How To Continue With Loop If User Decides To Not Quit

Mar 29, 2015

I have this program I have to write(attached). I am having problems with what the structure will look like. The following what I have so far. The questions I have are in bold.

>get userInput of how many observations

>for(int i = 1; i <= userInput; i++)
>for(int j = 1; j <= 1; j++)
>use a switch(case) method to ask user to select an option(1,2,3)
>example, user chooses option 1:
>ask to input time
>print displacement
>ask user to stop application(Y/N)
>IF "No" is selected --------->>

How do I continue with the loop if user decides to not quit? -- And do I need to put this in each 'case'?

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I have everything else working. My problem is that when i type "quit" to close the outer loop. It still runs the inner loop. The National Bank manager wants you to code a program that reads each clients charges to their Credit Card account and outputs the average charge per client and the overall average for the total number of clients in the Bank.

Hint: The OUTER LOOP in your program should allow the user the name of the client and end the program when the name entered is QUIT.In addition to the outer loop, you need AN INNER LOOP that will allow the user to input the clients charge to his/her account by entering one charge at a time and end inputting the charges whenever she/he enters -1 for a value. This INNER LOOP will performed the Add for all the charges entered for a client and count the number of charges entered.

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John Smith average $850.00
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Code:

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