can compare the two that I am missing?

public class BTNode<E> {
private E data;
private BTNode<E> left, right;
//constructor
public BTNode(E initialData, BTNode<E> initialLeft, BTNode<E> initialRight) {
data = initialData;
left = initialLeft;
right = initialRight;

[Code] ....

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Jul 3, 2014

I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.

Java Code:

String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');

What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.

I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.

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Dec 24, 2014

I need to compare an int with an array of values generated with a for loop previously. I have something like that for the search..

for( int i = 0; i < 5; i++){
System.out.print("Indovina.. inserisci un valore: ");
// I memorize the value taken input
n = sc.nextInt();

[Code] ....

Also, I need to print the array each time I insert a value that is in the array. But, hiding the values still not "guessed".

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Oct 27, 2014

So I am trying to create a code that searches if a word is square free. The user inputs a word (into an array) and then the code is suppose to see if it is square free. A word being square free means that the word doesn't contain any consecutive sub words. For example, "abcabc" is not a square free word because abc is repeated, but "abcdabc" is a square free word because there is a "d" separating the "abc".

So far I have this :

import java.util.Scanner;
public class A3Q2 {
public static void main(String[] args) {
// part (a) of the main
Scanner keyboard = new Scanner(System.in);

[Code] ....

I've been trying to experiment with different ways such as checking to see if there any duplicate elements such as,

public static char isSquareFree(char[] word){
for(char i = 1; i < word.length; i++) {
if(word[i] == word[i - 'a']) {
System.out.println("Duplicate: " + word[i]);
}
}
return word; }
}

And other methods but I'm just not getting it.

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How To Compare Int To A Empty String To Input Error Message To User

Apr 16, 2015

I made a guess a number program but I am having issue figuring out a way that when a user enter's in nothing for the program to spit out a message saying "hey entering nothing doesn't work try again" then ask for input. I have done some research and from what I have found is to read the input in as a String rather than int, and use something like Integer.valueOf() to get the integer value but I am completely lost on how to apply that to my program here is my code

//import statements
import java.util.*; //for scanner class
// class beginning
public class Guess {
public static void main(String[] args ) {
//Declare variables area
int guess, secretNumber = (int) (Math.random() * 10 + 1), lowGuess,highGuess;

[Code] ....

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How To Use Value Of String Variable Cel1 As Variable Name

May 23, 2014

I have a JFrame jf and JPanel jp on it. jp has five TextFields named cel1, cel2.. cel5. I wish to construct a String Cel + for loop index and run a for loop to reset the values of all the text fields using a single statement such as cel1.SetText("abc"). Similar things can be done in foxfro. How does one do it in java?

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Write A Statement That Reads User Input Integer Into Defined Variable

Jan 20, 2015

so i'm following a java tutorial from the book and it has a few challenge questions. and i'm stucked on one. i think i just don't understand what is it that its asking me. heres the question, Write a statement that reads a user's input integer into the defined variable, and a second statement that prints the integer. assuming scanner is given, and i checked my heading code is ok.
 
Scanner scnr = new Scanner(System.in);
int userNum = 0;
System.out.println("What is the product of 8 time 2");
userNum = scnr.nextInt();

[code]....

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Nov 11, 2014

I have a 2-D character array and I was wondering if I can compare a given index to an out of bounds index and what would I have to write? For instance

if(array[0 - 1][0 - 1] == 'indexoutofbounds'){ **// I know that 'indexoutofbounds' is probably not the right wording**
stuff happens
}

If I can do this what would I actually have to write in where it says 'indexoutofbound' ?

I will be using this for many indexes so it wont always be [0 - 1][0 - 1] it could be [4 - 1][3 - 1] in which case it wouldn't be out of bounds and wouldn't move onto "stuff happens"....

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Aug 10, 2014

How can I access the index of one character array and store those indexes into another array? I need this array of indices so as to perform an addition with another array.

Suppose I have a char array that stores all the letters of the alphabet (say alpha) and I have an another char array (say letter) that contains some letters in it. I want to retrieve those letters from the "letter" array and check its index in the "alpha" array and store that index into another integer array.

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Apr 29, 2014

Code:
public static void main(String[] args) {
// TODO code application logic here
Calendar time = Calendar.getInstance();
int min = 1;//time.get(Calendar.MINUTE);
String blank = "0";
int checker = ((min > 10 ) ? min : blank+min);
System.out.println("The time is " + "12" + ":" + checker );
}

This is my code, as you can see, I have if the min is less than 10, display the string "0" next to it so it will be something like

blank is zero and min is one

So it will display as 01 but after min reaches 10 and above, the 0 goes away. Problem I have is, you just cant add "blank" to int checker because checker is an int and blank is a string. So what must I do in order for it to display the 0 under checker?

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Sep 24, 2014

I've started writing a new program that Scans for some strings. I want to specify a random Integer to those Strings in order to do my desired idea. what should I do?!! my codes are here :

import java.util.Random;
import java.util.Scanner;
public class Draw {
public static void main(String[] args) {
System.out.println("This Program is written to solve little problems in families cause of doing unwanted works!!");

[code].....

now I want to Specify an Integer to each person that has been scanned! for example if the first person is " David " , which is a String, in the next step :

Random randomNumber = new Random();
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int David = randomNumber.NextInt(101);

I want to what should I do?

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May 21, 2014

I have to make a programm where the user gives you the bank sorting code and the account number and you give him the IBAN. That was so far no problem and I was done within minutes except of one thing that I simply can't figure out even though im trying since weeks. At some point I have to convert a string to integer. My research told me its with parseInt() and I dont get a syntax error when I compile my programm (using BlueJ). But when executing the programm stops and gives me some weird bug message. Here is code and bug message:

Java Code:

public class IBAN {
public IBAN(String Bankleitzahl, String Kontonummer) {
Bankleitzahl=Bankleitzahl.replace(" ",""); // Die Leerzeichen werden entfernt
int Anzahl=Bankleitzahl.length(); // Auf der Variabel Anzahl wird die Anzahl der Zeichen von der Bankleitzahl gespeichert

[Code] .....

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I want to conver String value into Integer, and I have this :

String timeInterval = tfInputTinter.getText();

Integer tint=(Integer.parseInt(timeInterval))*1000;

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I am having problem in converting JSTL variable into integer type in JSP (not using Spring). I am looking to do something like below:

<c:set var="total_amt">${list.totalAmount}</c:set>
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If I use the class DecimalFormat to format long number, how can I convert it back to integer?

DecimalFormat longFormat = new DecimalFormat("#,###");
long testLong=11000;
String strLong=longFormat.format(testLong);
System.out.println("NUM : " + strLong);
//Assume that at this point I don't have
//testLong, I have only the strLong value...
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//java.lang.NumberFormatException: For input string: "11,000

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